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Transcript
Gregor Mendel
1
Mendelian
Inheritance
Gregor Mendel
Austrian monk
Studied science and mathematics at
University of Vienna
Conducted breeding experiments with the
garden pea Pisum sativum
Carefully gathered and documented
mathematical data from his experiments
Formulated fundamental laws of heredity in
early 1860s
Had no knowledge of cells or chromosomes
Did not have a microscope
2
Fruit and Flower of the
Garden Pea
3
Garden Pea Traits
Studied by Mendel
4
Mendelian
Inheritance
5
Blending Inheritance
Theories of inheritance in Mendel’s time:
Based on blending
Parents of contrasting appearance produce
offspring of intermediate appearance
Mendel’s findings were in contrast with this
He formulated the particulate theory of
inheritance
Inheritance involves reshuffling of genes from
generation to generation
Mendel’s Monohybrid Crosses:
An Example
6
Mendelian
Inheritance
One-Trait Inheritance
Mendel performed cross-breeding
experiments
Used “true-breeding” (homozygous) plants
Chose varieties that differed in only one trait
(monohybrid cross)
Performed reciprocal crosses
- Parental generation = P
- First filial generation offspring = F1
- Second filial generation offspring = F2
Formulated the Law of Segregation
7
Mendel’s Monohybrid Crosses:
Mendelian
Inheritance
An Example
8
Mendelian
Inheritance
9
Law of Segregation
Each individual has a pair of factors (alleles)
for each trait
The factors (alleles) segregate (separate)
during gamete (sperm & egg) formation
Each gamete contains only one factor (allele)
from each pair
Fertilization gives the offspring two factors for
each trait
Mendelian
Inheritance
Modern Genetics View
Each trait in a pea plant is controlled by two
alleles (alternate forms of a gene)
Dominant allele (capital letter) masks the
expression of the recessive allele (lowercase)
Alleles occur on a homologous pair of
chromosomes at a particular gene locus
Homozygous = identical alleles
Heterozygous = different alleles
10
Homologous Chromosomes
11
Mendelian
Inheritance
12
Genotype Versus Phenotype
Genotype
Refers to the two alleles an individual has for
a specific trait
If identical, genotype is homozygous
If different, genotype is heterozygous
Phenotype
Refers to the physical appearance of the
individual
Mendelian
Inheritance
13
Punnett Square
Table listing all possible genotypes resulting
from a cross
All possible sperm genotypes are lined up on
one side
All possible egg genotypes are lined up on the
other side
Every possible zygote genotypes are placed
within the squares
Punnett Square Showing
Earlobe Inheritance Patterns
14
Try this one
MONOHYBRID CROSS
Cross a heterozygous tall plant with
a heterozygous tall plant (use T =
tall and t = short) Determine
expected genotype and phenotype
ratios.
15
16
Try these!
Show work
1. Cross a heterozygous red flower with a white
flower. What is the genotype and phenotype
ratio for the offspring? Key: R = red r = white
Mendelian
Inheritance
17
Two-Trait Inheritance
Dihybrid cross uses true-breeding plants
differing in two traits
Observed phenotypes among F2 plants
Formulated Law of Independent Assortment
- The pair of factors for one trait segregate
independently of the factors for other traits
- All possible combinations of factors can occur
in the gametes
Mendelian
Inheritance
18
Try Mendel’s Classic Dihybrid Cross
Cross two heterozygous tall, heterozygous
green pod producing plants. Use a punnett
square to show expected offspring and
complete a phenotype ratio.
Key:
T = tall
G = green pods
t = short
g = yellow pods
Mendelian
Inheritance
19
Two-Trait (Dihybrid) Cross
20
Must Know Your Vocab!
Homozygous?
Heterozygous?
Genotype?
Phenotype?
21
Try this one – DIHYBRID CROSS
2 traits
Key: T = tall R = red
-
t = short r = white
Cross two heterozygous tall,
heterozygous red flowered plants.
What is the phenotypic ratio of the
offspring?
22
Two-Trait (Dihybrid) Cross
23
P-square practice
Practice crosses – on a separate
sheet of paper.
• Show parental cross
• Show p-square
• Show phenotype ratio
24
25
WHAT’s IN YOUR GENES?
Mom = 22 autosomes plus X sex
chromosome
Dad = 22 autosomes plus X or Y
chromosome
26
Boy or Girl?
Dad determines this – sperm carries
22 autosomes and either an X or Y
sex chromosome
BOYS – your mom gave you the X
and dad gave you the Y – so what?
27
28
29
Sex-linked – disorders carried on the
X chromosome
- Colorblindness
- Hemophilia
- Baldness (?)
30
Analyze Sex-linked traits
Due tom!
31
32
33
34
- Albinism ppt
- Huntingtons ppt
- Final concepts
Autosomal Recessive Pedigree Chart
35
Autosomal Dominant Pedigree Chart
36
37
INHERITING
A GENE ALBINISM
38
This is an
albino
skunk. The
cells are not
able to
produce the
protein that
causes
color.
39
Cells in the skin produce a blackbrown pigment called melanin.
40
The chemical
melanin is
produced by
specialized cells
in the epidermis
called
melanocytes.
41
The melanin leaves the
melanocytes and enters other
cells closer to the surface of
the skin.
42
Different
shades of skin
colors is
determined by
the amount of
melanin
deposited in
these
epidermal cells
43
Sunlight
causes
melanocytes
to increase
production
of melanin.
44
A tan fades because the cells break down the melanin.
45
Some
organisms,
such as the
octopus,
can
rapidly
change
from light
to dark.
46
They control the color by scattering the
melanin in the cell for a dark color,
and concentrating the melanin in the
center for light color.
47
Melanin is made by the melanocytes
by chemically changing the amino
acid, phenylalanin, into tyrosine and
then into melanin.
48
An enzyme is required
to change tyrosine into
melanin.
49
If the enzyme is not
present, then melanin
cannot be produced by the
melanocytes.
50
The result of no melanin is an albino.
51
The eyes of an albino appear pink
because there is no dark melanin
in the eye to absorb light.
52
The blood in the retina and iris
reflects red light, resulting in pink
53
The gene
that
produces
this
enzyme
is on
chromosome 9
54
If both the
genes produce
the enzyme
tyrosinase,
there is plenty
to convert
tyrosine to
melanin.
55
If neither
gene
produces
tryosinase,
no melanin is
produced
and…
56
The
crow is
an
albino
rather
than the
normal
black
57
What if one
gene is
normal and
one gene does
not produce
the enzyme?
58
The one normal gene produces
enough enzyme to make normal crow
color
59
This albino squirrel received one albino gene from
the father and one albino gene from the mother.
60
But what if a squirrel
gets a normal gene
from one parent and
an albino gene from
the other parent?
61
The one
functioning
gene produces
enough enzyme
to make
melanin for
normal
coloration.
62
Is it
possible
for two
normal
colored
cockatiels
to have an
albino
offspring?
63
Yes!
Remember
the albino
has two
genes for
albinism.
One gene
from the
father and
one gene
from the
mother.
64
To be albino,
both genes
must be
albino genes
65
A normal
colored bird
could have
one albino
gene and one
normal gene.
66
If the sperm of a normal colored male pigeon
has an albino gene and the ova it fertilizes has
an albino gene than the offspring will be albino.
67
The same
happens in
humans. A
normal
pigment
father and
mother can
have an
albino
offspring.
68
We can see this in a genetic “family tree”
called a pedigree. The circles are
females, the squares are males. The open
symbols are normal coloration, the black
symbols are albino.
69
The parents in the circle have
normal pigment.
70
Most of the offspring received
at least one normal gene from
a parent.
71
But one female offspring
received an albino gene from
both the mother and the father.
72
A Punnett square is a matrix to show
the genetics of a mating.
73
What is the probability
of an albino doe giving
birth to a “normal”
fawn if she has mated
with a “normal” male?
The 74
female
must
have two
albino
genes
(use small
“a” for
the albino
gene
- aa
75
Since the albino gene is
relatively rare, the male
probably has two normal
genes of color. (Capital
“A” stands for the
normal gene)
- AA
AA X aa
76
77
Next, add the possible sperm and
ova genes.
A
A
a
Aa
Aa
a
Aa
Aa
As long as there is one normal
gene, none of the offsprings will
be albino
A
A
a
Aa
Aa
a
Aa
Aa
78
79
Therefore, all offsprings will have
a normal and an albino gene.
A
A
a
Aa
Aa
a
Aa
Aa
80
An albino must get one
albino gene from the
father and one albino
gene from the mother.
81
Then how
could an
albino
female
penguin
have an
albino chick.
82
The “normal” colored
father must have one
“normal coloration gene
and one albino gene.
83
There is only one
way for two normal
colored parents to
produce an albino
offspring.
84
Both parents must
have one normal
gene and one albino
gene.
Both
parents
have one
gene for
normal
and one
gene for
albinism.
Aa X Aa
85
The
father’s
sperm is
50%
with
normal
gene and
50%
with
albino
gene.
Aa X Aa
A
a
86
50% of
the
mother’s
ova have
a normal
gene and
50% of
the ova
have the
albino
gene
Aa X Aa
A
a
A
a
87
The ova and
sperm may
combine to
form an
offspring
with two
normal
genes, a
normal gene
and an albino
gene, or two
albino genes.
Aa X Aa
A
a
A AA Aa
a Aa aa
88
Only the
offspring
with two
albino
genes will
lack
pigment.
Aa X Aa
A
a
A AA Aa
a Aa aa
89
Sometimes an albino is born and
there is no history of albinism in
the colony.
90
91
The color
gene in the
cell that
produced this
white flower
changed to an
albino gene.
92
A change in a gene is called a mutation.
93
94
95
96