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Click Here For Integrated Guidance Programme http://upscportal.com/civilservices/online-course/integrated-free-guidance-programme Number System 3 CHAPTER 1 Number System A Civil Servant should be well-versed in basics of Number System. In the Civil Services Aptitude Test Paper 2, in Basic Numeracy, certainly there will be asked some questions based on types of, and operations on numbers. In Indian system, numbers are expressed by means of symbols 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, called digits. Here, 0 is called insignificant digit whereas 1, 2, 3, 4, 5, 6, 7, 8, 9 are called significant digits. We can express a number in two ways. Notation: Representing a number in figures is known as notation as 350. Numeration: Representing a number in words is known as numeration as ‘Five hundred and forty five’. Place Value (Indian) Crore Ten Crore 100000000 108 Lakh Crore 10000000 107 Ten Lakhs 1000000 106 Lakh 100000 105 Thousand Ten Thousands 10000 104 Unit Thousand 1000 103 Hundred 100 102 Tens 10 101 One 1 100 Place Value (International) Million Hundred Millions 100000000 108 Thousand Ten Millions One Million 10000000 102 1000000 106 Hundred Thousands 100000 105 Ten Thousands 10000 104 Unit Thousand Hundred Tens One 1000 103 100 102 10 101 1 100 Face Value and Plac e Value of a Digit Face Value: It is the value of the digit itself eg, in 3452, face value of 4 is ‘four’, face value of 2 is ‘two’. Place Value: It is the face value of the digit multiplied by the place value at which it is situated eg, in 2586, place value of 5 is 5 × 102 = 500. Num be r C a te g o rie s Natural Numbers (N): If N is the set of natural numbers, then we write N = {1, 2, 3, 4, 5, 6,…} The smallest natural number is 1. Whole Numbers (W): If W is the set of whole numbers, then we write W = {0, 1, 2, 3, 4, 5,…} The smallest whole number is 0. © 2011 www.upscportal.com Click Here to Buy This Study Kit http://upscportal.com/civilservices/online-course/study-kit-for-ias-pre-gs-paper-2-2012 Click Here For Integrated Guidance Programme http://upscportal.com/civilservices/online-course/integrated-free-guidance-programme Number System Integers (I): If I is the set of integers, then we write I = {– 3, –2, –1, 0, 1, 2, 3, …} Rational Numbers: Any number which can be expressed in the form of p/q, where p and q are both integers and q # 0 are called rational numbers. eg, 3 7 , ,5, 2 2 9 There exists infinite number of rational numbers between any two rational numbers. Irrational Numbers Non-recurring and non-terminating decimals are called irrational numbers. These p numbers cannot be expressed in the form of q . eg, 3, 5, 29, Real Numbers: Real number includes both rational and irrational numbers. B asic Ru les o n Na tura l Numbers 1. One digit numbers are from 1 to 9. There are 9 one digit numbers. ie, 9 × 100. 2. Two digit numbers are from 10 to 99. There, are 90 two digit numbers. ie, 9 × 10. 3. Three digit numbers are from 100 to 199. There are 900 three digit numbers ie, 9 × 102. In general the number of n digit numbers are 9 × 10(n–1) 4. Sum of the first n, natural numbers ie, 1 + 2 + 3 + 4 + … + n = n n 1 2 5. Sum of the squares of the first n natural numbers ie. 12 + 23 + 32 + 42 + …+ n2 = 6. Sum of the cubes of the first n natural ie, 12 + 23 + 32 + …+ n3 n n 1 2n 1 6 = n n 1 2 2 Example: What is the value of 51 + 52 + 53 + … + 100 ? Solution. 51 + 52 + 33 + ... + 100 = (1 + 3 + …+ 100) – (1 + 2 + 3 + ... + 50) = 100 101 50 51 = 5050 —1275 = 3775 2 2 D iffe ren t Type s o f Num be rs Even Numbers: Numbers which are exactly divisible by 2 are called even numbers. eg, – 4, – 2, 0, 2, 4… Sum of first n even numbers = n (n + 1) Odd Numbers: Numbers which are not exactly divisible by 2 are called odd numbers. eg, – 5, –3, –1, 0, 1, 3, 5… Sum of first n odd numbers = n2 Prime Numbers: Numbers which are divisible by one and itself only are called prime numbers. eg, 2, 3, 5, 7, 11… • 2 is the only even prime number. © 2011 www.upscportal.com Click Here to Buy This Study Kit http://upscportal.com/civilservices/online-course/study-kit-for-ias-pre-gs-paper-2-2012 Click Here For Integrated Guidance Programme http://upscportal.com/civilservices/online-course/integrated-free-guidance-programme Number System • 1 is not a prime number because it has two equal factors. • Every prime number greater than 3 can be written in the form of (6K + 1) or (6K – 1) where K is an integer. ® There are 15 prime numbers between 1 and 50 and l0 prime numbers between 50 and 100. Relative Prime Numbers: Two numbers are said to be relatively prime if they do not have any common factor other than 1. eg, (3, 5), (4, 7), (11, 15), (15, 4)… Twin Primes: Two prime numbers which differ by 2 are called twin primes. eg, (3, 5), (5, 7), (11, 13),… Composite Numbers Numbers which are not prime arc called composite numbers eg, 4, 6, 9, 15,… 1 is neither prime nor composite. Perfect Number: A number is said to be a perfect number, if the sum of all its factors excluding itself is equal to the number itself. eg, Factors of 6 are 1, 2, 3 and 6. Sum of factors excluding 6 = 1 + 2 + 3 = 6. 6 is a perfect number. Other examples of perfect numbers are 28, 496, 8128 etc. Rules for Divisibility Divisibility by 2: A number is divisible by 2 when the digit at ones place is 0, 2, 4, 6 or 8. eg, 3582, 460, 28, 352, .... Divisibility by 3: A number is divisible by 3 when sum of all digits of a number is a multiple of 3. eg, 453 = 4 + 5 + 3 = 12. 12 is divisible by 3 so, 453 is also divisible by 3. Divisibility by 4: A number is divisible by 4, if the number formed with its last two digits is divisible by 4. eg, if we take the number 45024, the last two digits form 24. Since, the number 24 is divisible by 4, the number 45024 is also divisible by 4. Divisibility by 5: A number is divisible by 5 if its last digit is 0 or 5. eg, 10, 25, 60 Divisibility by 6: A number is divisible by 6, if it is divisible both by 2 and 3. eg, 48, 24, 108 Divisibility by 7: A number is divisible by 7 when the difference between twice the digit at ones place and the number formed by other digits is either zero or a multiple of 7. eg, 658 65 – 2 × 8 = 65 – 16 = 49 As 49 is divisible by 7 the number 658 is also divisible by 7. Divisibility by 8: A number is divisible by 8, if the number formed by the last 3 digits of the number is divisible by 8. eg, if we take the number 57832, the last three digits form 832. Since, the number 832 is divisible by 8, the number 57832 is also divisible by 8.. Divisibility by 9: A number is divisible by 9, if the sum of all the digits of a number is a multiple of 9. eg, 684 = 6 + 8 + 4 = 18. 18 is divisible by 9 so, 684 is also divisible by 9. Divisibility by 10: A number is divisible by 10, if its last digit is 0. eg, 20, 180, 350,…. Divisibility by 11: When the difference between the sum of its digits in odd places and in even places is either 0 or a multiple of 11. © 2011 www.upscportal.com Click Here to Buy This Study Kit http://upscportal.com/civilservices/online-course/study-kit-for-ias-pre-gs-paper-2-2012 Click Here For Integrated Guidance Programme http://upscportal.com/civilservices/online-course/integrated-free-guidance-programme Number System eg, 30426 3 + 4 + 6 = 13 0+2 =2 13 – 2 = 11 As the difference is a multiple of 11 the number 30426 is also divisible by 11. ‘Smart’ Facts • If p and q are co-primes and both are factors of a number K, then their product p x q will also be a factor of r. eg, Factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24 prime factors of 24 are 2 and 3, which are co-prime also. Product of 2 × 3 = 6, 6 is also a factor of 24. • If ‘p’ divides ‘q’ and ‘r’, then p’ also divides their sum or difference. eg, 4 divides 12 and 20. Sum of 12 and 20 is 32 which is divisible by 4. Difference of 20 and 12 is 8 which is divisible by 4. • If a number is divisible by another number, then it must be divisible by each of the factors of that number. 48 is divisible by 12. Factors of 12 are 1, 2, 3, 4, 6, 12. So, 48 is divisible by 2, 3, 4 and 6 also. Divis ion on Nu mbers In a sum of division, we have four quantities. They are (i) Dividend, (ii) Divisor, (iii) Quotient and (iv) Remainder. These quantities are connected by a relation. (a) Dividend = Divisor × Quotient + Remainder. (b) Divisor = (Dividend – Remainder) ÷ Quotient. (c) Quotient = (Dividend – Remainder) – Divisor. Example 2: In a sum of division, the quotient is 110, the remainder is 250, the divisor is equal to the sum of the quotient and remainder. What is the dividend ? Solution. Divisor = (110 + 250) = 360 Dividend = (360 × 110) + 250 = 39850 Hence, the dividend is 39850. Example 3: Find the number of numbers upto 600 which are divisible by 14. Solution. Divide 600 by 13, the quotient obtained is 46. Thus, there are 46 numbers less than 600 which are divisible by 14. F ac t o rs a nd Mult iple s Factor: A number which divides a given number exactly is called a factor of the given number, eg, 24 = 1 × 24, 2 × 12, 3 × 8, 4 × 6 Thus, 1, 2, 3, 4, 6, 8, 12 and 24 are factors of 24. • 1 is a factor of every number • A number is a factor of itself • The smallest factor of a given number is 1 and the greatest factor is the number itself. • If a number is divided by any of its factors, the remainder is always zero. • Every factor of a number is either less than or at the most equal to the given number. • Number of factors of a number are finite. Number of Factors of a Number: If N is a composite number such that N = am bn c°... where a, b, c ... are prime factors of N and m, n, o ... are positive integers, then the number of factors of N is given by the expression (m + 1) (n + 1) (o + 1) © 2011 www.upscportal.com Click Here to Buy This Study Kit http://upscportal.com/civilservices/online-course/study-kit-for-ias-pre-gs-paper-2-2012 Click Here For Integrated Guidance Programme http://upscportal.com/civilservices/online-course/integrated-free-guidance-programme Number System Example 4: Find the number of factors that 224 has. Solution. 224 = 25 × 71 Hence, 224 has (5 + 1) (1 + 1) = 6 × 2 = 12 factors. Multiple: A multiple of a number is a number obtained by multiplying it by a natural number eg, Multiples of 5 are 5, 10, 15, 20 Multiples of 12 are 12, 24, 36, 48 • • • • Every number is a multiple of 1. The smallest multiple of a number is the number itself. We cannot find the greatest multiple of a number. Number of multiples of a number are infinite. EXERCISE 1. Evaluate: 2. 3. 4. 5. 6. 7. 9 3 5 5 4 ÷10 3 5 2 × 4 ÷ 2 (a) 9/10 (b) –8/17 (c) –16/19 (d) 4/7 The sum of three consecutive natural numbers each divisible by 3 is 72. What is the largest among them? (a) 25 (b) 26 (c) 27 (d) 30 55% of a number is more than one-third of that number by 52. What is two-fifth of that number? (a) 96 (b) 240 (c) 144 (d) 142 The digits of a two-digit number are in the ratio of 2 : 3 and the number obtained by interchanging the digits is bigger than the original number by 27. What is the original number? (a) 63 (b) 48 (c) 96 (d) 69 What least number would be subtracted from 427398 so that the remaining number is divisible by 15? (a) 13 (b) 3 (c) 16 (d) 11 If 45% of a number is added to the another number, the first number becomes 135 times of the another number. What is the ratio of these two numbers? (a) 8 : 7 (b) 3 : 2 (c) 7 : 8 (d) None of these A number gets reduced to its one-third when 48 is subtracted from it. What is two -third of that number? 8. 9. 10. 11. 12. (a) 22 (b) 76 (c) 36 (d) 48 One-fifth of a number is equal to 5/8th of another number. If 35 is added to the first number, it becomes four times of the second number. Find the second number. (a) 39 (b) 70 (c) 40 (d) 25 Five- eighth of three-tenth of four-ninth of a number is 45. What is the number? (a) 470 (b) 550 (c) 560 (d) 540 Which of the following numbers should be added to 11158 to make it exactly divisible by 77? (a) 9 (b) 8 (c) 6 (d) 7 n If n is odd, (11) + 1 is divisible by: (a) 11 + 1 (b) 11 – 1 (c) 11 (d) 10 + 1 X and Y are positive integers and X is less than Y. If X2 + Y2 equals two times 5 and XY equals two times 2, X / Y will equal: (a) 3 (b) 1 2 (c) 1 (d) 2 13. Find unit digit in (515)31 + (515)90: (a) 0 (b) 5 (c) 1 (d) 4 n n 1 14. Consider the number, where n is a 2 positive integer. Which of the following is necessarily false? 2 n n 1 is divisible by the sum of first n (a) 2 natural numbers. 2 © 2011 www.upscportal.com Click Here to Buy This Study Kit http://upscportal.com/civilservices/online-course/study-kit-for-ias-pre-gs-paper-2-2012 Click Here For Integrated Guidance Programme http://upscportal.com/civilservices/online-course/integrated-free-guidance-programme Number System n n 1 is divisible by the sum of the cubes (b) 2 of first n natural numbers. (c) {n(n + 1)}2 is always even. 2 n n 1 is never divisible by 237. (d) 2 The number 899 is: (a) a number with 5 factors (b) a number with 4 factors (c) a number with more than 4 factors (d) a perfect cube The numerator of a fraction is multiple of two numbers. One of the numbers is greater than the other by 2. The greater number is smaller than the denominator by 1. If the denominator is given as 5 + c(c is a constant), then the minimum value of the fraction is: (a) 2/3 (b) –2 (c) –1/2 (d) 1/2 Find the number which when multiplied by 13 is increased by 180: (a) 20 (b) 15 (c) 124 (d) 5 Find the number of divisors of 10800. (a) 57 (b) 60 (c) 72 (d) 62 The sum of the digits in a two-digit number is 5. If 9 is subtracted from the number, the result is the number with the digits reversed. The number is: (a) 23 (b) 24 (c) 41 (d) 14 Three consecutive numbers such that twice the first, 3 times the second and 4 times the third together make 182. The numbers in question are: (a) 18, 22 and 23 (b) 18, 19 and 20 (c) 19, 20 and 21 (d) 20, 21 and 22 Find the product of place value and face value of 5 in 65231. (a) 28000 (b) 25000 (c) 27000 (d) 26000 Find the least value of K so that 39 K20 is divisible by 3. (a) 1 (b) 3 (c) 5 (d) 2 Find the least value of K so that 36 K36 is divisible by 6. 2 15. 16. 17. 18. 19. 20. 21. 22. 23. 24. 25. 26. 27. 28. 29. 30. 31. 32. 33. 34. 35. 36. (a) 1 (b) 6 (c) 2 (d) 3 Find the least value of K so that 2718 K6 is divisible by 9. (a) 9 (b) 3 (c) 2 (d) 8 What least value must be given to K so that the number 39 K 0 is divisible by 11. (a) 1 (b) 2 (c) 9 (d) 6 Find the sum of the first 50 natural numbers. (a) 1275 (b) 1025 (c) 1235 (d) 1205 Find the sum of all natural numbers from 100 to 175. (a) 10456 (b) 10452 (c) 10450 (d) 10455 Find the sum of all natural numbers between 100 and 175. (a) 10450 (b) 10175 (c) 10170 (d) 10435 Find the sum of first 50 even numbers. (a) 2550 (b) 2540 (c) 2050 (d) 2060 Find the sum of all the even numbers up to 300. (a) 22650 (b) 22675 (c) 22600 (d) 22690 Find the sum of all even numbers from 100 to 175. (a) 2218 (b) 5216 (c) 5206 (d) 5200 Find the sum of first 50 odd numbers. (a) 1950 (b) 1800 (c) 2000 (d) 2500 Find the sum of all odd numbers between 100 and 175. (a) 5069 (b) 5065 (c) 5070 (d) 5050 Find the sum of the squares of first 50 natural numbers. (a) 42925 (b) 42900 (c) 42860 (d) 42875 Find the sum of the cubes of first 10 natural numbers. (a) 3010 (b) 3040 (c) 3025 (d) 3020 Find the number of digits that are to be used in numbering a book of 500 pages. (a) 1392 (b) 1346 (c) 1325 (d) 1352 © 2011 www.upscportal.com Click Here to Buy This Study Kit http://upscportal.com/civilservices/online-course/study-kit-for-ias-pre-gs-paper-2-2012 Click Here For Integrated Guidance Programme http://upscportal.com/civilservices/online-course/integrated-free-guidance-programme Number System 37. Which of the following is divisible by 15 ? (a) 3975 (b) 3575 (c) 3970 (d) 3580 38. What least number must be subtracted from 3475 to make it divisible by 50 ? (a) 75 (b) 100 (c) 25 (d) 50 39. What least number must be added to 5718 to make it exactly divisible by 40 ? (a) 0 (b) 1 (c) 2 (d) 3 40. Find the least number by which 3900 be multiplied to make it a perfect square. (a) 3 (b) 13 (c) 39 (d) 56 41. How many numbers upto 800 are divisible by 24? (a) 30 (b) 29 (c) 33 (d) 26 42. How many numbers upto 700 are divisible by both 3 and 5? (a) 42 (b) 46 (c) 39 (d) 52 43. Find the number nearest to 2559 which is exactly divisible by 35. (a) 2535 (b) 2555 (c) 2540 (d) 2560 44. How many three digit numbers are divisible by 18 ? (a) 55 (b) 50 (c) 52 (d) 56 45. How many integers from 3 to 30, inclusive are odd ? (a) 13 (b) 14 (c) 15 (d) 16 46. Sum of all prime numbers between 50 and 90 is (a) 485 (b) 572 (c) 722 (d) 635 47. What is the unit digit in (476 × 198 × 359 × 242)? (a) 8 (b) 6 (c) 4 (d) 2 48. For any natural number n, what is the value of 1 1 1 1.2 2.3 3.4 1 n n 1 (a) 1 (b) > 1 (c) < 1 (d) Can’t be determined 49. Which is smallest prime number ? (a) 0 (b) 1 (c) 2 (d) 3 50. Three natural numbers are in the ratio 2 : 3 : 4. If the sum of squares of these numbers is 116, then determine the numbers. (a) 2, 3, 4 (b) 4, 6, 8 (c) 6, 9, 12 (d) 8, 12, 16 51. Find the number of divisors excluding 1 and itself for the number 4225. (a) 8 (b) 7 (c) 9 (d) 6 52. Find the number of prime factors of 211 × 75 × 116 . (a) 22 (b) 21 (c) 6 (d) 18 53. How many integers from 1 to 100 exist such that each is divisible by 6 and also has 6 as a digit. (a) 6 (b) 4 (c) 5 (d) 8 54. Sum of two numbers is 60 and their difference is 12. Find their product. (a) 864 (b) 852 (c) 824 (d) 836 55. If 4/5 of a number is 36. Find 3 of the number. (a) 27 (b) 25 (c) 22 (d) 21 56. If a piece of road is 3000 m and we have to supply some lamp posts. One post is at each end and distance between two consecutive lamp post is 75 m. Find the number of posts required. (a) 41 (b) 39 (c) 40 (d) 36 57. The sum of the digits of a two digit number is 9. If 9 is added to the number, then the digits are reversed. Find the number. (a) 36 (b) 63 (c) 45 (d) 54 58. If 2/7 of a number increased by 25 gives 45. Find the number. (a) 81 (b) 63 (c) 72 (d) 70 59. Out of four consecutive prime numbers, the product of first three is 385 and the product of the last three is 1001. Find the last number. (a) 7 (b) 11 (c) 13 (d) 17 60. Three numbers are in the ratio 3 : 5 : 6. Sum of the greatest and the smallest is equal to the sum of the middle and 16. Find the smallest number. (a) 12 (b) 20 (c) 24 (d) 16 © 2011 www.upscportal.com Click Here to Buy This Study Kit http://upscportal.com/civilservices/online-course/study-kit-for-ias-pre-gs-paper-2-2012 Click Here For Integrated Guidance Programme http://upscportal.com/civilservices/online-course/integrated-free-guidance-programme Number System 61. Sum of squares of two numbers is 60 and difference of the squares is 12. Find the sum of two numbers. (a) 4 (b) 10 (c) 6 (d) 8 62. The product of two consecutive integers is 600. Then, the sum of their squares is (a) 1203 (b) 1206 (c) 1201 (d) 1204 63. Thrice a number diminished by 2 is 19. Find the number. (a) 5 (b) 7 (c) 4 (d) 6 64. The sum of 50 natural numbers is always divisible by (a) 17 (b) 3 (c) 5 (d) All of these 65. N = n; where n is natural number. The unit’s digit of N can’t be (a) 2 (b) 6 (c) 5 (d) 0 555 66. Given that 4A =333 + 555333, then A is divisible by (a) 2 (b) 3 (c) 37 (d) All of these 67. N = (a × b × c × d), where a, b, c, d are distinct integers lying between –7 and 12, both inclusive. The minimum value of N is (a) –9240 (b) –840 (c) –2520 (d) None of these 68. The sum of two numbers is 85 and their difference is 9. What is the difference of their squares? (a) 765 (b) 845 (c) 565 (d) 645 69. Find the unit digit in the expansion of 32545 (a) 0 (b) 5 (c) 1 (d) 2 70. Find the unit digit in the expansion of 31448. (a) 6 (b) 4 (c) 8 (d) 2 71. A worker was engaged for a certain number of days and was promised to be paid ` 1755. He remained absent for some days and was paid ` 1365 only. What were his daily wages ? (a) ` 182 (b) ` 195 (c) ` 185 (d) ` 192 72. Which of the following cannot be a digit in the unit’s place of a perfect square ? 73. 74. 75. 76. 77. 78. 79. 80. 81. 82. (a) 7 (b) 1 (c) 5 (d) 0 The smallest number, which when added to the sum of square of 9 to 10 gives a perfect square is (a) 0 (b) 3 (c) 8 (d) 15 (9992 – 9982) is equal to (a) 1 (b) 999 (c) 1997 (d) 998 A number when divided by 119 leaves the remainder 19. If the same number is divided by 17, the remainder will be (a) 19 (b) 10 (c) 7 (d) 2 If n is any positive integer, then 34n – 43n is always divisible by (a) 7 (b) 17 (c) 112 (d) 145 The number zero (0) is surrounded by the same two digit number on both (left and right) sides: for example 25025, 67067 etc. The largest number that always divides such a number is (a) 7 (b) 11 (c) 13 (d) 1001 The least number of five digits exactly divisible by 456 is (a) 10000 (b) 10012 (c) 10032 (d) 10056 Ashok had to do a multiplication. Instead of taking 35 as one of the multipliers, he took 53. As a result, the product went up by 540. What is the new product ? (a) 1050 (b) 1590 (c) 1440 (d) None of these Which of the following is a multiple of 88 ? (a) 1392578 (b) 138204 (c) 1436280 (d) 143616 Which of the following fractions is less than 7/8 and greater than 1/3 ? (a) 1/4 (b) 23/24 (c) 11/12 (d) 17/24 If the numbers : 169, 248, 416, 974, 612, 325 and 517 are arranged in descending order based on the sum of the digits of each of these numbers, the middle number will be (a) 248 (b) 517 (c) 612 (d) 974 © 2011 www.upscportal.com Click Here to Buy This Study Kit http://upscportal.com/civilservices/online-course/study-kit-for-ias-pre-gs-paper-2-2012 Click Here For Integrated Guidance Programme http://upscportal.com/civilservices/online-course/integrated-free-guidance-programme Number System 83. Which of the following is true, if a = 3/4, b = 4/5 and c = 5/6? (a) a < c < b (b) a < b < c (c) c < a < b (d) b < a < c 84. In the array 48392874362754869364, the number of instances where an even number is followed by two odd numbers is (a) 1 (b) 2 (c) 3 (d) 4 85. How many integers from 1 to 100 exist such that each is divisible by 5 and also has 5 as a digit ? (a) 10 (c) 12 (b) 11 (d) 20 86. If x is an even integer, which of the following is an odd integer ? (a) 3x + 2 (b) 7x (c) 8x + 5 (d) x3 87. When the integer n is divided by 6, the remainder is 3. Which of the following is not a multiple of 6? (a) n – 3 (b) n + 3 (c) 2n (d) 3n. ANSWER 1. (c) 11. (a) 21. (b) 31. (c) 41. (c) 51. (b) 61. (b) 71. (b) 81. (d) 2. 12. 22. 32. 42. 52. 62. 72. 82. (c) (a) (a) (d) (b) (a) (c) (a) (b) 3. 13. 23. 33. 43. 53. 63. 73. 83. (a) (a) (d) (a) (b) (c) (b) (d) (b) 4. 14. 24. 34. 44. 54. 64. 74. 84. (d) (d) (b) (a) (b) (a) (d) (c) (c) 5. 15. 25. 35. 45. 55. 65. 75. 85. (b) (b) (d) (c) (b) (a) (c) (d) (b) 6. 16. 26. 36. 46. 56. 66. 76. 86. (d) (c) (a) (a) (d) (a) (d) (b) (c) 7. 17. 27. 37. 47. 57. 67. 77. 87. (d) (b) (c) (a) (c) (c) (a) (d) (d) 8. 18. 28. 38. 48. 58. 68. 78. (c) (d) (b) (c) (c) (d) (a) (c) 9. 19. 29. 39. 49. 59. 69. 79. (d) (d) (a) (c) (c) (c) (b) (b) 10. 20. 30. 40. 50. 60. 70. 80. EXPLANATIONS 9 3 5 5 4 10 1. 3 5 2 4 2 = 9 2 3 5 5 4 10 8 2 = 18 2 16 = 15 4 19 2. 3x + (3x + 3) + (3x + 6) = 72 9x + 9 = 72 = 9x = 72 – 9 45 135 45 35 x+y = ×y x = y 100 100 100 100 x : y = 35 : 45 = 7 : 9 7. Let the number be x. Then 63 =7 9 The largest of them = 27. 3. Let the number be x. or x = 55 1 x = x 52 100 3 13 x = 52 x = 240 60 1 1 2 x – 48 = x x x = 48 x = 48 3 3 3 8. 2 x = 2 ´ 240 = 96 5 5 4. Let the number be 10x – y x:y=2:3 (10y + x) – (10x + y) = 27 9y – 9x = 27 y – x = 3 y = x + 3 Putting this value of y, in (i) x 2 = x=6 y=9 x 3 3 Hence the number is 69. 5. Apply the divisibility tears of 3 and 5. 6. Let the numbers be x and y 1 5 x = y 5 8 ...(i) 35 + x = 4y ...(ii) Solving (i) and (ii), ...(i) 35 25 y = 4y 8 y = 40 © 2011 www.upscportal.com Click Here to Buy This Study Kit http://upscportal.com/civilservices/online-course/study-kit-for-ias-pre-gs-paper-2-2012 (d) (d) (a) (c) (b) (a) (a) (d) Click Here For Integrated Guidance Programme http://upscportal.com/civilservices/online-course/integrated-free-guidance-programme Number System 5 3 4 x = 45 9. 8 10 9 45 9 10 8 = 540 4 3 5 10. Dividing 11158 by 70 we get 70 as remainder. Thus 7 is to be added to make it divisible by 77. 11. We know that (an + 1) is always divisible by (a + 1) when n is odd. 12. Given that x 2 + y 2 + 2XY = 10 and XY = 4 (Y + X)2 = X2 + Y2 + 2XY = 10 + 8 = 18 (Y + X) = 3 2 ...(i) (Y – X)2 = X2 + Y2 – 2XY = 10 – 8 = 2 (Y – X) = 2 ...(ii) Sovling (i) and (ii), X = 2Y = 2 2 , X 1 = Y 2 14. Clearly, for n = 237 (Q n is any positive integer) the expression is divisible by 237. So it is false. 15. The number 899 lies between the squares of 29 and 30. Dividing 899 by the prime numbers less than 30 we see that it is divisible by 29, so it is not a prime number. The number 899 has 4 factors 1, 29, 31 and 899. 16. According to the given condition the fraction is ( 2 + c)( 4 + c) (5 +c) Put 5 + c = t c = t – 5 So, the fraction becomes = = 50 50 1 2 50 51 1275 2 27. From 100 to 175 mean including both 100 and 175. Sum of natural numbers upto 99 (t - 3)(t -1) t 2 - 4t + 3 = t t 99 100 = 4950 2 Sum of natural numbers upto 175 = 3 (t - 2)2 1 t - 4+ = t t t Hence the given expression is minimum if (t – 2)2 = 0 i.e., t = 2. Therefore c = –3 and for this value the minimum value of the fraction is 17. 13x = 180 + x 13x – x = 180 or, 12x = 180 180 or, x = x = 15 12 18. 10800 = 24 × 52 × 33 Number of divisors = (4 + 1) (2 + 1) (3 + 1) = 60. 19. Choosing 32 we see that the sum of the digits is 5 and when 9 is substracted from 32 the number obtained is 23. 20. Let the number be x, x + 1, x + 2. 2x + 3(x + 1) + 4(x + 2) = 182 9x + 11 = 182x = 19 The numbers are 19, 20, 21. 21. Place value = 5 × 1000 = 5000 Face value = 5 Product = 5000 × 5 = 25000 22. 3 + 9 + K + 2 + 0 = 14 + K Least value of K is 1. 23. Given number is divisible by 6, if it is divisible by both 2 and 3. The least value of K is 3. 24. 2 + 7 + 1 + 8 + K + 6 = 24 + K Least value of K is 3. 25. 3 + K = 9 + 0 K=6 26. Sum of the first 50 natural numbers 1 . 2 175 176 = 15400 2 Sum of all natural numbers from 100 to 175 = 15400 – 4950 = 10450 28. Between 100 and 175 means excluding 100 and 175. Sum of natural numbers upto 100 = = 100 101 5050 2 © 2011 www.upscportal.com Click Here to Buy This Study Kit http://upscportal.com/civilservices/online-course/study-kit-for-ias-pre-gs-paper-2-2012 Click Here For Integrated Guidance Programme http://upscportal.com/civilservices/online-course/integrated-free-guidance-programme Number System Sum of natural numbers upto 174 = 174 175 15225 2 Required sum = 15225 – 5050 = 10175 29. Sum of first 50 even numbers = 50(50 + 1) = 2550 300 = 150 even numbers Sum 2 of 150 even numbers = 150 (150 + 1) = 22650 30. Upto 300, there are 99 1 = 49 even numbers Sum 2 of 49 even numbers = 49 (49 + 1) = 2450 Upto 31. Upto 99, there are 175 1 = 87 even numbers Sum of 2 87 even numbers = 87 (87 + 1) = 7656 Required sum = 7656 – 2450 = 5206 32. Sum of first 50 odd numbers = (50)2 = 2500 175, there are 100 = 50 odd numbers Sum 2 of first 50 odd numbers = (50)2 = 2500 33. Upto 100, there are Upto 174, there are 174 = 87 odd numbers 2 Sum of first 87 odd numbers = (87)2 = 7569 Required sum = 7569 – 2500 = 5069 34. Sum of squares of first 50 natural numbers = = 50 50 1 2 50 1 50 51 101 = 42925 6 35. Sum of cubes of first 10 natural numbers 2 10 11 2 43. 35)2559(73 245 109 105 4 The two numbers nearest to 2559 divisible by 35 are (a) 2559 – 4 = 2555 (b) 2559 + (35 – 4) = 2590 The required number is 2555. 44. Three digit numbers are from 100 to 999. Upto 100, there are 6 10 10 1 = 2 37. A number is divisible by 15, if it is both divisible by 3 and 5. 3975 is the only number divisible by both 3 and 5. 38. Remainder when 3475 is divided by 50 is 25. Least number that should be subtracted = 25 39. Remainder when 5718 is divided by 40 is 38. Least number that should be added = 40 –38 =2 40. 3900 = 2 × 2 × 5 × 5 × 3 × 13 The least number by which 3900 be multiplied to make it a perfect square = 3 × 13 = 39 41. Quotient when 800 is divided by 24 is 33. There are 33 numbers upto 800 divisible by 24. 42. Quotient when 500 is divided by the LCM of 3 and 5 ie, 15 is 46. There are 46 numbers upto 700. 2 = 552 = 3025 36. One digit numbers from 10 to 9 = 9 Two digit numbers from 100 to 99 = 90 Three digit numbers from 100 to 500 = 401 Total number of digits that are to be used = (9 × 1) + (90 × 2) + (401 × 3) = 9 + 180 + 1203 = 1392 100 = 5 numbers 18 Upto 999, there are 999 = 55 numbers Required number = 55 – 5 = 50 numbers 45. Total number of numbers between 3 to 30 inclusive = 28 Out of which number of odd numbers = number of even numbers = 28 14 2 46. Required sum = 53 + 59 + 61 + 67 + 71 + 73 + 79 + 83 + 89 = 635 47. Unit digit in 476 × 198 × 359 × 242 = unit digit in 6 × 8 × 9 × 2 = unit digit in 864 = 4 © 2011 www.upscportal.com Click Here to Buy This Study Kit http://upscportal.com/civilservices/online-course/study-kit-for-ias-pre-gs-paper-2-2012 Click Here For Integrated Guidance Programme http://upscportal.com/civilservices/online-course/integrated-free-guidance-programme Number System 48. Given expression 1 1 1 1.2 2.3 3.4 59. Let the four numbers be p, q, r and s. pqr = 385, qrs = 1001 1 n n 1 1 1 1 1 1 = 1 2 2 3 3 4 qrs 1001 13 pqr 385 5 1 1 1 n n 1 n 1 n 1 n 1 Denominator is greater than numerator.) 49. 2 is smallest prime number. 50. Let the required numbers be 2x, 3x and 4x. Then, (2x)2 + (3x)2 + (4x)2 = 116 29x2 = 116 x2 = 4 x = 2 = 1 51. 52. 53. 54. 55. The numbers, are 4, 6, 8. 4225 = 52 × 132 Total divisor = (2 + 1) (2 + 1) = 3 × 3 = 9 The number of divisors excluding 1 and itself =9–2=7 Number of prime factors = 11 + 5 + 6 = 22 The required numbers = 6, 36, 60, 66, 96 = 5 numbers Let the 2 numbers be x and y. Solving, x = 24, y = 36 Product = 24 × 36 = 864 Let the number be x. 4 x 36 5 60. 61. 62. 63. 64. x = 45 3 3 x 45 27 5 5 56. Number of lamp posts required Now, 65. 3000 1 = 40 + 1 = 41 = 75 57. Let the units place digit be x and tens place digit be y. x+y=9 ...(i) (l0y + x) + 9 = (y + 10x) ... (ii) Solving, x = 5 and y = 4. The required number is 45. 58. Let the number be x. 2 x 25 = 45. Solving, x = 70 7 66. 67. 68. s 13 p 5 So, p = 5 and s = 13. Required number is 13. Let the numbers be 3x, 5x and 6x. Now, 3x + 6x = 5x + 16 x =4 The smallest number is 3x = 12. Let the number be x and y. x2 + y2 = 60, x2 – y2 = 12 Adding, 2x 2 = 72 x = 6 and y = 4 Required sum is 10. Let the two numbers be x and x + 1. x (x + 1) = 600 Solving x = 24, so the numbers are 24 and 25. The sum of their squares is = 242 + 252 = 1201 Let the number be x. 3x – 2 = 19 Solving x=7 The required number is 7. Sum of first 50 natural numbers 50 51 = 25x51 2 which is divisible by 3, 5, 17. Since, n ! is always even for n > 1. Therefore, 5 cannot be the unit digit. Since, 4A = 333555 + 555333 is a very large number so taking a similar smaller exponent. (Here, the exponent is odd which is 1.) 4A = 3331 + 5551 4A = 888 A = 222 which is divisible by 2, 3 and 37. Take, –7, 12, 11 and 10 because these will give minimum value. x + y = 85 ... (i) x–y=9 ... (ii) On multiplying Eqs. (i) and (ii) (x + y) (x – y) = 85 × 9 x2 – y2 = 765 © 2011 www.upscportal.com Click Here to Buy This Study Kit http://upscportal.com/civilservices/online-course/study-kit-for-ias-pre-gs-paper-2-2012 Click Here For Integrated Guidance Programme http://upscportal.com/civilservices/online-course/integrated-free-guidance-programme Number System 69. The units digit in 32545 is the same as that of 545 Now, 51 = 5,52 = 25,53 = 125, 54 = 625, … We see that, the units digit is always 5. The units digit in 32545 is 5. 70. The units digits in the expansion of 31448 is the same as that of 448. Now, 41 = 4, 42 =16,43 = 64,44 = 256. We see that, the units digit in 41 is the same as that in 43. So, the units digit is 448 is the same as is 448 = 6. 71. The daily wages of the worker is the HCF of 1755 and 1365. HCF of 1755 and 1365 is 195. The daily wages of the worker is `195. 72. Perfect squares are 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, … Clearly, 7 cannot be at unit’s digit. 73. 92 + 102 = 81 + 100 =181, 196 is the nearest perfect square. Hence, 15 should be added. 74. 9992 – 9982 = (999 + 998) (999 – 998) = (1997) (1) = 1997 75. The number is = 119n + 19 = 138,257 When these numbers are divided by 17, then remainder is 2. 76. 34(1) – 43(1) = 81 – 64 = 17, 34(2) – 43(2) = 812 – 642 = 2465 It is always divisible by 17. 77. The largest such number is 1001. 78. The least five digit number is 10000. When it is divided by 456 the remainder is 424. So, the least five digit number that is exactly divisible by 456 = 10000 + 456 – 424 = 10032. 79. Suppose, one of the multiplier is x, then 53x – 35x = 540 18x = 540 x =30 New multiplication = 30 × 53 = 1590 80. Only 143616 is a multiple of both 11 and 8 so it is a multiple of 88. 7 23 = 0.875, 3 = 0.333, 1 = 0.25, = 0.958 8 24 7 1 0.875, 0.333, 8 3 1 23 0.25, 0.958 4 24 11 17 0.916, 0.708 12 24 Clearly, 0.708 lies between 0.333 and 0.875. Required fraction is 17/24. 82. 1 + 6 + 9 = 16 ... (ii) 2 + 4 + 8 = 14 ...(iii) 4 + 1 + 6 = 11 ...(v) 9 + 7 + 4 = 20 ...(vi) 6 + 1 + 2 = 9 ...(vii) 3 + 2 + 5 = 10 ...(vi) 5 + 1 + 7 = 13 ...(iv) The middle number will be 517. 81. 83. a= 3 0.75 4 b= 4 0.800 5 5 0.833 6 a<b<c In the array 48392874362754869364; 8, 2 and 6 ie, three number of required instances. These numbers are following 5, 15, 25, 35, 45, 50, 55, 65, 75, 85, 95 So, total 11 such type of numbers. If x is an even integer, then clearly 8x will also be an even integer. So, 8x + 5 will be an odd integer. If n is divided by 6 and the remainder is 3, then n – 3 and n + 3 are divisible by 6. 2n is also divisible by 6. But, 3n is not divisible by 6. ‘ c= 84. 85. 86. 87. © 2011 www.upscportal.com Click Here to Buy This Study Kit http://upscportal.com/civilservices/online-course/study-kit-for-ias-pre-gs-paper-2-2012