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Proof by Contradiction 1 .Complete the following proof by contradiction to show that β2 is irrational. π Assume that β2 is rational. Then β2 can be written in the form of π, where π and π are positive integers without a common factor. .β . π2 = 2π2 .β . 2 is a factor of π2 .β . 2 is a factor of π, therefore π = 2π, where π is an integer [4] 2. Complete the following proof by contradiction to show that if π is a positive integer and 3π + 2n3 is an odd number, then π is an odd number. We know that 3π + 2π3 is an odd number. Assume that π is an even number, therefore n= 2π. [2] 3. Use proof by contradiction to prove the following statement. When π₯ is real and positive, π₯+ 49 β₯ 14 π₯ The first line of the proof is given below. Assume that x has a real and positive value so that π₯+ [4] 49 < 14 π₯ 4. Complete the following proof by contradiction to show that β3 is irrational. a Assume that β3 is rational. Then we can write β3 in the form of b where π and π are integers without common factors. .β . π2 = 3π2 . .β . 3 is a factor of π2 .β . 3 is a factor of π, therefore π = 3π, where π is an integer. 5. Complete the following proof by contradiction to show that π₯ + [4] 25 π β₯ 10 where π₯ is real and positive. Assume that π₯ + 25 π₯ < 10 , where π₯ is real and positive. Because π₯ is positive, multiplying both sides of the inequation by π₯ gives π₯2 + 25 < 10π₯. [4] 6. Use proof by contradiction to prove the following statement. If π and π are real positive numbers, then π + π β₯ βππ . The first line of the proof is given below Assume that the real and positive numbers π and π exist so that π + π β€ 2βππ . [3]