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Power Supplies Objective -- to supply a constant direct voltage VL in spite of variations in the source voltage VS (e.g. from a transformer - rectifier - smoothing arrangement) and the load current IL. (Less commonly they are required to supply a constant direct current). Perhaps the simplest idea At least it is simple! The problems are that the value of R must be high to produce a constant output voltage, but low to allow much output current to flow. We can, however, use the circuit as the basis of a better circuit ... The Series Regulator The transistor operates as an emitter follower, so the effective output resistance is low and variation in the output current will have little effect on IL. VL will settle at a value which will make the two op-amp inputs of equal voltage approximately, so VZ = R2VL/(R1 + R2) .. or VL = VZ(1 + R1/R2). This circuit performs much better than the resistor and Zener arrangement would on its own. Such circuits are available in integrated form .. see RS, Farnell, etc. catalogues. A problem with it is that an output short-circuit will blow the series transistor it is usual to provide overcurrent protection. This can take two forms: 1. The simple version R4 Q2 Q1 IL R R1 R3 VS VL + - R2 The operation is as before provided that the output current is not large enough to drop more than about 0.7 volt across R4. If it is, the base current of Q2 is diverted through the two diodes and further rise in I Lis prevented (well, almost !). The foldback circuit IL Q1 Rm R R1 R1 VS VL + Q2 - R2 R2 The circuit does not affect the performance of the regulator as long as there is insufficient voltage dropped across Rm to switch transistor Q2 on. Once Q2 does switch on, the output current of the op-amp is diverted away from the base of Q1, so Q1 is unable to supply all the "demanded" load current - and the output current is limited to the short-circuit output current of the op-amp (only typically 30 mA or so). This current is LESS than the full-load current -which is why the arrangement is called the foldback circuit. The switched-mode circuit L VS VL C Otherwise known as "diode-pump circuits", these supplies have the advantage of much higher efficiency than the series regulator -- the switch is either fully on (so there is no voltage drop across it) or fully off (so no current flows in it) and, since power = VI, no power is dissipated in the switch. (In fact, it will not be totally ideal and some power will be dissipated, but very little in relation to that dissipated in the transistor of the series regulator). The switch is opened and closed at high frequency (typically 50 kHz or above) and the output voltage is equal to VS times the proportion of the time for which the switch stays closed. The inductor current is "pumped up" whilst the switch is closed; when it opens, the "flywheel diode" allows the load current to keep flowing, though it will fall slightly in value until the switch closes again. Feedback is used to control the "mark-space ratio" of the switch (the ratio of ON time to OFF time) such as to open it more if VL rises and to close it more if VL falls. Other circuits working on the same principle allow us to produce voltages higher than Vs or of the opposite polarity to Vs (see Horowitz and Hill, among other good books !)