# Download mosfet based boost converter

Spark-gap transmitter wikipedia , lookup

Power engineering wikipedia , lookup

Mercury-arc valve wikipedia , lookup

Stepper motor wikipedia , lookup

Pulse-width modulation wikipedia , lookup

Power inverter wikipedia , lookup

History of electric power transmission wikipedia , lookup

Electrical ballast wikipedia , lookup

Three-phase electric power wikipedia , lookup

Electrical substation wikipedia , lookup

Resistive opto-isolator wikipedia , lookup

Variable-frequency drive wikipedia , lookup

Integrating ADC wikipedia , lookup

Stray voltage wikipedia , lookup

Schmitt trigger wikipedia , lookup

Current source wikipedia , lookup

Surge protector wikipedia , lookup

Voltage optimisation wikipedia , lookup

Voltage regulator wikipedia , lookup

Power electronics wikipedia , lookup

Mains electricity wikipedia , lookup

Alternating current wikipedia , lookup

Current mirror wikipedia , lookup

Switched-mode power supply wikipedia , lookup

MOSFET BASED BOOST CONVERTER AIM To design the boost converter and evaluate the performance. PRINCIPLE Boost converter A Boost DC-DC converter is essentially a step up chopper for which the average output voltage is higher than the input voltage. Hence the name is boost. The circuit operation can be divided into 2 modes Mode 1 begins when MOSFET is switched on at t=0. The input current, which rises flows through filter inductor L, and switch. Mode 2 begins when the MOSFET is switched off at t=t1. The current that was flowing through the switch through L,C, load and diode Dm. The inductor current falls initial MOSFET turned on the next cycle . The energy stored in inductor L is transferred to the load . CIRCUIT DIAGRAM OBSERVATIONS SL NO DUTY RATIO OUTPUT VOLTAGE VOLTAGE AND CURRENT WAVE FORM PROCEDURE 1. Simulated the given circuit diagram using Matlab simulink. 2. Observe and record the load voltage and load current. DESIGN Given: Vs , input voltage = 5V Va, Required output voltage = 15V Average load current, Ia = 0.5A Frequency = 25kHz ∆I = 0.89A & ∆Vc = 60.61mV R = Va/Ia = 15/0.5 = 30Ω Va = Vs/(1-k) or k = 2/3 = 0.6667 L = [Vs*(Va-Vs)]/[f*Va*∆I] = 150µH. C = Ia*k/f*∆Vc = 220µF RESULT The boost converter is designed and evaluated its performance.