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Transcript
IGCSEFM Proof
Dr J Frost ([email protected])
Objectives: (from the specification)
Last modified: 22nd February 2016
Overview
From GCSE, you should remember that a β€˜proof’ is a sequence of justified steps,
sometimes used to prove a statement works in all possible cases.
Algebraic Proofs
Geometric Proofs
β€œProve that the sum of three
consecutive even numbers is a
multiple of 6.”
πŸπ’ + πŸπ’ + 𝟐 + πŸπ’ + πŸ’
= πŸ”π’ + πŸ”
= πŸ”(𝒏 + 𝟏)
which is a multiple of 6.
?
Recall that the key at the
end is to factorise out the 6.
Prove that 𝑦 = π‘₯
(We will need to recap
some circle theorems)
Algebraic Proof
Two common types of question:
Prove that the difference between the squares of two consecutive odd
numbers is a multiple of 8.
Let numbers be πŸπ’ βˆ’ 𝟏 and πŸπ’ + 𝟏.
𝟐
𝟐
πŸπ’ + 𝟏 βˆ’ πŸπ’ βˆ’ 𝟏
= πŸ’π’πŸ + πŸ’π’ + 𝟏 βˆ’ πŸ’π’πŸ βˆ’ πŸ’π’ + 𝟏
?
= πŸ’π’πŸ + πŸ’π’ + 𝟏 βˆ’ πŸ’π’πŸ + πŸ’π’ βˆ’ 𝟏
= πŸ–π’
which is divisible by 8.
We could have also used
2𝑛 + 1 and 2𝑛 + 3.
Prove that π‘₯ 2 βˆ’ 4π‘₯ + 7 > 0 for all π‘₯.
π’™πŸ βˆ’ πŸ’π’™ + πŸ•
= π’™βˆ’πŸ πŸβˆ’πŸ’+πŸ•
= π’™βˆ’πŸ 𝟐+πŸ‘
?
𝟐
Since 𝒙 βˆ’ 𝟐 β‰₯ 𝟎, thus 𝒙 βˆ’ 𝟐
𝟐
+πŸ‘>𝟎
Bro Hint: We know that
anything β€˜squared’ is at least 0.
Could we perhaps complete
the square?
Test Your Understanding
1 [Specimen2 Q12] 𝑛 is an integer.
Prove that 𝑛 βˆ’ 2 2 + 𝑛 8 βˆ’ 𝑛 is
always a multiple of 4.
π’πŸ βˆ’ πŸ’π’ + πŸ’ + πŸ–π’ βˆ’ π’πŸ
= πŸ’π’ + πŸ’ ?
= πŸ’(𝒏 + 𝟏)
2
3
[June 2013 P2 Q12] Prove that
5𝑛 + 3 𝑛 βˆ’ 1 + 𝑛(𝑛 + 2) is a
multiple of 3 for all integer values of 𝑛.
= πŸ“π’πŸ + πŸ‘π’ βˆ’ πŸ“π’ βˆ’ πŸ‘ + π’πŸ + πŸπ’
= πŸ”π’πŸ βˆ’ πŸ‘
?
= πŸ‘ πŸπ’πŸ βˆ’ 𝟏
[Jan 2013 P1 Q5] 𝑛 is a positive integer.
(a) Write down the next odd number
after 2𝑛 βˆ’ 1
πŸπ’ +?
𝟏
(b) Prove that the product of two
consecutive odd numbers is always
one less than a multiple of 4.
πŸπ’ βˆ’ 𝟏 πŸπ’ + 𝟏 = πŸ’π’πŸ βˆ’ 𝟏
? of 4.
πŸ’π’πŸ is a multiple
4
Prove that for all values of π‘₯,
π‘₯ 2 βˆ’ 6π‘₯ + 10 > 0
π’™πŸ βˆ’ πŸ”π’™ + 𝟏𝟎 = 𝒙 βˆ’ πŸ‘ 𝟐 + 𝟏
𝒙 βˆ’ πŸ‘ 𝟐 β‰₯ 𝟎 thus ?𝒙 βˆ’ πŸ‘ 𝟐 + 𝟏 > 𝟎
5
[Set 4 P1 Q16] Prove that, for all values of π‘₯,
2π‘₯ 2 βˆ’ 8π‘₯ + 9 > 0
πŸ—
𝟐
𝟐 𝒙 βˆ’ πŸ’π’™ +
𝟐
πŸ—
=𝟐 π’™βˆ’πŸ πŸβˆ’πŸ’+
𝟐
?𝟐 𝟏
=𝟐 π’™βˆ’πŸ +
𝟐
=𝟐 π’™βˆ’πŸ 𝟐+𝟏
𝒙 βˆ’ 𝟐 𝟐 β‰₯ 𝟎 therefore 𝟐 𝒙 βˆ’ 𝟐 𝟐 + 𝟏 > 𝟎
Identities
What values of π‘₯ make the following equality hold true?
π‘₯ is 2 or -2?
π‘₯2 = 4
π‘₯2 βˆ’ π‘₯ = π‘₯ π‘₯ βˆ’ 1
π‘₯ could be?anything!
! The identity 𝑓(π‘₯) ≑ 𝑔(π‘₯) means that 𝑓 π‘₯ = 𝑔(π‘₯) for all
values of π‘₯. e.g.
π‘₯2 βˆ’ π‘₯ ≑ π‘₯ π‘₯ βˆ’ 1
So π‘₯ 2 ≑ 4 would be wrong as
it is not true when say π‘₯ is 1.
When you have a quadratic/cubic/etc, all the coefficients must match to
guarantee both sides of the identity are equal for all 𝒙.
[Set 4 P1 Q2] In this identity, β„Ž and π‘˜ are integer constants.
4 β„Žπ‘₯ βˆ’ 1 βˆ’ 3 π‘₯ + β„Ž = 5 π‘₯ + π‘˜
Work out the values of β„Ž and π‘˜
πŸ’π’‰π’™ βˆ’ πŸ’ βˆ’ πŸ‘π’™ βˆ’ πŸ‘π’‰ = πŸ“π’™ + πŸ“π’Œ
Comparing 𝒙 terms:
πŸ’π’‰ βˆ’
?πŸ‘ = πŸ“ β†’ 𝒉 = 𝟐
Comparing constant terms: βˆ’πŸ’ βˆ’ πŸ‘π’‰ = πŸ“π’Œ β†’ π’Œ = βˆ’πŸ
Test Your Understanding
[Set 3 P1 Q2] 5 3π‘₯ βˆ’ 2 βˆ’ 3 π‘₯ βˆ’ β„Ž ≑ 4(π‘˜π‘₯ + 2)
Work out the values of β„Ž and π‘˜.
πŸπŸ“π’™ βˆ’ 𝟏𝟎 βˆ’ πŸ‘π’™ + πŸ‘π’‰ ≑ πŸ’π’Œπ’™ + πŸ–
πŸπŸπ’™ βˆ’ 𝟏𝟎 + πŸ‘π’‰ = πŸ’π’Œπ’™ + πŸ–
Comparing 𝒙 terms: 𝟏𝟐 = πŸ’π’Œ β†’ ?π’Œ = πŸ‘
Comparing constant terms: βˆ’πŸπŸŽ + πŸ‘π’‰ = πŸ– β†’ 𝒉 = πŸ”
AQA Worksheet (Algebraic Proof)
BONUS QUESTIONS:
1 Prove algebraically that the sum of two
consecutive odd numbers is divisible by 4.
πŸπ’ βˆ’ 𝟏 + πŸπ’ + 𝟏 = πŸ’π’ which is
divisible by 4.
3
?
?
2 [GCSE] I think of two consecutive integers.
Prove that the difference of the squares of
these integers is equal to the sum of the
two integers.
Two numbers are: 𝒙 and 𝒙 + 𝟏
Difference of squares:
𝒙 + 𝟏 𝟐 βˆ’ π’™πŸ = πŸπ’™ + 𝟏
Sum of numbers: 𝒙 + 𝒙 + 𝟏 = πŸπ’™ + 𝟏
These are equal.
?
Prove that the difference between two
consecutive cubes is one more than a
multiple of 6.
𝒏 + 𝟏 πŸ‘ βˆ’ π’πŸ‘
= π’πŸ‘ + πŸ‘π’πŸ + πŸ‘π’ + 𝟏 βˆ’ π’πŸ‘
= πŸ‘π’πŸ + πŸ‘π’ + 𝟏
= πŸ‘π’ 𝒏 + 𝟏 + 𝟏
The product of two consecutive
integers is even, thus πŸ‘π’(𝒏 + 𝟏) is
divisible by 6.
4
Prove that the product of four
consecutive numbers is one less than a
square number.
𝒂 𝒂+𝟏 𝒂+𝟐 𝒂+πŸ‘
= π’‚πŸ + 𝒂 π’‚πŸ + πŸ“π’‚ + πŸ”
= π’‚πŸ’ + πŸ”π’‚πŸ‘ + πŸπŸπ’‚πŸ + πŸ”π’‚ + 𝟏
?
= π’‚πŸ + πŸ‘π’‚ + 𝟏
𝟐
Geometric Proof
A recap of general angle theorems and Circle Theorems:
! Alternate angles
? are equal.
! Corresponding angles are equal.
? as β€˜F’ angles)
(Sometimes known
π‘Ž
π‘Ž + 𝑏 = 180°
𝑏
! Vertically opposite
? angles are equal.
! Cointerior angles
? sum to πŸπŸ–πŸŽ°.
RECAP :: Circle Theorems
Angle between radius
and tangent is 90°.
?
Opposite angles of cyclic
quadrilateral are equal.
?
Angle in semicircle is
90°
?
Angles in same
segment are equal.
Tangents from a point to a
circle are equal in length.
?
?
Angle at centre is twice
angle at circumference.
?
Alternate Segment
Theorem.
?
Form of a Geometric Proof
Set 1 Paper 1 Q8
! Write statements in the form:
∠𝐴𝐡𝐢 = π‘£π‘Žπ‘™π‘’π‘’ (π‘Ÿπ‘’π‘Žπ‘ π‘œπ‘›)
βˆ π‘‚πΆπ΅ = π‘₯ (base angles of isosceles
triangle are equal) ?
βˆ π΅π‘‚πΆ = 2π‘₯ (angle at centre is double
?
angle at circumference)
Angles in Δ𝑂𝐡𝐢 add to 180° ∴
π‘₯ + π‘₯ + 2π‘₯ = 180
?
4π‘₯ = 180
π‘₯ = 45
βˆ π΅π‘‚πΆ = 2π‘₯ = 90°
Test Your Understanding
Triangle 𝐴𝐡𝐢 is isosceles with 𝐴𝐢 = 𝐡𝐢.
Triangle 𝐢𝐷𝐸 is isosceles with 𝐢𝐷 = 𝐢𝐸.
𝐴𝐢𝐷 and 𝐷𝐸𝐹 are straight lines.
a) Prove that angle 𝐷𝐢𝐸 = 2π‘₯
∠π‘ͺ𝑩𝑨 = 𝒙 (base angles of isosceles triangle are
equal)
? in πš«π‘¨π‘©π‘ͺ add to 180)
βˆ π‘¨π‘ͺ𝑩 = πŸπŸ–πŸŽ βˆ’ πŸπ’™ (angles
βˆ π‘«π‘ͺ𝑬 = πŸπ’™ (angles on straight line add to 180)
b) Prove that 𝐷𝐹 is perpendicular to 𝐴𝐡.
πŸπŸ–πŸŽβˆ’πŸπ’™
βˆ π‘«π‘¬π‘ͺ = 𝟐 = πŸ—πŸŽ βˆ’ 𝒙 (base angles of isosceles
triangle are equal)
?
βˆ π‘«π‘­π‘¨ = πŸπŸ–πŸŽ βˆ’ πŸ—πŸŽ βˆ’ 𝒙 βˆ’ 𝒙 = πŸ—πŸŽ°
∴ 𝑫𝑭 is perpendicular to 𝑨𝑩.
Last Step
What do you think we would be the last step in your proof in each of these cases?
𝐷
Prove that 𝐴𝐡𝐢 is a straight line.
𝐢
…
βˆ π‘¨π‘©π‘« + βˆ π‘«π‘©π‘ͺ = πŸπŸ–πŸŽ
therefore 𝑨𝑩π‘ͺ is a straight?line.
𝐡
𝐴
Bro Tip: It’s a good
idea to finish by
stating the thing
you’re trying to prove.
𝐡
𝐢
𝐴
𝐷
𝐡
𝐴
𝐢
Prove that the line 𝐴𝐢 bisects ∠𝐡𝐴𝐷.
…
βˆ π‘©π‘¨π‘ͺ = ∠π‘ͺ𝑨𝑫 therefore 𝑨π‘ͺ bisects
?
βˆ π‘©π‘¨π‘«.
Prove that triangle 𝐴𝐡𝐢 is isosceles.
…
βˆ π‘©π‘¨π‘ͺ = βˆ π‘¨π‘ͺ𝑩 therefore
? πš«π€ππ‚ is isosceles.
Exercises
Question 1 [Set 4 Paper 1 Q4]
𝐴𝐡𝐢 is a right-angled triangle. Angle
𝐴𝐢𝐡 = π‘₯. Angle 𝐡𝐴𝐷 = 90 βˆ’ 2π‘₯.
Prove that 𝐴𝐢𝐷 is an isosceles triangle.
?
Question 2
𝐴𝐡𝐢𝐷 is a quadrilateral.
Prove that π‘₯ = 𝑦.
?
Question 3
𝐴𝐡 is parallel to 𝐢𝐷.
Is 𝑃𝑄 parallel to 𝑆𝑅? You must show your working.
?
Question 4
𝑃𝑄𝑅𝑆 is a cyclic quadrilateral. 𝑄𝑆 = 𝑄𝑅.
𝑉𝑆𝑇 is a tangent to the circle.
Work out the value of π‘₯. You must show
your working.
?
Question 5
𝐴, 𝐡, 𝐢 and 𝐷 are points on the circumference
of a circle such that 𝐡𝐷 is parallel to the
tangent to the circle at 𝐴.
Prove that 𝐴𝐢 bisects angle 𝐡𝐢𝐷. Give reasons
at each stage of your working.
?
Question 6
Prove that 𝐴𝐡 is parallel to 𝐷𝐢.
?
Question 7
𝐴𝐡𝐢 is a triangle. 𝑃 is a point on 𝐴𝐡 such that
𝐴𝑃 = 𝑃𝐢 = 𝐡𝐢. Angle 𝐡𝐴𝐢 = π‘₯.
a) Prove that angle 𝐴𝐡𝐢 = 2π‘₯.
b) You are also given that 𝐴𝐡 = 𝐴𝐢. Work out
the value of π‘₯.
?