Objective Reaction Type Structural Feature How to figure out how reactants react?
... to Mevalonolactone. Suggest a reasonable mechanism for this reaction. For each step, use curved arrow to show bonds breaking and forming. What other organic product is formed? ...
... to Mevalonolactone. Suggest a reasonable mechanism for this reaction. For each step, use curved arrow to show bonds breaking and forming. What other organic product is formed? ...
Name: Chem 22 Final exam Spring `00 What product is formed when
... a) In an organometallic compound, the carbon bonded to the metal is the nucleophile. b) An epoxide is more reactive than an ether. c) In a Hofmann elimination, a proton is removed from the beta carbon that is bonded to the greater number of hydrogens. d) Thioethers are also called sufides ...
... a) In an organometallic compound, the carbon bonded to the metal is the nucleophile. b) An epoxide is more reactive than an ether. c) In a Hofmann elimination, a proton is removed from the beta carbon that is bonded to the greater number of hydrogens. d) Thioethers are also called sufides ...
Chapter 7 Alkenes and Alkynes I
... Some hydrogen halides can eliminate to give two different alkene products ...
... Some hydrogen halides can eliminate to give two different alkene products ...
Octenes from E1 versus E2 Eliminations
... the tube. (You can start setting up the E2 reaction below while this is heating.) After heating for 20 to 30 min, insert a clean Pasteur pipet into the reaction vapors about 1 cm above the boiling liquid and draw up the vapors into the Pasteur pipet. The vapors will condense and the small drop of li ...
... the tube. (You can start setting up the E2 reaction below while this is heating.) After heating for 20 to 30 min, insert a clean Pasteur pipet into the reaction vapors about 1 cm above the boiling liquid and draw up the vapors into the Pasteur pipet. The vapors will condense and the small drop of li ...
Problem set #8.
... Phenols are typically a million times more acidic than alcohols owing to the resonance stabilization of the phenoxide ion that delocalizes the negative charge from the oxygen into the ring. If this is not clear, look over the lecture notes where you will find myriad resonance structures of phenol an ...
... Phenols are typically a million times more acidic than alcohols owing to the resonance stabilization of the phenoxide ion that delocalizes the negative charge from the oxygen into the ring. If this is not clear, look over the lecture notes where you will find myriad resonance structures of phenol an ...
EXPERIMENT 3: Preparation and Reactivity of Alkyl Halides
... nucleophilic, unimolecular in the rate-determining step). An SN1 mechanism may also be involved when R is a secondary group or when R can form a resonance-stabilized carbocation, such as an allyl or benzyl cation. (The more stable the carbocation, the more likely the SN1 mechanism) If R is a primary ...
... nucleophilic, unimolecular in the rate-determining step). An SN1 mechanism may also be involved when R is a secondary group or when R can form a resonance-stabilized carbocation, such as an allyl or benzyl cation. (The more stable the carbocation, the more likely the SN1 mechanism) If R is a primary ...
Slide 1
... They are stronger acids (pKa = 10) than alcohols, but do not exhibit hydrogen-binding ...
... They are stronger acids (pKa = 10) than alcohols, but do not exhibit hydrogen-binding ...
11. Reactions of Alkyl Halides
... – Reaction of (-)-malic acid with PCl5 gives (+)chlorosuccinic acid – Further reaction with wet silver oxide gives (+)-malic acid – The reaction series starting with (+) malic acid gives (-) acid ...
... – Reaction of (-)-malic acid with PCl5 gives (+)chlorosuccinic acid – Further reaction with wet silver oxide gives (+)-malic acid – The reaction series starting with (+) malic acid gives (-) acid ...
Chapter 18 Reactions of aromatics
... • Aromatic rings are inert to catalytic hydrogenation under conditions that reduce alkene double bonds • Can selectively reduce an alkene double bond in the presence of an aromatic ring • Reduction of an aromatic ring requires more powerful reducing conditions (high pressure or rhodium catalysts) ...
... • Aromatic rings are inert to catalytic hydrogenation under conditions that reduce alkene double bonds • Can selectively reduce an alkene double bond in the presence of an aromatic ring • Reduction of an aromatic ring requires more powerful reducing conditions (high pressure or rhodium catalysts) ...
Exp`t 70
... formation of the relatively stable tertiary carbocation followed by loss of a proton either from a primary carbon atom to give the terminal olefin, 2-methyl-1-butene, or from a secondary carbon to give 2-methyl-2-butene. ...
... formation of the relatively stable tertiary carbocation followed by loss of a proton either from a primary carbon atom to give the terminal olefin, 2-methyl-1-butene, or from a secondary carbon to give 2-methyl-2-butene. ...
Microsoft Word - Final Exam Study Guide
... alcohols/ethers/epoxides, multistep synthesis, protecting groups, redox reactions, reagents for redox reactions, Grignard reaction 1. Mechanisms. These are the very basic types of mechanisms. You should also be able to explain regiochemistry and stereochemistry outcomes, as well as rearrangements, e ...
... alcohols/ethers/epoxides, multistep synthesis, protecting groups, redox reactions, reagents for redox reactions, Grignard reaction 1. Mechanisms. These are the very basic types of mechanisms. You should also be able to explain regiochemistry and stereochemistry outcomes, as well as rearrangements, e ...
Transition Metal Chemistry 2 2011.12.2 Ⅰ Fundamental
... 3-5 Olefin insertion into M-H bond: Peri-syn-planar transition state ...
... 3-5 Olefin insertion into M-H bond: Peri-syn-planar transition state ...
Answer Key - OISE-IS-Chemistry-2011-2012
... 1. Carbon is able to form large numbers of organic compounds because carbon can a. form 4 bonds b. form single, double and triple bonds c. form chains, rings, spheres and sheets d. the carbon-carbon bond is very stable e. all of the above 2. From the following list, select the two molecules that are ...
... 1. Carbon is able to form large numbers of organic compounds because carbon can a. form 4 bonds b. form single, double and triple bonds c. form chains, rings, spheres and sheets d. the carbon-carbon bond is very stable e. all of the above 2. From the following list, select the two molecules that are ...
Relative Reactivity of Aldehydes and Ketones: Generally
... electron density and forms a hydrate easily, welcoming in a second oxygen atom with electron density. But this is an exception, as is the hydration of trichloroacetaldehyde: O Cl3C ...
... electron density and forms a hydrate easily, welcoming in a second oxygen atom with electron density. But this is an exception, as is the hydration of trichloroacetaldehyde: O Cl3C ...
Document
... • Because alkyl tosylates have good leaving groups, they undergo both nucleophilic substitution and elimination, exactly as alkyl halides do. • Generally, alkyl tosylates are treated with strong nucleophiles and bases, so the mechanism of substitution is SN2, and the mechanism of elimination is E ...
... • Because alkyl tosylates have good leaving groups, they undergo both nucleophilic substitution and elimination, exactly as alkyl halides do. • Generally, alkyl tosylates are treated with strong nucleophiles and bases, so the mechanism of substitution is SN2, and the mechanism of elimination is E ...
Topic 8 Assessed Homework Task - A
... In a typical procedure, a mixture of 1.00 g of propanone, 5.00 g of ethane-1,2-diol and 0.100 g of benzenesulphonic acid, C6H5SO3H, is heated under reflux in an inert solvent. Benzenesulphonic acid is a strong acid. Which one of the following statements is not true? ...
... In a typical procedure, a mixture of 1.00 g of propanone, 5.00 g of ethane-1,2-diol and 0.100 g of benzenesulphonic acid, C6H5SO3H, is heated under reflux in an inert solvent. Benzenesulphonic acid is a strong acid. Which one of the following statements is not true? ...
CN>Chapter 22CT>Carbonyl Alpha
... and loses CO2 (“decarboxylation”) to yield a substituted monoacid ...
... and loses CO2 (“decarboxylation”) to yield a substituted monoacid ...
Document
... Each step of the reaction mechanism is reversible and, therefore, the reaction reaches equilibrium. Le Chatelier’s principle suggests that the amount of ester produced in an equilibrium reaction might be increased either by using an excess of one of the reactants or by removing one of the products. ...
... Each step of the reaction mechanism is reversible and, therefore, the reaction reaches equilibrium. Le Chatelier’s principle suggests that the amount of ester produced in an equilibrium reaction might be increased either by using an excess of one of the reactants or by removing one of the products. ...
orgchem rev integ odd numbers
... 1. What is the predominant product from the reaction of 2 – hexanol with ...
... 1. What is the predominant product from the reaction of 2 – hexanol with ...
Some comments and hints for the March 9 Biochemistry
... c. The reduction of fructose creates a new tetrahedral stereocenter. This can be examined best by looking at Fischer projections of the sugars. d. The first method will convert the alcohols to methyl ethers. The second will produce silyl ethers. 2. The leaving group in hydrolysis, the amine, is more ...
... c. The reduction of fructose creates a new tetrahedral stereocenter. This can be examined best by looking at Fischer projections of the sugars. d. The first method will convert the alcohols to methyl ethers. The second will produce silyl ethers. 2. The leaving group in hydrolysis, the amine, is more ...
STUDY GUIDE FOR CHAPTER 4 1. Functional Groups – these are
... is then reasonable to recognize that higher in energy TS would mean slower reaction. But the TS of the rate-determining step of SN 1 reactions are product-like, i.e. resembling the carbocations. We can therefore conclude that ANY FACTOR that affects the stability of the carbocation would affect in a ...
... is then reasonable to recognize that higher in energy TS would mean slower reaction. But the TS of the rate-determining step of SN 1 reactions are product-like, i.e. resembling the carbocations. We can therefore conclude that ANY FACTOR that affects the stability of the carbocation would affect in a ...
Discuss on Reactions of Alcohols
... dioxide and hydrogen chloride formed as byproducts are gasses and therefore easily removed from the reaction. Mechanistically, the alcohol initially reacts to form an ...
... dioxide and hydrogen chloride formed as byproducts are gasses and therefore easily removed from the reaction. Mechanistically, the alcohol initially reacts to form an ...
NCEA Level 2 Chemistry (91165) 2012 Assessment Schedule
... must have two different atoms / groups attached to it. Compound A has a double bond, but the atoms attached to one carbon are both the same (two hydrogen atoms) so it does not form a geometric isomer. ...
... must have two different atoms / groups attached to it. Compound A has a double bond, but the atoms attached to one carbon are both the same (two hydrogen atoms) so it does not form a geometric isomer. ...
NCEA Level 2 Chemistry (91165) 2012
... must have two different atoms / groups attached to it. Compound A has a double bond, but the atoms attached to one carbon are both the same (two hydrogen atoms) so it does not form a geometric isomer. ...
... must have two different atoms / groups attached to it. Compound A has a double bond, but the atoms attached to one carbon are both the same (two hydrogen atoms) so it does not form a geometric isomer. ...
Chemistry 199 - Department of Chemistry | Oregon State University
... have a double bond located at the third carbon from the end of the chain. The term omega-3 is used because omega indicates the first carbon at the end of the chain and the 3 indicates the third carbon atom in. ...
... have a double bond located at the third carbon from the end of the chain. The term omega-3 is used because omega indicates the first carbon at the end of the chain and the 3 indicates the third carbon atom in. ...
Tiffeneau–Demjanov rearrangement
The Tiffeneau–Demjanov rearrangement (TDR) is the chemical reaction of a 1-aminomethyl-cycloalkanol with nitrous acid to form an enlarged cycloketone.The Tiffeneau–Demjanov ring expansion, Tiffeneau–Demjanov rearrangement, or TDR, provides an easy way to increase amino-substituted cycloalkanes and cycloalkanols in size by one carbon. Ring sizes from cyclopropane through cyclooctane are able to undergo Tiffeneau–Demjanov ring expansion with some degree of success. Yields decrease as initial ring size increases, and the ideal use of TDR is for synthesis of five, six, and seven membered rings. A principal synthetic application of Tiffeneau–Demjanov ring expansion is to bicyclic or polycyclic systems. Several reviews on this reaction have been published.