Download 19-3 Esters and Anhydrides (PPT)

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project

Document related concepts

Ring-closing metathesis wikipedia , lookup

Phenols wikipedia , lookup

Bottromycin wikipedia , lookup

Asymmetric induction wikipedia , lookup

Wolff–Kishner reduction wikipedia , lookup

Haloalkane wikipedia , lookup

Hydroformylation wikipedia , lookup

Wolff rearrangement wikipedia , lookup

Alcohol wikipedia , lookup

Strychnine total synthesis wikipedia , lookup

Petasis reaction wikipedia , lookup

Nucleophilic acyl substitution wikipedia , lookup

Transcript
With less basic nucleophiles, especially under acidic conditions, substitution
through the addition-elimination mechanism may occur.
In the esterification of a carboxylic acid, an alcohol and a carboxylic acid react in
the presence of acid to form an ester and water.
The acid serves to protonate both the carbonyl oxygen, activating the
carbonyl towards nucleophilic addition, and the carboxy OH, converting it into
a better leaving group.
19-8
Carboxylic Acid Derivatives: Alkanoyl (Acyl) Halides
Alkanoyl (acyl) halides are formed by using inorganic derivatives of
carboxylic acids.
Alkanoyl (acyl) halides can be prepared from carboxylic acids by using reagents
such as SOCl2 or PBr3.
The reaction with either reagent begins with the conversion of the poor leaving
group, -OH, into a good leaving group.
Acids combine with alkanoyl halides to produce anhydrides.
An alkanoyl halide is activated to attack by weaker nucleophiles by the
electronegative power of its halogen atom.
Treatment of alkanoyl halides with carboxylic acids leads to carboxylic anhydrides.
5- or 6-membered cyclic anhydrides can be prepared by simple heating of the
corresponding dicarboxylic acids.
Because the halogen in an alkanoyl halide and the RCO2 group in an anhydride are
good leaving groups, alkanoyl halides and anhydrides are often useful
intermediates during the preparation of other compounds.
19-9
Carboxylic Acid Derivatives: Esters
Carboxylic acids react with alcohols to form esters.
Esters can be formed in an equilibrium process by combining a carboxylic acid and
an alcohol in the presence of catalytic amounts of a mineral acid.
Ho is usually close to 0 for an esterification reaction. Since So is also close to
zero, Go will be close to zero and the equilibrium constant for the reaction will be
close to 1.
The equilibrium can be shifted in the direction of the products by using an excess
of one of the starting materials, or by removing either water or the ester from the
reaction mixture.
Esterifications are most often carried out using the alcohol as the solvent.
Esterifications are most often carried out using the alcohol as the solvent.
Etherification proceeds through acid-catalyzed addition-elimination.
Acid catalysis in an esterification reaction functions first to protonate the carbonyl
oxygen, making the carbonyl carbon a better electrophile, and then to protonate
the –OH group in the tetrahedral intermediate making it a better leaving group.
All of the steps are reversible.
Addition of alcohol or removal of water favors esterification.
Hydroxy acids may undergo intramolecular esterification to lactones.
Hydroxy carboxylic acids may form 5- or 6-membered cyclic esters, or lactones, when
treated with catalytic amounts of mineral acid through a process called intramolecular
esterification.