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Chem 390 Physical Chemistry II Spring 2007 Boltzmann factors and partition functions revisited A brief summary of material from McQuarrie & Simon, Chapters 17 and 18, on the partition function and its use in the calculation of some equilibrium properties. You have already seen this material in Chem 389. The concepts outlined here will be applied in Chem 390 to a number of important problems. Partition function as a normalization factor for probabilities For a system in equilibrium at (absolute) temperature T , the probability of finding the system in the quantum state with energy Ej is proportional to the Boltzmann factor pj ∝ e−Ej /kB T ≡ e−βEj (1) where kB is Boltzmann’s constant, and we have defined the useful combination β ≡ 1/kB T . Each pj is (and has to be ) > 0. As the probability of finding the system in any state j is 1, we must have X pj = 1, (2) j A suitable normalization factor is then 1/Q, where Q is the partition function X Q≡ e−Ej /kB T , (3) j so that the properly normalized probabilities pj are [McQ&S, eq. (17.13)] pj = e−βEj e−βEj = P −βEj . Q je (4) Calculation of average energy For a system of N particles (for example, a gas of particles in a container of volume V ), the energies Ej are the eigenvalues of the Schrödinger equation ĤΨj = Ej Ψj . (5) The system energies Ej will naturally be functions of how many particles there are (N ) and how big the box is (V ), so Ej = Ej (N, V ), and the full dependence of Q and the pj s is X Q(N, V, T ) = e−Ej (N,V )/kB T (6a) j pj (N, V, T ) = e−βEj (N,V ) Q(N, V, T ) (6b) or Q(N, V, β) = X e−βEj (N,V ) (7a) j pj (N, V, β) = e−βEj (N,V ) Q(N, V, β) 1 of 4 (7b) Physical Chemistry II Chem 390 Spring 2007 where it is important to note that we can use either the temperature T or β = 1/kB T as an independent variable in addition to N and V . The average energy of the system hEi, which we equate with the observed energy U , is calculated by evaluating the sum of each energy Ej multiplied by the corresponding probability pj hEi = X 1 X Ej (N, V )e−βEj (N,V ) Q j Ej p j = j (8) which is (McQ&S, equations (17.20) and (17.21)) ∂ln Q 2 ∂ln Q hEi = − = kB T . ∂β N,V ∂T N,V (9) We therefore have the first essential route from the quantum levels Ej to an equilibrium bulk property {Ej } =⇒ Q(N, V, T ) =⇒ U (N, V, T ). (10) Heat capacity (constant volume) Once we have (in principle) the average energy as a function of T , N and V , we can calculate the rate at which hEi changes as we change T at constant N and V : this is the (constant volume) heat capacity CV (eq. (17.25)) ∂U ∂hEi = . (11) CV = ∂T N,V ∂T N,V Calculation of the pressure For a macroscopic system in level j, energy Ej , the associated level pressure Pj is directly related to the rate at which the energy Ej (N, V ) changes as the volume of the system varies: ∂Ej Pj (N, V ) = − . (12) ∂V N The equilibrium pressure p at temperature T is obtained by averaging the level pressures Pj over the probabilities pj X p ≡ hPi = pj Pj (13a) j =− X pj j =− 1 X Q j ∂Ej ∂V ∂Ej ∂V (13b) N e−βEj . (13c) N We therefore have (17.32) p= 1 β ∂ln Q ∂V = kB T N,T ∂ln Q ∂V (14) N,T and a second essential route from the quantum levels Ej to an equilibrium bulk property {Ej } =⇒ Q(N, V, T ) =⇒ p(N, V, T ). In principle we can calculate the equation of state, p = p(N, V, T ) from the {Ej }. 2 of 4 (15) Physical Chemistry II Chem 390 Spring 2007 The partition function for independent subsystems: distinguishable versus indistinguishable Independent subsystems Independent means that the interaction energy between the particles is effectively zero. The total energy for the N particle system, Ej , can then be written as a sum of contributions εα i from independent subsystems (molecules) α X Ej = εα (16) i . α Distinguishable subsystems Distinguishable means that, although the particles have the same chemical identity, they are localized in distinct regions of space and are (in principle) experimentally identifiable (“taggable”) according to their location. (Example: molecules fixed at distinct sites in a crystal lattice.) From (16), the partition function Q for independent and distinguishable particles factors into the product of partition functions qα for each identical subsystem, (17.35): Q(N, T, V ) = Y qα (V, T ) = [q(V, T )]N (17) X (18) α with q(V, T ) = e−εj /kB T . j Indistinguishable subsystems Indistinguishable means that there is no way in principle to identify individual particles according to their location in space. (Example: identical gas molecules moving around inside a container of volume V .) If the criterion: number of quantum states per particle with energy εj . kB T N is satisfied, the partition function Q for N independent and indistinguishable particles is given by Boltzmann statistics, (17.38) Q(N, V, T ) = [q(V, T )]N . N! (19) The partition function for a subsystem (molecule) whose energy is the sum of separable contributions Quantized molecular energy levels can often be written to very good approximation as the sum of independent contributions from translational, rotational, vibrational and electronic motions (17.45) vib elec ε = εtrans + εrot i j + εk + ε ` (20) so that the single-molecule partition function q(V, T ) has the product form (17.46) q(V, T ) = qtrans qrot qvib qelec . 3 of 4 (21) Physical Chemistry II Chem 390 Spring 2007 Partition functions for molecular motions • Translation Consider a particle of mass m in a 1D box of length L. Replacing the sum over quantum states with an integral we have 1/2 mkB T L (22) q1D (V, T ) = 2π~2 For a particle of mass m in a 3D volume V at temperature T , mkB T qtrans (V, T ) = 2π~2 3/2 V McQ&S, eq. (18.20) (23) • Rotation Consider a rigid heteronuclear diatomic, with rotational energy levels EJ = BJ(J + 1), J = 0, 1, . . . B = ~2 /2I. The rotational partition function is X qrot = (2J + 1)e−Θrot J(J+1)/T McQ&S, eq. (18.33) (24) (25) J=0,1,... where Θrot = B/kB . For T Θrot we can replace the sum over rotational quantum number J by an integral, ⇒ qrot = 2IkB T T = Θrot ~2 McQ&S, eq. (18.34) . In general qrot = T σΘrot (26) (27) where σ is the symmetry number, σ = 1 for a heteronuclear diatomic, σ = 2 for a homonuclear. • Vibration For a single molecular vibrational mode treated as a harmonic oscillator, vibrational frequency ν, vibrational quantum hν = ~ω, qvib = X 1 e−~ω(n+ 2 )/kB T (28a) n=0,1,... e−β~ω/2 1 − e−β~ω e−Θvib /2T = 1 − e−Θvib /T = McQ&S, eq. (18.23) with Θvib = ~ω/kB . For T Θvib , qvib = 4 of 4 McQ&S, eq. (18.24) . T . Θvib (28b) (28c) (29)