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Punnetts 2 - Answers a. 50% 1. b. Women need 2 faulty X genes to be colorblind, and men only need the 1 faulty X MOM XC XC DAD Y XCXC XCY XC XCXC XCY 2. a. XHXh, XhXh b. If your father, mother, son, or daughter has the disorder MOM XH Xh DAD Y XHXh XHY Xh XhXh XhY 3. a. FF, Ff b. Both parents were heterozygous; they each had a recessive gene MOM F F DAD f FF Ff f Ff ff #2 on Pg. 203 • Because males have only one X chromosome, they show all the traitsgenes on that X. Females have two X’s, so they have two chances to get a gene that is good, and can show the good trait. Example: If females, have one gene on an X for colorblindness, and one gene on the other X for normal vision, she will have normal vision. • incomplete dominance – when neither gene is dominant, you have a blend (Ex: red gene + white gene = pink flower) • codominance – when both genes show up as a trait (Ex: red gene + white gene = red and white spots) (Ex: type A gene + type B gene = type AB blood) • polygenic – when more than 1 pair of genes controls a trait (Ex: skin color, eye color, hair color)