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Published by the Applied Probability Trust © Applied Probability Trust 2004 13 Sorting Sequences JONATHAN SMITH Take any sequence of numbers, e.g. 17, 54, 23, 31, 17, 3 . There are various algorithms to sort these numbers into ascending order (with the lowest number on the left). With a sorting algorithm there need to be a certain number of comparisons made between numbers and a certain number of swaps made. Only adjacent numbers can be compared or swapped. The number of comparisons needed gives some idea of the efficiency of the algorithm, but the number of swaps is the same regardless of the algorithm. For readers who are familiar with sorting algorithms, sorting the above sequence into ascending order using the bubble sort algorithm requires 15 comparisons and 10 swaps. Using the shuttle sort algorithm requires 14 comparisons and 10 swaps. Notice that the number of swaps is the same, as expected. Given A distinct numbers there are A! ways of arranging them in a sequence. If we treat the left-hand number as the most significant, followed by the next one in and so on, we can arrange the sequences in an order and then label them from 0 to (A! − 1) in ascending order, giving us the sequence number. For example, if we take sequences with three numbers, there are 3! = 6 possible sequences. We will number these 0 to 5 as in table 1. Table 1 Sequences of three numbers. Sequence 1 1 2 2 3 3 2 3 1 3 1 2 3 2 3 1 2 1 Sequence number 0 1 2 3 4 5 The aim of this article is to show how to work out the sequence number of a given sequence and, conversely, how to work out the sequence with a given sequence number. 1. Reducing the problem to standard form The numbers in a sequence can be in any order, but it is important that they are the numbers {1, 2, 3, . . . , A} . If they are not, then replace the lowest number with 1, the next lowest with 2 and so on. If there are any duplicate digits, then these should be assigned numbers in ascending order, starting from the left-hand side. Thus, the sequence 17, 54, 23, 31, 17, 3 becomes 2, 6, 4, 5, 3, 1 .