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GRIFFITH QUANTUM THEORY SEMINAR 10 NOVEMBER 2003 Entanglement, correlation, and errorcorrection in the ground states of manybody systems Henry Haselgrove School of Physical Sciences University of Queensland Michael Nielsen - UQ Tobias Osborne – Bristol Nick Bonesteel – Florida State quant-ph/0308083 quant-ph/0303022 – to appear in PRL When we make basic assumptions about the interactions in a multi-body quantum system, what are the implications for the ground state? Basic assumptions --- simple general assumptions of physical plausibility, applicable to most physical systems. Nature gets by with just 2-body interactions Far-apart things don’t directly interact Implications for the ground state --- using the concepts of Quantum Information Theory. Error-correcting properties Entanglement properties Why ground states are really cool Physically, ground states are interesting: T=0 is only thermal state that can be a pure state (vs. mixed state) Pure states are the “most quantum”. Physically: superconductivity, superfluidity, quantum hall effect, … Ground states in Quantum Information Processing: Naturally fault-tolerant systems Adiabatic quantum computing Part 1: Two-local interactions N interacting quantum systems, each d-level Interactions may only be one- and two-body Consider the whole state space. Which of these states are the ground state of some (nontrivial) two-local Hamiltonian? 1 3 2 4 … N Two-local interactions 2 1 4 3 Classically: Quantum-mechanically: Two-local Hamiltonians N quantum bits, for clarity Any imaginable Hamiltonian is a real linear combination of basis matrices An, {An} = All N-fold tensor products of Pauli matrices, Any two-local Hamiltonian is written as where the Bn are N-fold tensor products of Pauli matrices with no more than two non-identity terms. Example is two-local, but is not. Why two-locality restricts ground states: parameter counting argument 2 O(N ) O(2N) parameters Necessary condition for |> to be twolocal ground state We have and Take E=0 Not interested in trivial case where all cn=0 So the set must be linearly dependent for |i to be a two-local ground state Nondegenerate quantum error-correcting codes A state |> is in a QECC that corrects L errors if in principle the original state can be recovered after any unknown operation on L of the qubits acts on |> The {Bn} form a basis for errors on up to 2 qubits A QECC that corrects two errors is nondegenerate if each {Bn} takes |i to a mutually orthogonal state Only way you can have is if all cn=0 ) trivial Hamiltonian A nondegenerate QECC can not be the eigenstate of any nontrivial two-local Hamiltonian In fact, it can not be even near an eigenstate of any nontrivial two-local Hamiltonian H = completely arbitrary nontrivial 2-local Hamiltonian = nondegenerate QECC correcting 2 errors E = any eigenstate of H (assume it has zero eigenvalue) Want to show that these assumptions alone imply that || - E || can never get small Nondegenerate QECCs Radius of the holes is Part 2: When far-apart objects don’t interact In the ground state, how much entanglement is there between the ●’s? We find that the entanglement is bounded by a function of the energy gap between ground and first exited states Energy gap E1-E0: Physical quantity: how much energy is needed to excite to higher eigenstate Needs to be nonzero in order for zero-temperature state to be pure Adiabatic QC: you must slow down the computation when the energy gap becomes small Entanglement: Uniquely quantum property A resource in several Quantum Information Processing tasks Is required at intermediate steps of a quantum computation, in order for the computation to be powerful Some related results Theory of quantum phase transitions. At a QPT, one sees both a vanishing energy gap, and correlations in the ground state. Theory usually applies to infinite quantum systems. long-range Non-relativistic Goldstone Theorem. Diverging correlations imply vanishing energy gap. Applies to infinite systems, and typically requires additional symmetry assumptions Extreme case: maximum entanglement A B C Assume the ground state has maximum entanglement between A and C or A B C That is, whenever you have couplings of the form A B C it is impossible to have a unique ground state that maximally entangles A and C. So, a maximally entangled ground state implies a zero energy gap Same argument extends to any maximally correlated ground state Can we get any entanglement between A and C in a unique ground state? Yes. For example (A, B, C are spin-1/2): 0.1X X 0.1X = 0.1 (XX + YY + ZZ) … has a unique ground state having an entanglement of formation of 0.96 Can we prove a general trade-off between ground-state entanglement and the gap? 1.4000 1.0392 1.0000 0.6485 -1.0000 -1.0000 -1.0392 -1.0485 General result A B C Have a “target state” |i that we want “close” to being the ground state |E0i --- measure of closeness of target to ground --- measure of correlation between A and C The future… At the moment, our bound on the energy gap becomes very weak when you make the system very large. Can we improve this? The question of whether a state can be a unique ground state is closely related to the question of when a state is uniquely determined by its reduced density matrices. Explore this question further: what are the conditions for this “unique extended state”? Conclusions Simple yet widely-applicable assumptions on the interactions in a many-body quantum system, lead to interesting and powerful results regarding the ground states of those systems 1. 2. Assuming two-locality affects the errorcorrecting abilities Assuming that two parts don’t directly interact, introduces a correlation-gap trade-off.