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2009 Application 8 Isolating, cloning Sequencing DNA page 1 OVERVIEW Genomic DNA Recombinant plasmid vector Plasmid 1. Cut out gene of interest and plasmid with the same restriction enzyme 2. leaving complementary sticky ends. 3. Mix the plasmid and genomic DNA fragments 4. and allow the sticky ends to anneal. 5. Add ligase to allow phosphodiester bonds to form. 6. Recombinant DNA molecules form in ligation mixture. 7. Transform competent* bacterial host cells in ligation mixture, which has recombinant plasmid. 8. Need to identify bacteria host cell which has taken up recombinant plasmic with gene of interest (The genomic DNA sample will produce many restriction fragments). Prepared by Nah S C 2009 Application 8 Isolating, cloning Sequencing DNA page 2 (a) Describe the natural function of restriction enzymes. What are restriction enzymes? o Produced by bacteria to cleave foreign DNA ( e.g. from bacteriophage ) into noninfective fragments o recognise specific base sequences in double-stranded DNA and hydrolyse a phosphodiester bond on each strand of the DNA at specific places known as restriction sites. o Most restriction sites are about 6 bases long and palindromic. Features of restriction enzymes? o Some restriction enzymes produce blunt ends while others produce sticky ends (a) sticky ends enzymes leave a staggered cut with single stranded ends. These short extensions/ overhangs will anneal with complementary single-stranded stretches on other DNA molecules cleaved with the same restriction enzyme (b) blunt ends enzymes make a simple cut across both strands at a single point Why don’t they cut their own bacteria DNA? o (b) Bacteria DNA protected by methylation –CH3 of adenine or cytosine within restriction site. Explain the formation of recombinant DNA molecule 1. ISOLATE vector (e.g. plasmid from bacteria) & gene of interest (e.g. DNA from human cell) 2. Cut both DNA with the SAME RESTRICTION ENZYME. Preferably one that produces complimentarty sticky ends 3. Mix plasmid and cut DNA. Allows annealing of complimentary sticky ends between plasmid and gene of interest 4. Add DNA ligase to seal fragments with phosphodiester bonds 5. a recombinant DNA (plasmid of bacteria) now contains a foreign (human) gene Prepared by Nah S C 2009 Application 8 Isolating, cloning Sequencing DNA page 3 (c)(i) Outline the procedures for cloning a gene in a bacterial plasmid (c) (ii) and describe the properties of plasmids that allow them to be used as DNA cloning vectors. What is a vector? o is a DNA molecule into which fragments of DNA may be inserted. o It then acts as an agent of transfer to carry the fragments of DNA into a host cell. o Within the host, the vector replicates by using the DNA-synthesising machinery (ie: DNA polymerase) of the host cell. o Commonly used vectors include plasmids & phages/virus. o Yeast have plasmids What features must plasmids have to be useable in recombination technology? EcoRI A selectable marker gene coding for ampicillin (an antibiotic) resistance. Insertion of gene of interest in either ampr or tetr genes will inactivate these genes. The region for such an insertion is actually located within the ampr or tetr gene. BamHI ampr pBR322 tetr A selectable marker gene coding for tetracycline (an antibiotic) resistance. ori Origin of replication, or ori. Replication begins here with the formation of a replication bubble. It allows the plasmid to duplicate autonomously of bacterial chromosome. (a) are capable of replicating independently of the bacterial chromosome - so that during cloning, copies of the recombinant DNA molecule are passed to daughter cells as the cell divides. (b) Have high copy numbers - present in the cell in multiple copies (30 – 40 per host cell) so that large quantities of the recombinant DNA molecule can be obtained from each cell. (c) have a single origin of replication - host cell enzymes (e.g.: DNA polymerase) bind to initiate replication. Prepared by Nah S C 2009 Application 8 Isolating, cloning Sequencing DNA page 4 (d) range in size (2 to several hundred kb). - limits size of DNA fragment insterted - Too large – hard to transform cells (e) Contain 2 selectable markers Ampicillin + lacZ genes (coding for the enzyme -galactosidase). Ampicillin + tetracycline Has Restriction site within second gene Gene of interest is inserted within the site inactivating the gene (f) Gene of interest is insert under control of bacterial promoter (eukaryotic promoter differ in sequence) (c) (ii) Outline the procedures for cloning an eukaryotic gene in a bacterial plasmid ………… (d) Explain how eukaryotic genes are cloned using E. coli cells to produce eukaryotic proteins to avoid the problems associated with introns. What is the problem faced with using eukaryotic gene for cloning into bacterial cells? 1. bacteria lack post-transcriptional mechanism like mRNA splicing a. introns are not removed b. solution: use cDNA synthesized from mRNA by reverse transcriptase c. chemically synthesised gene without its introns 2. bacteria RNA do not recognize eukaryote promoter a. Need to place eukaryotic gene next to bacteria promoter. 3. Prokaryotes do not carry out post –translational modifications a. E.g. no glycolysation b. Mechanism for correct folding into 30 formation 40 structure 1. ISOLATE GENE OF INTEREST mRNA for Anti-thrombin III is isolated from liver cells. (where it is found in high quantities) reverse transcriptase is used to make RNA-DNA hybrid alkali used to partially break down RNA in hybrid DNA polymerase used to synthesize complimentary DNA strand 2. Making RECOMBINANT PLASMID Prepared by Nah S C 2009 Application 8 Isolating, cloning Sequencing DNA page 5 cDNA is blunt ended use terminal transferase to add cytosine residues to blunt ends thus forming sticky ends Cut plasmid to linearise leaving blunt ends Use terminal transferase to as guanines to 3’ ends Mix plasmid and gene of interest; To allow annealing to each other add ligase to seal nicks with phosphodiester bonds Sticky ends CCC GGG CCC GGG ampr Inactivated tetr Linearised plasmid ori 3. TRANSFORMATION of bacteria transformation = process where a host cell assimilates external DNA Treat with Ca2+ + heat shock 420C - CaCl2 may be responsible for binding DNA to cell surface What are the different types of plasmids that may result from the recombination? o Rejoined non-recombinant plasmids o Combination of 2 plasmids o Plasmid with several DNA fragments o Plasmid with gene of interest 4. SCREEN for bacteria cell with gene of interest A. screen for cell that has taken up plasmid vector o Plate bacteria on agar containing ampicillin o Only cells with plasmid that have ampR gene produce resistance to ampicillin and grow / other cells die B How do we recognize cell clones that has taken up recombinant plasmids? o By REPLICA PLATING o Master plate with ampicillin o Make a Replica plate of the master plate onto Petri dish with tetracycline Prepared by Nah S C 2009 Application 8 Isolating, cloning Sequencing DNA page 6 o If gene of interest has been inserted in the tetracycline restriction site the colony will not grow on the agar plate o Colonies which grew on ampicillin but not later on tetracycline plates are the successful recombinants. Stamper Sterile velvet 37C 12hr Amp Master plate (ampicillin) Tet Replica plate (tetracycline) Tet Replica plate (tetracycline) Amp Tet Method 2: Use Plasmid carries 2 genes o AmpR resistance to ampicillin o lacZ gene encodes ß galactosidase o hydrolyses sugar X-galactose (X-gal) to form blue product o lacZ. Gene contains single restriction site recognize by the restriction enzyme used o Plate bacteria in ampicilin + X-gal. o Colonies with functional lacZ. Gene. (no gene of interest inserted) produce ßgalactosidase, which hydrolyses Xgal and are blue o Those with insert have a non-functional LacZ gene, and are unable to metabolize Xgal: they therefore produce white colonies. 5. HOW DO YOU IDENTIFY RECOMBINANT CLONES WITH GENE OF INTEREST a. Look for the gene b. look at/for its protein product Nucleic acid probe hybridization o Make a short single stranded nucleic acid (either RNA or DNA) o Called DNA probe o Complementary to gene of interest with complementary base pair o Probe labeled with radio active isotope or fluorescent tag Prepared by Nah S C 2009 Application 8 Isolating, cloning Sequencing DNA page 7 Procedure 1. bacteria with recombinant plasmids are grown on a master plate 2. nitrocellulose filter is pressed on master plate 3. Filter is maked with X to note relative positions of colonies 4. filter treated with NaOH to lyse cells and denature DNA molecules to single strands 5. wash away cell debris 6. bake to 80OC. ssDNA sticks to filter 7. incubate in radio active DNA probe 8. excess probe washed off 9. filter laid on photographic plate 10. black spots correspond to location where colonies carrying gene of interest are found 6. LARGE SCALE PRODUCTION Colonies with gene of interest grown in bioreactor Culture induced to produce protein of interest Protein extracted, purified and packaged. Prepared by Nah S C 2009 Application 8 Isolating, cloning Sequencing DNA page 8 What is a GENOMIC LIBRARY, What are their limitations? 1. Start with fragments of entire genome of an organism 2. each fragment cloned into vector (plasmid) 3. complete set of plasmids, each carrying a particular segment of the original genome = genomic library limitations a. genomic DNA contain introns cannot be sliced out if transformed into bacterial cells b. eukaryote genome too large library too extensive to be screened may contain enormous tracts of non-coding DNA. c. Gene of interest my be cut up by restriction enzyme will not be a single functional unit Usefulness Can be used to study introns, regulatory sequences (which would be absent in cDNA library) What is a cDNA library Collection of cDNA clones generated in virto form mRNA sequences isolated forma particular cell type/tissue. Represents all of mRNA present in a particular tissue (total mRNA) which has been converted back to dsDNA using reverse transcriptase Use Study coding sequence of gene (introns absent) Want to trace changes in pattern of gene expression in same cell type at different time in development of organism Limitation Genes not expresses at a certain stage of development of the tissue cannot be harnessed FEATURES a. Lack introns genes will be correctly expressed in bacteria b. Cells have abundance of particular mRNA. Choice of tissues increases chances of obtaining correct clone (e) Distinguish between a genomic DNA and cDNA library. Point of comparison Genomic library cDNA library 1. Contains entire DNA content of an organism including all coding & non-coding sequences. Contains entire protein-encoding DNA content. Coding only 2. Requires chromosomal DNA isolation Requires total mRNA isolation Prepared by Nah S C 2009 Application 8 Isolating, cloning Sequencing DNA page 9 3. Starting material can be from any cell/tissue. (total) mRNA should be isolated from a cell/tissue where the particular protein is likely to be produced in large quantities. 4. Genomic DNA is cleaved with restriction enzymes before cloning into a vector. Messenger RNA reversetranscribed into cDNA before cloning into a vector. 5. Used for studying introns or regulatory sequences associated with a gene. Cannot be used for studying introns or regulatory sequences associated with a gene. OR Used for studying the exact coding sequence of the gene. 6. Cannot be used for studying physiological/developmental-based changes in gene expression. Used for tracing changes in patterns of gene expression under different developmental/physiological conditions. 7. Can be used for the screening and isolation of a gene, the expression of which takes place in a cell that is currently unknown. Cannot be used for screening of a gene when the cell type that expresses it is unknown. 8. intactness of genes Genes may be fragmented since restriction sites may be in middle of gene sequence Genes intact because source = mRNA 9. frequency of ‘genes’ Generally equal representation Unequal proportions – some genes represented in higher amounts f. Outline 2 important proteins and other products that can be produced by genetic engineering technique (eg. human growth hormone, anti-thrombin, etc). 1 Outline how human growth hormone can be produced by genetic engineering 2 Outline how anti-thrombin can be produced by genetic engineering 3 Outline how other products can be produced by genetic engineering 1 Outline how human growth hormone can be produced by genetic engineering Produced by cells of the anterior pituitary gland Stimulates growth and cell reproduction at all stages of development Excess leads to agromegaly (uncontrolled bone growth), deficiency leads to dwarfism etc mRNA was first obtained from pituitary gland to create a cDNA library. Prepared by Nah S C 2009 Application 8 Isolating, cloning Sequencing DNA 2 page 10 A small segment of the cDNA fragment was removed (codon 0 to 24). This gap was replaced by a fragment, which provided the correct signals for translation in E. coli. Entire coding fragment is inserted behind E. coli lac promoter The recombinant plasmid is used to transform a bacteria cell Bacteria colony is induced to produce somatotrophin Outline how anti-thrombin can be produced by genetic engineering o Antithrombin is a small protein molecule that inactivates several enzymes of the coagulation system. o Is a glycoprotein produced by the liver o Antithrombin deficiency is a rare hereditary disorder o that generally comes to light when a patient suffers recurrent venous thrombosis and pulmonary embolism. o (Thrombosis is the formation of a clot or thrombus inside a blood vessel, obstructing the flow of blood through the circulatory system.) o (Pulmonary embolism is blockage of the pulmonary artery (or one of its branches) by a blood clot, fat, air or clumped tumor cells.) o mRNA was obtained from human liver to create a cDNA library. o For efficient gene expression in E. coli, the E. coli trp promoter was used. o Prepared by Nah S C