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Section 7.7 (Complex Numbers) Thus far we have mainly dealt with the real number system which excludes some roots of negative numbers (square root of -4 or -9, for example, do not exist in the real number system) This section covers a number system that contains these roots (in addition to the subset of real numbers) and allows us to solve equations such as x2 + 1 = 0 (called the complex number system) o The imaginary unit i is used to denote the square root of -1 ( i2 = -1 and 1 = i ) Example: Write the following using i notation (complex number system) 25 1 25 (note: since 3 3i 50 can be easily confused with 3 i we will write 3 i as i 3 ) Keep in mind that the product rule for radicals doesn’t necessarily hold true for imaginary numbers (when multiplying, always write numbers in terms of i first) 4 9 (4)(9) 36 6 NO 4 9 2i(3i) 6i 2 6(1) 6 YES Examples: Multiply / Divide 25 1 27 3 2 7 8 2 A complex number is a number that can be written in the form a + bi where a and b are real numbers (note that the real numbers are a subset => 7.2 = 7.2 + 0i as an example) Complex numbers can be manipulated as follows (given a + bi and c + di as complex numbers) o a+bi = c+di if and only if the real parts are equal and the imaginary parts are equal (a=b & c=d) o sum => add the real parts and then add the imaginary parts => (a+bi) + (c+di) = (a+c) + (b+d)i o difference => same as sum but with subtraction => (a+bi) – (c+di) = (a-c) + (b-d)i o product => multiply as though they are binomials and use i2 = -1 to simplify Examples: Add / Subtract / Multiply (5 + 2i) + (4 – 3i) = 6i – (2 – i) = (-2 – 4i) – (-3) = -5i * 3i = -2i (6 – 2i) = (3 – 4i)(6 + i) = (1 – 2i)2 = (6 + 5i)(6 – 5i) = Complex numbers (a + bi) and (a – bi) are called complex conjugates and (a + bi)(a – bi) = a2 + b2 (real) We use complex conjugates to divide a complex number (multiply top and bottom by the conjugate of the denominator to eliminate imaginary number in the denominator) Examples: Divide (write in the form a + bi) => (recall that division can be checked by multiplication) 3i 2 3i 6 5i Example: Using i2 = -1, find the following higher powers of i (you might also use i4) i1 = i5 = i9 = i40 = i2 = i6 = i10 = i50 = i3 = i7 = i11 = 4 i = 8 i = 12 i = i-10 = Bonus (+0 points): How is it possible to trace this design in one continuous movement without crossing a line on the way?