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Q ui ck Ti m e ™ an d a T I FF ( U nc om p r es se d) de co m pr e ss or ar e n ee de d t o s ee t h is pi ct u re . RF EFFECTS IN PHOTO-INJECTORS Massimo Ferrario INFN-LNF solenoid Zb B z E Ez z z E Z1 Z2 Z C Madison, June 28 - July 2 • Trapping a plane wave in a box • Longitudinal RF effects • Transverse RF effects The solutions to the electromagnetic wave equation in free space are transversely polarized waves (the electric field is transverse to the propagation vector) that have phase velocity c, the speed of light. These properties are problematic from the viewpoint of charged particle acceleration, because in order for a charged particle to absorb energy from an applied electric force, the motion of the charged particle must have a component parallel to the electric field: dU q v E dt If the motion of the particle in an accelerating wave is rectilinear in the zdirection, the electric field must be rotated to have a longitudinal component in order for acceleration to occur. This can be accomplished by using a smoothwalled waveguide. Let us consider a charge co-propagating in the z direction with a wave having a longitudinal component Ez v z c Ez,t Eze the particle experiences an accelerating voltage z ct Vacc Re Vacc Re itkz L i t kz o Eze dz o Ee L z i kz o c z dz o The energy gain depends on the spatial pattern of the field and on the phase relation (phase slippage) The wave is syncronous when k c Vacc Re L Ez z e i o dz o Interaction with a plane wave: particle at rest y Ex cBy x B H 0 E E z Non relativistic approx: x e Ex v z By coskz t mo e ÝzÝ v x By coskz t mo ÝxÝ z Interaction with a plane wave: particle/wave co-propagating y Ex cBy x B H 1 E E E' (Ex 0,0) z E E ' v B' Ex E'x v B B' 2 E ' By E'x Ex c c c a -1 b 1 1 2 1 1 2 2 F e Ex cBy cost kz FE E' using kz kct t -1 FB=FE e1 E x cos 1 t eEx 2 cos 2 2 2 Interaction with a plane wave with an angle Wave front x z Ez Eo sin e i t k z cos y sin vz kz k cos c c cos Not yet suitable 1 cos t Plane wave reflected by a perfectly conducting plane xy E+ E- H+ H- ' zz ' In the plane xz the field is given by the superposition of the incident and reflected wave Ex,z,t E x o ,z o ,t o e itik E x o ,z o ,t o e itik ' z cos x sin ' z cos ' x sin ' E and H // only Boundary conditions require that E,H H// E n H E // x Ez 0,z E sin e ikzcos E sin ' e ikzcos ' 0 E E z Taking into account the boundary conditions the longitudinal component of the field becomes Ez x,z,t E sin e itikz cos x sin E sin e itikz cos x sin ikx sin ikx sin e e E sin e itikz cos 2i 2i 2iE sin sinkx sin e itikz cos x-SW pattern z-TW pattern xy 2d EEz Notice that Ez a,z,t 0 Not only on the conductor: a nd d 2 sin E+ d E+ d/ 2 Ez E- - 1 z We can confine the plane wave with a second parallel conducting plane located where Ez = 0 so that boundary condition are fulfilled Ez a,z,t 0 x n k sin a n= 1 n= 2 n= 3 z nx itkz z nx Ez x,z,t ReiA sin e sint kz z A sin a a A 2E sin kz k cos This is a guided plane wave also called TMn mode n indicates the number of half wavelength between the two plates Not all angles are possible for a given distance a between the two plates d 2 sin If a would be sin ==> a c then c 2a 2 Implying a normal incidence and no propagation 2 Cut-Off condition:Only waves with < c = 2a can propagate sin 1 c The phase velocity is given by c vz kz k cos cos c 1 c 2 c 1 sin 2 > c if < c Im if > c The previous relation is identical to ckz c2 2 2 =kzc That is a dispersion relation c kz We must slow down the wave propagation In order to slow down the waves we have to load the cavity by introducing some periodic obstacle into it d z Ez (z) E0 Im n 2 n an expi z d With this general form of the solution, the field can be viewed as the sum ofmany wave components, which are termed spatial harmonics, having different longitudinal wave-numbers kz,n 2 n / d , and thus different phase velocities . v ,n / kz,n Beam Dinamycs in Photo-Injectors: RF effects Micro-Bunch Production with rf photo-injectors Luca Serafini (INFN - Milan) Workshop on 2nd Generation Plasma Accelerators, Kardamyli, Greece, June 1995 Longitudinal RF effects solenoid Zb B z E Ez z z z exit N 1 / 2 E Z1 Z2 Z C 2 Ez Eo coskz sint o Eo peak accelerating field o phase as the particle lives the cathode surface Let us try to compute the energy gain for a particle with =0 N 1 / 2 / 2 T eEo coskzsint dz o 0 1 kz kct t Impulsive Approximation to Electron Capture: assuming a constant electric field nearby the cathode surface (z~0) Ez Eo sin The longitudinal equation of motion becomes d eEo sin // dt mc assuming 1 1 //2 d // eEo sin 1 //2 dt mc eEo sin t // eEo sin t 2 mc 1 mc giving 2 eEo sin t mc z 1 1 eEo sin mc 2 eEo Introducing the dimensionless vector potential amplitude 2mc 2 k and 1 2kct sin 2 We obtain ˜z 2 sin 1 2 sin Wich has an asymptotic behavior 1 ˜z kct 2 sin t 1 ˜z kz Defining the phase slippage as o t kz ˜z t kc It has an asymptotic behavior given by 1 o 2 sin Which has a minimum at = /2 that is also the phase of maximum acceleration and it is small if > 1/2 ( ex: n= 2.856 GHz, Eo = 100 MV/m ==> =1.63 ) Assuming that the photo-electrons are emitted from the cathode directly at the speed of light, at a phase equal to the asymptotic phase, the energy gain is simply given by N 1 / 2 T eEo cos˜zsin˜z dz 0 1 T 1 2 2 mc N 1 / 2 cos˜zsin˜z d˜z 0 1 N 1 / 2 sin cos where the non relativistic part of the motion has been considered equivalent to a new definition of the injection phase Phase Compression Defining o o o as the phase separation between two different photo-electrons emitted at two launching pahse, their asimptotical distance will be given by: o d o o d By defining the relative change in phase distance between the two electrons d 1 o d cot 1 2 sin The final length of the emitted electron bunch will be given by: cot Lbunch 1 Llaser 2 sin The injection phase o which corresponds to an asymptotic phase treshold below which we have Phase Compression = /2 is the and above which Phase Expansion. For injection phases close to o = 0 the Compression can produce bunching even down to a factor 4 Energy Spread At the gun exit we have 1 N 1 / 2sin cos substituting II order expansion around <> sin sin cos 2 cos cos sin 2 1 2 1 N 1 / 2 sin cos 1 2 N 1 / 2cos sin 2 2 sin cos We are interested in the phase giving 2 1 2 1 N 1 / 21 2 and 1 N 1 / 2 1 1 2 2 So that Or in terms of the rms quantity 2 k z 2 k z Electron phase, energy at gun exit (2nd iris): simulations vs. analytical Exercise: show that the Longitudinal emittance is given by where In particular for a Gaussian distribution show that The fields that accelerate the charged particles in a radio-frequency linac cavity also give rise to transverse components of the Lorentz force that deflect the particles. Transverse RF effects Assuming cylindrical symmetry, transverse electromagnetic fields in an accelerating structure can be obtained by a linear expansion near the axis of the Maxwell equations: r D e Er 1 r Ez z 0 D H Je t r B 1 rc 2 0 ˜rd˜r r0 Ez t r Ez 2 z ˜rd˜r r0 r0 r Ez 2c 2 t r0 The radial component of the Lorentz force becomes Fr q Er v0 B qr Ez 2 z qr dEz 2 dz qr Ez 2 z 1 Ez r0 c t 0 Ez c t r0 r0 r0 (v0 c ). r0 Thus in the ultra-relativistic limit , the net radial Lorentz force is simply proportional to the total z-derivative of the accelerating field. Considering as a longitudinal component Ez r,z,t Ez z sint o Eo coskz sint o r dEz z Er r,z,t sint o 2 dz r k B r,z,t Ez z cost o 2c Tc Tnc Symmetric structure If we integrate the radial forces through an isolated electromagnetic structure with constant velocity and radial offset we obtain for the full momentum transfer er pr 2mc 2 Tnc Tc dEz er dt E T Ez T c 2 z nc dt 2mc er E sin 2n Eo sin 0 2 o 2mc This result explicitly shows that the sum of all inward and outward impulses applied within the structure cancel for an ultra-relativistic particle traversing a cylindrically symmetric structure. But in the last half cell Anti-symmetric structure Tc er pr 2mc 2 Texit Tc z Texit dEz er dt E sin kr sin 2 o dt 2mc This represents a defocussing kick when 0 < < r pr 2 10 mrad @ S band, 100 MV / m Thus it usually will be necessary to focus the beam immediately after leaving the cavity Transverse RF emittance Rewriting pr in Cartesian coordinates: It gives the phase space distribution: a collection of lines with different slopes corresponding to different The normalized transverse emittance is: By inserting px we obtain and assuming that is small writing so that sin sin cos sin 2 2 2 sin sin 2cos sin one obtains from: 2 2 2 cos 2 sin 2 It has a minimum for <>=/2 Away from the minimum we have 2 2 For a Gaussian beam distriution x, y, z 1 x 2 y 2 z 2 2 2 2 z x 1 2 3/2 x2 z e The rms quantitie are 2 k 2 z2 4 k 4 z4 And the emittance becomes: rf xmin k 3 x 2 z2 2 Exercise: show that for a uniform distribution in a cylinder of radius a and length L, the relevant moments for the distribution are: And the transverse emittance is: Second order transverse focusing in electromagnetic accelerating fields Tc Tnc Symmetric structure if one relaxes the assumptions of constant velocity and offset from the design orbit and examines the effects of the alternating gradient forces, one finds that they give rise to a second order secular focusing force 2 x 0 sinkpz x 0 1.50 1.00 x 0.50 0.00 -0.50 -1.00 -1.50 0.0 1.0 2.0 3.0 k z 4.0 5.0 6.0 sec The approximation we will employ here assumes that the motion can be broken down into two components, one which contains the small amplitude fast oscillatory motion (the perturbed part of the motion), and the other that contains the slowly varying or secular, large amplitude variations in the trajectory. x xosc xsec The oscillatory component is analyzed by making the approximation that the offset x=xsec is constant over an oscillation so that: 2 0 xosc sinkpz xsec 0 Which has a simple solution 02 xosc sinkp z 2 kp xsec The original equation becomes 2 x 02 sin(k p z)x 02 sin(k p z)1 sin k p z 02 x sec k p The last step is to convert it into an averaged expression over a period, that gives the behavior of the secular component of the motion xsec x '' x sec 2 2 0 sin(k p z)1 sin k p z 02 x sec k p xsec 4 0 2 2kp xsec 0 d z Simple Fourier decomposition of the on-axis solution then gives the useful form Ez (z) E0 Im n 2 n an expi z d With this general form of the solution, the field can be viewed as the sum of many wave components, which are termed spatial harmonics, having different longitudinal wave-numbers kz,n 2 n / d , and thus different phase velocities . v ,n / kz,n we assume the n=0 spatial harmonic is synchronous with the relativistic particle motion, or / kz,0 c For a particle located at a phase with respect to maximum acceleration, we have Ez E0Im an e i (2k0 nz n ) n q dEz F 2 dz 0 qE0 Im ik0 nan e i (2k0 nz n ) n If the energy variation is ignorably small over a period, then one may proceed to find the secular radial equation of motion by averaging the lowest order oscillatory motion given by the previous equation over a structure period. osc F sec 2m0 c 2 qE i (2k0 nz n ) 0 sec Im ik na e 0 n m0 c 2 n witch has a steady-state solution osc qE0 an i (2k0 nz n ) sec 1 Im e 2 ik0 n 4 m c 0 n Substitution of the value of osc and averaging, we have sec F 2m0 c 2 1 qE0 sec 2 8 m0 c 2 2 a n2 a n 2a n an sin(2 ) n1 This radial focusing force, like that derived from the solenoid provides equal focusing in both x and y, which is second order in applied field strength . In the case of the solenoid, the net radial force is second order due to the accompanying rotation, while in the present case it is of second order because of the fast radial oscillatory motion due to alternating gradient focusing ( ) 2 an2 an 2an an sin(2 ) n1 represents a sum over all spatial harmonics that contribute to the alternating gradient force, and is equal to 1 for a pure harmonic standingwave. Note that the synchronous harmonic (n=0) does not contribute to the first or second order force in the ultrarelativistic limit, so that =0 for a pure forward traveling wave (ao=1, all other an vanishing). the alternating gradient focusing effect arises from the existence of non-synchronous spatial harmonics Because we have kept the energy constant, we have not kept the effects of adiabatic damping in the equation of motion. Acceleration can be taken into account by use of the damping term. Because the focusing is symmetric, the resulting equations of motion in x, y and are all equivalent, and are of the form 2 x x x 0 2 8 sin