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Transcript
1
Atomic Structure
Introduction
• All substances are made up of matter and
the fundamental unit of matter is the atom.
• The atom constitutes the smallest particle of
an element which can take part in chemical
reactions and may or may not exist
2
independently.
Introduction
• Most of what is known about atomic structure
is based on basically 2 types of research:– Electrical nature of matter
– Interaction of matter with light energy
3
Dalton’s Atomic Theory
• Beginning of modern atomic theory credited
to John Dalton.
4
Dalton’s Atomic Theory
• Dalton’s model was formulated on a number
“laws” about how matter behaves in a
chemical reaction.
– These laws were based on experimental
evidence
– Observations on many chemical substances &
their reactions
– These laws are the foundation on which the
modern atomic theory is based
5
Dalton’s Atomic Theory
• Dalton formulated his theory:
– All matter is made up of atoms (small, indivisible,
indestructible, fundamental particles)
– Atoms can neither be created or destroyed (they persist
unchanged for all eternity)
– Atoms of a particular element are all alike (in size, mass
& properties)
– Atoms of different elements are different from one
another (different sizes, masses & properties)
– A chemical reaction involves either the union or the
separation of individual atoms
6
Dalton’s Atomic Theory
• We know now that Dalton’s theory is not
entirely true, for example:
– Atoms are not the most fundamental particles –
they are composed of smaller particles
– Atoms can be created or destroyed but a nuclear
process is needed to do so
• Nonetheless, Dalton’s model was superb for
his time and it laid the foundation for further
developments in atomic theory
7
Fundamental Particles
• Three fundamental particles make up atoms.
• The following table lists these particles together
with their masses and their charges.
8
The Discovery of Electrons
9
The Discovery of Electrons
• Earliest evidence for atomic structure was
supplied in the early 1800’s by the English
chemist, Humphrey Davy
• Davy passed electricity
through compounds
and noted:
– that the compounds
decomposed into elements.
– concluded that compounds
are held together by
electrical forces.
10
The Discovery of Electrons
• Most convincing evidence came from Cathode Ray
Tubes experiments performed in the late 1800’s &
early 1900’s.
– Consist of two electrodes sealed in a glass tube
containing a gas at very low pressure.
– When a voltage is applied to the cathodes a glow
discharge is emitted.
11
The Discovery of Electrons
• These “rays” are emitted from cathode (- ve
end) and travel to anode (+ve end).
– Cathode Rays must be negatively charged!
• J.J. Thomson modified the cathode ray tube
experiments in 1897 by adding two
adjustable voltage electrodes.
– Studied the amount that the cathode ray beam
was deflected by additional electric field.
12
The Discovery of Electrons
• Modifications to the basic cathode ray tube
experiment show the nature of cathode rays
(a) A cathode ray discharge tube,
showing the production of a beam
of electrons (cathode rays). The
beam is detected by observing the
glow on a flourescent screen
(b) A small object placed in front of
the beam, casts a shadow
indicating that cathode rays
travel in straight lines
13
(c) Cathode rays have a negative
electrical charge, as demonstrated
by their deflection in an electrical
field
(d) Interaction with a magnetic field
also consistent with negative
charge
(e) Cathode rays have mass, as
shown by their ability to turn a
small paddle wheel in their path.
The Discovery of Electrons
• Thomson used his modification to measure
the charge to mass ratio of electrons.
Charge to mass ratio
e/m = -1.75881 x 108 coulomb/g of e-
• Thomson named the cathode rays
electrons.
• Thomson is considered to be the
“discoverer of electrons”.
15
Model for Atomic Structure
• By early 1900s it was clear that atoms contained
regions of +ve and -ve charge
• But how these charges were distributed was still
unclear
• 1st model for the structure of the atom was
proposed by Thomson based on the following:
• Atoms contain small –ve charged
particles (e-s)
• Atoms of an element behave as if
they had no electrical charge
• So there must be something in
the atom to neutralize the –ve
electrons (protons not yet
discovered)
16
Rutherford and the Nuclear Atom
• Further insight into atomic structure was provided by Ernest Rutherford
• He has established that - particles were +ve charged particles
– They are emitted by some radioactive atoms (when they disintegrate
spontaneously)
• Bombarded thin Au foils with - particles from a radioactive source
– Gave us the basic picture of the atom’s structure.
• If Thompson’s model was
correct then any - particles
passing through the foil
would be deflected by small
angles.
• Unexpectedly most of the particles passed through the
foil with little or nor
deflections.
• A few however, were
deflected a very large angles
17
Rutherford and the Nuclear Atom
18
Rutherford and the Nuclear Atom
•
Rutherford’s major conclusions from the particle scattering experiment
1. The atom is mostly empty space.
2. It contains a very small, dense center called the
nucleus.
3. Nearly all of the atom’s mass is in the nucleus.
4. The nuclear diameter is 1/10,000 to 1/100,000
times less than atom’s radius.
19
Neutrons
• James Chadwick in 1932 analyzed the
results of -particle scattering on thin Be
films.
• Chadwick recognized existence of massive
neutral particles which he called neutrons.
– Chadwick discovered the neutron.
20
Canal Rays and Protons
• In 1886 Eugene Goldstein noted that cathode ray tube also
generated streams of positively charged particles that moved toward
the cathode.
– Particles move in opposite direction of cathode rays.
– Called “Canal Rays” because they passed through holes
(channels or canals) drilled through the negative electrode.
• Canal rays must be positive.
– Goldstein postulated the existence of a positive fundamental
particle called the “proton”.
21
Atomic Number
• The atomic number = # of protons in the nucleus.
– Sometimes given the symbol Z.
– On the periodic chart Z is the uppermost number in
each element’s box.
• In 1913 H.G.J. Moseley realized that the atomic
number determines the element .
– The elements differ from each other by the number of
protons in the nucleus.
• So… it is the number of protons that determine the identity of
an element
– The number of electrons in a neutral atom is also
equal to the atomic number.
22
Nucleon Number and Isotopes
• Nucleon number (formerly Mass number) is given
the symbol A.
• A = # of protons + # of neutrons.
– If Z = proton number
– Then A = Z + N
and N = neutron number
23
• The Standard Notation used to show mass and
proton numbers is:
Charge of
particle
Mass
number
(= p + n)
A
Z
X
C
Symbol of
the atom
(= # of p )
A
Z
E for example
12
6
48
20
C, Ca,
197
79
• Can be shortened to this symbolism.
14
63
N, Cu,
107
Ag, etc.
Au
Mass Number and Isotopes
• Isotopes are atoms of the same element but with
different neutron numbers.
– Isotopes have different masses and A values but are the
same element.
Isotopes of Hydrogen
Protium
(Hydrogen - 1)
Deuterium
(Hydrogen - 2)
Tritium
(Hydrogen - 3)
25
Mass Number and Isotopes
• The stable oxygen isotopes provide another
example.
• 16O is the most abundant stable O isotope.
• How many protons and neutrons are in 16O?
8 protons and 8 neutrons
•
17O
is the least abundant stable O isotope.
• How many protons and neutrons are in 17O?
8 protons and 9 neutrons
•
18O
is the second most abundant stable O isotope.
•How many protons and neutrons in 18O?
8 protons and 10 neutrons
26
Mass Spectrometry & Isotopic Abundances
• Identifies chemical composition of a compound or sample on the basis
of the mass-to-charge ratio of charged particles
• A gas sample at low pressure is bombarded with high-energy
electrons
– This causes electrons to be ejected from some of the gas molecules 
creating +ve ions
• Positive ions then focused into a very narrow beam and accelerated
by an electric field
• Then passes through a magnetic field which deflects the ions from
their straight path
27
Mass Spectrometry
• There are four factors which determine the extent
of deflection:
1 accelerating voltage
• Higher voltages  beams move more rapidly and deflected less
than slower moving beams produced by lower voltages.
2 magnetic field strength
• Stronger fields give more deflection
3 masses of particles
• Heavier particles deflected less than lighter ones
4 charge on particles
• Particles with higher charges interact more strongly with
magnetic fields and are thus deflected more than particles of
equal mass with small charge.
28
Mass Spectrometry
A modern mass spectrometer
29
Fig. 5-10a, p. 176
Mass Spectrometry & Isotopic Abundances
• Mass spectrum of Ne+ ions shown below.
– How do scientists determine the masses and
abundances of the isotopes of an element?
• Neon consists of 3
isotopes, of which Neon20 is the most abundant
(90.48%).
• The number by each peak
corresponds to the fraction
of all the Ne+ ions
represented by the isotope
with that mass.
30
Mass Spectrometry & Isotopic Abundances
• The mass of an atom is measured relative to the C-12 atom
– Its’ mass is defined as exactly 12 atomic mass units (amu)
• Therefore the amu is 1/12 the mass of a C-12 atom
• Example: What is the mass in amu of a 28Si atom?
– The spectrometer will measure the ratio of the mass of an 28Si atom
to 12C:
» Mass of 28Si atom
Mass of 12C atom
= 2.331411
– From this mass ratio, the isotopic mass of the 28Si can be found:
» 2.331411 x 12 amu = 27.97693 amu
– The mass of the isotope relative to the mass of the C-12 isotope
31
Table 5-3, p. 178
Isotopes
• Small differences in physical properties
• Similar chemical properties because
isotopes have same number of p and e
• Some isotopes are radioactive
– nuclear behavior of isotopes is unique
– Radioactive isotopes are biologically useful
– Example: radioactive I-131 to study thyroid
gland
33
Atomic Weight
• The relative atomic weight (also called
relative atomic mass) of an element is the
weighted average of the masses of its stable
isotopes
34
Atomic Weight
• Atoms are amazingly small
• Their masses are compared with the mass of
an atom of the carbon-12 isotope, as the
standard.
– One atom of the C-12 iostope weight exactly 12
units (Atomic mass units, amu)
– E.g. an atom of the most common isotope of Mg
weighs twice as much as one atom of C-12, its
relative isotopic mass is 24.
35
Atomic Weight
• “weighted average” e.g. Chlorine
– Cl- 35 75%
– Cl-37  25%
– If you had 100 atoms, 75 would be Cl-35 and 25
would be Cl-37
– The weighted average is closer to 35 than 37
because there are more Cl-35 than Cl-37 atoms
36
Atomic Weight
• Example: Naturally occurring Cu consists of
2 isotopes.
– It is 69.1% 63Cu with a mass of 62.9 amu,
– and 30.9% 65Cu, which has a mass of 64.9 amu.
– Calculate the atomic weight of Cu to one decimal
place.
atomic weight  (0.691)(62 .9 amu)  (0.309)(64 .9 amu)


 


63
Cu isotope
65
Cu isotope
atomic weight  63.5 amu for copper
37
Atomic Weight
• Example: The relative atomic mass of
boron is 10.811 amu. The masses of the two
naturally occurring isotopes are 510B and
11B, are 10.013 and 11.009 amu,
5
respectively. Calculate the fraction and
percentage of each isotope.
You do it!
• This problem requires a little algebra.
– A hint for this problem is x + (1-x) = 1
38
Atomic Weight
10.811 amu  x(10.013 amu)  1  x (11.009 amu)

 

10
B isotope
11
B isotope
 10.013 x  11.009 - 11.009 x  amu
10.811 - 11.009 amu  10.013 x - 11.009 x  amu
- 0.198  -0.996 x
0.199  x
39
Atomic Weight
• Note that because x is the multiplier for the
10B isotope, our solution gives us the fraction
of natural B that is 10B.
• Fraction of 10B = 0.199 and % abundance of
10B = 19.9%.
• The multiplier for 11B is (1-x) thus the fraction
of 11B is 1-0.199 = 0.801 and the %
abundance of 11B is 80.1%.
40
Questions
1. Calculations: Chemistry 9th Edition, Chapter 4,
Exercises 28 – 38.
2. What are the main points in Dalton’s atomic theory?
3. Briefly outline how the mass spectrometer works to
help determine the isotopic abundance and isotopic
41
mass. Include a diagram in your answer.