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Transcript
COLORADO STATE UNIVERSITY
ECE 332: ELECTRONIC PRINCIPLES II
HOMEWORK 7
1. For an NMOS differential pair with a
common-mode voltage ๐‘‰๐ถ๐‘€ applied,
as shown in the figure,
let ๐‘‰๐ท๐ท = ๐‘‰๐‘†๐‘† = 1.0 ๐‘‰,
๐‘˜ โ€ฒ ๐‘› = 0.4 ๐‘š๐ด/๐‘‰ 2 , (๐‘Š/๐ฟ)1,2 = 12.5,
๐‘‰๐‘ก๐‘› = 0.5 ๐‘‰, ๐ผ = 0.2๐‘š๐ด, ๐‘…๐ท = 10๐‘˜ฮฉ,
and neglect channel-length
modulation.
a) Find ๐‘‰๐‘ ๐‘Ž๐‘ก & ๐‘‰๐บ๐‘† for each transistor.
b) For ๐‘‰๐ถ๐‘€ = 0, find
๐‘‰๐‘† , ๐ผ๐ท1 , ๐ผ๐ท2 , ๐‘‰๐ท1 , and ๐‘‰๐ท2.
c) Repeat (b) for ๐‘‰๐ถ๐‘€ = +0.3 ๐‘‰.
d) Repeat (b) for ๐‘‰๐ถ๐‘€ = โˆ’0.1 ๐‘‰.
e) What is the highest value of ๐‘‰๐ถ๐‘€ for which ๐‘„1 and ๐‘„2 remain in saturation?
f) If current source I requires a minimum voltage of 0.2V across it to operate properly (i.e.
0.2V is its compliance voltage), what is the lowest value allowed for ๐‘‰๐‘† and hence for
๐‘‰๐ถ๐‘€ ?
2. For the PMOS differential amplifier shown in the
figure, let ๐‘‰๐‘ก๐‘ = โˆ’0.8 ๐‘‰ and ๐‘˜ โ€ฒ ๐‘ (๐‘Š/๐ฟ) = 4 ๐‘š๐ด/๐‘‰ 2 .
Neglect channel-length modulation.
a) For ๐‘ฃ๐บ1 = ๐‘ฃ๐บ2 = 0๐‘‰, find ๐‘‰๐‘ ๐‘Ž๐‘ก and ๐‘‰๐บ๐‘† for each of
๐‘„1 and ๐‘„2 . Also, find ๐‘‰๐‘† , ๐‘‰๐ท1 , and ๐‘‰๐ท2.
b) If the current source requires a minimum voltage
of 0.5V (compliance voltage), find the input
common-mode range.
Page 1 of 3
3. Design the circuit shown in the figure below to obtain a DC voltage of +0.2V at each of the
drains of ๐‘„1 and ๐‘„2 when๐‘ฃ๐บ1 = ๐‘ฃ๐บ2 = 0๐‘‰. Operate all transistors at ๐‘‰๐‘ ๐‘Ž๐‘ก = 0.2๐‘‰ and assume
that for the process technology in which the circuit is fabricated, ๐‘‰๐‘ก๐‘› = 0.5 ๐‘‰ and ๐œ‡๐‘› ๐ถ๐‘œ๐‘ฅ =
250๐œ‡๐ด/๐‘‰ 2 . Neglect channel-length modulation. Determine the values of ๐‘…, ๐‘…๐ท , and the ๐‘Š/๐ฟ
ratios of ๐‘„1 , ๐‘„2 , ๐‘„3 , and ๐‘„4 . What is the input common-mode voltage range for your design?
4. Design the MOS differential amplifier of the figure shown below to operate at ๐‘‰๐‘ ๐‘Ž๐‘ก = 0.25๐‘‰
and to provide a transconductance ๐‘”๐‘š = 1 ๐‘š๐ด/๐‘‰. Determine the ๐‘Š/๐ฟ ratios and the bias
current. The technology available provides ๐‘‰๐‘ก = 0.8 ๐‘‰ and ๐œ‡๐‘› ๐ถ๐‘œ๐‘ฅ = 100๐œ‡๐ด/๐‘‰ 2 .
Page 2 of 3
5. The figure below shows a circuit for a differential amplifier with an active load. Here ๐‘„1 and
๐‘„2 form the differential pair, while the current source transistor ๐‘„4 and ๐‘„5 form the active
loads for ๐‘„1 and ๐‘„2 , respectively. The DC bias circuit that establishes an appropriate DC
voltage at the drains of ๐‘„1 and ๐‘„2 is not shown. It is required to design the circuit to meet the
following specifications:
a)
b)
c)
d)
Differential gain ๐ด๐‘‘ = 80๐‘‰/๐‘‰
๐ผ๐‘…๐ธ๐น = ๐ผ = 100๐œ‡๐ด.
The DC voltage at the gates of ๐‘„6 and ๐‘„3 is +1.5V.
The DC voltage at the gates of ๐‘„7 , ๐‘„4 and ๐‘„5 is -1.5V.
The technology available is specified as follows: ๐œ‡๐‘› ๐ถ๐‘œ๐‘ฅ = 3๐œ‡๐‘ ๐ถ๐‘œ๐‘ฅ = 90๐œ‡๐ด/๐‘‰ 2 ; ๐‘‰๐‘ก๐‘› = |๐‘‰๐‘ก๐‘ | =
0.7๐‘‰, ๐‘‰๐ด๐‘› = |๐‘‰๐ด๐‘ | = 20๐‘‰. Determine the required value of ๐‘… and ๐‘Š/๐ฟ ratios for all transistors.
Also determine ๐ผ๐ท and |๐‘‰๐บ๐‘† | at which each transistor is operating. For DC bias calculations
you may neglect channel-length modulation. List the final results in a table with respect to
each transistor in the circuit.
Page 3 of 3