Assignment CHE-04 TMA-01,02 Year 2005
... 7. 50 mol of a monoatomic ideal gas occupies a volume of 0.8314 m3 at 1.50×105 Pa and 3.00×102 K. The gas undergoes expansion and the final pressure is 7.50×104 Pa. Calculate the final volume of the gas, assuming that it proceeds through (i) reversible isothermal process and (ii) reversible adiabat ...
... 7. 50 mol of a monoatomic ideal gas occupies a volume of 0.8314 m3 at 1.50×105 Pa and 3.00×102 K. The gas undergoes expansion and the final pressure is 7.50×104 Pa. Calculate the final volume of the gas, assuming that it proceeds through (i) reversible isothermal process and (ii) reversible adiabat ...
L25 - University of Iowa Physics
... Charging by friction (triboelectric effect) • If you rub plastic with cat’s fur, electrons are rubbed onto the plastic making it negative • if you rub glass or plastic with silk, electrons are rubbed off the glass making it positive • the charge can be transferred to other ...
... Charging by friction (triboelectric effect) • If you rub plastic with cat’s fur, electrons are rubbed onto the plastic making it negative • if you rub glass or plastic with silk, electrons are rubbed off the glass making it positive • the charge can be transferred to other ...
Neutrinos and Supernovae
... internal pressure inside the core starts to increase dramatically, and once the Los Alamos Science Number 25 1997 ...
... internal pressure inside the core starts to increase dramatically, and once the Los Alamos Science Number 25 1997 ...
review – electric charge One Coulomb is a HUGE charge electrons
... – we call this e = 1.6 x10-19 C Îcharges cannot be divided into smaller units than this. ...
... – we call this e = 1.6 x10-19 C Îcharges cannot be divided into smaller units than this. ...
Chapter 5 The Gaseous State
... In an autoclave, steam at 100 oC is generated at 1.00 atm. After the autoclave is closed, the steam is heated at constant volume until the pressure gauge indicated 1.13 atm. What is the new temperature in the autoclave? ...
... In an autoclave, steam at 100 oC is generated at 1.00 atm. After the autoclave is closed, the steam is heated at constant volume until the pressure gauge indicated 1.13 atm. What is the new temperature in the autoclave? ...
Neutron Stars
... additional periodicity imposed on the pulse stream. A straightforward application of Kepler’s Law The Doppler shift of the pulses, together with the orbital period, revealed that the combined masses of the two stars was about 2.8 M . The fact that no tidal distortions were apparently affecting the o ...
... additional periodicity imposed on the pulse stream. A straightforward application of Kepler’s Law The Doppler shift of the pulses, together with the orbital period, revealed that the combined masses of the two stars was about 2.8 M . The fact that no tidal distortions were apparently affecting the o ...
Ch13ov1
... L Temperature increases may result in greater or lesser solubility. • Temperature effect is not related to ∆Hsoln. • Rate of dissolving is usually enhanced at higher temperature, regardless of the effect on solubility limit. Non-reactive Gas Solutes L Gases are more soluble at higher pressure. L Gas ...
... L Temperature increases may result in greater or lesser solubility. • Temperature effect is not related to ∆Hsoln. • Rate of dissolving is usually enhanced at higher temperature, regardless of the effect on solubility limit. Non-reactive Gas Solutes L Gases are more soluble at higher pressure. L Gas ...
THERMODYNAMICS. Elements of Physical Chemistry. By P. Atkins
... Potential energy (PE) = mgh – energy stored in bonds ...
... Potential energy (PE) = mgh – energy stored in bonds ...
THERMODYNAMICS. Elements of Physical Chemistry. By P. Atkins
... Potential energy (PE) = mgh – energy stored in bonds ...
... Potential energy (PE) = mgh – energy stored in bonds ...
Plasma Orbital Expansion of the Electrons in Water
... testable properties that show something is different about this gas. This paper shows the possibilities that exist to help explain this phenomenon. One of the key differences in Browns gas is that some of the water molecules go into an excited isomer plasma state; hence Brown’s Gas has more energy d ...
... testable properties that show something is different about this gas. This paper shows the possibilities that exist to help explain this phenomenon. One of the key differences in Browns gas is that some of the water molecules go into an excited isomer plasma state; hence Brown’s Gas has more energy d ...
Determination of the Molar Volume of a Gas KClO3 breaks down
... reaction catalyst makes the reaction go more smoothly. Because molecular oxygen is the only volatile product of this reaction, the loss of mass of a tube containing potassium chlorate upon heating indicates the mass of the molecular oxygen produced. The number of moles of oxygen liberated can be cal ...
... reaction catalyst makes the reaction go more smoothly. Because molecular oxygen is the only volatile product of this reaction, the loss of mass of a tube containing potassium chlorate upon heating indicates the mass of the molecular oxygen produced. The number of moles of oxygen liberated can be cal ...
Document
... •Convenient to measure q through electrical work •Numerical value depends on path between initial and final states. Most common are constant V or P. ...
... •Convenient to measure q through electrical work •Numerical value depends on path between initial and final states. Most common are constant V or P. ...
11-16 States of Matter
... 3. Evaporation is the change of state from a liquid to gas. Evaporation occurs at the surface of a liquid that is below its boiling point. Boiling is the change of a liquid to a gas throughout the liquid. The temperature a liquid boils is its boiling point. Boiling Point is 212F or 100C. ...
... 3. Evaporation is the change of state from a liquid to gas. Evaporation occurs at the surface of a liquid that is below its boiling point. Boiling is the change of a liquid to a gas throughout the liquid. The temperature a liquid boils is its boiling point. Boiling Point is 212F or 100C. ...
chemistry 101 spring 2002 part 1
... answer, put the same answer down for both questions for 5 pts. If you cannot decide between two answers, put one answer down for one question and the other answer down for the other question. If you get one correct you'll get half credit for 2.5 pts. If there is an ambiguous multiple choice question ...
... answer, put the same answer down for both questions for 5 pts. If you cannot decide between two answers, put one answer down for one question and the other answer down for the other question. If you get one correct you'll get half credit for 2.5 pts. If there is an ambiguous multiple choice question ...
Chapter 13 - Humble ISD
... • Relate the amount of gas present to its pressure, temperature, and volume using the ideal gas law. • Compare the properties of real and ideal gases. ...
... • Relate the amount of gas present to its pressure, temperature, and volume using the ideal gas law. • Compare the properties of real and ideal gases. ...
1 Stoichiometry Problems Volume of CO2 (g) produced from the
... Assume one liter of gas (so the mass can be determined for one liter). PV = nRT n = PV/RT = (1.00 atm)(1.00 L)/(0.0821 L•atm/mol•K)(273 K) = 0.0446 moles SF6 146.06 g 0.0446 moles SF6 = 6.51 grams SF6 1mole ...
... Assume one liter of gas (so the mass can be determined for one liter). PV = nRT n = PV/RT = (1.00 atm)(1.00 L)/(0.0821 L•atm/mol•K)(273 K) = 0.0446 moles SF6 146.06 g 0.0446 moles SF6 = 6.51 grams SF6 1mole ...
chm3400testfin
... 1. (24 points) The temperature of 1.000 mol of chlorine gas (Cl2(g)) is changed from an initial value T i = 250.0 K to a final temperature Tf = 350.0 K. The process is carried out reversibly at a constant pressure p = 0.500 bar. For the conditions of the problem you may assume that chlorine gas beha ...
... 1. (24 points) The temperature of 1.000 mol of chlorine gas (Cl2(g)) is changed from an initial value T i = 250.0 K to a final temperature Tf = 350.0 K. The process is carried out reversibly at a constant pressure p = 0.500 bar. For the conditions of the problem you may assume that chlorine gas beha ...
SCH3U Exam Review 1 11U CHEMISTRY EXAM
... c) Explain your answer to b). 5. a) J.J Thomson discovered the __________________ while studying ___________________ rays b) Very briefly describe Thomson's model of the atom. 6. Rutherford did an experiment that disproved Thomson's model of the atom. In his experiment Rutherford shot a beam of ____ ...
... c) Explain your answer to b). 5. a) J.J Thomson discovered the __________________ while studying ___________________ rays b) Very briefly describe Thomson's model of the atom. 6. Rutherford did an experiment that disproved Thomson's model of the atom. In his experiment Rutherford shot a beam of ____ ...
11U CHEMISTRY EXAM REVIEW QUESTIONS June 2010
... c) Explain your answer to b). 5. a) J.J Thomson discovered the __________________ while studying ___________________ rays b) Very briefly describe Thomson's model of the atom. 6. Rutherford did an experiment that disproved Thomson's model of the atom. In his experiment Rutherford shot a beam of ____ ...
... c) Explain your answer to b). 5. a) J.J Thomson discovered the __________________ while studying ___________________ rays b) Very briefly describe Thomson's model of the atom. 6. Rutherford did an experiment that disproved Thomson's model of the atom. In his experiment Rutherford shot a beam of ____ ...
Chemistry 215 Quiz 1 (20 points)
... it is not compressible one mole of it occupies exactly 1 liter at standard temperature and pressure it can be shown to occupy zero volume at 0C. its behavior is described by the ideal-gas equation one mole of it in a one-liter container exerts a pressure of exactly 1 atm at room temperature Of the ...
... it is not compressible one mole of it occupies exactly 1 liter at standard temperature and pressure it can be shown to occupy zero volume at 0C. its behavior is described by the ideal-gas equation one mole of it in a one-liter container exerts a pressure of exactly 1 atm at room temperature Of the ...
Chapter 1 - Atoms: The Quantum World
... Note: In accordance with Hund’s rule, the two electrons in the 2p-subshell occupy separate orbitals with parallel spins. Any two of the three 2p-orbitals may be occupied and both spins could also be pointing down; such configurations are all degenerate. Example 1.12e Write the ground-state electron ...
... Note: In accordance with Hund’s rule, the two electrons in the 2p-subshell occupy separate orbitals with parallel spins. Any two of the three 2p-orbitals may be occupied and both spins could also be pointing down; such configurations are all degenerate. Example 1.12e Write the ground-state electron ...
PowerPoint Template
... - the work done by a gas as it expands and drives back the atmosphere - The term ‘expansion work’ also includes work associated with negative changes of volume, that is, compression ...
... - the work done by a gas as it expands and drives back the atmosphere - The term ‘expansion work’ also includes work associated with negative changes of volume, that is, compression ...
PowerPoint Template
... - the work done by a gas as it expands and drives back the atmosphere - The term ‘expansion work’ also includes work associated with negative changes of volume, that is, compression ...
... - the work done by a gas as it expands and drives back the atmosphere - The term ‘expansion work’ also includes work associated with negative changes of volume, that is, compression ...
Department of Chemistry, IIT-Delhi CY110N Tutorial
... 17. Calculate the maximum work and the maximum non-expansion work that can be obtained from the freezing of supercooled water at −5 o C and 1.0 atm. The densities of water and ice are 0.999 and 0.917 g cm−3 , respectively at −5 o C. 18. One mole of He is heated from 200 o C to 400 o C at a constant ...
... 17. Calculate the maximum work and the maximum non-expansion work that can be obtained from the freezing of supercooled water at −5 o C and 1.0 atm. The densities of water and ice are 0.999 and 0.917 g cm−3 , respectively at −5 o C. 18. One mole of He is heated from 200 o C to 400 o C at a constant ...