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Chapter 16 The Molecular Basis of Inheritance PowerPoint Lectures for Biology, Seventh Edition Neil Campbell and Jane Reece Lectures by Chris Romero Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Overview: Life’s Operating Instructions • In 1953, James Watson and Francis Crick shook the world – With an elegant double-helical model for the structure of deoxyribonucleic acid, or DNA Figure 16.1 Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • DNA, the substance of inheritance – Is the most celebrated molecule of our time • Hereditary information – Is encoded in the chemical language of DNA and reproduced in all the cells of your body • It is the DNA program – That directs the development of many different types of traits Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Concept 16.1: DNA is the genetic material • Early in the 20th century – The identification of the molecules of inheritance loomed as a major challenge to biologists Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings The Search for the Genetic Material: Scientific Inquiry • The role of DNA in heredity – Was first worked out by studying bacteria and the viruses that infect them Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Evidence That DNA Can Transform Bacteria • Frederick Griffith was studying Streptococcus pneumoniae – A bacterium that causes pneumonia in mammals • He worked with two strains of the bacterium – A pathogenic strain and a nonpathogenic strain Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Griffith found that when he mixed heat-killed remains of the pathogenic strain – With living cells of the nonpathogenic strain, some of these living cells became pathogenic EXPERIMENT Bacteria of the “S” (smooth) strain of Streptococcus pneumoniae are pathogenic because they have a capsule that protects them from an animal’s defense system. Bacteria of the “R” (rough) strain lack a capsule and are nonpathogenic. Frederick Griffith injected mice with the two strains as shown below: Living S (control) cells Living R Heat-killed (control) cells (control) S cells Mixture of heat-killed S cells and living R cells RESULTS Mouse dies Mouse healthy Mouse healthy Mouse dies Living S cells are found in blood sample. Figure 16.2 CONCLUSION Griffith concluded that the living R bacteria had been transformed into pathogenic S bacteria by an unknown, heritable substance from the dead S cells. Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Griffith called the phenomenon transformation – Now defined as a change in genotype and phenotype due to the assimilation of external DNA by a cell Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Evidence That Viral DNA Can Program Cells • Additional evidence for DNA as the genetic material – Came from studies of a virus that infects bacteria Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Viruses that infect bacteria, bacteriophages – Are widely used as tools by researchers in molecular genetics Phage head Tail Tail fiber Figure 16.3 Bacterial cell Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 100 nm DNA • Alfred Hershey and Martha Chase – Performed experiments showing that DNA is the genetic material of a phage known as T2 Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • The Hershey and Chase experiment EXPERIMENT In their famous 1952 experiment, Alfred Hershey and Martha Chase used radioactive sulfur and phosphorus to trace the fates of the protein and DNA, respectively, of T2 phages that infected bacterial cells. 1 Mixed radioactively labeled phages with bacteria. The phages infected the bacterial cells. Phage 2 Agitated in a blender to 3 Centrifuged the mixture separate phages outside so that bacteria formed the bacteria from the a pellet at the bottom of bacterial cells. the test tube. Radioactive Empty protein protein shell Radioactivity (phage protein) in liquid Bacterial cell Batch 1: Phages were grown with radioactive sulfur (35S), which was incorporated into phage protein (pink). Batch 2: Phages were grown with radioactive phosphorus (32P), which was incorporated into phage DNA (blue). 4 Measured the radioactivity in the pellet and the liquid DNA Phage DNA Centrifuge Radioactive DNA Pellet (bacterial cells and contents) Centrifuge Radioactivity (phage DNA) Pellet in pellet RESULTS Phage proteins remained outside the bacterial cells during infection, while phage DNA entered the cells. When cultured, bacterial cells with radioactive phage DNA released new phages with some radioactive phosphorus. Figure 16.4 CONCLUSION Hershey and Chase concluded that DNA, not protein, functions as the T2 phage’s genetic material. Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Additional Evidence That DNA Is the Genetic Materia • Prior to the 1950s, it was already known that DNA – Is a polymer of nucleotides, each consisting of three components: a nitrogenous base, a sugar, and a phosphate group Sugar-phosphate backbone 5 end O– 5 O P O CH2 O 1 O– 4 H H H H 2 3 H O O P O CH2 O O– H H H H H O O P O CH2 O O– H H H H H Figure 16.5 O 5 O P O CH2 O 1 O– 4 H H PhosphateH H 3 2 OH H Sugar (deoxyribose) 3 end Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Nitrogenous bases CH3 O H N N H O Thymine (T) H N H N N N N H H Adenine (A) H H H N H N N O Cytosine (C) H N N N O N H N H H Guanine (G) DNA nucleotide • Erwin Chargaff analyzed the base composition of DNA – From a number of different organisms • In 1947, Chargaff reported – That DNA composition varies from one species to the next • This evidence of molecular diversity among species – Made DNA a more credible candidate for the genetic material Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Building a Structural Model of DNA: Scientific Inquiry • Once most biologists were convinced that DNA was the genetic material – The challenge was to determine how the structure of DNA could account for its role in inheritance Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Maurice Wilkins and Rosalind Franklin – Were using a technique called X-ray crystallography to study molecular structure • Rosalind Franklin – Produced a picture of the DNA molecule using this technique Figure 16.6 a, b (a) Rosalind Franklin Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings (b) Franklin’s X-ray diffraction Photograph of DNA • Watson and Crick deduced that DNA was a double helix – Through observations of the X-ray crystallographic images of DNA G C A T T A 1 nm C G C A T G C T A T A A T T A G A Figure 16.7a, c 3.4 nm G C 0.34 nm T (a) Key features of DNA structure Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings (c) Space-filling model • Franklin had concluded that DNA – Was composed of two antiparallel sugarphosphate backbones, with the nitrogenous bases paired in the molecule’s interior • The nitrogenous bases – Are paired in specific combinations: adenine with thymine, and cytosine with guanine Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 5 end O OH Hydrogen bond P –O 3 end OH O O A T O O O CH2 P –O O H2C O –O P O O G O C O O CH2 P O O– O P H2C O O C O G O O O CH2 P –O O– O O O– O P H2C O O A O T O CH2 OH 3 end O O– P O Figure 16.7b (b) Partial chemical structure Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings O 5 end DNA • Stands for Deoxyribonucleic acid • Made up of subunits called nucleotides • Nucleotide made of: 1. Phosphate group 2. 5-carbon sugar 3. Nitrogenous base Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 20 DNA Nucleotide Phosphate Group O 5 CH2 O=P-O O O N C1 Nitrogenous ba C4 Sugar (deoxyribose) C3 Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings (A, G, C, or T C2 21 Pentose Sugar • Carbons are numbered clockwise 1’ to 5’ 5 CH2 O C1 C4 Sugar (deoxyribose) C3 Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings C2 22 DNA 5 O 3 3 P 5 O O C G 1 P 5 3 2 4 4 P 5 P 2 3 1 5 O O T A 3 O 3 Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 23 5 P P • Watson and Crick reasoned that there must be additional specificity of pairing – Dictated by the structure of the bases • Each base pair forms a different number of hydrogen bonds – Adenine and thymine form two bonds, cytosine and guanine form three bonds Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings H N N N N Sugar O H H CH3 N N N O Sugar Thymine (T) Adenine (A) H O N N Sugar N H N N N N N Figure 16.8 H H Guanine (G) Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings H O Sugar Cytosine (C) • Concept 16.2: Many proteins work together in DNA replication and repair • The relationship between structure and function – Is manifest in the double helix Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings The Basic Principle: Base Pairing to a Template Strand • Since the two strands of DNA are complementary – Each strand acts as a template for building a new strand in replication Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • In DNA replication – The parent molecule unwinds, and two new daughter strands are built based on basepairing rules T A T A T A C G C G C T A T A T A A T A T A T G C G C G C G A T A T A T C G C G C G T A T A T A T A T A T C G C G C A G (a) The parent molecule has two complementary strands of DNA. Each base is paired by hydrogen bonding with its specific partner, A with T and G with C. (b) The first step in replication is separation of the two DNA strands. Figure 16.9 a–d Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings (c) Each parental strand now serves as a template that determines the order of nucleotides along a new, complementary strand. (d) The nucleotides are connected to form the sugar-phosphate backbones of the new strands. Each “daughter” DNA molecule consists of one parental strand and one new strand. • DNA replication is semiconservative – Each of the two new daughter molecules will have one old strand, derived from the parent molecule, and one newly made strand First Second Parent cell replication replication (a) Conservative model. The two parental strands reassociate after acting as templates for new strands, thus restoring the parental double helix. (b) Semiconservative model. The two strands of the parental molecule separate, and each functions as a template for synthesis of a new, complementary strand. Figure 16.10 a–c (c) Dispersive model. Each strand of both daughter molecules contains a mixture of old and newly synthesized DNA. Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Experiments performed by Meselson and Stahl – Supported the semiconservative model of DNA replication EXPERIMENT Matthew Meselson and Franklin Stahl cultured E. coli bacteria for several generations on a medium containing nucleotide precursors labeled with a heavy isotope of nitrogen, 15N. The bacteria incorporated the heavy nitrogen into their DNA. The scientists then transferred the bacteria to a medium with only 14N, the lighter, more common isotope of nitrogen. Any new DNA that the bacteria synthesized would be lighter than the parental DNA made in the 15N medium. Meselson and Stahl could distinguish DNA of different densities by centrifuging DNA extracted from the bacteria. 1 Bacteria cultured in medium containing 15N 2 Bacteria transferred to medium containing 14N RESULTS 3 DNA sample centrifuged after 20 min (after first replication) 4 DNA sample centrifuged after 40 min (after second replication) Less dense More dense The bands in these two centrifuge tubes represent the results of centrifuging two DNA samples from the flask Figure 16.11 in step 2, one sample taken after 20 minutes and one after 40 minutes. Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings CONCLUSION Meselson and Stahl concluded that DNA replication follows the semiconservative model by comparing their result to the results predicted by each of the three models in Figure 16.10. The first replication in the 14N medium produced a band of hybrid (15N–14N) DNA. This result eliminated the conservative model. A second replication produced both light and hybrid DNA, a result that eliminated the dispersive model and supported the semiconservative model. First replication Conservative model Semiconservative model Dispersive model Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Second replication DNA Replication: A Closer Look • The copying of DNA – Is remarkable in its speed and accuracy • More than a dozen enzymes and other proteins – Participate in DNA replication Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Getting Started: Origins of Replication • The replication of a DNA molecule – Begins at special sites called origins of replication, where the two strands are separated Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • A eukaryotic chromosome – May have hundreds or even thousands of replication origins Origin of replication 1 Replication begins at specific sites where the two parental strands separate and form replication bubbles. Bubble Parental (template) strand Daughter (new) strand 0.25 µm Replication fork 2 The bubbles expand laterally, as DNA replication proceeds in both directions. 3 Eventually, the replication bubbles fuse, and synthesis of the daughter strands is complete. Two daughter DNA molecules (a) In eukaryotes, DNA replication begins at many sites along the giant DNA molecule of each chromosome. Figure 16.12 a, b Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings (b) In this micrograph, three replication bubbles are visible along the DNA of a cultured Chinese hamster cell (TEM). DNA Replication • Enzyme Helicase unwinds and separates the 2 DNA strands by breaking the weak hydrogen bonds • Single-Strand Binding Proteins attach and keep the 2 DNA strands separated and untwisted Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 35 DNA Replication • Enzyme Topoisomerase attaches to the 2 forks of the bubble to relieve stress on the DNA molecule as it separates Enzyme Enzyme DNA Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 36 DNA Replication • Before new DNA strands can form, there must be RNA primers present to start the addition of new nucleotides • Primase is the enzyme that synthesizes the RNA Primer • DNA polymerase III can then add the new nucleotides Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 37 Elongating a New DNA Strand • Elongation of new DNA at a replication fork – Is catalyzed by enzymes called DNA polymerases, which add nucleotides to the 3 end of a growing strand New strand 5 end Sugar Template strand 3 end A Base Phosphate T A T C G C G G C G C A T A OH Pyrophosphate 3 end P OH Figure 16.13 3 end 5 end Nucleoside triphosphate C P C 2 P 5 end Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 5 end Antiparallel Elongation • How does the antiparallel structure of the double helix affect replication? Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • DNA polymerases add nucleotides – Only to the free 3end of a growing strand • Along one template strand of DNA, the leading strand – DNA polymerase III can synthesize a complementary strand continuously, moving toward the replication fork Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • To elongate the other new strand of DNA, the lagging strand – DNA polymerase III must work in the direction away from the replication fork • The lagging strand – Is synthesized as a series of segments called Okazaki fragments, which are then joined together by DNA ligase Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Synthesis of leading and lagging strands during DNA replication 1 DNA pol Ill elongates DNA strands only in the 5 3 direction. 3 5 Parental DNA 5 3 Okazaki fragments 2 1 3 5 DNA pol III 2 One new strand, the leading strand, can elongate continuously 5 3 as the replication fork progresses. 3 The other new strand, the lagging strand must grow in an overall 3 5 direction by addition of short segments, Okazaki fragments, that grow 5 3 (numbered here in the order they were made). Template strand 3 Leading strand Lagging strand 2 Template strand Figure 16.14 1 DNA ligase Overall direction of replication Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 4 DNA ligase joins Okazaki fragments by forming a bond between their free ends. This results in a continuous strand. Priming DNA Synthesis • DNA polymerases cannot initiate the synthesis of a polynucleotide – They can only add nucleotides to the 3 end • The initial nucleotide strand – Is an RNA or DNA primer Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Only one primer is needed for synthesis of the leading strand – But for synthesis of the lagging strand, each Okazaki fragment must be primed separately Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 1 Primase joins RNA nucleotides into a primer. 3 5 5 3 Template strand RNA primer 3 5 3 DNA pol III adds DNA nucleotides to the primer, forming an Okazaki fragment. 2 5 3 1 After reaching the next RNA primer (not shown), DNA pol III falls off. Okazaki fragment 3 3 5 1 5 4 After the second fragment is primed. DNA pol III adds DNA nucleotides until it reaches the first primer and falls off. 5 3 5 3 2 5 1 DNA pol 1 replaces the RNA with DNA, adding to the 3 end of fragment 2. 5 3 6 5 1 DNA ligase forms a bond between the newest DNA and the adjacent DNA of fragment 1. 5 3 Figure 16.15 3 2 7 The lagging strand in this region is now complete. 3 2 1 Overall direction of replication Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 5 Other Proteins That Assist DNA Replication • Helicase, topoisomerase, single-strand binding protein – Are all proteins that assist DNA replication Table 16.1 Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • A summary of DNA replication Overall direction of replication 1 Helicase unwinds the parental double helix. 2 Molecules of singlestrand binding protein stabilize the unwound template strands. 3 The leading strand is synthesized continuously in the 5 3 direction by DNA pol III. DNA pol III Lagging Leading strand Origin of replication strand Lagging strand OVERVIEW Leading strand Leading strand 5 3 Parental DNA 4 Primase begins synthesis of RNA primer for fifth Okazaki fragment. 5 DNA pol III is completing synthesis of the fourth fragment, when it reaches the RNA primer on the third fragment, it will dissociate, move to the replication fork, and add DNA nucleotides to the 3 end of the fifth fragment primer. Replication fork Primase DNA pol III Primer 4 DNA ligase DNA pol I Lagging strand 3 2 6 DNA pol I removes the primer from the 5 end of the second fragment, replacing it with DNA nucleotides that it adds one by one to the 3 end of the third fragment. The replacement of the last RNA nucleotide with DNA leaves the sugarphosphate backbone with a free 3 end. Figure 16.16 Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 1 3 5 7 DNA ligase bonds the 3 end of the second fragment to the 5 end of the first fragment. The DNA Replication Machine as a Stationary Complex • The various proteins that participate in DNA replication – Form a single large complex, a DNA replication “machine” • The DNA replication machine – Is probably stationary during the replication process Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Proofreading and Repairing DNA • DNA polymerases proofread newly made DNA – Replacing any incorrect nucleotides • In mismatch repair of DNA – Repair enzymes correct errors in base pairing Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • In nucleotide excision repair – Enzymes cut out and replace damaged stretches of DNA 1 A thymine dimer distorts the DNA molecule. 2 A nuclease enzyme cuts the damaged DNA strand at two points and the damaged section is removed. Nuclease DNA polymerase 3 Repair synthesis by a DNA polymerase II fills in the missing nucleotides. DNA ligase Figure 16.17 Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 4 DNA ligase seals the Free end of the new DNA To the old DNA, making the strand complete. Proofreading New DNA • DNA polymerase initially makes about 1 in 10,000 base pairing errors • Enzymes (DNA polymerase II) proofread and correct these mistakes • The new error rate for DNA that has been proofread is 1 in 1 billion base pairing errors Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 51 Crash Course Biology DNA Structure and Replication • https://www.youtube.com/watch?v=8kK2zwjRV 0M Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Replicating the Ends of DNA Molecules • The ends of eukaryotic chromosomal DNA – Get shorter with each round of replication 5 End of parental DNA strands Leading strand Lagging strand 3 Last fragment Previous fragment RNA primer Lagging strand 5 3 Primer removed but cannot be replaced with DNA because no 3 end available for DNA polymerase Removal of primers and replacement with DNA where a 3 end is available 5 3 Second round of replication 5 New leading strand 3 New lagging strand 5 3 Further rounds of replication Figure 16.18 Shorter and shorter daughter molecules Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Eukaryotic chromosomal DNA molecules – Have at their ends nucleotide sequences, called telomeres, that postpone the erosion of genes near the ends of DNA molecules Figure 16.19 Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 1 µm • If the chromosomes of germ cells became shorter in every cell cycle – Essential genes would eventually be missing from the gametes they produce • An enzyme called telomerase – Catalyzes the lengthening of telomeres in germ cells Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • In eukaryotes, the DNA-protein complex, is called chromatin – Is ordered into higher structural levels than the DNA-protein complex in prokaryotes Figure 19.1 Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Both prokaryotes and eukaryotes – Must alter their patterns of gene expression in response to changes in environmental conditions Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Chromatin structure is based on successive levels of DNA packing • Eukaryotic DNA – Is precisely combined with a large amount of protein • Eukaryotic chromosomes – Contain an enormous amount of DNA relative to their condensed length Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Nucleosomes, or “Beads on a String” • Proteins called histones – Are responsible for the first level of DNA packing in chromatin – Bind tightly to DNA • The association of DNA and histones – Seems to remain intact throughout the cell cycle Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • In electron micrographs – Unfolded chromatin has the appearance of beads on a string • Each “bead” is a nucleosome – The basic unit of DNA packing 2 nm DNA double helix Histones Histone tails Histone H1 Linker DNA (“string”) Nucleosome (“bad”) (a) Nucleosomes (10-nm fiber) Figure 19.2 a Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 10 nm Higher Levels of DNA Packing • The next level of packing – Forms the 30-nm chromatin fiber 30 nm Nucleosome (b) 30-nm fiber Figure 19.2 b Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • The 30-nm fiber, in turn – Forms looped domains, making up a 300-nm fiber Protein scaffold Loops 300 nm (c) Looped domains (300-nm fiber) Figure 19.2 c Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Scaffold • In a mitotic chromosome – The looped domains themselves coil and fold forming the characteristic metaphase chromosome 700 nm 1,400 nm (d) Metaphase chromosome Figure 19.2 d Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • In interphase cells – Most chromatin is in the highly extended form called euchromatin Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Gene expression can be regulated at any stage, but the key step is transcription • All organisms – Must regulate which genes are expressed at any given time • During development of a multicellular organism – Its cells undergo a process of specialization in form and function called cell differentiation Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Differential Gene Expression • Each cell of a multicellular eukaryote – Expresses only a fraction of its genes • In each type of differentiated cell – A unique subset of genes is expressed Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Many key stages of gene expression – Can be regulated in eukaryotic cells Signal NUCLEUS Chromatin Chromatin modification: DNA unpacking involving histone acetylation and DNA demethlation DNA Gene available for transcription Gene Transcription RNA Cap Exon Primary transcript Intron RNA processing Tail mRNA in nucleus Transport to cytoplasm CYTOPLASM mRNA in cytoplasm Degradation of mRNA Translation Polypetide Cleavage Chemical modification Transport to cellular destination Active protein Degradation of protein Figure 19.3 Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Degraded protein Regulation of Chromatin Structure • Genes within highly packed heterochromatin – Are usually not expressed Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Histone Modification • Chemical modification of histone tails – Can affect the configuration of chromatin and thus gene expression Chromatin changes Transcription RNA processing mRNA degradation Translation Protein processing and degradation Histone tails DNA double helix Amino acids available for chemical modification Figure 19.4a (a) Histone tails protrude outward from a nucleosome Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Histone acetylation (acetyl group COCH3) – Seems to loosen chromatin structure and thereby enhance transcription Unacetylated histones Figure 19.4 b Acetylated histones (b) Acetylation of histone tails promotes loose chromatin structure that permits transcription Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings DNA Methylation • Addition of methyl (CH3) groups to certain bases in DNA – Is associated with reduced transcription in some species Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Epigenetic Inheritance • Epigenetic inheritance – Is the inheritance of traits transmitted by mechanisms not directly involving the nucleotide sequence Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Regulation of Transcription Initiation • Chromatin-modifying enzymes provide initial control of gene expression – By making a region of DNA either more or less able to bind the transcription machinery Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings