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Objective: objective of this experiment is to study the equivalent circuit of transformer. And determine the transformer parameter by short circuit and open circuit test. The purpose of this two types of test is to determine the magnetizing reactance, equivalent core loss resistance and equivalent impedance of transformer. Circuit Diagram: Fig:01 Short circuit test of transformer. Fig: open circuit test of transformer. Data: For open circuit test: 𝑉𝑂𝐶 56V 𝐼𝑜 .05A 𝑃𝑜𝑐 3W 𝐼𝑓𝑒 .053A 𝑅𝑓𝑒 𝑋𝑀 1054.34Ω 3200Ω 𝐼𝑚 0.017A For short circuit test: 𝑉𝑇 𝐼𝑆𝐶 .01A 18V 𝑃𝑆𝐶 1.5W 𝑍𝑒𝑞,1−2 2000Ω 𝑅𝑒𝑞,12 15000Ω 𝑋𝑒𝑞1−2 J14866 Ans the post lab report question no 01 Here , equivalent parameter for High side 𝑉𝑠𝑐 =18V, 𝐼𝑆𝐶 =.01A 𝑃𝑆𝐶 =1.5w Now 𝑍𝑒𝑞𝐻𝑆 = 𝑉𝑂𝐶 𝑅𝑒𝑞𝐻𝑆 = =1800, 𝐼𝑆𝐶 𝑃𝑆𝐶 𝐼𝑠𝑐 2 =15000 𝑋𝑒𝑞𝐻𝑆 =√(𝑅𝑒𝑞𝐻𝑆 2 +𝑍𝑒𝑞𝐻𝑆 2 )=14866 𝑍𝑒𝑞𝐻𝑆 1800Ω 𝑅𝑒𝑞𝐻𝑆 15000Ω 𝑋𝑒𝑞𝐻𝑆 14866Ω Here, equivalent parameter for Low side 𝑉𝑂𝐶 =56V 𝐼𝑜 =0.05A 𝑃𝑜𝑐 =3W 𝐼𝑓𝑒 = 𝑃𝑜𝑐 𝑉𝑂𝐶 =0.05357A 𝑉𝑂𝐶 𝑅𝑓𝑒 = 𝐼𝑓𝑒 =1045.33 𝐼𝑀 =√(𝐼𝑜 2 +𝐼𝑓𝑒 2 )=0.0175 𝑋𝑚,𝐿𝑆 = 𝑉𝑂𝐶 𝐼𝑀 =3200 𝑅𝑓𝑒,𝐿𝑆 1045.33Ω 𝑋𝑚,𝐿𝑆 3200Ω Ans the question no 02 Open circuit test: the no load is connected to the secondary, the copper loss in the secondary are Zero. Copper loss in the primary are negligible. Thus the wattmeter reading is core loss. Short circuit test: In short circuit test, voltage is low but the current is standard. So the only losses are due to resistance of conductor. In short circuit the secondary causes the flux density to be reduce to a very low value, making the core loss insignificant. Thus the wattmeter reading in short circuit test is copper loss. Ans the question no 03 𝑬′𝑳𝒔 𝑰𝑳𝑺 𝑿𝒆𝒒𝑳𝒔 𝑽𝑳𝑺 ᶿ 𝐼𝐿𝑆 𝑅𝑒𝑞𝐿𝑆 𝑰𝑳𝑺 Fig: 01 inductive load ILS ILS XeqLs 𝐼𝐿𝑆 𝑅𝑒𝑞𝐿𝑆 VLS Fig: 02 capacitive load ILS XeqLs ᶿ VLS Fig:03 resistive load 𝐼𝐿𝑆 𝑅𝑒𝑞𝐿𝑆 Ans the question no o4 Why low tension side is short circuit: In short circuit test the test is performed at rated current. As the rated current on high voltage side is much more then less than low voltage side. So this the rated high voltage side current is easily achieved. Another we cannot perform short circuit on high voltage side, because the high voltage side essentially falls to zero and since KVA power=constant, so high voltage side current will be very high and can burn the winding. Also short circuit test can perform other side when rating is very small. Ans the question no 05 Modification in short circuit test: The test is conducted on the high-voltage (HV) side of the transformer where the low-voltage (LV) side or the secondary is short circuited. The supply voltage required to circulate rated current through the transformer is usually very small and is of the order of a few percent of the nominal voltage and this 5% voltage is applied across primary. The core losses are very small because applied voltage is only a few percentage of the nominal voltage and hence can be neglected. Thus the wattmeter reading measures only the full load copper loss Disscussion: In short circuit test the equivalent inpedence gives negative value Conclusion: after performing this experiment we know how to perform transformer test for open and short circuit test. Also know the transformer parameter can be obtain by short circuit and open circuit test. Know why short circuit test perform on high voltage side. DEPARTMENT OF ELECTRICAL AND ELECTRONIC ENGINEERING LAB REPORT Course Code : EEE 301 Experiment No : 02 Experiment Name : Determination of equivalent circuit parameter of a transformer. Performed date: 28/02/2015 Student Name: MD. Samiul Islam Submitted date: 04/03/2015 Student ID : 2013-1-80-014 Group : 04 Group members ID: 2013-1-80-011 2013-1-80-013 2012-3-80-040 2013-1-80-016