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Question 1 (1 point)
In a pathway controlling flower color, a functioning copy of gene A is needed to produce enzyme A, which
catalyzes the synthesis of red pigment. Without enzyme A, the flower only makes white pigment. A second gene,
gene R, encodes a repressor protein that inhibts enzyme A. If a plant were to have a genotype of AaRr, what color
would the flower be?
Question 1 options:
The flower would be white because the repressor protein is present and it is inhibiting enzyme A
The flower would be red because enzyme A is present and the repressor gene is broken
The flower would be white because the genes for enzyme A and the repressor are broken
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Question 2 (1 point)
In the question above, Gene R is dominant epistastic to Gene A.
Question 2 options:
True
False
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Question 3 (1 point)
Given the following pathway to produce blue flowers, Genes A and B encode two enzymes as shown in the
diagram below. You cross a fully heterozygous blue plant (AaBb) with a white plant (aabb). What proportion of
the offspring will be expected to have red flowers? (Assume complete dominance and no linkage)
White pigment ---Enzyme A---> Red pigment ---Enzyme B---> Blue pigment
Question 3 options:
1/8
1/4
1/2
3/16
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Question 4 (1 point)
A chromosome contains alleles for blue eyes and blond hair. After meiosis this original (but modified)
chromosome contains alleles for blue eyes and brown hair. This occurred because of
Question 4 options:
segregation.
independent assortment.
crossing over.
interference.
nondisjunction.
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Question 5 (1 point)
If alleles of different genes always maintain their parental association rather than assorting independently into
offspring, this is because
Question 5 options:
Mendel's experiments were flawed.
they are really alleles of a single gene.
there was a meiotic error.
they are very close together on the same chromosome.
they are on the same chromosome but far apart.
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Question 6 (1 point)
Genes that are linked
Question 6 options:
segregate to opposite poles during meiosis.
do not assort independently during meiosis.
segregate independently during meiosis.
are on nonhomologous chromosomes.
are always on the X chromosome.
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Question 7 (1 point)
The closer two genes are together on a chromosome,
Question 7 options:
the more likely there will be a recombination event between them.
the less likely there will be a recombination event between them.
the greater the chance that a double crossover will occur between them.
the more likely they are to be epistatic.
the less likely they are to be good genetic markers.
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Question 8 (1 point)
For a two-point testcross, if the percentage of recombinants is 50 percent, the two genes may be
Question 8 options:
on different chromosomes.
distant from each other on the same chromosome.
not linked.
both A and B.
all of the above.
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Question 9 (1 point)
One genetic map unit is equal to a recombination frequency of
Question 9 options:
1 percent.
5 percent.
10 percent.
100 percent.
50 percent.
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Question 10 (1 point)
Constructing a gene linkage map illustrates the exact physical locations of genes on a chromosome.
Question 10 options:
True
False
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Question 11 (1 point)
The map distance between two outside genes in a linkage group of three genes can be calculated by adding the
map distances between the two adjacent pairs of the three genes.
Question 11 options:
True
False
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Question 12 (1 point)
In yeast, mating aBD x Abd produces the following haploid spores:
aBD = 385; Abd = 386
ABD = 387; abd = 385
abD = 34; ABd = 35
aBd = 36; AbD = 37
What is the best conclusion that can be made from this data?
Question 12 options:
All 3 genes are unlinked
All 3 genes are linked
Genes A and B are linked, but gene D is unlinked
Genes B and D are linked, but gene A is unlinked
Genes A and D are linked, but gene B is unlinked
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Question 13 (1 point)
From a three-point testcross mapping experiment, the following gamete data is obtained:
ABC 365; abc 367
aBc 110; AbC 105
aBC 4; Abc 3
ABc 25; abC 21
From the above data, what can be said of the genes?
Question 13 options:
All the genes are unlinked
The gene order is ABC
The gene order is ACB
The gene order is CAB
2 of the genes are linked, and one of the genes is independently assorting
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Question 14 (1 point)
From a three-point testcross mapping experiment, the following gamete data is obtained:
ABC 365; abc 367
aBc 110; AbC 105
aBC 4; Abc 3
ABc 25; abC 21
From the above data, what is the distance between gene A and gene B?
Question 14 options:
21.5 mu
4.6 mu
22.2 mu
5.3 mu
27.5 mu
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Question 15 (1 point)
If genes G and H are linked and separated by 14 map units, what percent of the gametes produced by a GgHh
diploid will be parental?
Question 15 options:
86%
55%
28%
14%
7%
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Question 16 (1 point)
On an autosome, genes A and B are 10 map units apart. On another autosome, genes C and D are 20 map units
apart. An AABBCCDD male mates with an aabbccdd female. What percent of the gametes produced by their
hybrid offspring will be AbCd?
Question 16 options:
10%
0.5%
2%
18%
5%
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Question 17 (1 point)
On an autosome, genes A and B are 20 map units apart. An AABB male mates with an aabb female. What % of the
gametes produced by their hybrid offspring will be Ab?
Question 17 options:
5%
10%
20%
40%
80%
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Question 18 (1 point)
On an autosome, genes C and D are 10 map units apart. A CCDD male mates with a ccdd female. What % of the
gametes produced by their hybrid offspring will be CD?
Question 18 options:
5%
10%
20%
45%
90%
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