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Mendelelian Genetics 1 Gregor Mendel (1822-1884) Responsible for the Laws governing Inheritance of Traits 2 Gregor Johann Mendel Austrian monk Studied the inheritance of traits in pea plants Developed the laws of inheritance Mendel's work was not recognized until the turn of the 20th century 3 Gregor Johann Mendel Between 1856 and 1863, Mendel cultivated and tested some 28,000 pea plants He found that the plants' offspring retained traits of the parents Called the “Father of Genetics" 4 Site of Gregor Mendel’s experimental garden in the Czech Republic 5 Particulate Inheritance Mendel stated that physical traits are inherited as “particles” Mendel did not know that the “particles” were actually Chromosomes & DNA 6 Types of Genetic Crosses Monohybrid cross - cross involving a single trait e.g. flower color Dihybrid cross - cross involving two traits e.g. flower color & plant height 7 Punnett Square Used to help solve genetics problems 8 9 Genetic Terminology Trait - any characteristic that can be passed from parent to offspring Heredity - passing of traits from parent to offspring Genetics - study of heredity 10 Alleles - two forms of a gene (dominant & recessive) Dominant - stronger of two genes expressed in the hybrid; represented by a capital letter (R) Recessive - gene that shows up less often in a cross; represented by a lowercase letter (r) 11 Genotype - gene combination for a trait (e.g. RR, Rr, rr) Phenotype - the physical feature resulting from a genotype (e.g. red, white) 12 Genotypes Homozygous genotype - gene combination involving 2 dominant or 2 recessive genes (e.g. RR or rr); also called pure or purebred Heterozygous genotype - gene combination of one dominant & one recessive allele (e.g. Rr); also called hybrid 13 Genotype & Phenotype in Flowers Genotype of alleles: R = red flower r = yellow flower All genes occur in pairs, so 2 alleles affect a characteristic Possible combinations are: Genotypes RR Rr rr Phenotypes RED RED YELLOW 14 stop 15 Genes and Environment Determine Characteristics 16 Mendel’s Pea Plant Experiments 17 Why peas, Pisum sativum? Can be grown in a small area Produce lots of offspring Produce pure plants when allowed to self-pollinate several generations Can be artificially cross-pollinated 18 Reproduction in Flowering Plants Pollen contains sperm Produced by the stamen Ovary contains eggs Found inside the flower Pollen carries sperm to the eggs for fertilization Self-fertilization can occur in the same flower Cross-fertilization can occur between flowers 19 Mendel’s Experimental Methods Mendel hand-pollinated flowers using a paintbrush He could snip the stamens to prevent self-pollination He traced traits through the several generations 20 How Mendel Began Mendel produced pure strains by allowing the plants to selfpollinate for several generations 21 Eight Pea Plant Traits Seed shape --- Round (R) or Wrinkled (r) Seed Color ---- Yellow (Y) or Green (y) Pod Shape --- Smooth (S) or wrinkled (s) Pod Color --- Green (G) or Yellow (g) Seed Coat Color ---Gray (G) or White (g) Flower position---Axial (A) or Terminal (a) Plant Height --- Tall (T) or Short (t) Flower color --- Purple (P) or white (p) 22 23 24 Mendel’s Experimental Results 25 Did the observed ratio match the theoretical ratio? The theoretical or expected ratio of plants producing round or wrinkled seeds is 3 round :1 wrinkled Mendel’s observed ratio was 2.96:1 The discrepancy is due to statistical error The larger the sample the more nearly the results approximate to the theoretical ratio 26 Generation “Gap” Parental P1 Generation = the parental generation in a breeding experiment. F1 generation = the first-generation offspring in a breeding experiment. (1st filial generation) From breeding individuals from the P1 generation F2 generation = the second-generation offspring in a breeding experiment. (2nd filial generation) From breeding individuals from the F1 generation 27 Following the Generations Cross 2 Pure Plants TT x tt Results in all Hybrids Tt Cross 2 Hybrids get 3 Tall & 1 Short TT, Tt, tt 28 stop 29 Monohybrid Crosses 30 P1 Monohybrid Cross Trait: Seed Shape Alleles: R – Round r – Wrinkled Cross: Round seeds x Wrinkled seeds RR x rr r r R Rr Rr R Rr Rr Genotype: Rr Phenotype: Round Genotypic Ratio: All alike Phenotypic Ratio: All alike 31 P1 Monohybrid Cross Review Homozygous dominant x Homozygous recessive Offspring all Heterozygous (hybrids) Offspring called F1 generation Genotypic & Phenotypic ratio is ALL ALIKE 32 F1 Monohybrid Cross Trait: Seed Shape Alleles: R – Round r – Wrinkled Cross: Round seeds x Round seeds Rr x Rr R r R RR Rr r Rr rr Genotype: RR, Rr, rr Phenotype: Round & wrinkled G.Ratio: 1:2:1 P.Ratio: 3:1 33 F1 Monohybrid Cross Review Heterozygous x heterozygous Offspring: 25% Homozygous dominant RR 50% Heterozygous Rr 25% Homozygous Recessive rr Offspring called F2 generation Genotypic ratio is 1:2:1 Phenotypic Ratio is 3:1 34 What Do the Peas Look Like? 35 …And Now the Test Cross Mendel then crossed a pure & a hybrid from his F2 generation This is known as an F2 or test cross There are two possible testcrosses: Homozygous dominant x Hybrid Homozygous recessive x Hybrid 36 F2 Monohybrid Cross st (1 ) Trait: Seed Shape Alleles: R – Round r – Wrinkled Cross: Round seeds x Round seeds RR x Rr R r R RR Rr R RR Rr Genotype: RR, Rr Phenotype: Round Genotypic Ratio: 1:1 Phenotypic Ratio: All alike 37 F2 Monohybrid Cross (2nd) Trait: Seed Shape Alleles: R – Round r – Wrinkled Cross: Wrinkled seeds x Round seeds rr x Rr R r r Rr Rr r rr rr Genotype: Rr, rr Phenotype: Round & Wrinkled G. Ratio: 1:1 P.Ratio: 1:1 38 F2 Monohybrid Cross Review Homozygous x heterozygous(hybrid) Offspring: 50% Homozygous RR or rr 50% Heterozygous Rr Phenotypic Ratio is 1:1 Called Test Cross because the offspring have SAME genotype as parents 39 Practice Your Crosses Work the P1, F1, and both F2 Crosses. Pick 2 of the Pea Plant Traits that Mendel used. In your answer show the cross, the punnett square, and the Genotypic and Phenotypic ratios for all three crosses. 40 Mendel’s Laws 41 Results of Monohybrid Crosses Inheritable factors or genes are responsible for all heritable characteristics Phenotype is based on Genotype Each trait is based on two genes, one from the mother and the other from the father True-breeding individuals are homozygous ( both alleles) are the same 42 Law of Dominance In a cross of parents that are pure for contrasting traits, only one form of the trait will appear in the next generation. All the offspring will be heterozygous and express only the dominant trait. RR x rr yields all Rr (round seeds) 43 Law of Dominance 44 Law of Segregation During the formation of gametes (eggs or sperm), the two alleles responsible for a trait separate from each other. Alleles for a trait are then "recombined" at fertilization, producing the genotype for the traits of the offspring. 45 Applying the Law of Segregation 46 Law of Independent Assortment Alleles for different traits are distributed to sex cells (& offspring) independently of one another. This law can be illustrated using dihybrid crosses. 47 Dihybrid Cross A breeding experiment that tracks the inheritance of two traits. Mendel’s “Law of Independent Assortment” a. Each pair of alleles segregates independently during gamete formation b. Formula: 2n (n = # of heterozygotes) 48 Question: How many gametes will be produced for the following allele arrangements? Remember: 2n (n = # of heterozygotes) 1. RrYy 2. AaBbCCDd 3. MmNnOoPPQQRrssTtQq 49 Answer: 1. RrYy: 2n = 22 = 4 gametes RY Ry rY ry 2. AaBbCCDd: 2n = 23 = 8 gametes ABCD ABCd AbCD AbCd aBCD aBCd abCD abCD 3. MmNnOoPPQQRrssTtQq: 2n = 26 = 64 gametes 50 Dihybrid Cross Traits: Seed shape & Seed color Alleles: R round r wrinkled Y yellow y green RrYy RY Ry rY ry x RrYy RY Ry rY ry All possible gamete combinations 51 Dihybrid Cross RY Ry rY ry RY Ry rY ry 52 Dihybrid Cross RY RY RRYY Ry RRYy rY RrYY ry RrYy Ry rY ry RRYy RrYY RrYy RRyy RrYy Rryy RrYy rrYY rrYy Rryy rrYy rryy Round/Yellow: Round/green: 9 3 wrinkled/Yellow: 3 wrinkled/green: 1 9:3:3:1 phenotypic ratio 53 Dihybrid Cross Round/Yellow: 9 Round/green: 3 wrinkled/Yellow: 3 wrinkled/green: 1 9:3:3:1 54 Test Cross A mating between an individual of unknown genotype and a homozygous recessive individual. Example: bbC__ x bbcc BB = brown eyes Bb = brown eyes bb = blue eyes CC = curly hair Cc = curly hair cc = straight hair bC b___ bc 55 Test Cross Possible results: bc bC b___ C bbCc bbCc or bc bC b___ c bbCc bbcc 56 Summary of Mendel’s laws LAW DOMINANCE SEGREGATION INDEPENDENT ASSORTMENT PARENT CROSS OFFSPRING TT x tt tall x short 100% Tt tall Tt x Tt tall x tall 75% tall 25% short RrGg x RrGg round & green x round & green 9/16 round seeds & green pods 3/16 round seeds & yellow pods 3/16 wrinkled seeds & green pods 1/16 wrinkled seeds & yellow pods 57 Incomplete Dominance and Codominance (Exception to Mendel’s Law) 58 Incomplete Dominance F1 hybrids have an appearance somewhat in between the phenotypes of the two parental varieties. Example: snapdragons (flower) red (RR) x white (rr) r r RR = red flower rr = white flower R R 59 Incomplete Dominance r r R Rr Rr R Rr Rr produces the F1 generation All Rr = pink (heterozygous pink) 60 Incomplete Dominance 61 Codominance Two alleles are expressed (multiple alleles) in heterozygous individuals. Example: blood type 1. 2. 3. 4. type type type type A B AB O = = = = IAIA or IAi IBIB or IBi IAIB ii 62 Codominance Problem Example: homozygous male Type B (IBIB) x heterozygous female Type A (IAi) IA i IB IAIB IBi IB IAIB IBi 1/2 = IAIB 1/2 = IBi 63 Another Codominance Problem • Example: male Type O (ii) x female type AB (IAIB) IA IB i IAi IBi i IAi IBi 1/2 = IAi 1/2 = IBi 64 Codominance Question: If a boy has a blood type O and his sister has blood type AB, what are the genotypes and phenotypes of their parents? boy - type O (ii) AB (IAIB) X girl - type 65 Codominance Answer: IA IB i i IAIB ii Parents: genotypes = IAi and IBi phenotypes = A and B 66 Genetic Practice Problems 67 Breed the P1 generation tall (TT) x dwarf (tt) pea plants t t T T 68 Solution: tall (TT) vs. dwarf (tt) pea plants t t T Tt Tt produces the F1 generation T Tt Tt All Tt = tall (heterozygous tall) 69 Breed the F1 generation tall (Tt) vs. tall (Tt) pea plants T t T t 70 Solution: tall (Tt) x tall (Tt) pea plants T t T TT Tt t Tt tt produces the F2 generation 1/4 (25%) = TT 1/2 (50%) = Tt 1/4 (25%) = tt 1:2:1 genotype 3:1 phenotype 71 More Exceptions To Mendelian Genetics 72 Sex-linked Traits Traits (genes) located on the sex chromosomes Sex chromosomes are X and Y XX genotype for females XY genotype for males Many sex-linked traits carried on X chromosome 73 • Sex Linked Traits The genes for these traits are on the X chromosome, because boys only receive one X chromosome they are more likely to inherit disorders passed to them from their mother who would be a carrier. • Hemophilia and Colorblindness are sex linked traits, the punnet square below shows how a woman who is a carrier passes the trait to her son, but not her daughters. 74 75 Sex-linked Traits Example: Eye color in fruit flies Sex Chromosomes fruit fly eye color XX chromosome - female Xy chromosome - male 76 Sex-linked Trait Problem Example: Eye color in fruit flies (red-eyed male) x (white-eyed female) XRY x XrXr Remember: the Y chromosome in males does not carry traits. Xr Xr RR = red eyed Rr = red eyed R X rr = white eyed XY = male Y XX = female 77 Sex-linked Trait Solution: Xr XR XR Xr Y Xr Y Xr XR Xr Xr Y 50% red eyed female 50% white eyed male 78 Female Carriers 79 Multiple Allele Traits Traits that are controlled by more than two alleles. Blood type in humans is controlled by three alleles: A, B, and O Phenotype Genotype A AA or AO B BB or BO AB AB only O OO only 80 Examples of Blood Type Crosses 81 • Blood Transfusions Blood can only be transferred to a body of a person who's immune system will "recognize" the blood. • •• A and B are antigens on the blood that will be recognized. If the antigen is unfamiliar to the body, your body will attack and destroy the transfused blood as if it were a hostile invader (which can cause death). 82 • • • AB is the universal acceptor. A person with AB blood has both the A and B antigens already in the body. A and B blood can be transfused to the person (as well as O) and the body will recognize it and not attack. 83 • • • O is like a blank, it has no antigens. O is called the universal donor. A person can receive a transfusion from O blood without having an immune response 84 • • Polygenic Traits Traits controlled by many genes: hair color, height weight, intelligence While one gene may make only one protein, the effects of those proteins usually interact (for example widow's peak may be masked by expression of the baldness gene). 85 Polygenic Traits Novel phenotypes often result from the interactions of two genes, as in the case of the comb in chickens. The single comb is produced only by the rrpp genotype. Rose comb (b) results from R_pp. (_ can be either R or r). Pea comb (c) results from rrP_. Walnut comb, a novel phenotype, is produced when the genotype has at least one dominant of each gene (R_P_). – – –– 86 Chicken Combs 87 Sex Influenced Traits Traits are influenced by the environment. Pattern baldness affects men because testosterone activates the gene. 88 Environmentally Influenced Traits Siamese cats have dark ears and feet due to the temperature at birth. Height in humans is influenced by the environment (diet). • • 89 http://www.gwc.maricopa.edu/ class/bio202/cyberheart/ anthrt.htm 90