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Transcript
Note: All [DIAGRAMS] will be provided in the lecture
PHYSICS 244 NOTES
Lecture 36
Diodes, Transistors
I-V characteristic
The equation
I = I0 [ exp(eV/kT)-1 ]
is called the diode equation. Since eV/kT is about 4.25 when T = 273 K and V = 0.1 volt,
we see that the current increases by a factor of exp(4.25) = 70 for every voltage
increment of 0.1 volts. (Obviously you can’t put a very large forward voltage across the
junction!) Real junctions tend to follow a slightly different equation
I = I0 [ exp(eV/nkT)-1 ],
where n is slightly voltage-dependent, but n varies between 1 and 2. This correction is
mostly due to the fact that electron-hole pairs can recombine before they get entirely
across the junction.
I0 is called the reverse saturation current. It sets the overall scale for the I-V
characteristic, and –I0 is the observed current once the reverse bias voltage exceeds a
small fraction of a volt. Reverse bias raises the barrier and suppresses the diffusion
current, so the –I0 is entirely due to the drift current. It in turn is due to the thermal
generation of electron-hole pairs, so a large energy gap Eg means a small I0.
Reverse breakdown
At a certain reverse bias, usually around V = -0.2 volts, the current increases very
dramatically.
[[DIAGRAM]]
There are two possible mechanisms for this so-called reverse breakdown.
Zener tunneling
When the reverse bias is large, the wavefunctions of the electrons in the valence band on
the left or p side of the junction can overlap with the wavefunctions of the empty states in
the conduction band on the right or n side, and their energies can be equal because the
applied voltage can more than compensate for the energy gap.
[[DIAGRAM]]
Under these conditions, quantum tunneling can occur. The tunneling rate per electron is
not very high, but there are many electrons in the valence band and many empty states in
the conduction band. So the current can be substantial. Note that the electrons are
moving to the left, from the p to the n side, so this is a reverse current.
Avalanche breakdown
This occurs because the electrons and holes undergoing the drift current are strongly
accelerated under reverse bias, since the potential across the junction much increased.
The energy of an electron or hole becomes sufficient to excite an electron-hole pair. The
new electron and new hole are also accelerated and have the possibility of creating
further pairs. Once the multiplication factor is high enough, the current will quickly
increase, creating a break in the I-V characteristic.
Transistors
Consider any non-linear device with I-V characteristic I(Vd) in series with a battery and a
resistor. V = IR + Vd(I)
[[CIRCUIT DIAGRAM]]
To get the current and voltage in the circuit, we must solve the simultaneous equations:
1. I = V/R - Vd(I)/R
2. I = I(Vd).
[[DIAGRAM]]
Now add a control voltage Vg to the device.
[[CIRCUIT DIAGRAM]]
If the current in the control circuit is not too high, we can again solve for the current and
voltage in the circuit.
[[DIAGRAM]]
If the characteristic of the device is very sensitive to Vg, we can use this circuit as an
amplifier.