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Chromosomal Basis of Inheritance Featuring fruit fly: Drosophila Melanogaster Basic Terms/Information about Drosophila My diploid number is 2N = 8 Wild-type (+) refers to the most common phenotype in fruit flies. It’s usually dominant (but not necessarily) Mutants are non wild-type traits Sex-Linkage or (X-linked) In fruit flies, (R) is the dominant wild-type gene for red eyes, and (r) is the recessive, mutant gene forThe white eyes. The gene Y is found on the “X” chromosome only.chromosome This is considered Xis shorter than the linked. X Does the gene These are the for eye Y color X and exist on the “Y” chromosomes chromosome? of a male fly. Why Howor is why the Ynot? chromosome R r different from the X? XX r XY What Whatwould wouldbebethe the phenotype phenotypeofofthis thisfemale male fly? fly? No, because the gene for eye color is found on the longer segment of the X chromosome. This part is missing on the Y White eye Red eye male female Sex-Linkage or (X-linked) • When genes are sex-linked, we include the X and Y as part of their genotype. For example, the allele for red eye is not “R” but is written as XR. How would you write the allele for white eye? Xr Writing X-linked Genotypes What is the possible genotype(s) for the eye color of this fly if it is a female? XrRXXr R or XRXr What is the possible genotype for the eye color of this fly if it is male? XrRYY Answer the above questions again for this fly. Sample Problems Example 1: What is the F1 genotypic and phenotypic ratio of a female true-breeding wild-type fly for red eyes crossed with a white-eyed male? Phenotypic Ratio Genotypic Ratio Red-eye female:Red-eye male R r R X X :X Y 2:2 reduced to 1:1 2:2 reduced to 1:1 X XR XR Xr XRXr XRXr Y XRY XRY Sample Problems Example 2: What would the genotypes and phenotypes be of the F2 generation? X Genotypic Ratio XR Xr XR XRXR XRXr Y XRY XrY XRXR : XRXr : XRY : XrY 1 : 1 : 1 Phenotypic Ratio : 1 Red-eye female : Red-eye male : White-eyed male 2 : 1 : 1 X-linked disorders Definition: diseases or disorders whose genes are found on the X-chromosome, but not on the Y. Ex: hemophelia (Xh), color blindness (Xb), muscular distrophy (Xm) If the disorder is recessive, more males than females will tend to have the disorder. Why? Take, for example, colorblindness (Xb) If you have a normal female, what is her possible XBXB or _____ XBXb genotype(s)? _____, If you have a colorblind female, what is her genotype? ______ XbXb If you have a colorblind male, what is his genotype? ______ XbY How many colorblind genes do males need to inherit to be colorblind? _____ 1 Females? _____ 2 Who does the male inherit the colorblind gene from? _____________________________________ His mother, who donates the X chromosome Other traits and alleles of Drosophila melanogaster Wild Type Traits (+) Gray body = G+ Mutant Traits Normal wings = N+ Shriveled, vestigial wings = n Black body = g Body-color and wing-type are NOT located on the sex chromosome, so they are considered autosomal Things to think about independently….How would you confirm or test that these mutant traits are recessive? Example 3 In flies, grey bodies (G+) and normal-wing size (N+) are dominant to black bodies (g) and small wing size (n). Predict a cross between G+gN+n and ggnn. Surprising Predicted Results! Cross G+gN+n x ggnn G+N G+n gN+ gn gn gn gn gn 25% G+gN+n 25% G+gnn 25% ggN+n 25% ggnn Actual Results 8.5% 8.5% 41.5% 41.5% Why did this happen??? Linked Genes The genes for body color and wing size are linked, meaning they are found on the same chromosome. They will most likely be inherited together and will not undergo Mendel’s Law of Independent Assortment . unless cross over segregates the linked genes G+ G+ N+ n g g N+ n Homologous Chromosomes What are recombinants? Recombinants are offspring that have different phenotypes from those of the parents. Let’s look back at our original cross X X C B 8.5% D 8.5% 41.5% 41.5% A Which offspring (A-D) from this cross are the recombinants? How do we determine if two genes are linked or if two genes are located on different chromosomes? Answer Calculate the recombination frequency! If the frequency is less than 50%, it is assumed that the two genes are on same chromosomes. X C B 206 D 185 944 965 A Total Flies: 965 Frequency + 206 + 185= +recombinants 944 2500 flies Recombination / total flies = Calculate the= recombination 391/2500 = .156 =frequency 16% for+this Total number of recombinants: 206 185 =cross! 391 Gene Mapping Grey Body Black Body Normal wings Small wings • Genes are mapped on a chromosome based upon the recombination frequency. • For ex. the distance between the genes for body color and wing type is therefore 16 “map-units” apart (16% frequency) Using recombination frequencies, create a linkage map for the following a - c: between genes b and a = 10.5%; between genes c and a = 48%; between genes c and b = 37.5% 10.5% 37.5% 48% a b c