1314Summer14.pdf

... A logarithm is the power to which some fixed number, called a base, must be raised in order to obtain a specified number called the argument. Logarithms of specified numbers will have different values, depending on which base is used. The three most commonly used bases are 2, 10, and e. Scientific c ...

... A logarithm is the power to which some fixed number, called a base, must be raised in order to obtain a specified number called the argument. Logarithms of specified numbers will have different values, depending on which base is used. The three most commonly used bases are 2, 10, and e. Scientific c ...

PPT

... • No overflow when signs are the same for subtraction • Overflow occurs when the value affects the sign: – overflow when adding two positives yields a negative – or, adding two negatives gives a positive – or, subtract a negative from a positive and get a negative – or, subtract a positive from a ne ...

... • No overflow when signs are the same for subtraction • Overflow occurs when the value affects the sign: – overflow when adding two positives yields a negative – or, adding two negatives gives a positive – or, subtract a negative from a positive and get a negative – or, subtract a positive from a ne ...

Residue Number Systems

... Simple to Design if mi=2ai or 2ai-1 • Power of 2 Moduli Lead to Simple Design – Standard a-bit Binary Adder – Example: Use 16 Instead of 13 – Exception in Case of Lookup Table Implementation ...

... Simple to Design if mi=2ai or 2ai-1 • Power of 2 Moduli Lead to Simple Design – Standard a-bit Binary Adder – Example: Use 16 Instead of 13 – Exception in Case of Lookup Table Implementation ...

Limitations

... Prove: forall a:aexp. eval(a) is finite Base 1: eval(var) is finite Base 2: eval(const) is finite Ind1: suppose eval(b) is finite and eval(c) is finite prove eval(b+c) is finite Ind2: suppose eval(b) is finite and eval(c) is finite prove eval(b-c) is finite ...

... Prove: forall a:aexp. eval(a) is finite Base 1: eval(var) is finite Base 2: eval(const) is finite Ind1: suppose eval(b) is finite and eval(c) is finite prove eval(b+c) is finite Ind2: suppose eval(b) is finite and eval(c) is finite prove eval(b-c) is finite ...

Standards with notes regarding 2003 Standards

... Benchmark Notes 2.1.1.1 Read, write and represent whole numbers up to 1000. Representations may include numerals, addition, subtraction, multiplication, words, pictures, tally marks, number lines and manipulatives, such as bundles of sticks and base 10 blocks. Compare and 2.1.1.2 Use place value to ...

... Benchmark Notes 2.1.1.1 Read, write and represent whole numbers up to 1000. Representations may include numerals, addition, subtraction, multiplication, words, pictures, tally marks, number lines and manipulatives, such as bundles of sticks and base 10 blocks. Compare and 2.1.1.2 Use place value to ...

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... 2. How do the operations of decimals compare to the operations of whole numbers? 3. How can we create and interpret useful models that display division of fractions? 4. How are fractions, decimals and percents related? 5. Why are there negative numbers? 6. How do we compare and contrast numbers? 7. ...

... 2. How do the operations of decimals compare to the operations of whole numbers? 3. How can we create and interpret useful models that display division of fractions? 4. How are fractions, decimals and percents related? 5. Why are there negative numbers? 6. How do we compare and contrast numbers? 7. ...

Logarithms Tutorial for Chemistry Students 1

... In order to approximate the numerical values of non-trivial base-10 logarithms we will need (a) a good understanding CH102 Exam 1, Monday, February 9, 2009 of the rules for manipulating logarithms and (b) the values of log 2 and log 3, which are 0.30 and 0.48, respectively. Using these values and th ...

... In order to approximate the numerical values of non-trivial base-10 logarithms we will need (a) a good understanding CH102 Exam 1, Monday, February 9, 2009 of the rules for manipulating logarithms and (b) the values of log 2 and log 3, which are 0.30 and 0.48, respectively. Using these values and th ...