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Electricity. Electrostatic The Electric Field Electric charge. Conductors and Insulators Coulomb´s Law The Electric field. Electric Field Lines Calculating Electric Field for continous charge distribution Gauss´s Law. Charge and Field at Conductor Surface. Motion of Point Charges in Electric Field. Electric Dipoles in Electric Field Electric Potential Potential Difference Calculating Electric Potential for a System of Point Charges and for Continuous Charge distribution Potential vs. Electric Field. Field Lines and Equipotential Surfaces Electrostatic Energy and Capacitance Electrostatic Potential Energy Capacitance The Storages of Electric Energy Capacitors, Batteries and Circuits Dielectrics. Molecular View of a Dielectric The Electric Field Electric charge Conductors and Insulators Coulomb´s Law The Electric field. Electric Field Lines Calculating Electric Field for continous charge distribution Gauss´s Law Charge and Field at Conductor Surfaces Motion of Point Charges in Electric Field. Electric Dipoles in Electric Field Electric Charge: Objects carrying charges of opposite signs attract each other; Objects carrying charges of the same sign repel each other Positive, the charge acquired by a glass rod when is rubbed with a piece of silk, (Franklin criteria), then electrons are transferred to silk. The piece of silk acquires the same Negative charge Law of Conservation of Charge Charge Quantizacion The SI unit of charge is the coulomb [C] Fundamental Unit of Charge e = 1.602177 x 10-19 C Conductors Conductors the Insulators Insulators materials where the charges, usually electrons, are free to move about the entire material, such as copper, iron,.. materials where the charges can not move freely, such as glass, wood Charging by Induction An object that has separated equal and opposite charges is said to be What happens with polarized the charges distribution on the spheres once the rod is removed? Induction via grounding: using the earth as an infinitely large conductor Coulomb´s Law k Coulomb constant: 8.99x109 N. m2/C2 Is the force exerted by q1 on q2 Unit vector pointing from q1 to q2 In a hydrogen atom, the electron is separated from the proton by an average distance of about 5.3x10-11m. Calculate the magnitude of the electrostatic force of attraction. Compare the electrostatic force with the gravity force between the proton and the electron. Force exerted by a System of Charges: Principle of superposition of forces Coulomb´s torsion balance Three charges are placed as shown in the figure. Calculate the force exerted on the particle at top of the isosceles triangle. Q= 10 μC; q= 500 nC; d = 10 cm The Electric Field F E q F qE The force exerted on the charge q q is a small positive test charge SI units [N/C] [V/m] Electric Field for a system of charges To avoid the conceptual problem of the action at a distance – instantaneous transmission- the concept of electric field is introduced [Suppose that a charged particle at some point is suddenly moved. Does the force exerted on a particle some distance away change instantaneously?] Derive a general expression for the electric field on a point P due to a single charge Q. P is placed at a distance r of the charge. Estimate the value of the electric field for Q=10 nC and r= 15m. Electric Dipole A system of two equal and opposite charges separated by a small distance is called a electric dipole . Its strength and orientation is described by the electric dipole moment p q L, L 2a Exercise: Calculate the electric field of dipole in point P in the dipole axis. Consider the situation when x»a. E 2k p x 3 The Electric Field Lines, or Lines of Force At any given point, the field vector E is tangent to the field line. They are also called lines of force because they show the direction of the force exerted on the positive test charge. The density of the lines (the number of lines per unit of area perpendicular to the lines) at any point is proportional to the magnitude of the field at that point The Electric Field Lines The electric field lines for two conducting spheres are shown in the figure. What is the relative sign and magnitudes of the charges on the two spheres? (A) Picture a uniform vertical electric field E = -2000 N/C. (B)The same but the value of electric field is two times the previous value. Calculating Electric Field for Continous Charge Distribution In the macroscopic world charge can usually be described as continuosly distributed. When the charge is distributed on a volume When the charge is distributed on a surface When the charge is distributed along a line dQ Q ; average Volume charge density dV V dQ Surface charge density dS dQ Linear charge density dl Applying Coulomb´s Law and the principle of superposition E V k dq rˆ 2 r Calculating Electric Field for Continous Charge Distribution. E on the Axis of a finite Line charge E on the Axis of a finite Line charge E due to an infinite line charge Gauss´s Law Gauss´s Law is one of the so called Maxwell´s Equations that describe the electromagnetics phenomena. For static charges, Coulomb´s Law and Gauss´s Law are equivalent, but Gauss´s Law is more general. Gauss´s Law can be used to calculate the electric field for charge distribution with high degree of symmetry Gauss´s Law:The net number of lines out of any surface enclosing the charges is proportional to the net charge enclosed by the surface Gauss´s Law Electric Flux ϕ E A E nA d E dS E dSn The number of field lines penetrating a surface is called the electric flux. Units: N. m2/C If we consider a surface A perpendicular to E, In the case of surface that is not perpendicular to E, the dot product enables us to obtain the value of area perpendicular to the electric field. Calculating E from Gauss´s Law. The power of symmetry Electric field for a single point charge The electric field exhibits spherical symmetry around the charge. Then we consider a spherical surface with center on the charge to apply Gauss´s law. The value of E is constant in all points of this sphere. E dA E 4R 2 4 k Q A Ek The flux is independent from the selected sphere Q R2 Writing Gauss´s Law and Coulomb´s Law in terms of permitivity of free space 2 1 o 8.85x1012 C N m2 4k k 1 4 o 1 q E rˆ 2 4 o r net Qinside o Calculating E from Gauss´s Law. The power of symmetry Electric field for a Thin Spherical Shell of Charge The electric field exhibits spherical symmetry around the uniform charge distribution . Then we consider a spherical surface with the same center as the shell of charge to apply Gauss´s law. The value of E is constant in all points of this sphere. E dA E 4R 2 4 k Q A Ek Q 1 Q R 2 4o R 2 For a gaussian sphere inside of the shell charge In the Earth´s atmosphere, the electric field is 150 N/C downwards at an altitude of 250 m, and 170 N/C downwards at an altitude of 400 m. Calculate the volume charge density of the atmosphere assuming it to be uniform between both altitudes. E dA 0 A E 0 The flux is independent from the selected sphere