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BASIC GENETICS REVIEW Genetics  study of heredity (inheritance of traits). Father of  Austrian monk born in 1822. genetics  high school teacher and gardener. Gregor Mendel  studied inheritance in garden pea plants. What did Mendel know? What did Mendel do?  flowers have male and female parts.  produce pollen and egg cells.  fertilization: male and female sex cells join to form new cell  peas are self-pollinating.  true-breeds: produce offspring like themselves when s-p.  crossed true-bred peas: fertilized one plant with pollen from another.  hybrids: offspring (F1) of crosses between parents (P) with different traits.  true-bred short male(tt) X true-bred tall mom(TT)  hybrid offspring = Tt Trait  specific characteristic varies betw/ individuals. Heritable trait  trait that can be passed on to offspring. What did Mendel conclude? Principle of dominance What did Mendel do next? Law of Segregation  factors that control traits are passed from generation to generation.  genes: chemical factors that determine traits  alleles: contrasting forms of a gene.  e.g. gene for “tallness” or “shortness”  some alleles are dominant; some are recessive.  dominant allele: if present this trait is seen.  recessive allele: seen if dominant allele is not present.  e.g. trait = plant height tt = short plant Tt or TT = tall plant  crossed hybrid pea plants (Tt X Tt)  recessive trait not seen in F1.  recessive trait seen in F2!  alleles separate when gametes (sex cells) are formed (during meiosis).  SO…..4 possible combinations of gametes during fertilization Genetics and Probability Probability  likelihood that a particular event will occur.  each toss is separate: heads = ½ each toss. Genetics?  probability can be used to predict outcomes of genetic crosses.  predictions are averages not absolutes  larger sample sizes closer to predictions. Punnett Square  diagram used to record possible gene combinations from genetic crosses. Vocabulary genotype: genetic makeup: write out alleles:“3Tt: 1tt” phenotype: physical characteristics: “3 tall: 1 short” homozygous: 2 identical alleles for a trait: TT or tt heterozygous: 2 different alleles for a trait: Tt Monohybrid cross example  cross 2 heterozygous tall plants (Tt x Tt)  Offspring genotypes:  ¼ homozygous tall (TT);  2/4 heterozygous tall (Tt);  ¼ homozygous short (tt)  offspring phenotypes: ¾ tall; ¼ short Dihybrid cross  cross true-bred pea plants with 2 traits Example  dominant: round(R); yellow(Y)  recessive: wrinkled (r); green (y) Parents (P) Filial (F1)  RRYY (round/yellow) X rryy(wrinkled/green)  offspring: RrYy (hybrid)  cross 2 F1 plants RrYy X RrYy  possible gametes (FOIL): RY, Ry, rY, ry 2nd generation (F2) Principle of Independent Assortment Summary of Mendel’s Principles  genes for different traits segregate (separate) independently during formation of gametes.  creates variation in offspring. 1. Inheritance determined by genes passed from parents to offspring. 2. Alleles of genes can be are dominant or recessive. 3. Somatic cells have 2 copies of each gene (1 from mom; 1 from dad). 4. Genes segregate independently of each other (RrYy) = RY, Ry, rY, ry. OTHER PATTERNS OF INHERITANCE It’s not always so simple…… Incomplete Dominance Example  no allele is completely dominant.  heterozygote is blend of 2 homozygous phenotypes.  red carnation X white carnation = pink carnation. P genotype: ___X___ F1 genotype: ______ phenotype: ______ Codominance Example  both alleles dominant: both show up in phenotype of offspring.  red cow X white cow = roan cow (red and white). P genotype: ___X___ F1 genotype: ______ phenotype: ______ Multiple Alleles Example Blood type  more than 2 forms of a gene  more than one allele is dominant.  more than 2 phenotypes in population.  alleles: dominant = A B; recessive = O possible blood types Example P phenotype: ____X____ F1 genotype: ________ F1 phenotype: _______ genotype AA AO BB BO AB OO phenotype A A B B AB* O* Sex linked genes  Gene located on X or Y chromosome (more commonly X…the Y chromosome is tiny) Example 1. Colorblindness (recessive gene) located on X chromosome  possible genotypes: XC Xc , XCXC, XcXc, XCY, XcY  to be colorblind females need XcXc, males only need XcY P genotype: ____X_____ F1 genotype: ____________ F1 phenotype: __________ 2. Hemophilia carried on X chromosome  possible genotypes:XH Xh, XHXH, XhXh, XHY, XhY P genotype: ____X_____ F1 genotype: ____________ F1 phenotype: __________ Polygenic Traits Epigenetics (epi = above)  traits controlled by 2 or more genes.  human skin color, eye color, height.  AABBCCDD X aabbccdd…..many combinations.  MANY intermediate phenotypes possible  traits determined by interaction of genes and environment.  Genes are the PLAN.  ENVIRONMENT determines how plan unfolds.  smoking, diet, stress, prenatal nutrition, trauma, etc. can affect which genes are turned on or off.  chemical “tags” on DNA or change in histones.  may be inherited over multiple generations.  can change over a lifetime. MEIOSIS Mitosis Review Meiosis WHY?  1 cell division results in 2 genetically identical daughter cells  makes cells for growth, repair, asexual reproduction  occurs in somatic (body) cells  starts and results in diploid cells (2n)  2 sets of homologous chromosomes  1 set from mom; 1 set from dad  2 cell divisions results in 4 daughter cells with ½ the number of chromosomes  makes gametes (sex cells)  occurs in sex organs of animals, plants, fungi, etc.  starts with diploid cell (2n)  results in 4 haploid cells (n) Chromosomes  different number for each species.     humans: 2N = 46; 1N = 23 dog: 2N = 78; 1N = 39 shrimp: 2N = 254; 1N = 127 pineapple: 2N = 50; 1N = 25 Crossing over  homologous chromosomes exchange parts during Prophase I of meiosis  increases genetic variation Gene Linkage and Mapping  genes can be mapped to specific locations on chromosomes.  figured out with fruit flies.  linked traits are on the same chromosome.  linked genes not always inherited together  chromosomes cross-over during meiosis  linkage maps show relative location of genes  lower cross-over frequency = closer  cross-over frequencies: A-B=8% B-C=10% C-A=2%
 
									 
									 
									 
									 
									 
									 
									 
									 
                                             
                                             
                                             
                                             
                                             
                                             
                                             
                                             
                                             
                                             
                                            