Special Relativity and Fields Homework problem, due 13th October
... For simplicity, we consider the case where no external charges and currents are present. The primes indicate that the constitutive equations are valid in coordinate frames that are locally co-moving with the medium. In such frames the medium is locally at rest. Note that the velocity of the medium m ...
... For simplicity, we consider the case where no external charges and currents are present. The primes indicate that the constitutive equations are valid in coordinate frames that are locally co-moving with the medium. In such frames the medium is locally at rest. Note that the velocity of the medium m ...
Semester 1 Concept Questions
... (Motion in One & Two Dimensions, Newton’s Laws, Energy & Momentum, Circular Motion) For the final, you may use a 8.5”x11” page of notes. This page must be unique, HANDWRITTEN & one-sided. Motion in One & Two Dimensions: 1. A car accelerates from 13 m/s to 25 m/s in 6.0 sec a. What was its accelerati ...
... (Motion in One & Two Dimensions, Newton’s Laws, Energy & Momentum, Circular Motion) For the final, you may use a 8.5”x11” page of notes. This page must be unique, HANDWRITTEN & one-sided. Motion in One & Two Dimensions: 1. A car accelerates from 13 m/s to 25 m/s in 6.0 sec a. What was its accelerati ...
PowerPoint Presentation - 5. Universal Laws of Motion
... 10 m/s each second, or g = 10 m/s2. • The higher you drop the ball, the greater its velocity will be at impact. © 2004 Pearson Education Inc., publishing as Addison-Wesley ...
... 10 m/s each second, or g = 10 m/s2. • The higher you drop the ball, the greater its velocity will be at impact. © 2004 Pearson Education Inc., publishing as Addison-Wesley ...
Final Exam Review
... Answer: the rubber ball. F = p/t. For the rubber ball p=2mv, while for the putty, p=mv. 14. Suppose a little calculator and a big physics text are sliding toward you on a frictionless air table. Both have the same momentum, and you exert the same force to stop each. How do the time intervals to ...
... Answer: the rubber ball. F = p/t. For the rubber ball p=2mv, while for the putty, p=mv. 14. Suppose a little calculator and a big physics text are sliding toward you on a frictionless air table. Both have the same momentum, and you exert the same force to stop each. How do the time intervals to ...
RevfinQ2010AnsFa06
... Answer: F = p/t. Same F, same p for each object, so t must be the same. Which object travels further while slowing down? A: the little calculator. B: both travel the same distance. C: the big physics text. Answer: The little calculator. The momenta of the two objects were identical before slowin ...
... Answer: F = p/t. Same F, same p for each object, so t must be the same. Which object travels further while slowing down? A: the little calculator. B: both travel the same distance. C: the big physics text. Answer: The little calculator. The momenta of the two objects were identical before slowin ...
Study guide for Chapter 2 Test: Forces
... accelerate (speed up, slow down, change direction) 2nd law: The acceleration of an object depends on the force applied ...
... accelerate (speed up, slow down, change direction) 2nd law: The acceleration of an object depends on the force applied ...
Rules for Motion Maps
... location on the position vector is approximately correct The dot represents the location at the beginning of the time period, while the arrow represents the motion about to happen during the next instant of time. If the object is stationary for more than one time period the dots should be stacked ve ...
... location on the position vector is approximately correct The dot represents the location at the beginning of the time period, while the arrow represents the motion about to happen during the next instant of time. If the object is stationary for more than one time period the dots should be stacked ve ...
2009 Final Exam
... A beam of light approaches a barrier having four openings A, B, C and D of different sizes as shown. Which opening will cause the greatest amount of diffraction? ...
... A beam of light approaches a barrier having four openings A, B, C and D of different sizes as shown. Which opening will cause the greatest amount of diffraction? ...
Unit 4 Notetakers
... ______________________ of the path the object takes between the 2 points. (The work done depends only on the initial and final positions.) ...
... ______________________ of the path the object takes between the 2 points. (The work done depends only on the initial and final positions.) ...
Physics 103-02 Exam IV 4 Dec
... Part C: Work the following problem. Show your work, and use words and phrases to describe your reasoning. [10 points] 16. An ideal string is wrapped around a pulley. Hanging from the free end of the string is a mass, m = 4.0 kg. The axle of the pulley is frictionless, but the string does not slip o ...
... Part C: Work the following problem. Show your work, and use words and phrases to describe your reasoning. [10 points] 16. An ideal string is wrapped around a pulley. Hanging from the free end of the string is a mass, m = 4.0 kg. The axle of the pulley is frictionless, but the string does not slip o ...
Chapter 22 - The Nature of Light
... higher energy levels temporarily. When they fall back to a lower energy level, they give off a packet of energy called a ___________. When the electrons move back and forth, they give off a _________ of photons, making an ____ ___________ which carries the energy. Light has a __________ personality: ...
... higher energy levels temporarily. When they fall back to a lower energy level, they give off a packet of energy called a ___________. When the electrons move back and forth, they give off a _________ of photons, making an ____ ___________ which carries the energy. Light has a __________ personality: ...
Impulse Momentum (Problem and Solutions) 1. An object travels
... Impulse=change in momentum I=ΔP=40kg.m/s 3. Find the impulse and force which make 12m/s change in the velocity of object having 16kg mass in 4 s. F.Δt=ΔP=m.ΔV F.4s=16kg.12m/s F=48N F.Δt=Impulse=192kg.m/s 4. Applied force vs. time graph of object is given below. Find the impulse of the object between ...
... Impulse=change in momentum I=ΔP=40kg.m/s 3. Find the impulse and force which make 12m/s change in the velocity of object having 16kg mass in 4 s. F.Δt=ΔP=m.ΔV F.4s=16kg.12m/s F=48N F.Δt=Impulse=192kg.m/s 4. Applied force vs. time graph of object is given below. Find the impulse of the object between ...
IHS ppt 092710 ISA
... a time interval. Given a specified _____interval (e.g., one hour), the distance covered is proportional to the speed. If the amount of ____ is constant and speed increases, the distance traveled will increase. If time is constant, distance covered is proportional to rate. If time is constant and the ...
... a time interval. Given a specified _____interval (e.g., one hour), the distance covered is proportional to the speed. If the amount of ____ is constant and speed increases, the distance traveled will increase. If time is constant, distance covered is proportional to rate. If time is constant and the ...
Chp. 7 Outline: Circular Motion and Gravity Lecture Questions: 1
... Earth on the Moon? How did he do this? What is universal about gravity? 8) Write the Law of Universal gravitation verbally and mathematically. Define all variables and constants. In which direction is the force? 9) How will the gravitational force between two objects change if the following changes ...
... Earth on the Moon? How did he do this? What is universal about gravity? 8) Write the Law of Universal gravitation verbally and mathematically. Define all variables and constants. In which direction is the force? 9) How will the gravitational force between two objects change if the following changes ...
Physics 207: Lecture 2 Notes
... Provides a reality check (if dimensional analysis fails then there is no sense in putting in numbers) ...
... Provides a reality check (if dimensional analysis fails then there is no sense in putting in numbers) ...
File - USNA
... conventions for momentum from classical physics even if we use the velocity transformation equations from the special theory of relativity. There is no problem with the x direction, but there is a problem with the y direction along the direction the ball is thrown in each system. ...
... conventions for momentum from classical physics even if we use the velocity transformation equations from the special theory of relativity. There is no problem with the x direction, but there is a problem with the y direction along the direction the ball is thrown in each system. ...
Physics transition tasks
... You should already know that a quantity like speed only has a size (e.g. 13 ms–1), but there is another type of quantity (called a vector) that has a size and direction, e.g. a velocity of 13 ms–1 to the left. You can represent velocities with arrows – the longer the arrow the greater the size (spee ...
... You should already know that a quantity like speed only has a size (e.g. 13 ms–1), but there is another type of quantity (called a vector) that has a size and direction, e.g. a velocity of 13 ms–1 to the left. You can represent velocities with arrows – the longer the arrow the greater the size (spee ...
1st term exam solutions
... c. the object is instantaneously at rest at some instant d. the object never changes direction of motion ...
... c. the object is instantaneously at rest at some instant d. the object never changes direction of motion ...