* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
Download Short circuit test
Electromagnetic compatibility wikipedia , lookup
Printed circuit board wikipedia , lookup
Electrical ballast wikipedia , lookup
Ground (electricity) wikipedia , lookup
Portable appliance testing wikipedia , lookup
Three-phase electric power wikipedia , lookup
Fault tolerance wikipedia , lookup
Resistive opto-isolator wikipedia , lookup
History of electric power transmission wikipedia , lookup
Regenerative circuit wikipedia , lookup
Current source wikipedia , lookup
Opto-isolator wikipedia , lookup
Automatic test equipment wikipedia , lookup
Electrical substation wikipedia , lookup
Stray voltage wikipedia , lookup
Transformer wikipedia , lookup
Voltage optimisation wikipedia , lookup
Surge protector wikipedia , lookup
Circuit breaker wikipedia , lookup
Switched-mode power supply wikipedia , lookup
Buck converter wikipedia , lookup
Earthing system wikipedia , lookup
Mains electricity wikipedia , lookup
Alternating current wikipedia , lookup
RLC circuit wikipedia , lookup
Objective: objective of this experiment is to study the equivalent circuit of transformer. And determine the transformer parameter by short circuit and open circuit test. The purpose of this two types of test is to determine the magnetizing reactance, equivalent core loss resistance and equivalent impedance of transformer. Circuit Diagram: Fig:01 Short circuit test of transformer. Fig: open circuit test of transformer. Data: For open circuit test: πππΆ 56V πΌπ .05A πππ 3W πΌππ .053A π ππ ππ 1054.34β¦ 3200β¦ πΌπ 0.017A For short circuit test: ππ πΌππΆ .01A 18V πππΆ 1.5W πππ,1β2 2000β¦ π ππ,12 15000β¦ πππ1β2 J14866 Ans the post lab report question no 01 Here , equivalent parameter for High side ππ π =18V, πΌππΆ =.01A πππΆ =1.5w Now ππππ»π = πππΆ π πππ»π = =1800, πΌππΆ πππΆ πΌπ π 2 =15000 ππππ»π =β(π πππ»π 2 +ππππ»π 2 )=14866 ππππ»π 1800β¦ π πππ»π 15000β¦ ππππ»π 14866β¦ Here, equivalent parameter for Low side πππΆ =56V πΌπ =0.05A πππ =3W πΌππ = πππ πππΆ =0.05357A πππΆ π ππ = πΌππ =1045.33 πΌπ =β(πΌπ 2 +πΌππ 2 )=0.0175 ππ,πΏπ = πππΆ πΌπ =3200 π ππ,πΏπ 1045.33β¦ ππ,πΏπ 3200β¦ Ans the question no 02 Open circuit test: the no load is connected to the secondary, the copper loss in the secondary are Zero. Copper loss in the primary are negligible. Thus the wattmeter reading is core loss. Short circuit test: In short circuit test, voltage is low but the current is standard. So the only losses are due to resistance of conductor. In short circuit the secondary causes the flux density to be reduce to a very low value, making the core loss insignificant. Thus the wattmeter reading in short circuit test is copper loss. Ans the question no 03 π¬β²π³π π°π³πΊ πΏπππ³π π½π³πΊ αΆΏ πΌπΏπ π πππΏπ π°π³πΊ Fig: 01 inductive load ILS ILS XeqLs πΌπΏπ π πππΏπ VLS Fig: 02 capacitive load ILS XeqLs αΆΏ VLS Fig:03 resistive load πΌπΏπ π πππΏπ Ans the question no o4 Why low tension side is short circuit: In short circuit test the test is performed at rated current. As the rated current on high voltage side is much more then less than low voltage side. So this the rated high voltage side current is easily achieved. Another we cannot perform short circuit on high voltage side, because the high voltage side essentially falls to zero and since KVA power=constant, so high voltage side current will be very high and can burn the winding. Also short circuit test can perform other side when rating is very small. Ans the question no 05 Modification in short circuit test: The test is conducted on the high-voltage (HV) side of the transformer where the low-voltage (LV) side or the secondary is short circuited. The supply voltage required to circulate rated current through the transformer is usually very small and is of the order of a few percent of the nominal voltage and this 5% voltage is applied across primary. The core losses are very small because applied voltage is only a few percentage of the nominal voltage and hence can be neglected. Thus the wattmeter reading measures only the full load copper loss Disscussion: In short circuit test the equivalent inpedence gives negative value Conclusion: after performing this experiment we know how to perform transformer test for open and short circuit test. Also know the transformer parameter can be obtain by short circuit and open circuit test. Know why short circuit test perform on high voltage side. DEPARTMENT OF ELECTRICAL AND ELECTRONIC ENGINEERING LAB REPORT Course Code : EEE 301 Experiment No : 02 Experiment Name : Determination of equivalent circuit parameter of a transformer. Performed date: 28/02/2015 Student Name: MD. Samiul Islam Submitted date: 04/03/2015 Student ID : 2013-1-80-014 Group : 04 Group members ID: 2013-1-80-011 2013-1-80-013 2012-3-80-040 2013-1-80-016