Download 6hp_model - WordPress.com

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project

Document related concepts

Protein design wikipedia , lookup

List of types of proteins wikipedia , lookup

Rosetta@home wikipedia , lookup

Bimolecular fluorescence complementation wikipedia , lookup

Immunoprecipitation wikipedia , lookup

Protein wikipedia , lookup

Protein moonlighting wikipedia , lookup

Proteomics wikipedia , lookup

Protein structure prediction wikipedia , lookup

Protein mass spectrometry wikipedia , lookup

Implicit solvation wikipedia , lookup

Western blot wikipedia , lookup

Intrinsically disordered proteins wikipedia , lookup

Protein purification wikipedia , lookup

Homology modeling wikipedia , lookup

Protein domain wikipedia , lookup

Protein–protein interaction wikipedia , lookup

Nuclear magnetic resonance spectroscopy of proteins wikipedia , lookup

Folding@home wikipedia , lookup

Cyclol wikipedia , lookup

Protein folding wikipedia , lookup

Transcript
HP model
HP model for protein folding
K. Dill, Theory for the folding and stability of globular proteins.
Biochemistry, 24:1501-1509, 1985
red - Hydrophobic ; blue - Polar (hydrophylic) molecules
Reasons why HP model can explain
some key features of protein folding
HP model “game”
red - Hydrophobic ; blue - Polar (hydrophylic) molecules
N=14 beads, 7 H-H contacts
R.Hayes, Prototeins, American Scientist, Volume 86 , 216
21 beads - “folded” proteins (11 H-H contacts – maximum number) vs
“unfolded” proteins (0 or 1 H-H contacts – minimum number)
The aminoacid sequence for the protein
PHHHHP
a=[0 1 1 1 1 0]
n
2 configurations at length n
The folding sequence for the protein
1 (east), i (north), -1 (west), and -i (south).
f = [1 1 1 1 1] (n-1 bonds)
f = [1 1 i 1 1]
or
f(x+iy)= [0 1 2 2+1i 3+1i 4+1i]
n
43/32-1
(2.3683) * n
configurations
at length n for large n
Lattice walks can be represented as a list
of x,y coordinates, as compass directions
or as left, right and forward commands.
The last representation can also be
encoded in a ternary (base 3) number
Self-avoiding walks
Brian Hayes, “How to Avoid Yourself,”
American Scientist, July-August 1998,
Volume 86, p. 314
Berger B and Leighton T (1998) Protein folding in the hydrophobic-hydrophilic (HP)
model is NP-complete. J Comput Biol 5:27-40
Combinatorial explosion
Number of HP model
configurations at length n+1
n+1
n
43/32
2 * (2.3683)
*n
Millennium Prize Problems
P versus NP problem
Hodge conjecture
Poincaré conjecture (solved by Grigori Pelerman in 2003)
Riemann hypothesis
Yang–Mills existence and mass gap
Navier–Stokes existence and smoothness
Birch and Swinnerton-Dyer conjecture
P versus NP problem is a major unsolved
problem in computer science
P - decision problems solved on a
deterministic sequential machine in an
amount of time that is polynomial in the
size of the input
NP -"- exponential time
NP-complete problems are a set of problems to each of which any
other NP-problem can be reduced in polynomial time, and whose
solution may still be verified in polynomial time. That is, any NP
problem can be transformed into any of the NP-complete problems.
Informally, an NP-complete problem is an NP problem that is at least
as "tough" as any other problem in NP.
Pitfalls of HP model
Unrealistic feature – H ends are usually buried unlike real proteins
Reason: ends can form 3 HH contacts, instead middle H beads can
form maximum 2 HH contacts
Unrealistic feature –
unnatural extended polar loops
Original HP model does not take
in account compactness
Folding process
During the folding process the scaning of many configurations can slow folding.
HPPPPH protein folding
How to do it
c1 = [1 1 1 1 1]
Apply folding at third bead
f1 = [1 1 i i i]
c2 =c1*f1=[ 1 1 i i i]
or
C2(x+iy)= [0 1 2 2+1i 2+2i 2+3i]
Apply folding at fourth bead
f2 = [1 1 1 i i]
c3 = c2*f2 = [1 1 i -1 -1]
or
C3(x+iy) =[0 1 2 2+1i 1+1i 1i]
Basic operations:
Bending
c1 = [1 1 1 1 1]
Apply bending at third bead
f1 = [1 1 i i i]
c2 =c1*f1=[ 1 1 i i i]
or
C2(x+iy)= [0 1 2 2+1i 2+2i 2+3i]
Flipping c2 = [1 1 i i i]
Apply flipping at second and third bond
f2 = [1 i 1 i i]
c3 =c1*f2=[ 1 i 1 i i]
or
C3(x+iy)= [0 1 1+i 2+i 2+2i 2+3i]
 Suboptimal folded configuration with E = - 3
Native configuration with E = - 4