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Sec 3.4 & Sec 3.5 Complex Numbers & Complex Zeros Objectives: •To understand complex numbers. •To add, subtract & multiply complex numbers. •To solve equations with complex numbers as solutions. Complex Numbers If i 2 1 , then i 1 A complex number is a number of the form a bi where a and b are real numbers. The real part of the complex number is a and the imaginary part is bi. Ex 1. State the real and imaginary parts of the following complex numbers. a) 7 + 3i b) 9i c) -2 Operations on Complex Numbers To add complex numbers, add the real parts and add the imaginary parts. (a + bi) + (c + di) = (a + c) + (b + d)I To subtract complex numbers, subtract the real parts and subtract the imaginary parts. (a + bi) – (c + di) = (a – c) + (b – d)i Multiply complex numbers like binomials, using i 2 1 (a + bi) . (c + di) = (ac – bd) + (ad + bc)i Ex 2. Perform the indicated operation and write the result as a + bi. (a) (3 + 5i) + (4 – 2i) (b) (3 + 5i) – (4 – 2i) (c) (3 + 5i)(4 – 2i) Powers of i Any power of i can be reduced to one of the following: i i 1 i 1 2 i i 3 i 1 4 To reduce a power of i, just divide by 4 and the remainder will correspond to one of 23 these. For example, i i Because 23/4 has a remainder of 3 so the answer corresponds 3 to i Ex 3. Evaluate. a) i 35 b) i 56 c) i 62 d) i 19 Class Work Perform the indicated operation and write your answer in a + bi form. 1. (2 + 5i) + (4 – 6i) 2. (5 – 3i)(1 + i) 3. i 43 Square Roots of Negative Numbers Just as every positive real number r has two square roots r and r , every negative number has two square roots as well. If -r is a negative number, then its square roots are i r , because: i 2r r i r and 2 i r 2 i 2r r If –r is negative, then the principal square root of –r is: r i r For example: 3 i 3 Ex 4. Evaluate the expression. a 1 b 16 c 7 Ex 5. Evaluate and write the result in the form of a + bi. 12 3 3 4 Class Work Evaluate the expression and write your result in the form of a + bi. 4. 32 5. 25 6. 3 12 7. 3 4 6 8 Complex Roots of Quadratic Equations We know that if b2 – 4ac < 0 then the quadratic has no real solutions. However, in the complex number system, the equation will always have solutions. The solutions will be complex numbers and will have the form a + bi and a – bi. The solutions will always come in pairs, called conjugates. Ex 6. Solve each equation. (a) x2 + 9 = 0 (b) x2 + 4x + 5 = 0 Class Work Find all the zeros of the polynomial. 8. P( x) x3 x 2 x 9. P( x) x 7 x 18x 18; x 3 3 2 4 2 P ( x ) x x 2 x 2; x 1, 1 10. Ex 7. Find a polynomial with integer coefficients that have the given zeros. a) Degree 3 and zeros 2 and i. b) Degree 2 and zeros 1 + i, and 1 – i. HW Worksheet 3.4 & 3.5