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Chapter 23 Sections 2-4 Transition Metal Complexes © 2012 Pearson Education, Inc. Complexes • Commonly, transition metals can have molecules or ions that bond to them. • These give rise to complex ions or coordination compounds. Transition Metals © 2012 Pearson Education, Inc. Ligands The molecules or ions that bind to the central metal are called ligands (from the Latin ligare, meaning “to bind”). Transition Metals © 2012 Pearson Education, Inc. A. Yes. Ammonia is the Lewis acid. B. Yes. The metal cation is the Lewis acid. C. No. Ammonia is a neutral molecule and cannot can not accept electron density from a Lewis base. D. No. The metal cation cannot accept electron density from a Lewis base. Coordination Werner Theory The Swiss Alfred Werner One Thus, ofalthough the chemist properties the first that two has complexes led deduced to thein the that there was acomplexes difference between fascination table above with each have 3 chlorines, and transition inthe the first oxidation number of a metal andinthe number metals all threeisserve the wide as anions, range ofwhile stunning thecolors second of ligands itchlorines took on, is which hebound calledto the found one ofinthe them. tightly the coordination cobalt and the number. other two are counterions. Transition Metals © 2012 Pearson Education, Inc. Sample Exercise 23.1 Identifying the Coordination Sphere of a Complex Palladium(II) tends to form complexes with coordination number 4. A compound has the composition PdCl2 · 3 NH3. (a) Write the formula for this compound that best shows the coordination structure. (b) When an aqueous solution of the compound is treated with excess AgNO3(aq), how many moles of AgCl(s) are formed per mole of PdCl2 · 3 NH3? (a) By analogy to the ammonia complexes of cobalt(III) shown in Figure 23.7, we predict that the three NH3 are ligands attached to the Pd(II) ion. The fourth ligand around Pd(II) is one chloride ion. The second chloride ion is not a ligand; it serves only as a counterion (a noncoordinating ion that balances charge) in the compound. We conclude that the formula showing the structure best is [Pd(NH3)3Cl]Cl. (b) Because only the non-ligand can react, we expect to produce 1 mol of AgCl(s) per mole of complex. The balanced equation is [Pd(NH3)3Cl]Cl(aq) + AgNO3(aq) → [Pd(NH3)3Cl]NO3(aq) + AgCl(s) This is a metathesis reaction (Section 4.2) in which one of the cations is the [Pd(NH3)3Cl]+ complex ion. Practice Exercise Predict the number of ions produced per formula unit in an aqueous solution of CoCl2 · 6 H2O. Answer: three: [Co(H2O)6]2+ and two Cl– The Metal–Ligand Bond • The reaction between a metal and a ligand is a reaction between a Lewis acid (the metal) and Lewis base (the ligand). • The new complex has distinct physical and chemical properties. Transition Metals © 2012 Pearson Education, Inc. A. B. C. D. [Fe(H2O)4]3+(aq) + SCN–(aq) [Fe(H2O)3NCS]2+(aq) + H2O(l) [Fe(H2O)4]3+(aq) + S2+(aq) + CN–(aq) [Fe(H2O)5NCS]2+(aq) + H2O(l) Fe3+(aq) + 3SCN–(aq) FeCN3 (aq) + 3S–(aq) [Fe(H2O)6]3+ (aq) + SCN–(aq) [Fe(H2O)5NCS]2+(aq) + H2O(l) Coordination Numbers • The number of atoms directly bonded to the metal atom in a complex is the coordination number. Compound Coordination number [Ag(NH3)2]+ 2 [Co(NH3)6]Cl3 6 [Co(NH3)5Cl]Cl2 6 trans -[Co(NH3)4Cl2]Cl 6 cis -[Co(NH3)5Cl2]Cl 6 Transition Metals © 2012 Pearson Education, Inc. Sample Exercise 23.2 Determining the Oxidation Number of a Metal in a Complex What is the oxidation number of the metal in [Rh(NH3)5Cl](NO3)2? Solve The NO3 group is the nitrate anion, which has a 1– charge. The NH3 ligands carry zero charge, and the Cl is a coordinated chloride ion, which has a 1– charge. The sum of all the charges must be zero: x + 5(0) + (–1) + 2(–1) = 0 [Rh(NH3)5Cl](NO3)2 The oxidation number of rhodium, x, must therefore be +3. Practice Exercise What is the charge of the complex formed by a platinum(II) metal ion surrounded by two ammonia molecules and two bromide ions? Answer: zero Sample Exercise 23.3 Determining the Formula of a Complex Ion A complex ion contains a chromium(III) bound to four water molecules and to two chloride ions.What is the formula and charge of this ion? +3 + 4(0) + 2(–1) = +1 Cr(H2O)4Cl2 The charge on the ion is 1+, [Cr(H2O)4Cl2]+. Practice Exercise Write the formula for the complex described in the Practice Exercise accompanying Sample Exercise 23.2. Answer: [Pt(NH3)2Br2] Coordination Numbers • The coordination number of a metal depends upon the size of the metal and the size of the ligands. • While iron(III) can bind to 6 fluorides, it can only accommodate 4 of the larger chlorides. Transition Metals © 2012 Pearson Education, Inc. A. B. C. D. NH3—Zn—NH3 NH3—Pt—NH3 109.5° 120° 180° 120° 90° 109.5° 120° 90° Geometries: A. B. C. D. C.N. = 4 Octahedral Tetrahedral Octahedral Square planar C.N. = 6 Tetrahedral Octahedral Square planar Tetrahedral A. B. C. D. Two for both Three for both Four for both Six for both A. Bidentate ligand B. Monodentate ligand Common Ligands The table above contains some ligands commonly found in complexes. Monodentate ligands coordinate to one site on the metal, bidentate to two, and so forth. Transition Metals © 2012 Pearson Education, Inc. Common Ligands Bi and polydentate ligands are also called chelating agents. Transition Metals © 2012 Pearson Education, Inc. Chelates in Biological Systems • There are many transition metals that are vital to human life. • Several of these are bound to chelating agents. Transition Metals © 2012 Pearson Education, Inc. Chelates in Biological Systems • For instance, the iron in hemoglobin carries O2 and CO2 through the blood. Transition Metals © 2012 Pearson Education, Inc. A. B. C. D. On the protein group On the heme group On the NH group Where O2 binds Chelates in Biological Systems • For instance, the iron in hemoglobin carries O2 and CO2 through the blood. • Carbon monoxide and cyanide are poisonous because they will bind more tightly to the iron than will oxygen. Transition Metals © 2012 Pearson Education, Inc. A. B. C. D. 420 nm 500 nm 610 nm 650 nm A. It has a planar structure that enables the C-H bonds to absorb light in the visible region. B. The C-C bonds absorb light in the ultraviolet region. C. It has conjugated double bonds that absorb light in the visible region. D. It has C-H bonds that absorb light in the infrared region. Nomenclature in Coordination Chemistry 1. In naming complexes that are salts, the name of the cation is given before the name of the anion. Transition Metals © 2012 Pearson Education, Inc. Nomenclature in Coordination Chemistry 2. In naming complex ions or molecules, the ligands are named before the metal. Ligands are listed in alphabetical order, regardless of their charges. Transition Metals © 2012 Pearson Education, Inc. Nomenclature in Coordination Chemistry 3. The names of anionic ligands end in the letter o, but electrically neutral ligands ordinarily bear the name of the molecules. Transition Metals © 2012 Pearson Education, Inc. Nomenclature in Coordination Chemistry 4. Greek prefixes (di-, tri-, tetra-, etc.) are used to indicate the number of each kind of ligand when more than one is present. If the ligand contains a Greek prefix or is polydentate, the prefixes bis-, tris-, tetrakis-, etc. are used and the ligand name is placed in parentheses. Transition Metals © 2012 Pearson Education, Inc. Nomenclature in Coordination Chemistry 5. If the complex is an anion, its name ends in -ate. 6. The oxidation number of the metal is given in parentheses in Roman numerals following the name of the metal. Transition Metals © 2012 Pearson Education, Inc. Sample Exercise 23.4 Naming Coordination Compounds Name the compounds (a) [Cr(H2O)4Cl2]Cl, (b) K4[Ni(CN)4]. Solve (a) The ligands are four water molecules— tetraaqua—and two chloride ions—dichloro. By assigning all the oxidation numbers we know for this molecule, we see that the oxidation number of Cr is +3: Thus, we have chromium(III). Finally, the anion is chloride. The name of the compound is (b) The complex has four cyanide ion ligands, CN–, which means tetracyano, and the oxidation state of the nickel is zero: Because the complex is an anion, the metal is indicated as nickelate(0). Putting these parts together and naming the cation first, we have +3 + 4(0) + 2(–1) + (–1) = 0 [Cr(H2O)4Cl2]Cl tetraaquadichlorochromium(III) chloride 4(+1) + 0 + 4(–1) = 0 K4[Ni(CN)4] potassium tetracyanonickelate(0) Practice Exercise Name the compounds (a) [Mo(NH3)3Br3]NO3, (b) (NH4)2[CuBr4]. (c) Write the formula for sodium diaquabis(oxalato)ruthenate(III). Answer: (a) triamminetribromomolybdenum(IV) nitrate, (b) ammonium tetrabromocuprate(II) (c) Na[Ru(H2O)2(C2O4)2]