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UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede LECTURE NOTES 14 EM RADIATION FROM AN ARBITRARY SOURCE: We now apply the formalism/methodology that we have developed in the previous lectures on low-order multipole EM radiation {E(1), M(1), E(2), M(2)} to an arbitrary configuration of electric charges and currents, only restricting these to be localized charge and current distributions, contained within a finite volume v near the origin: r r r tr r r r tr r r 2 r 2 t r 2r r t r t t tr r c tr t r c For arbitrary, localized {total} electric charge and current density distributions tot r , tr and J tot r , tr , the retarded scalar and vector potentials, respectively are: 1 Vr r , t 4 o Ar r , t o 4 tot r , tr r v J tot r , tr r v d 1 4 o d o 4 tot r , t r c r v J tot r , t r c v r d with tr t r c d and r r 2 r 2 tr 2r r tr For EM radiation, we assume that the observation / field point r is far away from the localized r or: rmax r 1. source charge / current distribution, such that: rmax 2 r tr 2r r tr 2r r tr r r 1 Then keeping only up to terms linear in : r r 1 2 r r r2 r But: And: 1 1 for 1 1 2 r r tr rˆr tr r r 1 r 1 r2 r 1 1 1 1 r r tr 1 rˆr tr 1 for: 1 1 1 using: 2 r r r r tr r 1 r r r 1 r2 1 © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved 1 UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede r r r r tr r rˆr tr Now: tot r , tr tot r , t tot r , t 1 tot r , t 2 c c r c c Expand tot r , tr as a Taylor series in the present time t about the retarded time, at the origin { r 0 }: Defining the retarded time at the origin: to t r c {valid in the “far-zone limit} Then: 2 3 rˆr 1 rˆr 1 rˆr tot r , tr tot r , to tot r , to tot r , to tot r , to ... c 2! c 3! c d tot r , to Where: tot r , to etc. dtr We can drop / neglect all higher-order terms beyond the tot term, provided that: rmax c c , 1 , 2 c 1 3 , ... is satisfied… For a harmonically oscillating system (i.e. one with angular frequency ω), each of these ratios c c c c d e.g. , etc. is = and thus we have: rmax if rmax d , then 1, c r or equivalently{here}: max 1 . c r rmax rmax 1 etc… 1 , or more generally: max 1 and c r c amount to keeping only the first-order {the lowest-order, non-negligible} terms in r . The retarded scalar potential Vr r , t then becomes: The two approximations 1 Vr r , t 4 o v tot r , tr r d 1 4 o v 1 r tot r , tr d rˆr to 1 rˆr to r t r t 1 , , ... d o tot o tot r 4 o v r c 1 rˆ rˆ tot r , to d r to tot r , t0 d r to tot r , to d ... v v v 4 o r c r 1 Qtot to ptot to ptot to 1 rˆ rˆ d Vr r , t tot r , to d r to tot r , to d r to tot r , to d ... v 4 o r r v c dt v 2 © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved UIUC Physics 436 EM Fields & Sources II Or: Vr r , t Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede 1 Qtot to rˆ ptot to rˆ p tot to ... 2 r cr 4 o r In the static limit: monopole dipole term term vanishes in the static limit The retarded vector potential, to first order in r r r {with to t r c } then becomes: Ar r , t o 4 v J tot r , tr r d o 4 J tot r , t r c v r d o J tot r , to d 4 r v Griffiths Problem 5.7 (p. 214) showed that for localized electric charge / current distributions contained in the source volume v , that: dptot r , t v J tot r , tr d dt ptot r , t Thus: o p tot to Ar r , t 4 r Note that ptot to is already first order in r any additional refinements are therefore second order in r ; thus, the higher-order terms can be neglected/ignored (here). Next, we calculate the retarded E and B fields. Since we are only interested in the EM radiation fields (in the “far-zone” limit), we drop / neglect 1 r 2 , 1 r 3 , 1 r 4 , etc. terms, and keep only the 1 r radiation-field terms. Note that the radiation terms come entirely from those terms in the Taylor series expansions for tot r , to and J tot r , to in which we differentiate the argument to of tot r , to , J tot r , to . Since retarded time: to t r c 1 1 then: to r but: r rˆ to rˆ c c 1 rˆ p tot to ptot to 1 rˆ 1 rˆ ptot to rˆ Thus: Vr r , t to cr cr r 4 o c 2 4 o 4 o Ar r , t o ptot to And: t 4 r © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved 3 UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede The retarded electric field for EM radiation in the “far-zone” limit is: Ar r , t o ptot to 1 rˆ ptot to Er r , t Vr r , t rˆ t 4 o c 2 4 r r but: 1 o o c2 o rˆ ptot to rˆ ptot to o rˆ rˆ ptot to {using the BAC-CAB rule} Er r , t 4 r 4 r where the second time-derivative of the total electric dipole moment ptot to is evaluated at the retarded time to t r c and computed from the origin, { r 0 }: ptot to ptot 0, t r c . The retarded magnetic field for EM radiation in the “far-zone” limit is: o p tot to o Br r , t Ar r , t p to r 4 4 r ptot to o rˆ ptot to o to 4 rc 4 Where in first step we have used the relation v tr a tr tr {see “term (3)” P436 Lect. Notes 12 p. 11 and/or Griffiths Equation 10.55, p. 436} and in the last step on the RHS we have 1 {again} used the relation to rˆ . c o rˆ ptot to Br r , t 4 rc where the second time-derivative of the total electric dipole moment ptot to is evaluated at the retarded time to t r c and computed from the origin, { r 0 }: ptot to ptot 0, t r c . If we use spherical-polar coordinates, with the ẑ -axis pTot to , then noting that: rˆ ptot to ptot to rˆ zˆ but: zˆ cos rˆ sin ˆ ptot to rˆ cos rˆ sin ˆ = ptot to sin ˆ = rˆ rˆ 0 r̂ ˆ ˆ ˆ ˆ r̂ ˆ r̂ ˆ 4 © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Thus: p t sin Er r , , t o tot o 4 r And: p t sin Br r , , t o tot o ˆ 4 c r ˆ Lect. Notes 14 Prof. Steven Errede ← r̂ ˆ ˆ 1 and we also see that {again} Br r , , t rˆ Er r , , t , Br Er rˆ kˆ c The instantaneous retarded EM radiation energy density u r , , t in the “far-zone” limit is: 1 1 2 urrad r , , t o Er2 r , , t Br r , , t 2 0 2 2 p to sin 2 1 o2 p 2 to sin 2 1 o o 2 2 2 2 2 16 2 r o 16 c r p 2 t0 o p 2 to sin 2 1 o 2 16 2 c 2 16 2 c 2 r 2 rad Thus: ur r , , t 1 but: o o c 2 p 2 to sin 2 o 2 2 2 16 c r o p 2 to sin 2 (Joules/m3) 16 2 c 2 r 2 The instantaneous retarded Poynting’s vector in the “far-zone” limit is: 1 Watts S rrad r , , t Er r , , t Br r , , t 2 o m rad o p 2 to sin 2 Sr r , , t 16 2 c r 2 o p 2 to sin 2 ˆ ˆ 16 2 c r 2 rˆ c crˆ rad rˆ cur r , , t with rˆ kˆ The instantaneous retarded EM power radiated per unit solid angle in the “far-zone” limit is: dPrrad r , , t rad p 2 t S r , , t r 2 rˆ o 2 o sin 2 16 c d Watts steradian The instantaneous retarded total EM power radiated into 4 steradians, with vector area element da r 2 sin d d rˆ r 2 d rˆ in the “far-zone” limit is: p 2 t 2 2 o p 2 to sin sin Prrad t Srrad r , , t da o 2 o d d (Watts) S 16 c 0 0 6 2 c © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved 5 UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede The instantaneous retarded EM radiation linear momentum density in the “far-zone” limit is: o p 2 to sin 2 1 rad r , , t 2 Sr r , , t 16 2 c 3 r 2 c rad r kg rˆ 2 m sec The instantaneous retarded EM radiation angular momentum density in the “far-zone” limit is: rad r r , , t r rrad r , , t 0 The scalar EM wave characteristic radiation impedance of the antenna associated with this lowest-order EM radiation is: Er Er o o c Z o 120 377 Z rad 1 Hr o Br o The scalar EM wave radiation resistance of the antenna associated with this lowest-order EM radiation is: Rrad p 2 to rad o 2 Ohms Io 6 cI o2 Note that in the above, we deliberately/consciously neglected the electric monopole {E(0)} term r: in the retarded scalar potential for “far-zone” limit, rmax VrE(0) r , t 1 1 1 Qtot t0 r , to d v r 4 o r 4 o As mentioned previously (P436 Lect. Notes 13, p. 4), that because of electric charge conservation, a spherically-symmetric electric monopole moment cannot radiate transverselypolarized EM waves – spherical symmetry of the monopole moment restricts oscillations only to the radial direction – thus one could get radiation of one polarization from a certain dΩ solid angle element, but then radiation from other dΩ’s on the sphere also contribute, such that the net EM radiation from the entire sphere = 0 – total destructive interference. (Gauss’ Law encl E da Qtot o independent of the size of the spherically symmetric charge distribution S enclosed by the surface S´. Note also that for free-space EM radiation, B must be to E , and with both E and B to kˆ , the propagation direction. How do you do this for a spherically-symmetric source, where kˆ rˆ ? Note also that if electric charge were not conserved, then we would get a retarded electric 1 Q to rˆ n.b. this says nothing monopole field proportional to 1 r : ErE(0) r , t 4 o c r about the physical size of the spherically-symmetric charge distribution. 6 © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede Contrast the behavior of transverse waves associated with EM radiation from a sphericallysymmetric source (an oscillating electric monopole moment) ( no net EM radiation) to that of longitudinal sound waves / acoustic waves radiated from a spherically symmetric oscillating acoustic monopole sound source – e.g. a radially inward / outward oscillating sphere (a breathing bubble) – the latter of which very definitely can propagate / create sound precisely because sound waves are longitudinal, not transverse waves!! Now think about the electron – for EM radiation fields, electric dipole / quadrupole / etc. higher EM moments break the rotational invariance / rotational symmetry associated with the spherical monopole electric charge distribution of the source – thus transverse EM waves (EM radiation) can couple to such electric monopole {E(0)} sources – and also ones that lack rotational invariance!!! In the above Taylor series expansions for tot r , tr and J tot r , tr , we only kept terms to first-order in r´ in these expansions and then demonstrated that the first-order “far-zone” limit radiation terms were associated with the electric dipole moment {E(1)} . r the instantaneous retarded For E(1) electric dipole EM radiation to first-order in r´ for rmax scalar and vector potentials, electric and magnetic fields are: 1 rˆ p to Vr 4 o cr (1) o p to Ar r , t 4 r (1) r,t (1) o rˆ rˆ p to Er r , t r 4 (1) o rˆ p to Br r , t r 4 c n.b. proportional to p t0 (first time derivative of p to - “velocity”) n.b. proportional to p t0 (second time derivative of p to - “acceleration”) Suppose the (localized) charge / current distributions are such that there is no (time-varying) p r , tr 0 . E(1) electric dipole moment, p r , tr 0 and/or: p r , tr 0 , Then the Taylor series expansion of tot r , tr and J tot r , tr to first order in r would give nothing for potentials and fields associated with “far-zone” EM radiation. However, higherorder terms in these expansions might give rise to non-vanishing potentials and fields. The second order terms in r correspond to M(1) magnetic dipole and E(2) electric quadrupole EM radiation terms – in order to see/verify this, the second-order contribution needs to be / can be separated out into M(1) and E(2) terms. © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved 7 UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede Indeed, if we compare e.g. the ratio of EM power radiated for M(1) magnetic dipole vs. E(2) electric quadrupole radiation (in the “far-zone” limit): mo b 2 I o b 2 q o mo2 4 12 c3 I q where: o 2 6 e oQzz Qzze qdd 2b 2 q 3 d b 60 c rad M (1) rad(2) Thus: rad M (1) rad(2) o 2b 4 6 q 2 3 5 2b 4 12 c 5 1 2 1 4 d 2 2 4 6 o q d 60 c3 5 Similarly, the third order terms in r in the Taylor series expansion of tot r , tr and J tot r , tr correspond to M(2) magnetic quadrupole and E(3) electric octupole radiation terms – i.e. the third-order contribution needs to be / can be separated out into M(2) and E(3) terms! Similarly, the fourth order terms in r in the Taylor series expansion of tot r , tr and J tot r , tr correspond to M(3) magnetic octupole and E(4) electric sextupole radiation terms – i.e. the fourth-order contribution can be separated out into M(3) and E(4) terms! And so on, for each successive higher-order term r in the Taylor series expansion of tot r , tr and/or J tot r , tr !!! Griffiths Example 11.2: a.) An oscillating (i.e. harmonically varying) electric dipole has time-dependent dipole moment: p tr po cos tr where: p tr p tr zˆ po cos tr zˆ p tr dp tr po sin tr dtr p tr dp tr d 2 p tr 2 po cos tr dtr dtr2 zˆ cos rˆ sin ˆ with: to t r c Then: Vr 8 (1) r,t po 1 rˆ p to po rˆ zˆ sin to cos sin to 4 o cr 4 o cr 4 o cr © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved UIUC Physics 436 EM Fields & Sources II And: Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede (1) o p to o po zˆ cos rˆ sin ˆ sin to zˆ Ar r , t 4 r 4 r (1) o rˆ rˆ p to o rˆ rˆ zˆ 2 r r , t po cos to 4 r r 4 (1) o rˆ p to o rˆ zˆ Br r , t 2 po cos to 4 c 4 c r r But: rˆ zˆ rˆ cos rˆ sin ˆ sin rˆ ˆ sin ˆ And: rˆ rˆ zˆ rˆ ˆ sin ˆ sin sin ˆ Thus: p cos Vr (1) r , t o 4 o c r r sin t c p 1 r Ar (1) r , t o o sin t zˆ 4 r c with: to t r c where: zˆ cos rˆ sin ˆ (1) o po 2 sin r ˆ Er r , t cos t 4 r c p 2 sin r Br (1) r , t o o cos t ˆ 4 c r c Compare these results for the E(1) electric dipole EM radiation “far-zone” limit case with those we obtained P436 Lecture Notes 13 {see pages 8-11}, and/or P436 Lecture Notes 13.5 {the E(1)/M(1) summary / comparison page 11} – they are (of course) identical! b.) A single, point electric charge q can have (by definition) an electric dipole moment p tr qd tr where d tr is the position vector of the point electric charge q at the retarded time tr with respect to the (local) origin . (n.b. subject to all the caveats r.e. choice of origin for an EDM having a net charge – see P435 Lecture Notes. . . ) d d tr dp tr p tr q qv tr However: n.b. these two quantities do not dtr dtr depend on the choice of origin !!! dp tr dv tr p tr q qa tr And: dtr dtr v tr = velocity vector of point electric charge q at the retarded time tr a tr = acceleration vector of point electric charge q at the retarded time tr © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved 9 UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede Everything goes through as before – get the same retarded scalar and vector potentials, same retarded E and B fields, same u, S , P, etc. In particular, the radiated EM E(1) power associated with a moving point charge q is: o p 2 to Pq (Watts) But: 6 c Pq p to qa to o q 2 a 2 to Famous Larmor formula (EM power radiated from a point charge q) 6 c Note that the E(1) EM power radiated by a point charge q is proportional to the square of the acceleration a and also is proportional to the square of the electric charge q. This is the origin of statement: “Whenever one accelerates an electric charge q, it radiates away EM energy in the form of (real) photons”. It is the E(1) electric dipole term which dominates this radiation process. n.b. This is also true for decelerating charged particles – the time-reversed situation!!! Pq ~ a2 ← doesn’t care about sign of a {The EM interaction is time-reversal invariant}!!! Radiation from accelerated / decelerated +q vs. –q charges is the same if q q . (Pq doesn’t care about the sign of q!) But: Pq ~ q2 → so if double q → then Pq increases by factor of 4! For the same acceleration/deceleration, high-Z nuclei radiate EM energy {in the form of photons} much more than e.g. a proton (= hydrogen nucleus) – process is known as bremsstrahlung {= “braking radiation”, auf Deutsch}. e.g. A fully-stripped uranium nucleus (Zu = 92) gives 922 = 8464 more EM radiation than a proton for the same acceleration, a. EM Power Radiated by a Moving Point Electric Charge: The retarded electric field of an electric charge q in arbitrary motion is: q r 2 2 Er r , t c v u r u a 4 o r u 3 The associated retarded magnetic field is: 1 Br r , t rˆ Er r , t c As mentioned before, the first term in Er r , t , where: u crˆ v tr r r r tr r w tr r r r tr ct c t tr or: tr t r c . r 2 2 c v u 4 o r u 3 q is known as the generalized Coulomb field, or velocity field. 10 © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved UIUC Physics 436 EM Fields & Sources II The second term in Er r , t , Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede r r u a is known as the acceleration field 4 o r u 3 q (a.k.a. the radiation field). 1 1 Er r , t Br r , t where: Br r , t rˆ Er r , t The retarded Poynting’s vector is: S r r , t c o Use the A B C B AC C A B rule: 1 1 2 Sr r , t Er r , t rˆ Er r , t Er r , t rˆ rˆ Er Er r , t c o c o However, note that not all of this EM energy flux constitutes EM radiation (real photons) – some of it is still in the form of virtual photons, S r r , t S rvirt r , t S rrad r , t The metaphor Griffiths uses, that of flies “attached” to a moving garbage truck, is a reasonable picture to imagine here…. n.b. – In order to “detect” the total EM power radiated by a moving point charge q, we draw a huge sphere of radius r centered on the position of the charged particle w tr at the retarded time tr t r c and wait the appropriate time interval t t tr r c for the EM radiation radiated at the retarded time tr to arrive at the surface of the imaginary sphere. Note that in the “far-zone” limit, the retarded time tr is the correct retarded time for all points on the surface of the sphere S . Again, since the area of the sphere Asphere r 2 ( ~ r 2 ), then any term in S r r , t that varies as 1 r 2 will yield a finite answer for radiated EM power, Prad S r r , t da . S However, note that terms in S r r , t that vary as 1 r 3 , 1 r 4 , 1 r 5 … etc. will contribute nothing to Prad in the limit r → ∞. For this reason, only the acceleration fields represent true EM radiation (real photons) – hence their other name, that of radiation fields: q r r u a Erad r , t 3 4 o r u © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved 11 UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede The EM velocity fields do indeed carry EM energy – as the charged particle moves through space-time, this EM energy is dragged along with it – but it is not in the form of EM radiation. Note that Erad r , t is rˆ (due to the r u a term). The second term in S rad r , t vanishes: 1 2 1 2 S rad r , t Erad r , t rˆ rˆ Erad r , t Erad r , t E r , t rˆ o c rad o c Now if the point charge q happened to be {instantaneously} at rest ( v tr 0 ) at the retarded 0 time tr, then: u tr crˆ v tr crˆ {here}. Then in this case: q r q r Erad r , t u a r r crˆ a 3 3 4 o r u 4 o r crˆ 1 q r rˆ a 2 4 o c r 4 o c 2 q 2 1 rˆ rˆ a r o q ˆ ˆ r r a 4 r 1 since 2 o o c q q o rˆa rˆ rˆ rˆ a o rˆa rˆ a 4 r 4 r 1 Then {here} in this case { v tr 0 }: q2 1 2 2 S rad r , t Erad r , t rˆ o 2 a 2 rˆa rˆ o c 4 crˆ But: rˆa a cos where θ = opening angle between r̂ and acceleration a . o q 2 a 2 o q 2 a 2 sin 2 2 ˆ 1 cos r S rad r , t 4 cr 2 4 c r 2 rˆ Here again, we see that no power is radiated in the forward/backward directions (θ = 0 and θ = π) – radiated power is maximum when 2 90o , i.e. when rˆ a - get a donut-shaped intensity pattern about the instantaneous acceleration vector a tr : 12 © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede The power radiated by this point charge (instantaneously at rest at time tr) is: o q 2 a 2 tr sin 2 2 r sin d d Prad t Srad r , t da S 16 2 c r 2 o q 2 a 2 tr o q 2 a 2 t r 4 o q 2 a 2 tr 3 d 2 sin 0 3 6 c 8 16 2 c 8 Prad t 4 2 3 o q 2 a 2 tr Larmor power formula {again} !!! 6 c This formula was derived assuming v tr 0 , but in fact, we get the same formula as long as v tr c (i.e. non-relativistic motion). An exact treatment of v tr 0 is (much) more difficult / tedious. Note that in special relativity {inertial (non-accelerated) reference frames}, the choice v tr 0 merely represents a judicious choice of an (inertial) reference frame, with no loss of generality. If we can determine how Prad t transforms from one reference frame to another, then we can deduce the more general v tr 0 result (Liénard) from the (Larmor) v tr 0 result. (See e.g. Griffiths problem 12.69, p. 545). For the v tr 0 case, Erad r , t is more complicated (than the v tr 0 case). For the v tr 0 case, Srad r , t = the rate of energy passing through the (imaginary) large-radius surface S of the sphere, Srad r , t is NOT the same as the rate of energy when it left the charged particle at the retarded time tr. Consider the example of a person firing a stream of bullets (photons) out the window of a moving car, parallel to the direction of motion of the car: The rate at which the bullets strike a target, Rtgt (#/sec) is not the same as the rate of bullets leaving the gun, Rgun (#/sec) because of the relative motion of the car with respect to the target. This is again analogous to the Doppler effect. It is purely due to a motional geometrical factor (i.e. it is not due to special relativity). For bullets moving parallel to the car’s velocity vector: Rgun 1 tr Rtgt or: Rtgt 1 1 tr Rgun where: tr v tr c © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved 13 UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede Whereas for bullets moving anti-parallel to the car’s velocity vector: Rgun 1 tr Rtgt or: Rtgt 1 1 tr Rgun v tr where: tr c For arbitrary directions, with rˆ unit vector from car to target: Rgun 1 rˆ tr Rtgt or: v tr 1 Rtgt Rgun where: tr c 1 rˆ tr dW = rate of energy passing through sphere of radius r then the rate at which energy leaves the dt dW dW dt dW tr rˆu dW tr c rc with u crˆ v tr . since: charge q is: t c dt dt dtr dt dtr t rˆu r u (see P436 Lect. Notes 12, p. 14-15, and/or Griffiths problem 10.17, p. 441) So if rˆu But: c rˆ crˆ v tr c 1 rˆv tr c 1 rˆ tr = retardation factor v tr dW rˆu dW dW dW 1 rˆ tr Then: where: tr c dtr c dt dt dt Thus, the power radiated into a patch of area da r 2 sin d d r 2 d on the sphere S , where d sin d d = solid angle into which the EM power is radiated into area element da on the q r r u a is given by: surface of the sphere S , with Erad r , t 4 o r u 3 rˆu tr 1 2 2 dPrad tr rˆu tr 2 S r,t r E r c rad c c rad d o 2 q2 1 rˆu tr r 2 r 2 r u t r a tr 6 2 2 16 o o c c r u t r 2 q2 r4 1 rˆu tr u t a t r r r 16 2 o2 o c c r u t 6 r Thus: 14 q2 16 2 o rˆ u tr a tr rˆu t 2 5 r 2 2 ˆ r u t a t dPrad t r r q 5 16 2 o d rˆu tr © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede dPrad t S d d over the sphere S (i.e. over θ and φ angles) is a pain…. However, the result of this integration {again!} yields the famous Liénard formula: Integrating 2 2 v tr a tr o q 2 6 2 o q 2 6 2 Prad t a tr a tr t r a tr 6 c c 6 c Where: tr v tr c and: tr 0 1 1 1 2 tr = Lorentz factor. 1 Note that the Liénard formula reduces to the Larmor formula for Prad t when v c . Note also that when v → c, the γ6 factor in the Liénard formula goes “berserk” – as the charged particle travels closer and closer to the speed of light c, the more one tries to accelerate it (in order to make it travel even closer to the speed of light, c), it radiates away more and more of the (absorbed) energy as v → c!!! very high energy electron accelerators are problematic in this regard, because the electron is so light, mass-wise, e.g. relative to the proton: me 0.511 MeV c 2 whereas m p 938.28 MeV c 2 . Griffiths Example 11.3: Suppose v tr and a tr are instantaneously collinear (i.e. parallel to each other). Find the angular distribution of radiated power dPrad t when v tr a tr v tr a tr (i.e. when v tr a tr ) d Then in this case: u tr crˆ v tr because v tr a tr 0 Thus: u tr a tr crˆ v tr a tr crˆ a tr v tr a tr crˆ a tr 2 dPrad t q 2 rˆ u tr a tr q 2 c 2 rˆ rˆ a tr Then: 5 5 16 2 o 16 2 o d rˆu tr rˆu tr 2 v tr tr c Work on denominator term: rˆu tr rˆ crˆ v tr c rˆv tr c 1 rˆ tr c 1 rˆ tr Work on numerator term: Thus: 1 rˆ rˆ a tr rˆa tr rˆ rˆ rˆ a tr rˆa tr rˆ a tr rˆ rˆ a tr a 2 tr rˆa tr 2 2 © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved 15 UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede a 2 t rˆa t 2 a 2 t rˆa t 2 2 r r r r dPrad t q c q Then: 5 5 2 2 3 5 d 16 o c 1 rˆ t 16 o c 1 rˆ tr r 2 2 If we let the ẑ -axis point along v tr – along tr v tr c {and hence also along a tr }: and: rˆv v cos or: rˆ cos where θ = opening angle between r̂ and acceleration a , as shown on page 12 above. Then: rˆa a cos 1 cos 2 dPrad t q 2 a 2 tr Thus: 16 2 o c 3 1 tr cos 5 d but: 1 o o c2 v tr dPrad t o q 2 a 2 tr sin 2 with: tr 5 2 c d 16 c 1 tr cos When β → 0: v 0 dPrad t o q 2 a 2 tr 2 sin Srad r , t r 2 rˆ 2 16 c d When β → 1: The donut of EM radiation intensity is folded forward by the factor 1 1 cos : 5 Note that there is still no radiation precisely in the forward direction, rather it is in a cone which becomes increasingly narrow as β → 1, of half-angle: max 1 2 {see Griffiths problem 11.15, p. 465} The total EM power radiated into 4 steradians by the point charge for v a is: dPrad t o q 2 a 2 tr sin 2 sin d d Prad t d 16 2 c 1 tr cos 5 d Let: 16 o q 2 a 2 tr sin 2 0 1 t cos 5 sin d 8 c r u = cosθ θ = 0 → u = +1 du = sinθdθ θ = π → u = 1 © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved UIUC Physics 436 EM Fields & Sources II Then: Prad t Prad t Fall Semester, 2015 Lect. Notes 14 o q 2 a 2 tr 1 1 u 1 1 u 5 du Integrate by parts: vdu uv udv 8 c 2 3 o q 2 a 2 tr 4 o q 2 a 2 tr 1 2 t 1 r 3 1 2 t 3 8 c 6 c r But: tr Prof. Steven Errede 1 1 2 with: tr tr v tr c o q 2 a 2 tr 6 tr Prad t 6 c This is the same/identical result as obtained directly from the Liénard formula when v tr a tr . It is also known as the classical formula for bremsstrahlung (“braking radiation” in german). Again, note that because Prad t ~ a 2 tr , the EM power radiated doesn’t depend on the sign of a tr – i.e. whether the charged particle is accelerating or decelerating. 2 2 Now it can also be shown that the Lorentz factor E mc , where E pc mc = total relativistic energy associated with a charged particle moving with tr v tr c . 2 2 Thus, when v → c, for a given {high} total energy E, then ~ 1 mc 2 and thus: Prad t ~ 1 m6 . Comparing EM bremsstrahlung radiation from an accelerated electron { me 0.511 MeV c 2 } vs. that of e.g. an accelerated muon { m 105.66 MeV c 2 }, for the same total energy E, an electron will radiate m me 206.8 7.8 1013 times more EM energy than a muon. 6 6 This explains why muons have such high penetrating power in traversing matter – they lose relatively little energy via bremsstrahlung, whereas high-energy electrons radiate EM energy “like crazy” in matter. © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved 17 UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede The Radiation Reaction on a Radiating Charged Particle According to the laws of classical electrodynamics, an accelerating electric charge radiates electromagnetic energy in the form of real photons ( = quanta of the EM radiation field). By conservation of energy, the EM radiation carries off / carries away energy – which must come at the expense of the charged particle’s kinetic energy {since its rest mass cannot change}. In other words, one puts in energy to accelerate the charged particle, but the charged particle winds up being accelerated less than e.g. an electrically neutral particle {of the same rest mass of the charged particle}, for the same amount of input energy! The devil is in the microscopic details of precisely how this is accomplished in both cases. At the microscopic level, an electrically charged particle of mass m is accelerated/increases its 2 {kinetic} energy T 1 mc by absorbing EM energy (either in the form of virtual or real photons) from a source of EM field(s). In order to accelerate/increase the {kinetic} energy T 1 mc 2 of an electrically neutral particle, it too must interact, at the microscopic level, via one of the four fundamental forces of nature, with a source {of fields} associated with that fundamental force. Feynman/Space-Time Diagram for Electron-Positron Scattering {QED} ct {time} e e e e x {space} In the electromagnetic case, if an electrically charged particle is decelerated and radiates EM energy away in the form of {real} photons, by energy conservation, the change in the kinetic energy of the charged particle must equal the sum of the energies associated with each of the n individual {real} photons radiated by the charged particle: n n i 1 i 1 KEq E i hf i 18 © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede This implies that the radiation must {somehow!} exert a force, Frad back on the electrically charged particle – i.e. a recoil force, analogous to that associated with firing a bullet from a gun. Thus, linear momentum p must also conserved in this process. In the emission of EM radiation {real photons}, linear momentum p i h i hf i c is also carried away by each of the {real} photons. This comes at the expense of the charged particle’s momentum pq and (non-relativistically, for vq c ): KEq pq2 2m E i n n n h pqrecoil c p i c ckˆ i hf i kˆ i i 1 i 1 i i 1 kˆ i kˆ i = wave vector for the ith photon B i Thus, if a similarly accelerated/decelerated neutral particle doesn’t radiate force quanta {of some kind} because it is accelerated/decelerated, then because the electrically-charged particle does radiate EM quanta {real photons} in the acceleration/deceleration process, then we can see that the final-state KEq KEo for similarly accelerated/decelerated neutral particle of the same mass m and initial/original kinetic energy as that of the electrically-charged particle. The Radiation Reaction Force on a Charged Particle For a non-relativistic particle ( vq c ) the Larmor formula for the total instantaneous EM radiated power is: Prad t o q 2 a 2 tr (Watts) 6 c Conservation of energy would then imply that this radiated EM power = the instantaneous rate at which the charged particle loses energy, due to the effect of the EM radiation back reaction / recoil force Frad tr : dW tr o q 2 a 2 tr Frad tr v tr Pq tr (Watts) dt 6 c This relation / equation is actually wrong. Why??? The reason is, that we calculated the radiated EM power by integrating Poynting’s vector S rad r , t for the EM radiation associated with the accelerating point charged particle over an “infinite” sphere of radius r ; in this calculation the EM velocity fields played no role, since they fall off too rapidly as a function of r to make any contribution to Prad t . However, the EM velocity fields do carry energy – because the total retarded electric field associated with the electrically charged particle is the sum of two terms – the EM velocity field and the EM acceleration field terms: Ertot r , t Erv r , t Era r , t © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved 19 UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede The total retarded EM energy density associated with the total retarded electric field is: 2 2 utot r , t 12 o Ertot r , t 12 o Erv r , t Era r , t 2 2 12 o Erv r , t 2 Erv r , t Era r , t Era r , t Energy stored in velocity field only (virtual photons) Generalized Coulomb fields only Cross term!!! Energy stored in mixture of velocity and acceleration field (both virtual & real photons!!) “Conversion” field virtual → real photons {and vice versa!} Note that: The Generalized Coulomb fields vary as ~ 1 r 4 The “Conversion” fields vary as ~ 1 r 3 The Radiation fields vary as ~ 1 r 2 Energy stored in acceleration field only (real photons) Radiation fields only Neither the Generalized Coulomb field nor the “Conversion” field contribute to EM radiation in the “far-zone” limit r r Clearly, the first two terms in the EM energy density formula associated with the electric field have energy associated with them. However, this energy stays with the charged particle – it is not radiated away. As the charged particle accelerates / decelerates, energy is exchanged between the charged particle and the velocity and acceleration fields. For the latter term (the last/ 3rd term in utot r , t above), this energy is irretrievably carried away (by real photons) out to r = ∞. dW tr q 2 a 2 tr Frad tr v tr o only accounts for the last / 3rd term 6 c dt 2 ( Era r , t ) in utot r , t above. Thus, Pq tr If we want to know the total recoil force exerted by the EM velocity and the EM acceleration fields on the point charge, then we need to know the total instantaneous power lost, not just the radiation-only contribution. Thus, in this sense, the term “radiation” (back)-reaction is a misnomer because it should more appropriately be called an EM field (back)-reaction. Note further that this EM field (back)reaction is also intimately connected with the issue of the so-called “hidden” EM momentum. Shortly, we’ll see that Frad tr is determined by the time derivative of the acceleration a tr , and can be non-zero even when the acceleration a tr is instantaneously zero! (The charged particle is not radiating at that retarded instant in time!) 20 © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede By energy conservation, the energy lost by the electrically charged particle in a given retarded time interval tr tr2 tr1 tr2 tr1 must equal the energy carried away by the EM radiation, plus whatever extra energy has been pumped into the EM velocity/generalized Coulomb field. If we consider time intervals tr tr2 tr1 such that “the system” (consisting of the pointcharged particle q and the EM velocity field – see drawing on following page) returns to its initial state, then (assuming that the energy in the EM velocity fields is the same at time tr2 as at time tr1 , then the only net energy loss is in the form of EM radiation (due to the emission of n real photons). dW tr q 2 a 2 tr Frad tr v tr o is incorrect, dt 6 c by suitably averaging this relation over a finite time interval, it is valid, with the restriction that state of “the system” is identical at the retarded times tr1 and tr2 : Thus, while instantaneously Pq tr 1 tr tr tr2 tr tr1 1 o q 2 Frad tr v tr dtr tr 6 c tr tr2 tr tr1 a 2 tr dtr For the case of periodic/harmonic motion, this means that the above integrals must be carried out over at least one (or more) complete / full cycles, tr tr2 tr1 n , n = 1, 2, 3, . . . For non-periodic motion, the condition that “the system” be identical at times tr1 and tr2 is more difficult to achieve – it is not enough that the instantaneous velocities and accelerations be equal at tr1 and tr2 , since the (retarded) fields farther out (at the present time t tr r c ) depend on v tr and a tr at the earlier retarded time tr !!! © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved 21 UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede For non-periodic motion, the condition that “the system” be identical at times tr1 and tr2 technically requires that not only v tr1 v tr2 and a tr1 a tr2 , but all higher derivatives of v tr must also likewise be equal at times tr1 and tr2 !!! However, in practice, for non-periodic motion, since the EM velocity fields fall off rapidly with r , it is sufficient that v tr1 v tr2 and a tr1 a tr2 , for a brief time interval, tr tr2 tr1 . The RHS of the above equation can be integrated by parts: tr tr2 a tr dtr 2 tr tr1 tr tr2 tr tr1 tr 2 tr tr2 d v t dv tr 2 dv tr dv tr r v tr dtr dtr v tr tr tr 2 dtr t dtr 1 dtr dtr r1 a tr Because of the restriction on v tr1 v tr2 and a tr1 a tr2 at the time endpoints tr1 and tr2 , tr dv tr 2 tr2 The term: v tr v tr a tr tr 0 1 dtr t r1 Thus: Or: tr tr2 tr tr1 tr tr2 tr tr1 o q 2 Frad tr v tr dtr 6 c tr tr2 tr tr1 a t v t dt r r r o q 2 a tr v tr dtr 0 Frad tr 6 c Mathematically, there are lots of ways this integral equation can be satisfied, but it will certainly be satisfied if: o q 2 Frad tr a tr Abraham-Lorentz formula 6 c This relation is known as the Abraham-Lorentz formula for the EM “radiation reaction” force. q2 Frad tr o a tr is the simplest possible form the EM radiation reaction force can take. 6 c Physically, note that this formula tells us only about the time-averaged force {albeit} over a very brief time interval tr tr2 tr1 , of the force component parallel to v tr - because of the original term Frad tr v tr . As such, it tells us nothing about Frad tr to v tr . n.b. These averages are also restricted to time intervals such that tr tr2 tr1 is chosen to ensure that v tr1 v tr2 and a tr1 a tr2 . 22 © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede o q 2 F t a tr also has disturbing, The Abraham-Lorentz radiation reaction force rad r 6 c seemingly unphysical implications that are still not fully understood today, despite the passage of nearly a century! Suppose a charged particle is subject to NO external forces. Then Newton’s 2nd law says that: q2 Frad tr o a tr ma tr where m = (real) rest mass of the charged particle. 6 c Then: o q 2 o q 2 Frad tr ma tr m a tr ma tr or: a tr a tr a tr 6 mc 6 mc The solution to this linear, first-order homogeneous differential equation is: a tr ao e tr q2 where ao = acceleration at the retarded zero of time, tr = 0, and o , which for the 6 mc electron is a time constant of : e 6 1024 sec . If ao ≠ 0, the acceleration exponentially increases (+ve, if ao > 0, ve, if ao < 0) as time progresses! This is a runaway solution, which is CRAZY !!! This can only be avoided if ao 0. However, if the runaway solutions are excluded on physical grounds, then the charged particle develops an acausal behavior – e.g. if an external force is applied, the charged particle responds before the force acts!! This acausal “pre-acceleration” “jumps the gun” by only a short time e 6 1024 sec, and since we know that quantum mechanics and uncertainty principle are operative on short distance/short timescales, perhaps this classical behavior shouldn’t be too unsettling to us. Nevertheless, to many it is…. (see Griffiths Problem 11.19, p. 469 for more aspects/ramifications of the Abraham-Lorentz formula…) Such difficulties also persist in the fully-relativistic version of the Abraham-Lorentz equation. Griffiths Example 11.4 – EM Radiation Damping: Calculate the EM radiation damping of an electrically charged particle attached to a spring of natural angular frequency ωo with driving frequency = ω The 1-dimensional equation of motion is: mx tr Fspring tr Frad tr Fdriving tr mo2 x tr m x tr Fdriving tr © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved 23 UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede With the system oscillating at the driving frequency ω: Instantaneous position: x tr xo cos tr Instantaneous velocity: x tr xo sin tr Instantaneous acceleration: x tr 2 xo cos tr x tr 3 xo sin tr 2 xo sin tr Instantaneous jerk: x tr Thus: x tr x tr 2 Thus: mx tr m 2 x tr mo2 x tr Fdriving tr Define the damping constant: 2 (SI units: 1 sec ) Then: mx tr m x tr mo2 x tr Fdriving tr ← 2nd-order linear inhomogeneous diff. eqn. n.b. In this situation, the EM radiation damping is proportional to v tr . Compare this to e.g. “normal” mechanical damping, which is proportional to v tr (e.g. friction / dissipation). The Physical Basis of the Radiation Reaction q2 We derived the Abraham-Lorentz EM radiation reaction force Frad tr o a tr from 6 c consideration of conservation of energy in the EM radiation process, from what was observable in the far-field region, r → ∞. Classically, if one tries to determine this radiation reaction force at the radiating point charge, we run into mathematical difficulties due to the mathematical point-behavior of the electric charge (e.g. at its origin) where the (static) electric field and corresponding scalar potential become singular, this problem correspondingly has infinite energy density at the point charge. This singular nature is also the present for the retarded EM fields associated with a moving point charge: q r 2 2 Er r , t c v u r u a 4 o r u 3 1 Br r , t rˆ Er r , t with: u crˆ v c Today, we know that quantum mechanics is operative, e.g. from the Heisenberg uncertainty principle on {e.g. 1-dimensional} distance scales of: xpx where: h 2 = Planck’s Constant / 2π, h 6.626 1034 J-sec Then: 24 x px but: px c me c 2 {for electrons} © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved UIUC Physics 436 EM Fields & Sources II Note that: x hc = 1240 eV-nm and: Fall Semester, 2015 (1 fm = 1015 m) e c 386 fm = reduced Compton wavelength of the electron 2 me c 2 and: e Thus: x e Prof. Steven Errede 1 nm = 109 m c 1240 eV-nm / 2 0.386 1012 m 386 fm 2 0.511 meV me c The quantity e Lect. Notes 14 hc 2427 fm = Compton wavelength of electron me c 2 c 386 fm 386 1015 m 2 me c For short distance scales of order x e c me c 2 386 fm {and less} the behavior of an electron will be manifestly quantum mechanical in nature. Thus, we should not be surprised that when extrapolating classical EM theory into this short-distance regime, we obtain erroneous answers – we have no reason to expect classical theory to {continue to} hold in the quantum domain !!! Ve r q 1 4 o r Similarly, we have no business extrapolating quantum mechanics to distance scales less than: reBH 2GN me 2 6.673 1011 m3 kg 1s 1 9.109 1031 kg 1.35 1057 m = 2 8 c2 3 10 m / s Schwartzschild radius of electron (event horizon) Where GN = Newton’s gravitational constant. The electron is a black hole at this distance scale – the Schwartzschild radius/event horizon of an electron is where space & time interchange roles! However, long before this regime is reached, at distance scales corresponding to the Planck energy/Planck mass m p c 2 c 3 GN 2.2 108 kg 1.2 1019 GeV 1.2 1028 eV {1 GeV = 109 eV}, is the regime of quantum gravity, where space-time itself becomes © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved 25 UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede “foam-like” (i.e. not continuous) – quantized/discretized {somehow…}. The distance scale where quantum gravity is operative is known as the Planck length: LP GN c 3 1.6 1035 m . The Planck length corresponds to a time-scale {known as the Planck time} of t P LP c GN c 5 5.4 1044 sec . Nevertheless, back in the early 1900’s, ignorance of quantum gravity and quantum mechanics did not stop Abraham, Lorentz, Poincaré {and many others} from applying classical EM theory electrodynamics to calculate the self-force / radiation back-reaction on a point electric charge. These efforts by-and-large modeled the point electron as {some kind of} spatially-extended electric charge distribution (of finite, but very small size), calculations could then be carried out and then (at the end of the calculation) the limit of the size of the charge distribution → 0. In general (as we have already encountered this before in electrodynamics), the retarded classical/macroscopic EM force of one part (A) acting on another part (B) is not equal and opposite to the force of B acting on A, Newton’s 3rd Law is seemingly violated: Fr AB rB , t Fr BA rA , t Adding up the imbalances of such force pairs, we obtain the net force (imbalance) of a charge on itself – the “self-force” acting on the charge. H.A. Lorentz originally calculated the classical self-force using a spherical charge distribution – tedious – see J.D. Jackson’s Classical Electrodynamics, 3rd ed., sec. 16.3 and beyond if interested in these details…. A “less realistic” model of a charge is to use a rigid dumbbell in which the total charge q is divided into 2 halves separated by a fixed distance d (simplest possible charge arrangement to elucidate the self-force mechanism): Assume that the dumbbell moves in x̂ -direction and (for simplicity) assume that the dumbbell is instantaneously at rest at the retarded time tr. Then the retarded electric field at (1) due to (2) is: Er21 r1 , t 26 r 2 r 2 q c r a u r u a c r a u r u a 3 4 o r u 8 o r u 3 1 2 q © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved UIUC Physics 436 EM Fields & Sources II Here: Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede u crˆ {because v tr 0 } Note that: r xˆ dyˆ rrˆ and thus: r 2 d 2 . Note also that: fcn a and: a tr a tr xˆ . r u tr xˆ dyˆ crˆ rrˆcrˆ cr and: r a tr xˆ dyˆ a tr xˆ a tr We are in fact only interested in the x̂ -component of Er21 r , t , since the ŷ -components of Er21 r , t and Er12 r , t will cancel when we add forces on the two ends of the dumbbell. Note further that since the two charges on the dumbbell are both moving in the same direction / parallel to each other, the magnetic forces associated one charge acting on the other will also cancel, thus Newton’s 3rd Law is manifestly obeyed {here}, in this particular situation / configuration. cr c c If u crˆ , then: u x u xˆ xˆ and since: r xˆ dyˆ then: u x lxˆ dyˆ xˆ r r r q r c 2 r a tr u x r u tr ax tr Thus: Er21x r1 , t 3 8 o r u t r And: r u tr cr and: r a tr xˆ dyˆ a tr xˆ a tr since: a tr a tr xˆ ax tr xˆ Then: q r 2 c Er21x r1 , t c a tr cra tr 3 3 r 8 o c r 1 2 q c a tr ra tr 2 2 r 8 o c r 2 1 c 2 a t r ra tr 2 2 r 8 o c r r q 2 2 1 c 2 a t r r a t r r 8 o c 2 r 2 r q 1 c 2 r 2 2 a tr but: r 2 2 d 2 or: r 2 2 d 2 2 3 8 o c r q d2 q 1 c 2 d 2 a tr 8 o c r 2 3 2 2 q c d a t r Thus: E r1 , t since: r 2 d 2 3 2 2 2 8 o c d 2 By symmetry: Er21x r1 , t Er12x r2 , t 21 rx © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved 27 UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede The net retarded force on the rigid dumbbell is: Frself r , t Fr21 r1 , t Fr12 r2 , t 12 qEr21 r1 , t 12 qEr12 r2 , t 8 o c c d a t xˆ Exact d 2 q2 2 r 2 2 2 3 2 We now expand Frself r , t in powers of d. Then when the size d of the electrically-charged dumbbell is taken to its limit of d → 0, all positive powers will disappear. Taylor’s Theorem: x t x tr x tr t tr 1 1 2 3 x tr t tr x tr t tr ... 2! 3! Recall that: x tr v tr 0 and that: fcn a tr Then: x tr x tr 1 1 a tr tr2 a tr tr3 ... where: tr t tr 2 6 But: ctr r 2 d 2 c 2 tr2 r 2 2 d 2 Or: 1 1 d r c t c t a tr tr2 a tr tr3 ... 6 2 2 2 2 2 r 2 2 2 2 r a tr tr a tr tr2 a tr tr a tr tr2 c t c t ... ctr 1 ... 6c 6c 2c 2c 2 2 ctr 2 r 2 2 2 r a 2 tr 3 tr tr4 ... 8c We want tr in terms of d. From above, it can be seen that we can solve for d in terms of tr . But we can solve for tr in terms of d using the reversion of series technique, which is a formal method that can be used to obtain an approximate value of tr by ignoring all higher powers of tr . To first order in d, we have: d ctr tr d use this as an approximation for obtaining a cubic correction term: c 2 3 a 2 tr d d a tr d d ctr tr c 8c5 8c c 3 a 2 tr 3 1 d d 4 ... Keep going. . . tr d 5 c 8c 28 © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede Thus: x t x tr a tr 2 a tr 3 1 1 a tr tr2 a tr tr3 ... d d d 4 ... 3 2 6 2c 6c Then: Frself r , t c d a t xˆ q 4 d 2 q2 8 o c 2 r 2 2 2 3 2 2 o a tr a tr d ... xˆ 2 3 4c d 12c {Note that a tr and a tr are evaluated at the retarded time tr.} Using the Taylor series expansion of a tr , we can rewrite this result in terms of the present time: a tr a t a t tr t ... a t a t tr ... a t a t Then: q2 Frself r , t 4 o d ... c a t a t 2 3 d ... xˆ 4c d 3c The first term inside the brackets on the RHS is proportional to acceleration of the charge q. If we put it on LHS, then by Newton’s 2nd Law F ma , we see that it adds to the mass m of the dumbbell – there is inertia associated with accelerating an electrically-charged particle. The total inertial mass of the dumbbell is therefore: mtot mdumbbell Or: 2 1 q2 1 12 q mdumbbell 4 o 4dc 2 4 o dc 2 2 1 12 q mtot c mdumbbell c 4 o d 2 rest mass energy, E mc 2 2 Note that the {repulsive} electrostatic potential energy associated with this dumbbell is: UE r d 1 2 12 q 2 1 12 q (Joules) q V r d 4 o d 4 o d 2 The fact that this works out “perfectly” is simply due to the fact that the initial choice of the dumbbell’s orientation was deliberately/consciously chosen to be transverse to the direction of motion. For a longitudinally oriented dumbbell, the EM mass correction is half this amount. For a spherical charge distribution, the EM mass correction is a factor of ¾ !! © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved 29 UIUC Physics 436 EM Fields & Sources II Fall Semester, 2015 Lect. Notes 14 Prof. Steven Errede The second term inside the brackets on the RHS of the Frself r , t relation is the EM radiation reaction term: int q 2 a t o q 2 a t ˆ Frad r , t x xˆ 12 o c 3 12 c int Note that Frad r , t differs from Abraham-Lorentz result by a factor of 2: A-L o q 2 Frad r , t a t 6 c int The reason for the factor of 2 difference is that physically, Frad r , t is force of one end of the dumbbell acting on the on other – i.e. an EM interaction between the two ends of the dumbbell. There is also a force of each end of the dumbbell acting on itself – an EM self-interaction self Frad r , t for each end. When the EM self-interactions for each end are included (see Griffiths Problem 11.20, p. 473), the total EM radiation-reaction is: tot q 2 a t 1 1 1 o q 2 a t ˆ Frad x xˆ r , t Fradint r , t 2 Fradself r , t o 6 c 2 4 4 6 c which agrees perfectly with Abraham-Lorentz radiation-reaction force formula. Thus, physically we see that the EM radiation reaction is due to the force of the charge acting on itself – an {apparent} self-force! Note also that Frad r , t does NOT depend on d ( Frad r , t is valid/well-behaved in limit of the size of the dumbbell, d → 0). 2 1 12 q when d → 0 !!! However, note that: mtot c mdumbbell c 4 o d 2 2 The inertial mass of the classical electron becomes infinite when when d → 0, because: UE r d 1 2 12 q 2 1 12 q when d → 0 !!! q V r d 4 o d 4 o d 2 {But we already knew this, as we learned long ago, in P435/last semester…} Note that this unpleasant/awkward problem also persists in the fully-relativistic, quantum electrodynamical theory {QED}. Infinities/singularities there are dealt with/side-stepped by a process known as mass renormalization, so as to avoid such infinities – look only at mass differences / energy differences… 30 © Professor Steven Errede, Department of Physics, University of Illinois at Urbana-Champaign, Illinois 2005-2015. All Rights Reserved