Download Big Idea 3 Test Review - Class Pages

A. 4
 B. 8
 C. 16
 D. 32

A. inerphase
 B. prophase
 C. metaphase
 D. telophase

A. to increase their potential energy
 B. to allow the chromosomes to move
without becoming entangled and
breaking
 C. to allow the chromosomes to fit within
the nuclear envelope
 D. to allow the sister chromatid to remain
attached


False.

False – neurons can’t divide at all
A. a groove in the plasma membrane
between daughter nuclei
 B. a ring of vesicles forming a cell plate
 C. the separation of divided prokaryotes
 D. the space that is created between
two chromatids during anaphase

A. changes in the order of cell cycle
stages
 B. lack of appropriate cell death
 C. inability to form spindles
 D. inability of chromosomes to meet at
the metaphase plate

A. a karyotype
 B. the complete set of an organism’s
genes
 C. representation of a complete set of a
cell’s polypeptides
 D. the complete set of a species’
polypeptides


True.
A. mitosis in her ovary
 B. metaphase I of one meiotic event
 C. telophase II of one meiotic event
 D. either anaphase I or II


True

Traits given to offspring from parents
inherited independently of each other

Specific proteins break the two strands
and re-join them with their homologs.

1. A female has two blue alleles and two
long genes. As her cells undergo meiosis,
what do her resulting egg cells look like?
› One blue gene and one long gene in all.

2. A female has one of each allele on
chromosome 12 and two short alleles. As
her cells undergo meiosis, what do her
resulting egg cells look like?
› All have the short allele, half have the blue
allele and half have the orange allele.
A. an egg cell
 B. a sperm cell
 C. a zygote
 D. a somatic cell of a male


Monohybrid crosses involve only one
trait, dihybrid crosses involve two traits.
A. are hybrids in the F2 generation.
 B. are true-breeding in the F1
generation.
 C. are hybrids in the F1 generation.
 D. are true-breeding in the F2
generation.


Nondisjunction occurs when
chromosomes fail to separate properly
during meiosis, resulting in gametes that
have either too many or too few
chromosomes.

False.
› Meiosis 1, Meiosis 2, Mother, Father.
A. principle of dominance
 B. principle of segregation
 C. principle of independent
assortment
 D. principle of probilitites


Either incomplete dominance or codominance.
A. 2:2
 B. 1:2
 C. 1:1
 D. 1:3

A. 0%
 B. 25%
 C. 50%
 D. 75%

A. 4
 B. 8
 C. 16
 D. 32


½, or 50%

0% - Impossible to get BB

1. If a homozygous bent wing fly mated with
a homozygous vestigial wing fly, what
would the genotype of the offspring look
like?
› All + bt + vg heterozygotes

2. If flies that are heterozygous for both the
bent wing gene and the vestigial wing
gene are mated, what is the probability of
offspring with bent wings only?
› 3/16

Linked genes are two different genes
that exist close together on the same
chromosome; sex-linked genes are
genes found on a sex chromosome.

Mother: Heterozygous – normal X +
mutant X; Father: normal X + Y

Most sex-linked genes are found on the X
chromosome. Males only have 1, so
whatever allele is on the one
chromosome determines the phenotype.
Females have two, so they would need
two recessive alleles in order to express
the recessive phenotype.
Barr bodies – condensed protein and
genetic material of one X chromosome
in females.
 Modification of a gene on the X
chromosome so only one X gene is
active.


Spot on the lagging strand of DNA during
DNA replication that is still bound to an
RNA primer – DNA polymerase cannot
properly replicate the lagging strand
because of the direction of the strand.

Genetic material (DNA or RNA)
surrounded by a protein coat (capsid)
Each team will have a guesser for each word.
The guesser will face the back wall, and the res
of the team will attempt to get them to say the
word/phrase on the board.
 Guessers!
› You MUST raise your hand, loudly proclaim
“PAUSE”, and wait to be called on in order to
give your guess.
 Team!
› You MAY NOT say, spell, or ‘sounds like’ any
part of any word on the board. There may be
some rounds where I restrict other words.
 The first team to guess correctly gets the point.


Cannot say homozygous

Cannot say chromsome

Cannot say HIV, bacteria, flu, ebola,
flubola

Cannot say lysogenic cycle

Cannot say cellular respiration,
chloroplast

Cannot say lytic cycle

Cannot say codominance

Cannot say transfer

Cannot say translation, nucleus

Cannot say protein

Cannot say ribosome, transcription

Cannot say photosynthesis,
mitochondria, powerhouse of the cell

Cannot say base, nucleotide

Cannot say bacteria

Cannot say X-Men

Cannot say incomplete dominance