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Transcript
Physics 30 Unit 2 Review Electrical Forces and Fields Electrical Forces & Fields Electrostatics: Law of Charges: repel and unlike charges Like charges _______ attract __________. Movement of Charges: electrons move within insulators Only _________ and conductors. Grounding: earth is both an unlimited The _______ electrons depository or source of ___________. end Charging by Friction: insulators together will Rubbing two ___________ force the movement of electrons ________ from one object into the other. Charging by Conduction: Touching two charged objects will cause transfer of charge. a ___________ Charging by Induction: charge separation Causing a ____________ ____within an touching it. object without ___________ end Examples: There are three equal sized spheres. Sphere A has a charge of +2.0 mC, sphere B has a charge of -4.0 mC, and sphere C has a charge of +8.0 mC. If sphere C touches A, then touches B, what are the charges on all spheres? A 2.0 B -4.0 A 5.0 B 0.5 A 5.0 B 0.5 C 8.0 C 5.0 C 0.5 C 0.5 end Examples: Explain how to charge an electroscope negatively through induction. You have a rod that when rubbed with fur becomes positively charged. •Ground the top of the electroscope. •Rub the rod with fur so it becomes positively charged through friction. •Bring a positively charged object near the electroscope but do not touch it. •Since opposite charges attract (law of charges), negative electrons will flow from the ground into the electroscope. •Disconnect the ground wire. •Remove the positively charged object. •The electroscope is now negatively charged. end Electric Field: •Is the direction a small, __________ positive test charge will travel when placed in the field. Drawing Electric Fields: - + end Drawing Electric Fields around charged objects: end end end ? + end Drawing Electric Fields between charged plates: - + Electric field is constant between the plates so long as the distance between them doesn’t change. zero Electric Fields inside a spherical conductor is _______________ end Charges flow along the outside of a conductor. − − − − − − − − If there’s an imperfection along the surface of the sphere, that more location will have ______________ charge. −− − −− − − − − − − end Electric Field Formulas: E •Electric Field has this notation: _______________ •Energy has this notation: _______________ E •Do not use +/- notation in formulas. Use the direction of a small ____________ test charge to find direction. positive Electric field a distance from a charged object. Units of N/C Electric field is used to find the force a charged object experiences when placed in the electric field. Units of N/C Electric field between electric plates. Units of N/C or V/m end Examples: Calculate the electric field 2.55 x 10-3 m away from a 3.82 mC object. (8.99x109)(3.82x10-6C) = = 5.28x109 N/C -3 2 (2.55x10 ) If a 1.12 mC charged sphere is brought to a distance of 2.55 x 10-3 m away from the object in the last question, what electrical force does it experience? = (5.28x109)(1.12x10-6C) = 5.92x103 N If the 1.12 mC charged sphere has a mass of 3.00 g, what acceleration will it experience in the electric field? = 5.92x103 N 3.00x10-3 kg = 1.97x106 m/s2 end Examples: Calculate the electric field between the plates below. Draw the direction of the electric field as well. + 9 V separated by 2.50 cm If an electron is placed in between the plates, what electrical force does it experience? What is the direction of this force? The direction is up towards the positive plate. end Examples: Calculate the electric field midpoint between two point charges of 4.00 mC and 3.25 mC that are 6.84 x 10-1 m apart. 4.0 3.25 0.342 m 0.342 m The electric fields point in opposite directions so subtract. to the right end Examples: Calculate the electric field at point “p” +1.66 mC 3.00 cm -2.82 mC p 4.00 cm end +1.66 mC 3.00 cm -2.82 mC p 4.00 cm Combine the electric fields using pythagorean theorem. end E of S end Electrical Energy: •Electric charges have electrical ____________ potential energy when placed objects or between __________ charged plates. near other charged _________ •Electric potential is also referred to as __________. voltage •Unlike electric field, the ___________ voltage experienced by a charge does change as it moves between electric plates. end Potential Difference: There is 100 V between the plates. What is the potential difference experienced by the positive particle in locations 1, 2, 3 and 4? + plate 4 100 V 3 75 V 2 50 V + 1 0V - plate end Potential Difference: There is 100 V between the plates. What is the potential difference experienced by the negative particle in locations 1, 2, and 3? + plate 3 0V 2 25 V - 1 100 V - plate end Examples: A proton is moved through two parallel plates that are 5.00 cm apart and have a potential difference of 90.0 V between them. How much work is done against the electric field when the proton moves 3.00 cm parallel to the plates? + The proton is not moved through a potential difference. + - No work is done against the electric field. What other force could be present to ‘make’ the electron follow a straight path between the plates? A magnetic force. What direction would the field need to be oriented in? end Examples: A proton is moved through two parallel plates that are 5.00 cm apart and have a potential difference of 90.0 V between them. How much work is done against the field when the proton moves 3.00 cm towards the positive plate? + 3.00 cm + - Method 1 The proton is moved through 3/5 of the potential difference. V=(3/5) (90.0 V) = 54 V end + 3.00 cm + Method 2 The electric field is constant between the plates. - end 1.50x103 V + 3.50x103 V Calculate the electric potential difference gained by the moving charge. Though the electric field remains constant, the charged object does experience a change in voltage. end Calculate the speed of the 3.00x10-12 C and 4.00x10-15 kg charge as it reaches the opposite plate if it started from rest.. 3.50x103 V end Examples: Calculate the vertical displacement of the electron as it travels between the plates if the plates are 9.00 cm long. + 7.00 X 106 m/s e- 9.00 cm 90 V separated by 6.50 cm - end + 7.00 X 106 m/s e- 9.00 cm Horizontally Vertically 0 end Examples: How many electrons travel through a wire in 0.100 s if the current is 3.00 A ? end Coulomb’s Law: Coulomb used a __________ torsion balance to measure the electric forces acting on between charged spheres so he could derive the following formula: His apparatus looked like: end Cavendish: Cavendish used a __________ torsion balance to measure the gravitational forces acting on between charged spheres so he could derive the following formula (this was done before Coulomb’s exp): His apparatus looked like: end Examples: What is the electric force between two charges of 5.00 mC and 3.00 mC if they are separated by 2.00 cm? end Examples: How far apart are two point charges of 2.00 𝜇C and 4.00 𝜇C if they produce an electric force of 5.00 x 10-1 N on each other? = (8.99𝑥109 )(2𝑥10−6 )(4𝑥10−6 ) 0.5 = 3.79 m end Examples: Two point charges produce an electric force of 6.00 x 10-2 N. What will be the force between them if their charges are tripled and the distance between them halved? end Examples: Find the net electric force on the middle sphere. -2.00 mC 3.00 mC 4.00 cm 4.00 cm (8.99𝑥109 )(2𝑥10−6 )(3𝑥10−6 ) = 3.00 mC (0.04)2 = 33.7 𝑁 (8.99𝑥109 )(2𝑥10−6 )(3𝑥10−6 ) = (0.04)2 50.6 84.3 𝑁 end Examples: Two equally charged, identical spheres are 0.100 m apart and have an electric force of 4.00 x 10-2 N between them. What is the magnitude of the charge on each sphere? end Examples: Find the net electric force on the middle sphere. -2.00 mC 3.00 mC (8.99𝑥109 )(3𝑥10−6 )(3𝑥10−6 ) = (0.04)2 4.00 cm 4.00 cm 50.6 𝑁 3.00 mC (8.99𝑥109 )(2𝑥10−6 )(3𝑥10−6 ) = (0.04)2 33.7 𝑁 end Use pythagorean theorem to combine the forces. 33.7 𝑁 50.6 𝑡𝑎𝑛 −1 33.7125 50.56875 33.7 = (33.7)2 +(50.6)2 60.8 𝑁 60.8 𝑁 𝑎𝑡 33.7° 𝑊 𝑜𝑓 𝑁 end