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Electrostatic Formula Electric Force F= 1 q1q2 4 p eo r2 = k q 1q 2 r2 k = 9.0x10 9 N m2 = 1 = -------1-----------C2 4 p eo 4 p 8.85x10-12 C2 N m2 Electric Force F= 1 q1q2 4 p eo r2 = k q 1q 2 r2 k = 9.0x10 9 N m2 = 1 = -------1-----------C2 4 p eo 4 p 8.85x10-12 C2 N m2 Electric Force F= 1 q1q2 4 p eo r2 = k q 1q 2 r2 k = 9.0x10 9 N m2 = 1 = -------1-----------C2 4 p eo 4 p 8.85x10-12 C2 N m2 Electric Force F= 1 q1q2 4 p eo r2 = k q 1q 2 r2 k = 9.0x10 9 N m2 = 1 = -------1-----------C2 4 p eo 4 p 8.85x10-12 C2 N m2 Electric Force F= 1 q1q2 4 p eo r2 = k q 1q 2 r2 k = 9.0x10 9 N m2 = 1 = -------1-----------C2 4 p eo 4 p 8.85x10-12 C2 N m2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x ) Electric Force F= 1 q1q2 4 p eo r2 = k q 1q 2 r2 k = 9.0x10 9 N m2 = 1 = -------1-----------C2 4 p eo 4 p 8.85x10-12 C2 N m2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x ) Electric Field associated with point charges E=F q F = kqq r2 therefore E = Kqq therefore E =kq r2q r2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x ) Electric Field associated with point charges E=F q F = kqq r2 therefore E = Kqq therefore E =kq r2q r2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x ) Electric Field associated with point charges E=F q F = kqq r2 therefore E = Kqq therefore E =kq r2q r2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x ) Electric Field associated with point charges E=F q F = kqq r2 therefore E = Kqq therefore E =kq r2q r2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x ) Electric Field associated with point charges E=F q F = kqq r2 therefore E = Kqq therefore E =kq r2q r2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x ) Electric Field associated with point charges E=F q F = kqq r2 therefore E = Kqq therefore E =kq r2q r2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x ) Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d2 d q d q Coulomb W=qEd W = Ed V = Ed V = E = Volts q d meter Capacitance C=Q V C = KAeo d K= dielectric constant A = area in m2 e0= 8.85x10-12 C2 N m2 d = distance between plates in m Capacitance C=Q V C = KAeo d K= dielectric constant A = area in m2 e0= 8.85x10-12 C2 N m2 d = distance between plates in m Capacitance C=Q V C = KAeo d K= dielectric constant A = area in m2 e0= 8.85x10-12 C2 N m2 d = distance between plates in m Capacitance C=Q V C = KAeo d K= dielectric constant A = area in m2 e0= 8.85x10-12 C2 N m2 d = distance between plates in m Capacitance C=Q V C = KAeo d K= dielectric constant A = area in m2 e0= 8.85x10-12 C2 N m2 d = distance between plates in m Capacitance C=Q V C = KAeo d K= dielectric constant A = area in m2 e0= 8.85x10-12 C2 N m2 d = distance between plates in m Capacitance C=Q V C = KAeo d K= dielectric constant A = area in m2 e0= 8.85x10-12 C2 N m2 d = distance between plates in m Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2 V C = Q V = Q therefore U = ½ QV = ½ Q2 V C C Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2 V C = Q V = Q therefore U = ½ QV = ½ Q2 V C C Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2 V C = Q V = Q therefore U = ½ QV = ½ Q2 V C C Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2 V C = Q V = Q therefore U = ½ QV = ½ Q2 V C C Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2 V C = Q V = Q therefore U = ½ QV = ½ Q2 V C C Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2 V C = Q V = Q therefore U = ½ QV = ½ Q2 V C C Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2 V C = Q V = Q therefore U = ½ QV = ½ Q2 V C C Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2 V C = Q V = Q therefore U = ½ QV = ½ Q2 V C C Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2 V C = Q V = Q therefore U = ½ QV = ½ Q2 V C C Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2 V C = Q V = Q therefore U = ½ QV = ½ Q2 V C C Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2 V C = Q V = Q therefore U = ½ QV = ½ Q2 V C C Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV2 V C = Q V = Q therefore U = ½ QV = ½ Q2 V C C Capacitance Cparallel = C1+C2+C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 = U=1.08x10-4 J What is the charged stored on each of the capacitors? CV=Q= 2x10-6F (3V) = 6x10-6C CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q 3V 12mF CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q Capacitance Cparallel = C1+C2+C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 = U=1.08x10-4 J What is the charged stored on each of the capacitors? CV=Q= 2x10-6F (3V) = 6x10-6C CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q 3V 12mF CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q Capacitance Cparallel = C1+C2+C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 = U=1.08x10-4 J What is the charged stored on each of the capacitors? CV=Q= 2x10-6F (3V) = 6x10-6C CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q 3V 12mF CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q Capacitance Cparallel = C1+C2+C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 = U=1.08x10-4 J What is the charged stored on each of the capacitors? CV=Q= 2x10-6F (3V) = 6x10-6C CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q 3V 12mF CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q Capacitance Cparallel = C1+C2+C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 = U=1.08x10-4 J What is the charged stored on each of the capacitors? CV=Q= 2x10-6F (3V) = 6x10-6C CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q 3V 12mF CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q Capacitance Cparallel = C1+C2+C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 = U=1.08x10-4 J What is the charged stored on each of the capacitors? CV=Q= 2x10-6F (3V) = 6x10-6C CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q 3V 12mF CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q Capacitance Cparallel = C1+C2+C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 = U=1.08x10-4 J What is the charged stored on each of the capacitors? CV=Q= 2x10-6F (3V) = 6x10-6C CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q 3V 12mF CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q Capacitance Cparallel = C1+C2+C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 = U=1.08x10-4 J What is the charged stored on each of the capacitors? CV=Q= 2x10-6F (3V) = 6x10-6C CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q 3V 12mF CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q Capacitance Cparallel = C1+C2+C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 = U=1.08x10-4 J What is the charged stored on each of the capacitors? CV=Q= 2x10-6F (3V) = 6x10-6C CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q 3V 12mF CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q Capacitance Cparallel = C1+C2+C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 = U=1.08x10-4 J What is the charged stored on each of the capacitors? CV=Q= 2x10-6F (3V) = 6x10-6C CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q 3V 12mF CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q Capacitance Cparallel = C1+C2+C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 = U=1.08x10-4 J What is the charged stored on each of the capacitors? CV=Q= 2x10-6F (3V) = 6x10-6C CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q 3V 12mF CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q Capacitance Cparallel = C1+C2+C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 = U=1.08x10-4 J What is the charged stored on each of the capacitors? CV=Q= 2x10-6F (3V) = 6x10-6C CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q 3V 12mF CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q Capacitance Cparallel = C1+C2+C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 = U=1.08x10-4 J What is the charged stored on each of the capacitors? CV=Q= 2x10-6F (3V) = 6x10-6C CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q 3V 12mF CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q Capacitance Cparallel = C1+C2+C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 = U=1.08x10-4 J What is the charged stored on each of the capacitors? CV=Q= 2x10-6F (3V) = 6x10-6C CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q 3V 12mF CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q Capacitance Cparallel = C1+C2+C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 12x10-6F (3V) = 36x10-6C or 3.6x10-5Q What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 12x10-6F(3V)2 = U=1.08x10-4 J What is the charged stored on each of the capacitors? CV=Q= 2x10-6F (3V) = 6x10-6C CV=Q= 4x10-6F (3V) = 12x10-6C or 1.2x10-5Q 3V 12mF CV=Q= 2x10-6F (3V) = 18x10-6C or 1.8x10-5Q Capacitance 1 =1+ 1 + 1 Cseries C1 C2 C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 1.09x10-6F (3V) = 3.27x10-6C What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 = U=1.47x10-5 J 3V 1/C = 1/2mF 1/4mF + 1/6mF 1/C = 11/12mF = 12mF/11=1.09 mF Capacitance 1 =1+ 1 + 1 Cseries C1 C2 C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 1.09x10-6F (3V) = 3.27x10-6C What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 = U=1.47x10-5 J 3V 1/C = 1/2mF 1/4mF + 1/6mF 1/C = 11/12mF = 12mF/11=1.09 mF Capacitance 1 =1+ 1 + 1 Cseries C1 C2 C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 1.09x10-6F (3V) = 3.27x10-6C What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 = U=1.47x10-5 J 3V 1/C = 1/2mF 1/4mF + 1/6mF 1/C = 11/12mF = 12mF/11=1.09 mF Capacitance 1 =1+ 1 + 1 Cseries C1 C2 C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 1.09x10-6F (3V) = 3.27x10-6C What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 = U=1.47x10-5 J 3V 1/C = 1/2mF 1/4mF + 1/6mF 1/C = 11/12mF = 12mF/11=1.09 mF Capacitance 1 =1+ 1 + 1 Cseries C1 C2 C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 1.09x10-6F (3V) = 3.27x10-6C What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 = U=1.47x10-5 J 3V 1/C = 1/2mF 1/4mF + 1/6mF 1/C = 11/12mF = 12mF/11= 1.09 mF Capacitance 1 =1+ 1 + 1 Cseries C1 C2 C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 1.09x10-6F (3V) = 3.27x10-6C What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 = U=1.47x10-5 J 3V 1/C = 1/2mF 1/4mF + 1/6mF 1/C = 11/12mF = 12mF/11= 1.09 mF Capacitance 1 =1+ 1 + 1 Cseries C1 C2 C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 1.09x10-6F (3V) = 3.27x10-6C What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 = U=1.47x10-5 J 3V 1/C = 1/2mF 1/4mF + 1/6mF 1/C = 11/12mF = 12mF/11= 1.09 mF Capacitance 1 =1+ 1 + 1 Cseries C1 C2 C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 1.09x10-6F (3V) = 3.27x10-6C What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 = U=1.47x10-5 J 3V 1/C = 1/2mF 1/4mF + 1/6mF 1/C = 11/12mF = 12mF/11= 1.09 mF Capacitance 1 =1+ 1 + 1 Cseries C1 C2 C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 1.09x10-6F (3V) = 3.27x10-6C What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 = U=1.47x10-5 J 3V 1/C = 1/2mF 1/4mF + 1/6mF 1/C = 11/12mF = 12mF/11= 1.09 mF Capacitance 1 =1+ 1 + 1 Cseries C1 C2 C3 2mF 4mF 6mF What is the total charge stored in the system? C = Q V CV = Q = 1.09x10-6F (3V) = 3.27x10-6C What is the energy stored in the system? U=1/2 QV U = ½ CV2 U= ½ 3.27x10-6F(3V)2 = U=1.47x10-5 J 3V 1/C = 1/2mF 1/4mF + 1/6mF 1/C = 11/12mF = 12mF/11= 1.09 mF