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BIOL. 303 EXAM II 10/26/09 ---------------------------------------------------------------------------------------------------------------------This exam consists of 40 multiple choice questions worth 2.5 points each. On the separate answer sheet, please fill-in the single best choice for each question. Please bubble-in your name on the answer sheet, leaving a space between first and last names. Also, bubble-in the last 5 digits of your social security number under “ID NUMBER” beginning in the left-most column. Good luck! ---------------------------------------------------------------------------------------------------------------------1. In humans, the genetic basis for determining the sex “male” is accomplished by A. the Y chromosome B. the presence of only one X chromosome C. a balance between the number of X chromosomes and the number of haploid sets of autosomes D. multiple alleles scattered throughout the autosomes 2. Klinefelter syndrome in humans, which leads to underdeveloped testes and sterility, is caused by which chromosomal condition? A. B. C. D. 47, XXY 47, 21+ 45, X 47, XYY 3. In birds, sex is determined by a ZW chromosome scheme, which is much like the typical XY scheme seen in humans and many other organisms. However, in birds the system is reversed. Males are ZZ (similar to XX in humans) and females are ZW (similar to XY in humans). A lethal recessive allele that causes death of the embryo occurs on the Z chromosome in pigeons. What would be the sex ratio in the offspring of a cross between a male heterozygous for the lethal allele and a normal female? A. 2:1 male to female B. 3:1 male to female C. 1:2 male to female D. 1:1 male to female 4. Hemophilia is caused by a sex-linked recessive gene. Assume that a man with hemophilia marries a normal woman whose father had hemophilia. What is the probability that their first born child has hemophilia? A. 1/16 B. 1/8 C. 1/4 D. 1/2 5. What is the expected number of Barr bodies in an individual with the karyotype XYYY? A. 0 B. 1 C. 2 D. 3 6. The genotype XYYY produces a A. female in Drosophila and a female in humans. B. female in Drosophila and a male in humans. C. male in Drosophila and a male in humans. D. male in Drosophila and a female in humans. 7. When an organism gains or loses one or more chromosomes but not a complete haploid set, the condition is known as A. polyploidy B. aneuploidy C. triploidy D. trisomy 8. When a diploid organism gains a complete haploid set of chromosomes, the condition is known as A. haploidy B. aneuploidy C. triploidy D. trisomy 9. A somatic cell from a human with a trisomy would contain a total of how many chromosomes? A. 46 B. 69 C. 45 D. 47 10. The condition known as cri-du-chat syndrome in humans has a genetic constitution designated as. A. 45, X B. 46,5pC. triploidy D. trisomy 11. If an organism is heterozygous for a chromosomal inversion, then A. a condition of “semisterility” will occur in the absence of any crossing over. B. the organism must be phenotypically abnormal C. chromosome number is likely altered D. meiotic crossovers within the inverted interval will not be recovered in offspring. 12. Consider the following figure: The above figure depicts A. B. C. D. 13. An abnormal chromosome containing two genetically identical arms is called A. B. C. D. 14. a Robertsonian translocation the formation of an inversion. an example of unequal crossing over a reciprocal translocation a centric fusion an inversion chromosome an isochromosome a ring chromosome Diseases associated with “genetic anticipation” are often caused by A. insertion of foreign DNA into a chromosome. B. expansion of trinucleotide repeats. C. multiple inversions in the X chromosome. D. single translocations in the X chromosome. 15. Trisomy 21, or Down syndrome, usually occurs when there is a normal diploid chromosomal complement of 46 chromosomes plus one extra chromosome #21. While there is impaired fertility of both sexes, females are more likely to be fertile than males. Assume that children are born to a female with Down syndrome and a normal 46chromosome male. What proportion of the offspring would be expected to have Down syndrome? A. One half of the offspring will be expected to have Down syndrome. B. None of the offspring would be expected to have Down syndrome. C. All the children would be expected to have Down syndrome. D. Two-thirds of the offspring would be expected to have Down syndrome. 16. Cells from an individual with the familial form of Down syndrome will likely contain how many chromosomes? A. 47 B. 45 C. 23 D. 46 17. DNA, originally called “nuclein,” was discovered by A. Hershey and Chase B. Watson and Crick C. Friedrich Miescher D. Klug, Cummings, Spencer, and Palladino 32 18. P and 35S were used in the classic experiment conducted by Hershey and Chase because A. 32P labels DNA and 35S labels protein B. 32P labels protein and 35S labels DNA C. both radioisotopes label an entire phage including DNA and protein D. 32P labels DNA and 35S labels RNA 19. The basic structure of a nucleotide includes which of the following components? A. amino acids. B. base, sugar, phosphate. C. phosphorous and sulfate. D. all of the above. 20. If 20% of the nitrogenous bases in a sample of DNA from a particular organism is thymine, what percentage should be cytosine? A. 15% B. 30% C. 40% D. 35% 21. Which of the following clusters of terms accurately describes DNA as it is generally viewed to exist in prokaryotes and eukaryotes? A. Double-stranded, parallel, (A+T)/(C+G)= variable, (A+G)/(C+T)=1.0 B. Single-stranded, antiparallel, (A+T)/(C+G)=1.0, (A+G)/C+T)=1.0 C. Double-stranded, antiparallel, (A+T)/(C+G)=variable, (A+G)/(C+T)=1.0 D. Double-stranded, antiparallel, (A+T)/C+G)=1.0, (A+G)/(C+T)=variable 22. Which of the following is a pyrimidine base? A. B. C. D. 23. The two strands of a DNA helix are held together (to each other) by A. covalent bonds. B. hydrogen bonds. C. phosphodiester bonds. D. glycosidic bonds. 24. If the sequence of one strand of DNA is 5’-GCATAGGCC-3’, then the sequence of the complementary strand is A. B. C. D. 25. 5’-GCATAGGCC-3’ 5-’CCGGATACG-3’ 5’-CGTATCCGG-3’ 5’-GGCCTATGC-3’ Which statement is true? A. B. C. D. All DNA is in the form of a right-handed double-helix all of the time. DNA is usually in the form of a left-handed helix. Structurally, the two strands of DNA in a helix have the same polarity. As a rule, a higher GC content means a higher melting point for a DNA helix. For questions 26-27 refer to the replication fork depicted below: 5’ 3’ B A 3’ 5’ B B C 5’ 3’ 26. Item A is called A. B. C. D. 27. the leading strand. primase. single strand binding protein. an Okazaki fragment. B is most likely: A. an RNA primer. B. a DNA primer. C. DNA polymerase III. D. an exonuclease. 28. The enzyme that appears to be inappropriately expressed in cancer cells and helps to maintain the very ends of eukaryotic chromosomes is called A. topoisomerase. B. ligase. C. telomerase. D. terminase. The “Hayflick limit” refers to 29. A. B. C. D. How far a DNA polymerase can travel along a template The limited number of cell divisions a human cell can undergo in vitro The temperature at which most DNA melts. The farthest distance anyone has ever thrown a piece of hay. 30. In addition to highly repetitive and unique DNA sequences, a third category of DNA sequences exists. What is it called and what types of elements are involved? A. B. C. D. 31. composite DNA, telomeres and heterochromatin dominant DNA, euchromatin and heterochromatin multiple gene family DNA, hemoglobin and 5.0S RNA middle repetitive DNA, SINEs, LINEs, and VNTRs The equation L = T + W has something to do with A. DNA supercoiling B. Mendel’s experiments C. balanced translocations D. None of the above 32. Chromatin of eukaryotes is organized into repeating interactions with protein octomers called nucleosomes. Nucleosomes contain which class of protein molecules? A. histones B. glycoproteins C. lipids D. nonhistone chromosomal proteins 33. An enzyme that controls supercoiling in DNA is called A. B. C. D. 34. telomerase polymerase reverse transcriptase topoisomerase Mutations which arise in nature from no particular artificial agent are called A. induced mutations. B. spontaneous mutations. C. chromosomal aberrations. D. cosmic mutations. 35. Microsatellite DNA sequences A. are present in one copy per haploid genome B. are completely deleted in Patau syndrome C. resemble tiny weather satellites D. are present in eukaryote genomes as tandem repeats of a very short sequence 36. In a transition mutation, A. a pyrimidine substitutes for a purine. B. a purine substitutes for a purine. C. a single nucleotide is inserted D. a translocation occurs. 37. Ultraviolet light causes pyrimidine dimers to form in DNA. Some individuals are genetically incapable of repairing dimers at normal rates. Such individuals are likely to suffer from A. xeroderma pigmentosum. B. phenylketonuria. C. muscular dystrophy. D. Huntington disease. 38. The DNA repair pathway that starts with the action of a DNA glycosylase is A. nucleotide excision repair B. photoreactivation C. base excision repair D. mismatch repair 39. In mammals, DNA double-strand breaks may be repaired by A. nonhomologous end-joining. B. base excision repair. C. nucleotide excision repair. D. mismatch repair. 40. During mismatch repair in bacteria, the newly synthesized strand is distinguished from the old strand by A. a strand break on the old strand. B. methylation on the new strand. C. methylation on the old strand. D. nothing; the strands cannot be distinguished. That’s all! Answer Key Q: 1, 2, 3, 4, 5, 6, 7, 8, 9,10,11,12,13,14,15,16,17,18,19,20, A: A, A, A, D, A, B, B, C, D, B, D, C, C, B, A, D, C, A, B, B, Q:21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40 A: C, A, B, D, D, D, A, C, B, D, A, A, D, B, D, B, A, C, A, C