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Transcript
Coupling Charged Particles to the
Electromagnetic Field:
The Bohm Aharanov Effect, Magnetic
Monopoles
Physics 212 2010, Electricity and Magnetism
Michael Dine
Department of Physics
University of California, Santa Cruz
November 2010
Physics 212 2010, Electricity and Magnetism
Coupling Charged Particles to the Electromagnetic Field: The Bo
The Lagrangian for Particles in an Electromagnetic
Field
We can guess a lagrangian by demanding gauge invariance.
Recalling that under gauge transformations:
φ(~x , t) = φ0 (~x , t) −
1 ∂Λ(~x , t)
c ∂t
~ ~x , t) = A
~ 0 (~x , t) + ∇Λ(
~ ~x , t) (1)
A(
the lagrangian
X ma d ~xa 2
L=
−
2
dt
a
Z
(2)
1~
~x , t) · ~J(~x , t)
d 3 x −φ(~x , t)ρ(~x , t) + A(
c
is invariant, due to current conservation.
Physics 212 2010, Electricity and Magnetism
Coupling Charged Particles to the Electromagnetic Field: The Bo
For a collection of point particles,
X
X
ρ(~x , t) =
qa δ(~x − ~xa (t)) ~J(~x , t) =
qa~va δ(~x − ~xa (t)) (3)
a
a
So, integrating over ~x ,
X ma
qa
~ ~xa , t) .
L=
− qa Φ(~xa , t) + ~va · A(
2
c
a
(4)
~ are functions of ~xa and t.
Note carefully that Φ and A
Physics 212 2010, Electricity and Magnetism
Coupling Charged Particles to the Electromagnetic Field: The Bo
The Lorentz Force Law
If all of this is correct, the Lorentz force law should emerge as
the Euler-Lagrange equation for this system. It is convenient, to
avoid getting confused about vector quantities, to work with
Cartesian indices. We need to evaluate:
∂L
j~i j
i
~
.
(5)
=
−q
∇
Φ
−
v
∇
A
a
a a
a
∂xai
After this, we drop the subscript a on the partial derivatives, to
streamline the writing, i.e.
∂L
~ i Φ − vaj ∂ i Aj .
=
−q
∂
a
∂xai
Physics 212 2010, Electricity and Magnetism
(6)
Coupling Charged Particles to the Electromagnetic Field: The Bo
d ∂L
qa i d i
A .
m
ẋ
+
=
a
a
dt ∂ ẋai
dt
c
(7)
To evaluate the time derivative, we need to keep in mind that
this is the total derivative, i.e.
dAi
∂Ai
=
+ vj ∂j Ai .
dt
∂t
(8)
So, now dropping the a subscript everywhere, which no longer
can lead to any ambiguity:
1
q
mẍ i = q(−∂i Φ − ∂t Ai ) + (+v j ∂i Aj − v j ∂j Ai ).
c
c
(9)
~ the
The first term we recognize immediately as giving us q E;
~
second is readily seen (using our favorite identity) to be q~v × B.
So indeed this lagrangian gives us the Lorentz force for each
charged particle!
Physics 212 2010, Electricity and Magnetism
Coupling Charged Particles to the Electromagnetic Field: The Bo
The Hamiltonian: passing to quantum mechanics
If we are interested in quantum mechanics, we need to
construct the Hamiltonian. For this, we first need the canonical
momentum.
1
∂L
(10)
= mẋai + Ai (~xa , t).
pai =
i
c
∂xa
Now we compute:
X
H=
qai pai − L = mẋai 2 + qa φ(~xa , t).
(11)
(We have written the argument of φ explicitly, again).
Physics 212 2010, Electricity and Magnetism
Coupling Charged Particles to the Electromagnetic Field: The Bo
~ does not appear in this expression. But the
Not surprisingly, A
Hamiltonian is not to be thought of as a function of the
velocities, but of the coordinates and momenta. So
X 1
2
~
H=
(~pa − qa A) + qa Φ
(12)
2ma
In passing to quantum mechanics, one takes
~a
~pa → −i~∇
(13)
~ appears in the Schrodinger equation.
so A
Physics 212 2010, Electricity and Magnetism
Coupling Charged Particles to the Electromagnetic Field: The Bo
Gauge invariance of the Schrodinger Equation
What happened to gauge invariance?
Consider
HΨ = i
∂
Ψ.
∂t
(14)
The full gauge invariance is now:
φ(~x , t) = φ0 (~x , t)−
1 ∂Λ(~x , t)
c ∂t
~ ~x , t) = A
~ 0 (~x , t)+ ∇Λ(
~ ~x , t) (15)
A(
Ψ = ei
qΛ
~
Ψ0 .
as you can readily check.
Physics 212 2010, Electricity and Magnetism
Coupling Charged Particles to the Electromagnetic Field: The Bo
The Aharanov-Bohm Effect
~ field, but
Consider an infinite solenoid. Outside, there is no B
~
~
inside, there is a net flux of B. As a result, the line integral of A
around the loop is non-zero:
I
I
~
~
d ` · A = dφAφ sin θr = ΦM .
(16)
~ vanishes outside, this is a
Despite the fact that B
gauge-invariant statement. This follows from the fact that,
under a gauge transformation, the left hand side is
I
I
~
~
~ · d ~` = Λ(φ + 2π) − Λ(φ).
d ` · A = ∇Λ
(17)
So as long as the gauge transformation is periodic
(single-valued), the integral is gauge invariant.
Physics 212 2010, Electricity and Magnetism
Coupling Charged Particles to the Electromagnetic Field: The Bo
~ must be a gauge
Since ΦM is non-zero, on the other hand, A
~
~
transformation of A = 0; in this way, the B field vanishes. Λ is
not periodic, so it is not really a gauge transformation:
~ =∇
~ Λ̃;
A
Λ̃ = ΦM φ.
(18)
Λ̃ is not a gauge transformation because it is not periodic.
Physics 212 2010, Electricity and Magnetism
Coupling Charged Particles to the Electromagnetic Field: The Bo
You are have some familiar with the Feynman path integral. We
want to consider the effect on the interference pattern, say in a
double slit experiment, of the solenoid. In general, Feynman
tells us that the amplitude to go from a point A to a point B
along a particular classical path is eiS(A,B)/~ . We have seen
~ field. So if we
how the action is modified in the presence of a A
turn on the solenoid, we the amplitude changes to
q
eiS(A,B)/~ ei ~
RB
A
d~
`·~
A
.
(19)
So if we compare to paths, one of which goes around one side
of the solenoid, and the other around the other, ending up at
the same point, they differ in phase (from their previous
difference in phase) by
ei
H
d~
`·~
A
= eiΦM /~ .
(20)
When squaring the sum of these amplitudes, there are new
(observable) interference effects.This is the Aharanov-Bohm
effect.
Physics 212 2010, Electricity and Magnetism
Coupling Charged Particles to the Electromagnetic Field: The Bo
In this light, one can understand the Dirac quantization
condition for electric charge. We have seen that if monopoles
exist, they are described by singular field configurations. This
singularity is seemingly a gauge artifact. It can be chosen, for
example, to lie in different directions by making a gauge
transformation. But this gauge transformation will have
observable consequences if it leads to modified interference
patters for particles of charge q. The string is detectable, like
the Bohm-Aharanov solenoid, in general. More precisely, the
singularity can be written:
~ = ∇Λ
~
A
iq
e~
This means:
H
Λ = 2gφ.
~
d~
`·∇Λ
= 1.
2gq
= n.
~
Physics 212 2010, Electricity and Magnetism
(21)
(22)
(23)
Coupling Charged Particles to the Electromagnetic Field: The Bo
This (with variants) is the only known explanation for the
quantization of electric charge.
Physics 212 2010, Electricity and Magnetism
Coupling Charged Particles to the Electromagnetic Field: The Bo