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Peer Instruction 5ʹ end of mRNA 3 2 2 Start of gene 1 (3ʹ end of template strand) 1 1 Protein Ribosome RNA polymerase 1) What is happening? 2) Why is this useful for the prokaryote? 3) Why can’t eukaryotes do this? End of gene (5ʹ end of template strand) Peer Instruction What is a disadvantage of the eukaryotic system? What is an advantage of the eukaryotic system? mRNA DNA Mature mRNA Mature mRNA Ribosome Protein Transcription and RNA processing in nucleus Translation in cytoplasm (not covered in your reading…) The following structure is sometimes found in the cytoplasm of a eukaryotic cell. What is going on here, and why? Peer Instruction A ‘guide’ protein that binds to both ends of the RNA 5’ cap A ribosome PolyA tail An RNA molecule Hint: Only one molecule is really moving… A new protein Monday January 23rd, 2017 Class 13 Learning Goals Genetic Codes • After this class, you should be able to: – Read and use a codon table for nearly every organism on Earth – Decode an open reading frame of DNA: – When given the frame – When you know that there is a start codon somewhere – On double-stranded DNA – Describe the advantages and disadvantages of coupling between transcription and translation in prokaryotes SECOND BASE Codon tables Phenylalanine (Phe) Tyrosine (Tyr) Cysteine (Cys) Stop codon Stop codon Stop codon Tryptophan (Trp) Histidine (His) Leucine (Leu) Isoleucine (Ile) Proline (Pro) Threonine (Thr) Methionine (Met) (Start codon) Glutamine (Glu) Arginine (Arg) Asparagine (Asn) Serine (Ser) Lysine (Lys) Arginine (Arg) THIRD BASE FIRST BASE Leucine (Leu) Serine (Ser) Aspartic acid (Asp) Valine (Val) Alanine (Ala) Glutamic acid (Glu) Glycine (Gly) Notice the redundancies (mostly, but not always, in the 3rd position) Peer Instruction What competitive disadvantage would you expect for a species that used a 2-base code? A 4-base code? In the diagram shown, what represents DNA? 3ʹ 5ʹ -35 -10 +1 TAC AUG UAG Do you think biologists are consistent in how they represent genes? N 5ʹ C 3ʹ Peer Instruction 5’ – AUG-UAC-GGC-CCU-UAA-3’ SECOND BASE Phenylalanine (Phe) Leucine (Leu) Serine (Ser) Tyrosine (Tyr) Cysteine (Cys) Stop codon Stop codon Stop codon Tryptophan (Trp) Histidine (His) Leucine (Leu) Isoleucine (Ile) Proline (Pro) Threonine (Thr) Methionine (Met) (Start codon) Glutamine (Glu) Arginine (Arg) Asparagine (Asn) Serine (Ser) Lysine (Lys) Arginine (Arg) Aspartic acid (Asp) Valine (Val) Alanine (Ala) Glutamic acid (Glu) Glycine (Gly) THIRD BASE FIRST BASE This RNA sequence starts from the start codon. Translate this sequence using the codon table. 5’–ATCTTAGCGGGAATTCATAGTC-3’ 5’–TAGAATCGCCCTTAAGTATCAG-3’ SECOND BASE Phenylalanine (Phe) Leucine (Leu) Serine (Ser) Tyrosine (Tyr) Cysteine (Cys) Stop codon Stop codon Stop codon Tryptophan (Trp) Histidine (His) Leucine (Leu) Isoleucine (Ile) Proline (Pro) Threonine (Thr) Methionine (Met) (Start codon) Glutamine (Glu) Arginine (Arg) Asparagine (Asn) Serine (Ser) Lysine (Lys) Arginine (Arg) Aspartic acid (Asp) Valine (Val) Alanine (Ala) Glutamic acid (Glu) Glycine (Gly) THIRD BASE FIRST BASE Peer Instruction Here is a piece of DNA. There is only one start codon. Translate! Peer Instruction What are the pieces of information that you need to be able to translate from any piece of DNA? Often, molecular biologists will say something like: “Please translate the sequence shown”. 5’–AATGAAGCGGGAATTCTAAGTC-3’ What is the incorrect assumption in this request? Imagine that this DNA is in an open reading frame. How many possible protein sequences could be encoded here? 5’–AACGAAGCG-3’ 3’–TTGCTTCGC-5’ Where does sigma bind? Peer Instruction In which direction does the RNA polymerase enzyme move? Termination signal for mRNA H -10 Promoter H -35 Where does the new RNA start and end? Termination signal for mRNA H This gene encodes the mRNA sequence shown. -10 Promoter H Peer Instruction -35 1: 5’-NNNNNNNNNNNNNCUUCAGC :20 21: GCCUGGUUUGCGCAUGUCCU :40 41: AUUGAGGGGACUUCUUAAAG :60 61: UGGNNNNNNN-3’ Where is the Start Codon? How long is the encoded protein? Concept Questions • • A single-celled eukaryote produces proteins more slowly than bacteria of similar size. – Why is this lack of coupling an advantage in highly mutagenic environments? – Why does the bacteria have an advantage in dark ocean-bottom environments with sporadic food surpluses? Create a random stretch of DNA of 40 bases long. – Translate in each direction as if the AUG was oriented to start the open reading frame at the 5’ end. – Then, retranslate by finding any start codons. – Do you have any unnecessary STOP codons in this DNA? – From your DNA, change the sequence to make it encode a 3-amino-acid protein. Do this with the least changes possible. Tuesday January 24th, 2017 Class 13 Learning Goals Mutations • After this class, you should be able to: – Assess whether or not a molecule is a likely mutagen based on specific chemical effects – Classify point mutations based on changes to a protein product – Predict the outcome of two different point mutations and infer which would likely have more influence on organism fitness – Predict relative effects of point mutations and chromosomal-scale mutations for organisms or cells – Define a gene What is a point mutation? Peer Instruction Examine the following changes. Does each change many proteins, change one protein, or have no impact? Δ in the DNA of a skin cell Δ in the DNA of a sperm cell Δ in a protein in a sperm cell Δ in an mRNA in a skin cell Which of these changes can impact fitness? Which of these changes is heritable? Is this a normal human karyotype? For a difference that you noticed: How many genes did this change impact? Peer Instruction Peer Instruction Match the following mutation types to the genes from the information found in this example: Genes: Regulatory enzyme Structural protein Mutation Type: Deletion Frameshift Ribosome factor Insertion ATP producer Missense Synonymous 16 Peer Instruction It would be helpful to define a gene. What would we need to include in a robust definition? 17 A working definition of the “gene”. A gene is a unit of genetic material that encodes the information necessary to produce one protein. – Usually DNA – Not necessarily continuous – Often guided by a promoter region Concept Questions • Create a random stretch of protein-coding DNA. Flip a coin, and if heads imagine that the promoter is on the left (and add the DNA needed to encode a start codon there as well). Pick any single base, and predict the mutation class: – If you remove the base – If you replace the base with two As – Change the base to a different base • Which of these changes for your DNA is most likely to destroy function of the protein? • Why are prenatal doctors much more likely to test for small chromosomal breakages than for point mutations of 5-20 bases? • Which is more likely to be mutagenic: – A cosmic ray that only changes A’s to U’s in DNA – A radioactive isotope that changes tyrosines to phenyalanines in proteins – An enzyme that can replace the DNA sequence ‘AGCGAGGTT’ with ‘AGTTAGGTT’ Here is section of double-stranded DNA. Assuming all possible mRNAs are made, which protein sequence or sequences will be created? 5-ACTAATGAGACCAGTATCATGTTAACG-3 3-TGAATACTCTGGTCATAGTACAATTGC-5 1. 2. 3. 4. 5. 6. A 6-amino-acid protein A 5-amino-acid protein A 4-amino-acid protein A 6-amino-acid protein and a 5-amino-acid protein A 5-amino-acid protein and a 4-amino-acid protein A 6-amino-acid protein and a 4-amino-acid protein Match the following mutation types to the mutations found in this example: Genes: Regulatory enzyme Structural protein Peer Instruction Mutation Type: Deletion Frameshift Ribosome factor Insertion ATP producer Missense Synonymous 21 Wednesday, January 25th, 2017 Class 14 Learning Goals DNA Replication • After this class, you should be able to: – Describe the genome-wide process of initiation of DNA replication – Define the role and predict a loss-of-function mutation result for each of the enzymes involved in replication – Given a diagram of replicating DNA, locate likely sites of action for each enzyme involved in replication – Assign descriptive terms appropriately to replication on the leading or lagging strands of a particular replication fork Peer Instruction A chromosome being replicated Circular chromosomes (like in prokaryotes) Old DNA New DNA Origin of replication Linear chromosomes (like most eukaryotes) 3 5 3 5 3 What is an ‘origin’? 5 New DNA 3 5 Replication bubble Old DNA Replication fork Why do eukaryotic chromosomes have multiple origins? Why is replication able to go in both directions? Primase synthesizes RNA primer (supplying a 3’ OH) 5ʹ 3ʹ 5ʹ Single-strand DNAbinding proteins (SSBP) Peer Instruction Topoisomerase relieves twisting forces Helicase opens double helix Why can’t DNA replication start without a primer? Why is ssBP important? What would be the phenotype of a mutation in: • Topoisomerase • Helicase Leading strand 3ʹ Peer Instruction Sliding clamp holds DNA polymerase III in place 5ʹ RNA primer 5ʹ The sliding clamp has no effect on DNA pol’s ability to catalyze one reaction. What does the sliding clamp do? Why is this called the ‘leading’ strand? In which direction is: • the replication fork moving? • the polymerase on this strand moving? Peer Instruction What is the engineering problem faced by the enzymes on the lagging strand? RNA primer 3ʹ 5ʹ 5ʹ Topoisomerase SSBPs Primase Helicase Describe the mechanisms shown here. 5ʹ 3ʹ 5ʹ Okazaki fragment Sliding clamp 3ʹ 5ʹ DNA polymerase III 5ʹ 3ʹ 3ʹ 5ʹ Okazaki fragment Okazaki fragment 5ʹ Peer Instruction Peer Instruction 5ʹ 3ʹ DNA polymerase I 3ʹ 5ʹ 5ʹ What is DNA polymerase I doing? 5ʹ 3ʹ DNA ligase 5ʹ 3ʹ 5ʹ What would be the phenotype of a deleterious mutation in the ligase-encoding gene? Homework: Replication Enzymes Chart Enzyme ssDBP Topoisomerase Helicase DNA Polymerase I DNA Polymerase III Sliding Clamp Primase Ligase Function Location Mutation Effects? Concept Questions • How does replication begin on a single small linear chromosome? What proteins are used? – How would this be different for an extremely large circular chromosome? • Complete the given chart for the enzymes involved in replication. For each enzyme, be able to justify the evolutionary advantage and protein cost of the enzyme. • Draw an upside down ‘Y’. Assume that the tail of the ‘Y’ is double stranded DNA. Fill in the locations of all of the enzymes from the chart based on where they are likely to act. You can assume that each arm of the ‘Y’ is 500 bases long and that an Okazaki fragment is 150 bases long on average. – When finished, complete the replication bubble with the other fork. • Which strand (leading or lagging) is best characterized as: – Simple? – Likely to have mutations? – More complicated in terms of enzymes – Likely to have a very long new strand – Bonus: Slower?