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Warm-Up #53 11/4/16 Solve the following quadratic equation. 1. x2 + 4x = 3 Complex Numbers Determine the number of real solutions. Section 4-8 11/4/16 2. 2x2 - 3x + 7 = 0 3. x2 = 6x + 5 EQ: What are complex numbers? Why are they based on a number whose square is -1? Finding Square Roots Complex Numbers Solve each quadratic function by finding square roots. The complex numbers are based on a number called the imaginary unit i, whose square is -1. 1. 7x2 - 63 = 0 x=±3 two real solutions and 2 2. 5x + 125 = 0 x2 = -25 no real solutions → imaginary solutions Example 5x2 + 125 = 0 Simplify a Number Using i Complex Numbers Write the following using the imaginary unit i. Complex numbers can be written in the form a + bi, where a and b are real numbers. 1. 3. 2. 4. If b = 0, the number a + bi is a real number. If a = 0 and b ≠ 0, the number a + bi is a pure imaginary number. Warm-Up #54 11/7/16 Solve each quadratic equation. Graphing Complex Numbers 3. 2x2 - 3x + 5 = 0 In the complex number plane, the point (a, b) represents a + bi. Example 2 + 3i The absolute value of a complex number is its distance from the origin in the complex plane. Graphing Complex Numbers Adding & Subtracting Complex Numbers Graph each number and find its distance from the origin. We can also add and subtract complex numbers. 1. -5 + 3i To do so, we combine the real parts and the imaginary parts separately, similar to combining like-terms. 1. 3x2 + 24 = 0 2. x2 + 4x = -5 2. 6i 3. 5 - i 1. (7 - 2i) + (-3 + i) 3. (5 - 3i) - (-2 + 4i) 2. (4 - 3i) + ( -4 + 3i) 4. (8 + 6i) - (8 - 6i) Multiplying Complex Numbers Dividing Complex Numbers What is each product? We can use complex conjugates to simplify quotients of complex numbers. Complex Conjugate 1. (3i)(-5 + 2i) 2. (4 + 3i)(-1 - 2i) 3. (6 + 2i)(6 - 2i) What is each quotient? Complex Conjugate (a + bi)(a - bi) = a2 + b2 1. 2. (a + bi)(a - bi) 3. Finding Imaginary Solutions We can solve any quadratic equation now using complex numbers. 1. x2 + 72 = 0 2. 3x2 - x + 2 = 0 3. x2 - 4x + 5 = 0