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An electric dipole is formed from ±5.0 nC point charges spaced 2.0 mm apart. The dipole is centered at the origin, oriented along the y-axis with the positive charge above the x-axis. What is the electric field at point (x,y) = (10 cm, 0 cm)? What is the electric field at point (x,y) = (0 cm, 10 cm)? We can make the following figure. Electric field at (10, 0) =? The distance between each charge location and (10, 0) = 102 0.12 100.01 cms. If field at (10, 0) due to each dipole charge is E, we will have E tan 5 109 9 109 100.01 100 2 45 1002 4499.55 N/C 100.01 0.1 0.572940 10 Hence, field at (10, 0) = 2 E cos 2 4499.55cos 0.572940 8998.65 N/C in x-direction. Electric field at (0, 10) =? Distance between 5nC charge and (0,10) = 10-0.1 = 9.9 cms. Distance between -5nC charge and (0,10) = 10+0.1 = 10.1 cms. Field at (0, 10) at +ve due to 5nC charge = 5 109 9 109 9.9 100 2 ay 45 1002 a y 4591.368a y N/C 9.92 Field at (0, 10) at +ve due to -5Nc charge 5 109 9 109 10.1 100 2 Hence, total field at (0,10) = (4591.368 – 4411.33)ay N/C = 180.038ay N/C 45 1002 ay a y 4411.33a y N/C 10.12