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7.9.1ElectricPotentialEnergy Achargedobjectinanelectricfieldhaspotentialenergy.Potentialenergyisa scalarquantity.Ifwemoveapositivelychargedobjecttowardsanother positivelychargedobject,theyrepel.Workisdoneinbringingonecharge towardsanother.Theworkthatisdoneisstoredaselectricpotentialenergy.The potentialenergyisdefinedtobezerowhentheobjectsareinfinitelyfarapart andincreasinglypositiveastheyarebroughttogether. Letusconsidertwopointpositivecharges: ThefirstpointpositivechargeQcreatesaradialelectric fieldEwhichvariesaccordingtotheexpressionwesaw inthepreviousunit(7.8): 1 𝑄 𝐸 = + 4𝜋𝜀' 𝑟 * F Thesecondpointpositivecharge𝑞,feelsarepulsiveforceFinthisfield: 1 𝑄𝑞 𝐹 = 𝑞𝐸 = 4𝜋𝜀' 𝑟 * Lookawaynowifyoudon’tliketrickymaths!Note:notinsyllabus. < < 9 34 9 34 workdone=forcexdistance=∫: 𝐹𝑑𝑟 = 567 ∫: : ; 𝑑𝑟 = 567 : 8 8 So,thepotentialenergy(𝐸-./ )of𝑞atadistancerfromQisgivenby: 1 𝑄𝑞 𝐸-./ = 4𝜋𝜀' 𝑟 !Calculatetheelectricpotentialenergyofapointchargeq=+3.0Catadistanceof 0.4mfromapointchargeQ=+10.0C. Unlikegravitationalpotentialenergy,whichisnegativeeverywhere,electrical potentialenergycanbepositiveornegative.Anegativepotentialenergyoccurs forunlikecharges. !Calculatetheelectricpotentialenergyofapointchargeq=-1.0Catadistanceof 0.2mfromapointchargeQ=+5.0C. ©2016flippedaroundphysics.com Electricpotentialenergyisadditive.Thismeansthatwhenwehavemorethan onechargeproducingelectricfields,youjustnumericallyaddtogetherthe differentcontributions. Considerthefollowingsituation: Ifwewanttoworkoutthe d1 potentialenergyofqlocated + q + Q1 atadistanced1fromQ1and distanced2fromQ2,wejust workouttheindividual d2 contributionsandaddthem together.Note,thatQ2isa negativecharge,sowill Q2 - produceanegativepotential energy. !Calculatetheelectricpotentialenergyforachargeq=+2.0Cinthediagram above,whereQ1=+5.0C,Q2=-10C,d1=10cm,d2=8cm. ©2016flippedaroundphysics.com