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Transcript
Notes-15. The helium atom and many-electron atoms
15-1. The helium atom
In the simplest model, a helium atom has two electrons outside a point charge with
Z=2. The Hamiltonian is written as
1 2
1 2 Ze 2 Ze 2
e2
p1 
p2 

  
2m
2m
r1
r2
r1  r2
This equation can be rewritten as
H  H (1)  H ( 2 )  V
(2)
H
(1)
where
e2
V

(3)
 
r1  r2
is treated as a perturbation. Then the zeroth-order Hamiltonian is separable and the
eigenfunctions are products of hydrogenic wavefunctions, given by
 


u( r1 , r2 )  n1l1m1 ( r1 ) n2l2m2 ( r2 )
(4)
where each u is a hydrogenic wavefunction with charge Z, and each electron is
designated by the quantum numbers n, , m . Within this model, each state of the helium
atom is given by 1s2, 1s2p, 2s3p, etc. However the wavefunction given in (4) is not
correct in general since the wavefunction is not antisymmetric. In addition, the spin from
each electron has to be considered. We learned earlier that two electrons can couple to
S=0 (singlet) or to S=1 (triplet). The S=0 spin function is antisymmetric under the
exchange of the two electrons, and S=1 spin function is symmetric.
For 1s2, the wavefunction, including the spin, is represented by
(5)


u0 ( r1 , r2 )  100 ( r1 ) 100 ( r2 )  sin glet
where the spin part is antisymmetric, and the spatial part is symmetric, under exchange of
electron 1 and 2. The wavefunction in (5) does not include the e-e interaction . Using the
first-order perturbation theory, it can be calculated by doing this integral
(6)
E  
 2 e2
 2
d r1d r2 100 ( r1 )   100 ( r2 )
r1  r2
3
3
Note that the spin function is integrated to one directly.
For two electrons designated by 1s2  , for example, we can have singlet or triplet states,
1
100 (r1 ) 2lm (r2 )  2lm ( r1 ) 100 ( r2 )  sin glet
2
1
100 (r1 )  2lm (r2 )   2lm (r1 ) 100 (r2 )  triplet

2
(7a)
u1( s ) 
(7b)
u 1( t )
Note that the spatial and spin functions are combined to give total antisymmetric
wavefunctions. Using first-order perturbation theory, the integral can be expressed by
1 2
*
e  d 3 r1  d 3 r2 100 ( r1 ) 2 l 0 (r2 )  2 l 0 (r1 ) 100 ( r2 ) 
2
1
100 ( r1 ) 2l 0 (r2 )  2l 0 (r1 ) 100 ( r2 ) 

r1  r2
E1( s.t ) 
 e 2  d 3 r1  d 3 r2 100 ( r1 ) 2 l 0 (r2 )
2
*
 e 2  d 3 r1  d 3 r2 100
( r1 ) 2*l 0 (r2 )
2
1
r1  r2
1
2 l 0 (r1 ) 100 ( r2 )
r1  r2
where the first integral is the classical expression for the interaction energy between two
electron clouds represented by the modulus square of each wavefunction. The second
term has no classical analog-- it is the exchange interaction. The latter is a consequence
of quantum effect, due to that the electrons are indistinguishable.
An isolated helium atom has spherical symmetry. If we do not include any spin
interaction, then the total orbital angular momentum is a good quantum number. Thus a
given state is designated by expressions like 1s2p 1P, 1s3d 3D, .. for example. In general
the total orbital and spin angular momenta are expressed as (2S+1)L. If the interactions
involving the spin are included, then the good quantum number is J from
 
  
 
J  L  S  ( 1   2 )  ( s1  s2 )
This is called LS coupling and the expression (2S+1)LJ is used. There are other coupling
scheme such as jj coupling, which is for the case when the spin-orbit interaction is large,
usually for the heavier atoms.
States such as 1s2s or 1s3d are called singly excited states since one of the electrons
occupies the same 1s orbital of the ground state. From the NIST's data table, you will
find that it takes at least 24.56 eV to ionize one electron in He. This number is called
single ionization energy.
If both electrons are excited, such as 2s3p or 3p4d, then these states are doubly excited
states, since both electrons are excited. These doubly excited states have binding energies
higher than the single ionization energy. Therefore these doubly excited states are not
stable and they are called autoionizing states.
In the autoionization process, the two electrons exchange energy and angular
momentum, with one electron returns to the ground 1s orbital, while the other is ionized.
Doubly excited states are designated like 2s2p or 2p3d, etc. Their energies lie higher
than the single ionization threshold. (see homework 15.2)
15.2. Further comments on He
(a) There are other corrections to eq. (1) for the Hamiltonian of He, including the
spin-orbit, spin-spin, spin-other-orbit interactions, and others. These are not discussed.
(b) There are many different theoretical methods to calculate the energy levels of He,
and they are not discussed here.
(c) with enough energy it is possible to remove both electrons from helium.
15.3. Many-electron atoms
The example in He shows that we can think that for each atom, there are electron
orbitals, designated by n  . Depending on the number of electrons available, one can put
each electron in one of the orbitals. Each one of these orbitals for a fixed n  is called a
subshell, and each fixed n is called a shell. For each  , one can accommodate 2(2   1)
electrons if the spin interaction is neglected. This is the shell model of atoms.
For the present purpose, each of these orbitals can be viewed like a hydrogenic orbital.
In a more advanced model, like the so-called Hatree-Fock model, the concept of the
orbitals is retained, but the potential each electron sees is not a Coulomb potential, but
rather a central field potential which includes some average electron-electron interactions.
The ground state is obtained by putting all the electrons from the lowest orbital up. If one
of the occupied outermost electrons is lifted to an upper level, we have singly excited
states. If the electron is removed from the inner shell, then an inner-shell hole is created.
These states are not stable and the atoms will stabilize by rearrangement, with one
electron falling down to fill the hole, and another electron gets emitted, in order to
conserve the total energy. The emitted electron is called an Auger electron. The
stabilization can also be achieved by emitting a radiation, or photon. This is the source of
characteristic X-rays.
Based on the shell model, the periodic table of the elements can be understood
qualitatively. This has been covered mostly in elementary modern physics and I will not
discuss further any more.
Homework15.1. Go to website of NIST to find out the energy levels of 1s2s states of helium, for
singlet and triplet states and including the fine structure (i.e., for different J's). Do the
same for 1s2p, and draw the energy levels to approximate correct relative scale.
15.2. For helium atom, if one electron is in the 1s state of He+, while the other electron is
ionized and far away at zero energy, what is the total energy of these two electrons (this
defines the single ionization threshold.)
If the two electrons are in the 2s2 doubly excited states, use the simpliest approximation
you know, estimate the binding energy of this state. If the state autoionizes, with the
ejection of another electron, what is the kinetic energy of the electron that is ionized.
15.3. To remove the first electron from He, it takes about 24.56 eV. Go to NIST data to
find the more accurate value. What is the energy does it take to remove both electrons
from He?