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THE CHEMISTRY OF ALDEHYDES AND KETONES A guide for A level students KNOCKHARDY PUBLISHING 2008 SPECIFICATIONS KNOCKHARDY PUBLISHING ALDEHYDES & KETONES INTRODUCTION This Powerpoint show is one of several produced to help students understand selected topics at AS and A2 level Chemistry. It is based on the requirements of the AQA and OCR specifications but is suitable for other examination boards. Individual students may use the material at home for revision purposes or it may be used for classroom teaching if an interactive white board is available. Accompanying notes on this, and the full range of AS and A2 topics, are available from the KNOCKHARDY SCIENCE WEBSITE at... www.knockhardy.org.uk/sci.htm Navigation is achieved by... either clicking on the grey arrows at the foot of each page or using the left and right arrow keys on the keyboard ALDEHYDES & KETONES CONTENTS • Prior knowledge • Bonding in carbonyl compounds • Structural differences • Nomenclature • Preparation • Identification • Oxidation • Nucleophilic addition • Reduction • 2,4-dinitrophenylhydrazine ALDEHYDES & KETONES Before you start it would be helpful to… • know the functional groups found in organic chemistry • know the arrangement of bonds around carbon atoms • recall and explain the polarity of covalent bonds CARBONYL COMPOUNDS - BONDING Bonding PLANAR WITH BOND ANGLES OF 120° the carbon is sp2 hybridised and three sigma (s) bonds are planar CARBONYL COMPOUNDS - BONDING Bonding the carbon is sp2 hybridised and three sigma (s) bonds are planar the unhybridised 2p orbital of carbon is at 90° to these P ORBITAL PLANAR WITH BOND ANGLES OF 120° CARBONYL COMPOUNDS - BONDING Bonding the carbon is sp2 hybridised and three sigma (s) bonds are planar the unhybridised 2p orbital of carbon is at 90° to these it overlaps with a 2p orbital of oxygen to form a pi (p) bond P ORBITAL PLANAR WITH BOND ANGLES OF 120° CARBONYL COMPOUNDS - BONDING Bonding the carbon is sp2 hybridised and three sigma (s) bonds are planar the unhybridised 2p orbital of carbon is at 90° to these it overlaps with a 2p orbital of oxygen to form a pi (p) bond P ORBITAL PLANAR WITH BOND ANGLES OF 120° ORBITAL OVERLAP CARBONYL COMPOUNDS - BONDING Bonding the carbon is sp2 hybridised and three sigma (s) bonds are planar the unhybridised 2p orbital of carbon is at 90° to these it overlaps with a 2p orbital of oxygen to form a pi (p) bond P ORBITAL PLANAR WITH BOND ANGLES OF 120° ORBITAL OVERLAP NEW ORBITAL CARBONYL COMPOUNDS - BONDING Bonding the carbon is sp2 hybridised and three sigma (s) bonds are planar the unhybridised 2p orbital of carbon is at 90° to these it overlaps with a 2p orbital of oxygen to form a pi (p) bond P ORBITAL PLANAR WITH BOND ANGLES OF 120° ORBITAL OVERLAP NEW ORBITAL as oxygen is more electronegative than carbon the bond is polar CARBONYL COMPOUNDS - STRUCTURE Structure carbonyl groups consists of a carbon-oxygen double bond the bond is polar due to the difference in electronegativity Difference ALDEHYDES - at least one H attached to the carbonyl group H CH3 C=O H C=O H CARBONYL COMPOUNDS - STRUCTURE Structure carbonyl groups consists of a carbon-oxygen double bond the bond is polar due to the difference in electronegativity Difference ALDEHYDES - at least one H attached to the carbonyl group H CH3 C=O H C=O H KETONES - two carbons attached to the carbonyl group CH3 C2H5 C=O CH3 C=O CH3 CARBONYL COMPOUNDS - FORMULAE Molecular C 3H 6O Structural C2H5CHO CH3COCH3 CH3 C2H5 C=O C=O H Displayed H CH3 H H H C C C H H Skeletal O O H H O H C C C H H O H CARBONYL COMPOUNDS - NOMENCLATURE Aldehydes C2H5CHO propanal Ketones CH3COCH3 propanone CH3CH2COCH3 butanone CH3COCH2CH2CH3 pentan-2-one CH3CH2COCH2CH3 pentan-3-one C6H5COCH3 phenylethanone CARBONYL COMPOUNDS - FORMATION ALDEHYDES Oxidation of primary (1°) alcohols RCH2OH + [O] ——> RCHO + H2O beware of further oxidation RCHO + [O] ——> RCOOH Reduction of carboxylic acids RCOOH + [H] ——> RCHO + H2O CARBONYL COMPOUNDS - FORMATION ALDEHYDES Oxidation of primary (1°) alcohols RCH2OH + [O] ——> RCHO + H2O beware of further oxidation RCHO + [O] ——> RCOOH Reduction of carboxylic acids RCOOH + [H] ——> RCHO + H2O KETONES Oxidation of secondary (2°) alcohols RCHOHR + [O] ——> RCOR + H2O CARBONYL COMPOUNDS - IDENTIFICATION Method 1 strong peak around 1400-1600 cm-1 in the infra red spectrum Method 2 formation of an orange precipitate with 2,4-dinitrophenylhydrazine Although these methods identify a carbonyl group, they cannot tell the difference between an aldehyde or a ketone. To narrow it down you must do a second test. CARBONYL COMPOUNDS - IDENTIFICATION Differentiation Tollen’s Reagent to distinguish aldehydes from ketones, use a mild oxidising agent ammoniacal silver nitrate mild oxidising agent which will oxidise aldehydes but not ketones contains the diammine silver(I) ion - [Ag(NH3)2 ]+ the silver(I) ion is reduced to silver Ag+(aq) + e¯ ——> Ag(s) the test is known as THE SILVER MIRROR TEST CARBONYL COMPOUNDS - IDENTIFICATION Differentiation Tollen’s Reagent Fehling’s Solution to distinguish aldehydes from ketones, use a mild oxidising agent ammoniacal silver nitrate mild oxidising agent which will oxidise aldehydes but not ketones contains the diammine silver(I) ion - [Ag(NH3)2 ]+ the silver(I) ion is reduced to silver Ag+(aq) + e¯ ——> Ag(s) the test is known as THE SILVER MIRROR TEST contains a copper(II) complex ion giving a blue solution on warming, it will oxidise aliphatic (but not aromatic) aldehydes the copper(II) is reduced to copper(I) a red precipitate of copper(I) oxide, Cu2O, is formed The silver mirror test is the better alternative as it works with all aldehydes Ketones do not react with Tollen’s Reagent or Fehling’s Solution CARBONYL COMPOUNDS - CHEMICAL PROPERTIES OXIDATION • • • • provides a way of differentiating between aldehydes and ketones mild oxidising agents are best aldehydes are easier to oxidise powerful oxidising agents oxidise ketones to a mixture of carboxylic acids ALDEHYDES easily oxidised to acids RCHO(l) + [O] ——> RCOOH(l) CH3CHO(l) + [O] ——> CH3COOH(l) CARBONYL COMPOUNDS - CHEMICAL PROPERTIES OXIDATION • • • • provides a way of differentiating between aldehydes and ketones mild oxidising agents are best aldehydes are easier to oxidise powerful oxidising agents oxidise ketones to a mixture of carboxylic acids ALDEHYDES easily oxidised to acids RCHO(l) + [O] ——> RCOOH(l) CH3CHO(l) + [O] ——> CH3COOH(l) KETONES oxidised under vigorous conditions to acids with fewer carbons C2H5COCH2CH3(l) + 3 [O] ——> C2H5COOH(l) + CH3COOH(l) CARBONYL COMPOUNDS - NUCLEOPHILIC ADDITION Mechanism occurs with both aldehydes and ketones involves addition to the C=O double bond unlike alkenes, they are attacked by nucleophiles attack is at the positive carbon centre due to the difference in electronegativities alkenes are non-polar and are attacked by electrophiles undergoing electrophilic addition Group Bond Polarity Attacking species Result ALKENES C=C NON-POLAR ELECTROPHILES ADDITION CARBONYLS C=O POLAR NUCLEOPHILES ADDITION CARBONYL COMPOUNDS - NUCLEOPHILIC ADDITION Reagent hydrogen cyanide - HCN (in the presence of KCN) Conditions reflux in alkaline solution Nucleophile cyanide ion CN¯ Product(s) hydroxynitrile (cyanohydrin) Equation CH3CHO Notes HCN is a weak acid and has difficulty dissociating into ions + HCN HCN ——> CH3CH(OH)CN 2-hydroxypropanenitrile H+ + CN¯ the reaction is catalysed by alkali which helps produce more of the nucleophilic CN¯ CARBONYL COMPOUNDS - NUCLEOPHILIC ADDITION Mechanism Nucleophilic addition STEP 1 Step 1 CN¯ acts as a nucleophile and attacks the slightly positive C One of the C=O bonds breaks; a pair of electrons goes onto the O CARBONYL COMPOUNDS - NUCLEOPHILIC ADDITION Mechanism Nucleophilic addition STEP 1 STEP 2 Step 1 CN¯ acts as a nucleophile and attacks the slightly positive C One of the C=O bonds breaks; a pair of electrons goes onto the O Step 2 A pair of electrons is used to form a bond with H+ Overall, there has been addition of HCN CARBONYL COMPOUNDS - NUCLEOPHILIC ADDITION Mechanism Nucleophilic addition STEP 1 STEP 2 Step 1 CN¯ acts as a nucleophile and attacks the slightly positive C One of the C=O bonds breaks; a pair of electrons goes onto the O Step 2 A pair of electrons is used to form a bond with H+ Overall, there has been addition of HCN CARBONYL COMPOUNDS - NUCLEOPHILIC ADDITION Mechanism Nucleophilic addition STEP 1 STEP 2 Step 1 CN¯ acts as a nucleophile and attacks the slightly positive C One of the C=O bonds breaks; a pair of electrons goes onto the O Step 2 A pair of electrons is used to form a bond with H+ Overall, there has been addition of HCN CARBONYL COMPOUNDS - NUCLEOPHILIC ADDITION ANIMATED MECHANISM CARBONYL COMPOUNDS - NUCLEOPHILIC ADDITION Watch out for the possibility of optical isomerism in hydroxynitriles CN¯ attacks from above CN¯ attacks from below CARBONYL COMPOUNDS - NUCLEOPHILIC ADDITION Watch out for the possibility of optical isomerism in hydroxynitriles CN¯ attacks from above CN¯ attacks from below CARBONYL COMPOUNDS - NUCLEOPHILIC ADDITION ANIMATED MECHANISM TO SHOW HOW DIFFERENT ISOMERS ARE FORMED CARBONYL COMPOUNDS - REDUCTION WITH NaBH4 Reagent sodium tetrahydridoborate(III) (sodium borohydride), NaBH4 Conditions aqueous or alcoholic solution Mechanism Nucleophilic addition (also reduction as it is addition of H¯) Nucleophile H¯ (hydride ion) CARBONYL COMPOUNDS - REDUCTION WITH NaBH4 Reagent sodium tetrahydridoborate(III) (sodium borohydride), NaBH4 Conditions aqueous or alcoholic solution Mechanism Nucleophilic addition (also reduction as it is addition of H¯) Nucleophile H¯ (hydride ion) Product(s) Alcohols Aldehydes are REDUCED to primary (1°) alcohols. Ketones are REDUCED to secondary (2°) alcohols. Equation(s) CH3CHO + 2[H] CH3COCH3 + 2[H] Notes The water provides a proton ——> ——> CH3CH2OH CH3CHOHCH3 CARBONYL COMPOUNDS - REDUCTION WITH NaBH4 Reagent sodium tetrahydridoborate(III) (sodium borohydride), NaBH4 Conditions aqueous or alcoholic solution Mechanism Nucleophilic addition (also reduction as it is addition of H¯) Nucleophile H¯ (hydride ion) Product(s) Alcohols Aldehydes are REDUCED to primary (1°) alcohols. Ketones are REDUCED to secondary (2°) alcohols. Equation(s) CH3CHO + 2[H] CH3COCH3 + 2[H] Notes The water provides a proton Question NaBH4 doesn’t reduce C=C bonds. WHY? CH2 = CHCHO + ——> ——> 2[H] CH3CH2OH CH3CHOHCH3 ———> CH2 = CHCH2OH CARBONYL COMPOUNDS - REDUCTION WITH NaBH4 Reagent sodium tetrahydridoborate(III) (sodium borohydride), NaBH4 Conditions aqueous or alcoholic solution Mechanism Nucleophilic addition (also reduction as it is addition of H¯) Nucleophile H¯ (hydride ion) CARBONYL COMPOUNDS - REDUCTION WITH NaBH4 Reagent sodium tetrahydridoborate(III) (sodium borohydride), NaBH4 Conditions aqueous or alcoholic solution Mechanism Nucleophilic addition (also reduction as it is addition of H¯) Nucleophile H¯ (hydride ion) Water is added CARBONYL COMPOUNDS - REDUCTION WITH NaBH4 Reagent sodium tetrahydridoborate(III) (sodium borohydride), NaBH4 Conditions aqueous or alcoholic solution Mechanism Nucleophilic addition (also reduction as it is addition of H¯) Nucleophile H¯ (hydride ion) Aldehyde Primary alcohol Water is added CARBONYL COMPOUNDS - REDUCTION WITH NaBH4 Reagent sodium tetrahydridoborate(III) (sodium borohydride), NaBH4 Conditions aqueous or alcoholic solution Mechanism Nucleophilic addition (also reduction as it is addition of H¯) Nucleophile H¯ (hydride ion) ANIMATED MECHANISM THE TETRAHYDRIDOBORATE(III) ION BH4 H H B atom has three electrons to share H each atom needs one electron to complete its outer shell H boron shares all 3 electrons to form 3 single covalent bonds H H B H B H H H H The hydride ion forms a dative covalent bond H B H H CARBONYL COMPOUNDS - REDUCTION WITH HYDROGEN Reagent hydrogen Conditions catalyst - nickel or platinum Reaction type Hydrogenation, reduction Product(s) Alcohols Aldehydes are REDUCED to primary (1°) alcohols. Ketones are REDUCED to secondary (2°) alcohols. Equation(s) CH3CHO + H2 CH3COCH3 + H2 Note ——> CH3CH2OH ——> CH3CHOHCH3 Hydrogen also reduces C=C bonds CH2 = CHCHO + 2H2 ——> CH3CH2CH2OH CARBONYL COMPOUNDS - REDUCTION Introduction Functional groups containing multiple bonds can be reduced C=C C=O CN Hydrogen is reduced to is reduced to is reduced to CH-CH CH-OH CH-NH2 H• H2 H+ (electrophile) H¯ (nucleophile) CARBONYL COMPOUNDS - REDUCTION Introduction Functional groups containing multiple bonds can be reduced C=C C=O CN Hydrogen Reactions is reduced to is reduced to is reduced to CH-CH CH-OH CH-NH2 H• H2 H+ (electrophile) H¯ (nucleophile) Hydrogen reduces C=C and C=O bonds CH2 = CHCHO + 4[H] ——> CH3CH2CH2OH Hydride ion H¯ reduces C=O bonds CH2 = CHCHO + 2[H] ——> CH2=CHCH2OH Explanation C=O is polar so is attacked by the nucleophilic H¯ C=C is non-polar so is not attacked by the nucleophilic H¯ CARBONYL COMPOUNDS - REDUCTION Example COMPOUND X What are the products when Compound X is reduced? H2 NaBH4 CARBONYL COMPOUNDS - REDUCTION Example What are the products when Compound X is reduced? COMPOUND X H2 NaBH4 C=O is polar so is attacked by the nucleophilic H¯ C=C is non-polar so is not attacked by the nucleophilic H¯ 2,4-DINITROPHENYLHYDRAZINE Structure C6H3(NO2)2NHNH2 Use reacts with carbonyl compounds (aldehydes and ketones) used as a simple test for aldehydes and ketones makes orange crystalline derivatives - 2,4-dinitrophenylhydrazones derivatives have sharp, well-defined melting points also used to characterise (identify) carbonyl compounds. Identification / characterisation A simple way of characterising a compound (finding out what it is) is to measure the melting point of a solid or the boiling point of a liquid. 2,4-DINITROPHENYLHYDRAZINE C6H3(NO2)2NHNH2 The following structural isomers have similar boiling points because of similar van der Waals forces and dipole-dipole interactions. They would be impossible to identify with any precision using boiling point determination. CHO CHO CHO Cl Cl Cl 2,4-DINITROPHENYLHYDRAZINE C6H3(NO2)2NHNH2 The following structural isomers have similar boiling points because of similar van der Waals forces and dipole-dipole interactions. They would be impossible to identify with any precision using boiling point determination. CHO CHO CHO Cl Cl Cl Boiling point 213°C 214°C 214°C 2,4-DINITROPHENYLHYDRAZINE C6H3(NO2)2NHNH2 The following structural isomers have similar boiling points because of similar van der Waals forces and dipole-dipole interactions. They would be impossible to identify with any precision using boiling point determination. CHO CHO CHO Cl Cl Cl Boiling point 213°C 214°C 214°C Melting point of 2,4-dnph derivative 209°C 248°C 265°C By forming the 2,4-dinitrophenylhydrazone derivative and taking its melting point, it will be easier to identify the unknown original carbonyl compound. 2,4-DINITROPHENYLHYDRAZINE C6H3(NO2)2NHNH2 The following structural isomers have similar boiling points because of similar van der Waals forces and dipole-dipole interactions. They would be impossible to identify with any precision using boiling point determination. CHO CHO CHO Cl Cl Cl Boiling point 213°C 214°C 214°C Melting point of 2,4-dnph derivative 209°C 248°C 265°C By forming the 2,4-dinitrophenylhydrazone derivative and taking its melting point, it will be easier to identify the unknown original carbonyl compound. THE CHEMISTRY OF ALDEHYDES AND KETONES THE END ©2009 JONATHAN HOPTON & KNOCKHARDY PUBLISHING