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Number Theory • Divides: b divides a if there is a whole number q such that a = qb. • Factor: b will be a factor of a. • Divisor: b is also a divisor of a. • Multiple: a is a multiple of b. Multiples • Multiples of 2 2x0, 2x1, 2x2, 2x3, 2x4,……… 0, 2, 4, 6, 8,…… Multiples of 3 3x0, 3x1, 3x2, 3x3,….. 0, 3, 6, 9,…….. Divisors or Factors • Divisors or Factors of 6: We need to find whole numbers b & q such that 6 = bq • Using arrays: 1x 6, 2x3 • Rainbow method: 1,2,3,6 Prime & Composite • Prime: a natural number that has exactly 2 different factors, namely 1 and itself is prime. • Composite: a natural number that has more than 2 different factors is composite. • One is called a unit and is neither Prime nor Composite Primes • Sieve of Eratosthenes 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 67 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 Factor Trees • • • • 180 600 675 360 Test for divisibility A number N is divisible by • 2 if the last digit is an even digit(0,2,4,6,8). • 3 if the sum of the digits is divisible by 3. • 5 if the last digit is a 0 or 5. • 6 if it is divisible by 2 & 3. • 9if the sum of the digits is divisible by 9. • 10 if the last digit is 0. Tell which of the following are divisible by 2,3,5,6,9,or10 • • • • 43,826 111,111 26,785 5,280 Divisiblity by 11 • If the difference between the sums of every other digit is divisible by 11 then the number is divisible by 11. • 34,567 • 343,244 • 92,252,191,213 Greatest Common Factor (Divisor) The Greatest Common Factor of two numbers m & n will be the number d the divides both m & n at the same time. GCF(m,n) = d GCF(18,45)= ? 18 = {1,2,3,6,9,18} 45 = {1,3,5,9,15,45} F18 F45 ={1,3,9} GCF(18,45) = 9 • GCF( 24,27) = • GCF( 14,27) = • GCF(110, 132) = Using Cuisenaire Rods • Pg 265 # 16 Least Common Multiple Least Common Multiple: the smallest common multiple of both m and n is called their Least common Multiple, LCM(m,n) LCM(9,15)= M9 = {9,18,27,36,45,54,63,72, 81,90,...} M15 = {15,30,45,60,75,90,105,…} M9 M15 = { 45,90,…} LCM(9,15) = 45 • Finding GCF & LCM by using Prime Power Representation. • Euclidean algorithm. Homework • Pg 241 # 5,6,8a,9 all,11,16,35-39 • Pg 253 # 1,5,6,7,8,9,23,24 • Pg 265 # 1,2,5,8all,9,17a,31-34