Download MAGNETISM 1. An electric charge experiences a magnetic force

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MAGNETISM

A magnetic field is a vector field that permeates space and which can exert a magnetic force on moving
electric charges and on magnetic dipoles.
We define the magnitude of the magnetic field by measuring the magnetic force on a moving cha rge q:
B=
1 T(Tesla) =
Direction at any location is the direction in which the north pole of the compass needl e points at that location.
Outside magnet: N → S
Inside magnet: S → N
(always closed loops)
1. An electric charge experiences a magnetic force when moving in a magnetic field.
Magnetic force acting on a charge q
Magnetic force on a wire carrying current I
in a magnetic Field B: F = qvB sinin a magnetic field B: F = I LB sin
 

q = charge [C]
v = velocity [m/s]
B = magnetic field [Tesla T]
 = angle between v and B
I = current [A]
L = length [m]
B = magnetic field [T]
 = angle between I and B
R-H-R 1: The direction of the magnetic force on a charge/current is given by the right-hand rule 1:
Outstretch fingers in the direction of v (or current I).
Curl fingers as if rotating vector v (I ) into vector B.
Magnetic force on a positive charge (or I) is in
the direction of the thumb.
Magnetic force on a negative charge points in opposite direction.

Charge q in elec. field E and mag. field B
The electric force: Felec = Eq
The magnetic force: Fmag = qvB sin
● is always parallel to the direction of the
● is always perpendicular to the direction of the
electric field.
● acts on a charged particle independent of the
particle’s velocity (even at rest).
● does the work when moving charge.
The work, W = Fel d cos θ1 , is converted into kinetic
energy which is, in the case of conductors,
transferred to thermal energy through collisions
with the lattice ions causing increased amplitude
of vibrations seen as temperature rise.
magnetic field
● acts on a charged particle only when the particle is in motion
and only if v and B do not point in the same or opposite
direction (sin 0 0 = sin 180 0 = 0).
● Force is perpendicular to the direction of the motion,
so the work done by magnetic force is zero.
W = Fmag d cos θ1 = 0 (cos 90 0 = 0).
W = ΔKE = 0
Hence change in kinetic energy of the charge is 0,
and that means that mag. force cannot change
the speed of the charge. Magnetic force can only
change direction of the velocity – therefore it acts
as centripetal force.
θ 1 is angle between F and direction of motion
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Examples of the Lorentz Force
Two important applications of the Lorentz force are
1)
the trajectory of a charged particle in a uniform magnetic field and
2) the force on a current-carrying conductor.
1) The trajectory of a charge q in a uniform magnetic field B
●
●
●
●
Force is perpendicular to B,v
Magnetic force does no work! (W = F d cos θ1 = 0 )
Speed is constant (W = Δ KE = 0 )
Circular motion
Centripetal force definition:
Motion in a circle represents accelerated motion, and requires a force directed toward the center of the
circle.
This force is called the centripetal force which means "center seeking" force.
It is forcing mass m to move in the circle of radius R with the speed v .
Centripetal force force has the magnitude
Charged particle in a magnetic field when v  B:
In the case the charge q is subject to the uniform field B, centripetal force F c
is magnetic force forcing the charge to move in a circle:
● massive or fast charges – large circles
● large charges and/or large B – small circles
Positive charge q
in magnetic field B
B = magnetic field [T]
is represented by the crosses – into the page
R =is the radius of the path
F is magnetic force on the charge directed
toward the centre of the circular path
m = mass [kg]
v = velocity [m/s]
q = charge [C]
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APPLICATION: A mass spectrometer – the path shown is for positive ions
Step 0 – if we want to find a mass of molecules
or atoms we have to ionize them first.
Step 1 – Acceleration through potential difference ΔV
ΔU = q ΔV = ½ mv2
v=
tep 2 - the velocity selector – Crossed fields
The ions emerge from the acceleration stage with a range of speeds (different masses – different accelerations).
Velocity selector/crossed fields is designed to allow ions of only a par ticular velocity to pass through undeflected.
Two forces are acting on the charge q
Felec = qE and Fmag = qvB
if qvB = qE the charge moves through crossed fields undeflected
so only ions with speed v = E/B are undeflected and will move in the straight line
Step 3 - mass separation
All these ions, with the same charge and velocity, enter the mass separation stage - a region
with a uniform magnetic field. Magnetic field will force the ion entering it with velocity
perpendicular to it, to travel in a circular path. The only thing different for these particles
is the mass, so the heavier ions travel in a circular path of larger radius than the lighter ones.
Charged particle in a magnetic field when v
qvB 
R
mv 2
R
 B:
massive or fast charges – large circles
large charges and/or large B – small circles
mv
qB
2. A moving charge produces a magnetic field.
R-H-R 2: The direction of the magnetic field produced by electric current is given by the right-hand rule 2:
If a wire is grasped in the right hand with the thumb in the direction of current flow, the fingers will curl in the
direction of the magnetic field.
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Magnetic field B around a wire with current I
Magnetic Field B Inside of a Solenoid
B = 0 n I
B=
= the permeability of free space 4×10 -7 T·m/A
I = current [A]
r = distance from the center of the conductor
n = N/L number of turns of wire per unit length
The magnetic field is concentrated
into a nearly uniform field in the
centre of a long solenoid. The field
outside is weak and diverging
Magnetic Force per unit length between Two Parallel Wires:
Current I1 creates magnetic field B1
at distance d from the wire
B1 =
F1 F2  0 I 1 I 2


L
L 2 d
Place a wire with current I2
at distance d from I1
The force on I2 is:
F2 = L I2 B1 = L I2
F2 = L
(a) two parallel currents
– the force between them is attractive
(b) two antiparallel curren ts
– the force between them is repulsive
One Ampere is defined as that current flowing in each of two infinitely-long parallel wires of negligible
cross-sectional area separated by a distance of one metre in a vacuum that results in a
force of exactly 2 x 10-7 N per metre of length of each wire.
Electricity can be produced from many different types of energy, and all of these methods make
use of a generator to convert mechanical energy to electrical energy.
Electrical generator
Electrical energy is usually produced by rotating coil in a uniform magnetic field.
Free electrons in a wire will experience magnetic force if the wire moves in a magnetic field; the
electrons inside it experience a force causing them to move to one end of the wire. This causes a
potential difference along the wire which can be used to create current in a circuit. We say that current
has been induced in the wire.
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A generator uses the same principle, but instead of the wire moving in a straight line, a coil rotates in
the magnetic field. As the coil rotates, resulting in a current that keeps changing direction, called an
alternating current or AC for short. To prevent the wires from getting twisted when the coil rotates,
there must be sliding contacts between the coil and circuit. However, friction between these sliding
components will eventually wear away the contacts. An alternative arrangement is for the magnets to
rotate inside the coils, this also results in an alternating current but has no sliding parts
Electric Motor
You find it everywhere: turntables, washing machined, any fan, air conditioners, wherever something is
moving there is an electric motor. There are many coils of wires, but b/c of simplicity we drew only one.
Each end of the coil is attached to a metallic half-ring. Rubbing against each of the half-rings is a graphite
contact called a brush. Half–rings rotate with the coil; the graphite brushes remain stationary.
Left picture: the current from the battery enters the coil through the left brush, goes around the coil,
and leaves through the right half-ring and brush. Forces on two vertical sides result in rotation (turning)
of the coil. The coil rotates until it riches the position shown in the middle picture. In this position t he
half rings momentarily lose electrical contact with the brushes: no current – no force, no ability of the
force to cause rotation (so called torque). But, b/c of its rotational inertia (moving object does not stop
momentarily) the coil continues to rotate, and half-rings reestablish contact with the brushes. So there
is again current in the coil, but now in opposite direction (the side that had current upwards, now has
current downwards b/c it is connected to different terminal). The split ring ensures that the current is
always in the proper direction such that the torque produces a continuous rotation of the coil.
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PRACTICE MAGNETISM 1
1.
Where is the magnitude of the magnetic field a round a permanent magnet greatest?
a . cl os e to the poles
b. fa r from the poles
c. The ma gnitude is equal a t all points on the fi eld.
d. The ma gnitude depends on the ma terial of the magnet.
2.
Whi ch compass needle orientation in the figure might
correctl y describe the magnet’s field at that point?
a. a
b. b
c.
c
d.
d
3.
If a proton i s released at the equator and falls toward Ea rth under the influence of gra vity, the magnetic force on the proton
wi l l be toward the
a . north.
b. s outh.
c. ea st.
d. wes t.
4.
Wha t i s the path of an electron moving perpendicular to a uniform magnetic field?
a . a s tra ight line
b. a ci rcl e
c. a n ellipse
d.
a pa rabola
Wha t i s the path of an electron moving parallel to a uniform magnetic field?
a . s tra ight l ine
b. ci rcl e
c. el lipse
d.
pa ra bola
5.
6.
A proton moves past a bar magnet as shown. Find the direction of the force it experiences i n each case.
7.
An el ectron is movi ng with a s peed of 3.0 x10 5 ms -1 i n a direction that is at ri ght a ngles to a uniform magnetic field of 3.0 x 10 -3
T. Ca l culate
a . the force exerted on the electron.
b. the ra dius of the path of the electron.
9. The ma gnetic field of a bar magnet is s hown i n the figure.
Is the magnet’s north pole at A or B?
10.
Fi nd the direction of the force on a n proton moving through the magnetic field shown .
11.Fi nd the direction of the force on an proton moving through the magnetic field s hown .
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12.
Fi nd the direction of the force on a n electron moving through the magnetic field s hown .
13.
Fi nd the direction of the force on a n electron moving through the magnetic field s hown .
14.
Fi nd the direction of the force on a n electron moving through the magnetic field s hown .
15.
A negative charge is moving through a magnetic field. The direction of motion a nd the direction of the force acting on i t at one
moment are s hown i n the figure. Find the direction of the magnetic field.
16. A negative charge is moving through a magnetic field. The direction of motion a nd the direction
of the force acting on i t at one moment are shown in the figure. Find the direction of
the ma gnetic field.
17.
A negative charge is moving through a magnetic field. The direction of motion a nd the direction of the force
a cti ng on it a t one moment are s hown i n the figure. Find the direction of the magnetic field.
18.
An el ectron moves north a t a velocity of 9.8  104 m/s a nd has a magnetic force of 5.6  10–18 N exerted on i t. If the magnetic
fi eld points upward, what is the magnitud e of the magnetic field?
19.
An el ectron moves north a t a velocity of 2.7  104 m/s a nd has a magnetic force of 9.5  10–18 N exerted on i t. If the magnetic
fi eld points upward, what is the magnitude of the magnetic field?
20.
A cha rged particle i s injected into a region of uniform magnetic fi eld and travels i n a circular a rc.
If the particle were to be injected with a greater speed, wha t would be true of the ma gnetic force
on i t a nd the ra dius of its path?
A.
B.
C.
D.
Force
Arc radius
grea ter
grea ter
s ma ller
s ma ller
grea ter
s ma ller
grea ter
s ma ller
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12.
The di agram below shows a charged particle about to enter a region of uniform magnetic field directed into the page.
Whi ch of the following correctly describes the ch ange, if a ny, i n the kinetic energy a nd the momentum of the particle i n the
ma gnetic field?
Ki netic energy
Momentum
A.
Cha nged
Cha nged
B.
Cha nged
Uncha nged
C.
Uncha nged
Cha nged
D.
Uncha nged
Uncha nged
22.
23.
A cha rged particle of mass m and charge q i s travelling in a uniform magnetic field with s peed v s uch that the magnetic force on
the pa rticle is F. The magnetic force on a particle of mass 2m, cha rge q a nd s peed 2v tra velling in the same direction in the
ma gnetic field is
A. 4F.
B. 2F.
C. F.
D. ½ F.
The di agram show a straight wire ca rrying current i in a uniform magnetic fi eld. The magnetic force on the wire is indicated by
a n a rrow but the magnetic field is not shown. Of the following possibilities, the direction of the magnet ic field is:
24.
Wha t i s the direction of a magnetic field in each of the four cases tha t results in a force on the current as s hown?
25.
A wi re that is ca rrying a current of 3.50 A ea st has 2.00 m of i ts length i n a uniform ma gnetic f ield of magnetic flux density of
5.00 x 10-7 T di rected verti cally i nto the paper.
Determine the magnitude and direction of the force it experiences.
MAGNETISM PRACTICE II
1. A bar magnet is placed in a uniform magnetic field as shown.
(a) Is there a net force on the bar magnet?
(b) Will it move? If so, how?
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2. Find the direction of the missing quantity from B, v and F in each of the cases shown. The circle represents a
positive charge.
3. ( challange) Figure shows two parallel plates with a potential difference of 120 V a distance 5.0 cm apart. The top
plate is at the higher potential and the shaded region is a region of magnetic field norma l to the page.
(a) What should the magnetic field magnitude and direction be such that an electron experiences zero net force
when shot through the plates with a speed of 2 x 10 5 ms -1
(b) Would a proton shot with the same speed through the plates experience zero net force?
(c) If the electron’s speed were doubled, would it still be undeflected if the magnetic field took the value you found
in (a)?
4. A wire that is carrying a current of 3.50 A east has 2.00 m of its length in a uniform magnetic field of magnetic flux
density of 5.00 x 10 -7 T directed vertically into the paper.
Determine the magnitude and direction of the force it experiences.
5. An electron is moving with a speed of 3.0 x10 5 ms -1 in a direction that is at right angles to a uniform magnetic field
of 3.0 x 10 -3 T. Calculate
a. the force exerted on the electron.
b. the radius of the path of the electron.
8. An electron is shot along the axis of a solenoid that carries current. Will it experience a magnetic force?
9. Wha t i s the direction of the magnetic field a t points P a nd Q i n the plane of a ci rcular l oop
ca rryi ng a counterclockwise current, as s hown?
10. A suitable unit of magnetic field strength is
A. A N-1 m-1
B. kg s -2 A-1
C. A m N-1
D. kg A s 2
11. The diagram below shows a point P on the Earth’s surface at which a compass needle is suspended freely.
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Which one of the following gives the correct direction in which the needle of the compass will point?
14. (challange)
A proton i s in a region where a uniform electric field of 5 × 10 4 V/m i s perpendicular to a uniform magnetic field
of 0.8 T. If i ts a cceleration is zero then i ts s peed must be:
A)
B)
C)
D)
E)
15.
0
6.3 × 104 m/s
1.6 × 104 m/s
4.0 × 105 m/s
a ny va l ue but 0
A l ong wire that carries a current I i s bent into five l oops as s hown i n the figure.
If the observer could "see" the magnetic field inside this arra ngement of l oops, how would i t appear?
16. The currents in two parallel wires are I and 3I in the directions shown in the diagram below.
The magnetic force on wire 2 due to the current in wire 1 is F. The
magnitude of the force on wire 1 due to the current in wire 2 is
A.
B.
C.
D.
F/3.
F/2.
F.
3F.
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17. Current in a loop is counter clock wise. In which direction is induced
magnetic field inside the loop and outside the loop in the plane of paper.
18. Electrons are going around a circle in a counterclockwise direction as shown. At the center of the circle they
produce a magnetic field that is:
A)
B)
C)
D)
E)
into the page
out of the page
to the left
to the right
zero
19.A long straight wire carries current as shown. Two electrons move with velocities that are parallel and perpendicular
to the current. Find the direction of the magnetic force experienced by each electron.
21.
The diagram below shows three parallel wires P, Q and R that are
equally spaced.
The currents in the wires are each of the same magnitude I and are in the directions shown. The resultant force on
wire Q due to the current in wire P and in wire R is
A. perpendicular and into the plane of the paper.
B. perpendicular and out of the plane of the paper.
C. in the plane of the paper to the right.
D. in the plane of the paper to the left.
22. A long, straight current-carrying wire is placed normal to the plane of the page. The current in the wire is into the
plane of the page.
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Which of the following diagrams best represents the magnetic field around the wire?
23. Two long parallel straight wires carry equal currents in opposite directions. At a point midway between the
wires, the magnetic field they produce is:
A) zero
B) non-zero and along a line connecting the wires
C) non-zero and parallel to the wires
D) non-zero and perpendicular to the plane of the two wires
E) none of the above
24. Magnetic field lines inside the solenoid shown are:
A) clockwise circles as one looks down the axis from the top of the page
B) counterclockwise circles as one looks down the axis from the top of the page
C) toward the top of the page
D) toward the bottom of the page
E) in no direction since B = 0
19.
A wire, connected to a battery and switch, passes through the center of a long current-carrying solenoid
as shown in the drawing.
When the switch is closed and there is a current in the wire,
what happens to the portion of the wire that runs inside
of the solenoid?
A.
There is no effect on the wire.
B.
The wire is pushed downward.
C.
The wire is pushed upward.
D.
The wire is pushed into the plane of the paper.
E.
The wire is pushed out of the plane of the paper.