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Prescott’s Microbiology, 9th Edition 16 Mechanisms of Genetic Variation CHAPTER OVERVIEW This chapter begins with a discussion of mutation and genetic variation and includes molecular mechanisms of mutation and repair. A general discussion of bacterial recombination, plasmids, and transposable elements follows, with examination of the acquisition of genetic information by conjugation, transformation, and transduction. LEARNING OUTCOMES After reading this chapter you should be able to: • distinguish spontaneous from induced mutations, and list the most common ways each arises • construct a table, concept map, or picture to summarize how base analogoues, DNA-modifying agents, and intercalating agents cause mutations • discuss the possible effects of mutations • differentiate mutant detections from mutant selection • design an experiment to isolate mutant bacteria that are threonine auxotrophs • propose an experiment to isolate revertants of a threonine auxotroph and predict the types of mutations that might lead to the revertant phenotype • explain how the Ames test is used to screen for potential carcinogens and evaluate its effectiveness • compare and contrast excision repair, direct repair, mismatch repair, and recombinational repair • propose a scenario that would elicit SOS response and describe the response to those conditions • describe in general terms how recombinant eukaryotic organisms arise • distinguish vertical gene transfer from horizontal gene transfer • summarize the four possible outcomes of horizontal gene transfer • compare and contrast homologous recombination and site-specific recombination • differentiate insertion sequences from transposons • distinguish simple transposition from replicative transposition • defend this statement “Transposable elements are important factors in the evolution of bacteria and archaea.” • identify the type of plasmids that are important creators of genetic variation • describe the features of the F factor that allow it to (1) transfer itself to a new host and (2) integrate into a host cell’s chromosome • outline the events that occur when an F+ cell encounters an F- cell • distinguish F+, Hfr and F’ cells from each other • explain how Hfr cells arise • outline the events that occur when an Hfr cell encounters an F- cell • describe the factors that contribute to a bacterium being naturally transformation competent • predict the outcomes of transformation using a DNA fragment versus using a plasmid • design an experiment to transform bacteria that carries genes encoding ampicillin resistance and the protein that generates green fluorescence • differentiate generalized transduction from specialized transduction • create a phage’s life cycle to its capacity to mediate generalized or specialized transduction • draw a figure, create a concept map, or construct a table that distinguishes conjugation, transformation, and transduction 1 © 2014 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Prescott’s Microbiology, 9th Edition CHAPTER OUTLINE I. II. Mutations A. Mutation overview 1. A mutation is a stable, heritable change in the genomic nucleotide sequence; this can be a single base change (point mutation), changes of several bases, or larger insertions, deletions, inversions, duplications, and translocations 2. Mutations can arise in two ways: a. Spontaneous mutations arise occasionally in the absence of any added agent b. Induced mutations are the result of exposure to a mutagen (physical or chemical agent) B. Spontaneous mutations 1. Arise occasionally in all cells without exposure to external agents; they are often the result of errors in replication or lesions to the DNA 2. Errors in replication can be due to tautomeric shifts, which cause base substitutions a. Transition mutation—substitution of one purine for another, or of one pyrimidine for another b. Transversion mutation—substitution of a purine for a pyrimidine or vice versa 3. Lesions in the structure of DNA; the loss of a nitrogenous base creating an apurinic or apyrimidinic site can cause spontaneous mutations C. Induced mutations 1. Mutations can be induced by agents that damage DNA, alter its chemistry, or interfere with its functioning 2. Base analogs are structurally similar to normal nitrogenous bases and can be incorporated into DNA during replication, but exhibit base-pairing properties different from the bases they replace 3. Specific mispairing occurs when a mutagen is a DNA-modifying agents that changes a base’s structure and thereby alters its pairing characteristics (e.g., alkylating agents) 4. Intercalating agents, which become inserted between the stacked bases of the helix, distort the DNA and thus induce single nucleotide pair insertions or deletions D. Effects of mutations 1. Forward mutation—a conversion from the most prevalent gene form (wild type) to a mutant form 2. Reversion mutation—a second mutation event that makes the mutant appear to be a wild type again a. Back mutation (true reversion)—conversion of the mutant nucleotide sequence back to the wild-type sequence b. Suppressor mutation—a reestablishment of the wild-type phenotype by a second mutation that overcomes the effect of the first mutation; can be in the same gene or a different gene, but does not restore the original sequence 3. Mutations in protein-coding genes a. Silent mutations are alterations of the base sequence that do not alter the amino acid sequence of the protein because of code degeneracy b. Missense mutations are alterations of the base sequence that result in the incorporation of a different amino acid in the protein; at the level of protein function, the effect may range from complete loss of activity to no change in activity c. Nonsense mutations are alterations that produce a translation termination codon; this results in premature termination of protein synthesis; location of the mutation within the protein will determine the extent of change in function d. Frameshift mutations are insertions or deletions of one or two base pairs that thereby alter the reading frame of the codons e. Conditional mutations are expressed only under certain environmental conditions f. Biochemical mutations result in changes in the metabolic capabilities of a cell; auxotrophs cannot grow on minimal media because they have lost a biosynthetic capability and require supplements; prototrophs are wild-type organisms that can grow on minimal media g. Resistance mutations result in acquired resistance to some pathogen, chemical, or antibiotic 4. Mutations in regulatory sequences Detection and Isolation of Mutants A. Mutant detection 2 © 2014 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Prescott’s Microbiology, 9th Edition 1. 2. Visual observation of changes in colony characteristics Auxotrophic mutants can be detected by replica plating on media with and without the growth factor required; mutants are those growing with the factor but not without it B. Mutant selection is achieved by finding the environmental condition under which the mutant will grow but the wild type will not (useful for isolating auxotrophic revertants, resistance mutants, and substrate utilization mutations) C. Mutagens and carcinogens 1. Many cancer-causing agents (carcinogens) are also mutagens, therefore tests for mutagenicity can be used as a screen for carcinogenic potential 2. The Ames test is a widely used mutagenicity test; it detects an increase in reversion of special strains of Salmonella typhimurium from histidine auxotrophy to prototrophy after exposure to a potential carcinogen III. DNA Repair A. Proofreading: The first line of defense 1. replicative DNA polymerases sometimes insert incorrect nucleotide sequences during DNA replication 2. DNA polymerases can evaluate and correct any errors B. Mismatch repair 1. The mismatch repair system corrects replication errors that result in mismatched base pairs; newly replicated DNA is detected by a lack of DNA methylation 2. The mismatch is detected by MutS and repaired through excision by MutH C. Excision repair 1. Corrects damage that causes distortions of DNA (e.g., thymine dimers, apurinic or apyrimidinic sites, damaged or unnatural DNA) 2. For nucleotide excision repair, the damaged area is excised, producing a single-stranded gap, and then the gap is filled in by DNA polymerase I, and DNA ligase joins the new fragment into the existing DNA strand 3. For base excision repair, DNA glycosylases remove the damaged base, and this signals AP nucleases to mark the damaged DNA, which is then excised and repaired by DNA polymerase I and ligase D. Direct repair 1. thymine dimers and alkylated bases repair occurs through photoreactivation or the action of alkyl- or methyltransferases, respectively 2. catalyzed by enzyme photolyase E. Recombinational repair 1. Recombination with an undamaged molecule, if available, is used to restore DNA that has damage in both strands through the action of RecA protein; an undamaged molecule can be available in rapidly dividing cells where there is a copy of the chromosome that has not yet segregated into daughter cells F. The SOS response 1. SOS repair is a type of recombination repair that depends on the RecA protein; it is used to repair excessive damage that halts replication; it is an error-prone process that results in many mutations 2. RecA derepresses the synthesis of a variety of DNA repair genes; very serious damage is treated by translesion DNA synthesis that is highly error prone IV. Creating Additional Genetic Variability A. Sexual reproduction and genetic variability 1. vertical gene transfer 2. observed in all organisms capable of sexual reproduction B. Horizontal gene transfer: creating variability the asexual way 1. Horizontal (or lateral) gene transfer moves genes from one mature, independent organism to another (compare this to vertical gene transfer—transmission of genes from parents to offspring) 2. Exogenote—donor DNA that enters the bacterium by one of several mechanisms a. Conjugation is direct transfer from donor bacterium to recipient while the two are temporarily in physical contact b. Transformation is transfer of a naked DNA molecule c. Transduction is transfer mediated by a bacteriophage 3 © 2014 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Prescott’s Microbiology, 9th Edition 3. Endogenote—the genome of the recipient a. Merozygote—a recipient cell that is temporarily diploid for a portion of the genome during the gene transfer process 4. Intracellular fates of exogenote a. Integration into the host chromosome b. Independent functioning and replication of the exogenote without integration (a partial diploid clone develops) c. Survival without replication (only the one cell is a partial diploid) d. Degradation by host nucleases (host restriction) C. Molecular recombination: joining DNA molecules together 1. General recombination usually involves a reciprocal exchange in which a pair of homologous sequences breaks and rejoins (double-stranded break model) in a crossover; nonreciprocal general recombination involves the incorporation of a single strand into the chromosome to form a stretch of heteroduplex DNA 2. Site-specific recombination is the nonhomologous insertion of DNA into a chromosome; often occurs during viral genome integration into the host, a process catalyzed by enzymes specific for the virus and its host 3. Transposition is a kind of recombination that occurs throughout the genome and does not depend on sequence homology V. Transposable Elements A. Transposition is the movement of pieces of DNA around in the genome; transposons are segments of DNA that can move about chromosomes, "jumping genes" B. Insertion sequences (IS elements) contain genes only for those enzymes required for transposition (e.g., transposase); they are bound on both ends by inverted terminal repeat sequences C. Some transposons carry other genes in addition to those needed for transposition (e.g., for antibiotic resistance, toxin production, etc.) D. Transposition can occur by two mechanisms: 1. Simple transposition is a cut-and-paste process involving transposase-catalyzed excision of a transposon and insertion into a new target site 2. Replicative transposition is a mechanism during which a replicated copy of the transposon inserts at the target site on the DNA, while the original copy remains at the parental site E. Effects of transposable elements 1. Insertional mutagenesis can cause deletion of genetic material at or near the target site, arrest of translation or transcription due to stop codons or termination sequences located on the inserted material, and activation of genes near the point of insertion due to promoters located on the inserted material 2. Fusion of plasmids and insertion of F plasmids into chromosomes 3. Generation of plasmids with resistance genes F. Conjugative transposons can move between bacteria through the process of conjugation VI. Bacterial Conjugation A. The transfer of genetic information via direct cell-cell contact; this process is mediated by fertility factors (F plasmids) B. F+ F– mating 1. In E. coli and other gram-negative bacteria, an F plasmid moves from the donor (F+) to a recipient (F–) while being replicated a. Replication is by the rolling circle mechanism where the 3' end is extended from a nick in one DNA strand, following around the circular genome, and displacing the 5' end b. The displaced strand is transferred via a sex pilus and then copied to produce double-stranded DNA; the donor retains the other parental DNA strand and its complement; thus the recipient becomes F+ and the donor remains F+ c. Chromosomal genes are not transferred C. Hfr conjugation 1. F plasmid integration into the host chromosome results in an Hfr (high frequency of recombination) strain of bacteria 4 © 2014 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Prescott’s Microbiology, 9th Edition The mechanics of conjugation of Hfr strains are similar to those of F+ strains The initial break for rolling-circle replication is at the integrated plasmid’s origin of transfer site a. Part of the plasmid is transferred first b. Chromosomal genes are transferred next c. The rest of the plasmid is transferred last 4. Complete transfer of the chromosome takes approximately 100 minutes, but the conjugation bridge does not usually last that long; therefore, the entire F factor is not usually transferred, and the recipient remains F– D. F conjugation 1. When an integrated F plasmid leaves the chromosome incorrectly, it may take with it some chromosomal genes from one side of the integration site; this results in the formation of an abnormal plasmid called an F plasmid 2. The F cell (cell harboring an F plasmid) retains its genes, although some of them are in the chromosome and some are on the plasmid; in conjugation, an F cell behaves as an F+ cell, mating only with F– cells 3. The chromosomal genes included in the plasmid are transferred with the rest of the plasmid, but other chromosomal genes usually are not 4. The recipient becomes an F cell, and a partially diploid merozygote E. Other examples of bacterial conjugation 1. Less is known about conjugative transfer in gram-positive bacteria 2. No sex pilus is formed; however, cells may directly adhere to each other using special plasmidencoded proteins VII. Bacterial Transformation A. Transformation—a naked DNA molecule from the environment is taken up by the cell and incorporated into its chromosome in some heritable form B. A competent cell is one that is capable of taking up DNA and therefore acting as a recipient; only a limited number of species are naturally competent; the mechanics of the natural transformation process differ from species to species C. Species that are not normally competent (such as E. coli) can be made competent by calcium chloride treatment and other methods that make the cells more permeable to DNA VIII. Transduction A. Transduction is the transfer of bacterial genes by viruses (bacteriophages); it occurs as the result of the reproductive cycle of the virus 1. Lytic cycle—a viral reproductive cycle that ends in lysis of the host cell; viruses that use this cycle are called virulent bacteriophages 2. Lysogeny—a reproductive cycle that involves maintenance of the viral genome (prophage) within the host cell (usually integrated into the host cell’s chromosome), without immediate lysis of the host; with each round of cell division, the prophage is replicated and inherited by daughter cells; bacteriophages reproducing by this mechanism are called temperate phages; certain stimuli (e.g., UV radiation) can trigger the switch from lysogeny to the lytic cycle B. Generalized transduction 1. Transfer of any portion of the bacterial genome; occurs during the lytic cycle of virulent and temperate bacteriophages 2. The phage degrades the host chromosome into randomly sized fragments 3. During assembly, fragments of host DNA of the appropriate size can be mistakenly packaged into a phage head (generalized transducing particle) 4. When the next host is infected, the bacterial genes are injected and a merozygote is formed a. Preservation of the transferred genes requires their integration into the host chromosome b. Much of the transferred DNA does not integrate into the host chromosome, but is often able to survive and be expressed; the host is called an abortive transductant C. Specialized transduction 1. Transfer of only specific portions of the bacterial genome; carried out only by temperate phages that have integrated their DNA into the host chromosome at a specific site in the chromosome 2. 3. 5 © 2014 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Prescott’s Microbiology, 9th Edition a. The integrated prophage is sometimes excised incorrectly and contains portions of the bacterial DNA that was adjacent to the phage’s integration site on the chromosome b. The excised phage genome is defective because some of its own genes have been replaced by bacterial genes; therefore, the bacteriophage cannot reproduce c. When the next host is infected, the donor bacterial genes are injected, leading to the formation of a merozygote 2. Low-frequency transduction lysates—lysates containing mostly normal phages and just a few specialized transducing phages 3. High-frequency transduction lysates—lysates containing a relatively large number of specialized transducing phages; created by coinfecting a host cell with a helper phage (normal phage) and a transducing phage; the helper phage allows the transducing phage to replicate, thus increasing the number of transducing phages in the lysate IX. Evolution in Action: The Development of A. Antibiotic Resistance in BacteriaSpread of drug resistant pathogens a serious threat to public health 1. MRSA- methicillin resistant S. aureus 2. VRE-vancomycin resistant enterococci B. Mechanisms of drug resistance 1. modify the target of the antibiotic by mutating a gene that functions in the synthesis of the target 2. drug inactivation by Beta-lactam ring of penicillins by the enzyme penicillinase 3. efflux pumps expel drugs C. The origin and transmission of drug resistance 1. antibiotic resistance “captured” by horizontal gene transfer (HG) 2. R plasmids are resistance plasmids, code for enzymes that destroy or modify drugs 3. transposons can also carry antibiotic resistance genes 4. integron consists of a gene encoding an integrase and one or more genes that form a “gene cassette,” which can be moved by a plasmid to another cell via conjugation CRITICAL THINKING 1. A strain of bacteria is protrophic. How would you isolate from this strain one that requires the amino acid leucine (i.e., it is a leucine auxotroph)? 2. You have a bacterial strain that is a tryptophan auxotroph and sensitive to the antibiotic streptomycin. You expose this strain to a mutagen. How would you isolate mutants that no longer require tryptophan (i.e., strains that have reverted to prototrophy)? How would you isolate mutants that are resistant to streptomycin? How would you isolate mutants that no longer require leucine and that are resistant to streptomycin? 3. Explain how cotransductional frequencies of gene markers during bacteriophage transduction or transfer rates during conjugation can be used to produce genetic maps. CONCEPT MAPPING CHALLENGE Construct a concept map that describes the types of DNA repair mechanisms employed by organisms to protect their DNA. Use the concepts that follow, any other concpts or terms you need, and your own linking words between each pair of concepts in your map. 6 © 2014 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part. Prescott’s Microbiology, 9th Edition Proofreading Excision repair Mismatch repair SOS response Direct Repair Homologous recombination DNA synthesis Error prone repair Thymine dimer Rec A protein 7 © 2014 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part.