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1 Problem set 3 Due dates: Official date is 12 Dec. However I will accept problem sets for full grades through Dec. 16 in recognition of the time it took me to finish providing problems. (Note also that the problems for Chapters 14 and 15 are shorter.) Chapter 16 will not be covered, for Chapter 17, please work the problems at the back fo the chapter for practice. Problem sets turned in on 12 Dec. will be graded by the morning of 18 Dec. Chapter 12 1 The library A genomic library of human is to be constructed in a plasmid that can accommodate 4 kbp inserts. How many individual clones must be in the library in order to have a 99 % chance that one carries a fragment of interest ? What if the library is constructed in a cosmid that can accommodate 40 kbp inserts ? What if the library is constructed in a YAC that can accommodate 2 Mbp inserts ? Write two primers, each 18 bases long that would enable you to PCR-amplify the gene for phenylalanyl tRNA, assuming for now that the nucleotide sequence in Fig.11.33 is encoded by the DNA. 2 Cloning You are trying to clone up the gene for a protein. You already purified a little of the protein. It took you three weeks working in the cold room and your yield was 0.2 mg from 10 kg of liver tissue. However that was enough to allow N-terminal sequencing and C-terminal sequencing (recall chapter 5). You now know that the protein begins with Met-Gln-Ala-Arg-Pro-Trp- and ends with -Met-Leu-Val-Gly-Asp-Asn. You never want to do that purification again, so you plan to use the amino acid sequence information to design primers and use the primers to amplify the gene for your protein by PCR. Use the genetic code provided in Table 30.1 to calculate: how many different primers will be needed to be sure to have a complement to the beginning of the coding region of the gene. How many different primer sequences will be needed to be sure to have a complement to the end of the coding region of the gene. mRNA is copied off the 'template strand' of DNA, NOT the 'coding strand' (Under this nomenclature, the coding DNA strand has the same sequence as the mRNA but with T replacing U). Figure out what the DNA template strand will have to be for the beginning of your gene, using the following codes to accommodate cases where the identity of the base can be more than one thing: R=purine, Y=pyrimidine, N anything. This will be part of one of your primers. Do the same for the end of your gene. Then write down the sequence of the primer you will use for this end of the gene. In addition to targeting the correct gene, you will want your product to have restriction endonuclease sites that will facilitate directional cloning. At the start end of the gene, 2 you can take advantage of the fact that the NcoI enzyme recognizes CCATGG, which contains the codon for Met. However it also requires that the next codon begin with G. Will this cause a change in the amino acid sequence ? If so, discuss the possible significance of the change for protein structure, solubility and stability (two sentences max). How many base mis-matches can the Nco1 site introduce into the base pairing you expect between your primer and the DNA ? Look up the cleavage site for Nde1, think of the considerations as we entertained for Nco1 and discuss the advantages and disadvantages of building on an Nde1 site instead of Nco1. Now write you extended your primer sequence, incorporating a cleavage site as well as the code for the first six amino acids (possibly mutated). Note that you would normally use slightly longer primers, but the logic is the same. Also, computer programs would do the back-translation you have just done. All the user does is type in amino acid codes. Finally the oligonucleotide synthesizing machine will even use mixtures of pyrimidines, purines or all nucleotides, wherever the customer requests Y, R or N. Also note that a few mismatched bases can be tolerated early in the PCR, and moreover can be compensated for with adjustments to the melting and annealing temperatures and times used. 3 3 Primers A successful PCR experiment often depends on designing the correct primers (above). Inn particular, the Tm for each primer should be approximately the same. What is the Tm ? Why should the two primers' Tms be approximately the same ? 4 Diagnosis of a problem A number of people were found not to be able to clear a certain drug from their bloodstream. This was found to be related to their version of gene M, which encodes enzyme m. Six people were tested for gene M integrity using molecular biological methods. 'A' is the positive control (clears the drug fine). 'B' is asymptomatic but has children who cannot clear the drug. Persons 'C' through 'F' cannot clear the drug. Tissue samples were obtained from each person. DNA was digested with restriction endonuclease HindIII in preparation for Southern analysis. Northern analysis on the mRNA was also performed, as was a Western analysis employing antibody to enzyme m. Based on the results shown to the right, say why person 'B' has no symptoms. Say why some of person 'B's children do have symptoms. For each of people 'C', 'D', 'E' and 'F' suggest a reason why they may not be able to clear the drug. Data for Problem 4 Chapter 13 (back to number answers !) 1 Antibiotic resistance: Some bacteria are resistant to penicillin because they export an enzyme that degrades penicillin by hydrolyzing it. One such enzyme is !-lactamase. The molecular weight of Staphylococcus aureus' !"lactamase is 29.6 kDa. Researchers measured the amount of penicillin hydrolyzed per minute in a 10 ml solution containing 10-9 g of pure !lactamase, for various concentrations of penicillin. The resulting initial velocities are provided below [Penicillin] Amount hydrolyzed per unit of time (eg. minute) (µM) (nmoles) 1 0.11 3 0.25 5 0.34 4 10 30 50 0.45 0.58 0.61 a Plot vo vs. [S] and also plot 1/vo vs. 1/[S] for the above data. Does this !lactamase obey Michaelis-Menten kinetics ? If yes, what is the KM ? b What is the value of Vmax ? c What is the enzyme's turnover number under the conditions used ? (assume one active site per 29.6 kDa molecule. d What is the catalytic efficiency of this enzyme ? Does this enzyme display catalytic perfection ? 2 Enzyme inhibition The kinetics of an enzyme are measured as a function of substrate concentration in the presence and in the absence of an inhibitor I ([I] = 2 mM). [S] (µ#) 3 5 10 30 90 vo (µM/min) no inhibitor 2 mM inhibitor 10.4 4.1 14.5 6.4 22.5 11.3 33.8 22.6 40.5 33.8 a What are the values of Vmax and KM in the absence of inhibitor ? b What are the values of Vmax and KM in the presence of inhibitor ? c What type of inhibition is this ? d What is the dissociation constant KI for this inhibitor ? e If [S] = 10 µM and [I] = 2 mM, what fraction of the enzyme molecules have a bound substrate ? a bound inhibitor ? f If [S] = 30 µM and [I] = 2 mM, what fraction of the enzyme molecules have a bound substrate ? a bound inhibitor ? Compare this ratio with the ratio of the reaction velocities under the same conditions. 5 3 Uncompetitive Inhibition Assume that an inhibitor I can bind reversibly to an ES complex (but not to E alone). The resulting IES complex does not go forward to produce product (see scheme). Use same the logic as S we did in deriving the Michaelis-Menten E ES equations to derive mathematical equations for the apparent Vmax' I and KM' applicable in this case. Vmax' is the maximum reaction velocity and Km' is the IES concentration of substrate producing halfmaximal velocity, at a given inhibitor concentration. You should get the results listed in Table 13.6 E+P K’I These expressions will make reference to the dissociation constant for [IES], KI'. 4 Linear relationships Recast the Michaelis - Menten equation in order to describe a plot of vo vs. vo/[S]. This is called an Eadie-Hofstee plot. Use excell or equivalent software to generate a data set and an Eadie-Hofstee plot of it. Along with vo, for each substrate concentration, also plot a point using that substrate concentration and 1.05x vo and another using the substrate concentration and 0.95x vo. These latter two point will demonstrate the effect of a 5% error in measuring Vo. Comment on the merits or cautions associated with using an Eadie-Hofstee analysis. 6 Chapter 14 1 Mutational analysis In a Ser protease, researchers found that mutating the active site His to Ala decreased the kcat by a factor of 105 (kca,mut = .00001 kcat). Mutation of the active site Ser to Ala causes kcat to decrease by a factor of 106. . Would you expect a doubly mutated protein to display 10-11 times the normal activity ? Explain the basis for your answer. 2 Designer enzyme If you had the gene for trypsin, but a mutation changed the codon for Asp 189 to a codon for Lys, what change might this produce in substrate specificity ? Would you expect your mutant trypsin to be as good a protease catalyst as the normal ("wild-type") trypsin ? (i.e. would it be as good at accelerating peptide bond cleavage ?) 3 Make your own mechanism Based on the mechanism of Ser proteases, propose a mechanism for a Cys protease. For your answer, draw a segment of the substrate peptide backbone in the presence of a Cys side chain from the enzyme active site. Use R and R' for the amino acid side chains adjacent to the peptide bond to be cleaved and don't bother drawing more distant portions of the substrate peptide (eg. terminate the backbone with a squiggle to indicate that it continues beyond the drawing). Then draw transition states and intermediates involving the enzyme Cys side chain and the peptide in which you can sketch in features you would expect a good enzyme active site to use to stabilize the transition states. A perfect answer will show what the enzyme's Cys side chain probably does, what some other active site residue could do to activate the Cys for that role, what the peptide transition state likely looks like and what the active site likely does to stabilize it. Draw analogous structures to indicate how the enzyme is restored to its starting state, and what is done by active site residues to favour transition states along the way. 4 Fundamentals of catalysis Based on the fundamental principles of catalysis, will an enzyme that accelerates the rate of A $ B affect the rate of B $ A ? What should its effect be ? (qualitative answer). A quantitative example: If Keq for A $ B is 10, (kcat/KM)A$B is 103 M-1 s-1, and knon,A$B is 1 s-1, calculate knon,B$A and (kcat/KM)B$A For inspiration, you can reread the 'deeper look' on page 443. Also recall that equilibrium constants can be expressed in terms of either concentrations or rate constants. 7 Chapter 15 1 A smart enzyme, by design. If you wish to build into your designer enzyme the possibility of turning it off/on on a timescale of microseconds, will you design in an allosteric site, sensitivity to covalent modification, or amino acid sequences that cause the protein to be degraded within an hour of biosynthesis in conjunction with regulatory sequences in the mRNA that favour production of the protein when it is needed ? What if you want the possibility of turning on or off your enzyme on a timescale of minutes and keeping it on or off for minutes at a time ? What if you want your enzyme to turn off an hour or so after it is administered to a patient ? 2 Anticooperativity In class, we looked at the effect of allosteric modulation of affinity for substrate. The case in class was one of positive cooperativity, wherein binding of the effector 'A' increased the protein's affinity for substrate 'B'. Indeed, KAB = 0.1 mM whereas KB = 1 mM in our excel example. Now, use the same equation (below) and KAB = 10 mM vs. KB = 1 to model negative cooperativity (anticooperativity between A and B). For KA = 0.7 mM, what is KBA ? Generate an excel (or equivalent) spread sheet for concentrations of B ranging from 0 to 50 mM. Generate a plot of the fractional saturation of B-binding sites when [A] = 0. [B] ! [A] $ 1+ B & K B #" KA % [PB] + [APB] Fractional saturation with respect to B = = [P]Tot [A] [B] ! [A] $ 1+ + 1+ B & K A K B #" KA % Do the same for [A] = 20 mM, [A] = 2 mM and [A] = 0.2 mM. How does the shape of the curve change ? What is the span of B concentrations in which the fractional saturation goes from approximately 10% to approximately 90% in each of the above four cases ? 3 Allosteric modulation of Vmax The above is an example of a K-system. Now model a V-system by holding KAB = KB = 1 mM but VAmax = 100 s-1 whereas Vmax = 10 s-1. Is A a positive effector or a negative effector ? Now that we are working on a V-system instead of a K-system, KAB = KB. What consequence does this have for KBA vs. KA ? (Write a very short equation.) Derive an equation for fractional saturation with respect to B. You can use the equation above as a starting point. Does this depend on [A] ? Should it ? 8 Use excel or equivalent means to plot vo as a function of [B] ([substrate]) for the simple Michaelis-Menten case, [B] ranging from 0 to 10 mM and [A] = 0. Now use KA = 0.4 mM, and [A]=0.2 mM, and calculate the fraction of the population with A bound ([AP*]/[P*]tot) and the fraction of the population without A bound ([P*]/[P*]tot. Because binding of A is not coupled to binding of B in this case, we can consider just binding of A alone, using the simple definition of the dissociation constant as applied to a single binding site. (The use of an asterisk above indicates no constraints on the contents of the B site (sum of all possibilities)). KA = [A][P*]/[AP*]. For the proteins with A bound, VAmax applies but for the proteins without A bound, VA applies. Calculate the effective Vmax,eff by taking the appropriately weighted average of the two Vmax values above. Use Vmax,eff in the Michaelis-Menten spread sheet and plot the vo vs. [S] for [A]=0.2 mM. Repeat the above and plot vo vs. [S] for [A]=0.4 mM, 0.6 mM, 0.8 mM 1.0 mM and 2 mM. Provide all seven plots in a single chart. You do not need to turn in separate charts of [A] = 0 mM and 0.2 mM.