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Transcript
Proof by Contradiction
1 .Complete the following proof by contradiction to show that √2 is irrational.
π‘Ž
Assume that √2 is rational. Then √2 can be written in the form of 𝑏, where π‘Ž and 𝑏 are positive
integers without a common factor.
.β‹…. π‘Ž2 = 2𝑏2
.β‹…. 2 is a factor of π‘Ž2
.β‹…. 2 is a factor of π‘Ž, therefore π‘Ž = 2π‘˜,
where π‘˜ is an integer
[4]
2. Complete the following proof by contradiction to show that if 𝑛 is a positive integer and
3𝑛 + 2n3 is an odd number, then 𝑛 is an odd number.
We know that 3𝑛 + 2𝑛3 is an odd number.
Assume that 𝑛 is an even number, therefore n= 2π‘˜.
[2]
3. Use proof by contradiction to prove the following statement.
When π‘₯ is real and positive,
π‘₯+
49
β‰₯ 14
π‘₯
The first line of the proof is given below.
Assume that x has a real and positive value so that
π‘₯+
[4]
49
< 14
π‘₯
4. Complete the following proof by contradiction to show that √3 is irrational.
a
Assume that √3 is rational. Then we can write √3 in the form of b where π‘Ž and 𝑏 are
integers without common factors.
.β‹…. π‘Ž2 = 3𝑏2 .
.β‹…. 3 is a factor of π‘Ž2
.β‹…. 3 is a factor of π‘Ž, therefore π‘Ž = 3π‘˜, where π‘˜ is an integer.
5. Complete the following proof by contradiction to show that π‘₯ +
[4]
25
𝑋
β‰₯ 10 where π‘₯ is
real and positive.
Assume that π‘₯ +
25
π‘₯
< 10 , where π‘₯
is real and positive.
Because π‘₯ is positive, multiplying both sides of the inequation by π‘₯ gives π‘₯2 + 25 <
10π‘₯.
[4]
6. Use proof by contradiction to prove the following statement.
If π‘Ž and 𝑏 are real positive numbers, then π‘Ž + 𝑏 β‰₯ βˆšπ‘Žπ‘ .
The first line of the proof is given below
Assume that the real and positive numbers π‘Ž and 𝑏 exist so that π‘Ž + 𝑏 ≀ 2βˆšπ‘Žπ‘ .
[3]