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Transcript
The Birth of Elements
[Part 1]
by
Francis Viren Fernandes
Natural Philosophy Alliance Video Conference
September 26, 2009
Copyright@2009
Acceleration, a due to gravity, g is voltage, V
m
g  a  Volts  2
s
Voltage is acceleration
Consider 511 keV for an electron
eV
V
e
511000
24

3
.
1894

10
Volts
19
1.60217653 10
c 2 107 (2.998 108 ) 2 107
24
Acceleration 


3
.
1894

10
r
2.817940325 1015
m/s2
Voltage is Acceleration
Consider the experimentally confirmed 511 KeV
value for an electron.
eV / e = V
510998.9168 / 1.60217653 x 10-19 = 3.189404583 x 1024 volts
Force = m x a
F = 9.1093826×10−31 ×3.189404583×1024 ×107 N
F = 29.05350661 N
Energy = F x r
E = 29.05350661 x 2.81790325 x 10 -15 J
E = 8.187 x 10 -14 J
eV is Heat
eVe is Energy
eV × e = m ×c2
Ether Energy = AMU Energy
1.60217653×10−19 × 3.189404583×1024 x 1.60217653×10−19 =
9.1093826×10−31 × (2.99792458×108 )2
E = 8.187 x 10 -14 J
eV IS NOT ENERGY ; eVe IS ENERGY
Feynman Apologetics
Feynman’s Blunder
An electron volt (eV), is the energy needed to move an
electron through a potential difference of one volt,
and that turns out to be about 1.6 x 10-19 J…. I am sorry
that we do that, but that's the way it is for the physicists.
R.P. Feynman
New Paradigm
e × V × e is the energy needed to accelerate a photon
mass thru its radial distance. The acceleration of a
photon is a measure of voltage. An electron is a type of
photon.
F. V Fernandes
Ohm’s Law Unveiled
V=I×R
v
a F
q
Acceleration, a as volts equals current, I the root of
force, F times resistance, R.
Resistance, R is current, I per photon mass about
one 186-seed ether or velocity per elementary
charge, qe
Proof of Ether
Current squared = force
H = I2 x R x t
511keV = I2 x v/q x t
511000 = I2 x (1.46885 x 10-13/q) x t
511000 = I2 x 916785.6776 x 9.399637032 x 10-24
I4 = (29.05350661 x 1.21 x 1044)
Force is due to ether and atomic mass
eV = I2 x R x t
Avatars of Force
•
•
•
•
•
F=mxa
F = 3 x Temperature, K x 10-7
F = Current squared, I2
F = 1.21 x 1044 N for 186-ether
F = 29.05350661 N for photo-electron
dynamics, couplets
• F = 2.9 x 10-3 / λ in Wien’s law
Hand of God
ALPHA, THE INVERSE OF 137
  0  ce / 2h
2
7
  4  10 c R10 / 2(M c )  2R / 
7
  2  R  137.036
No more relative charge
• ELEMENTARY CHARGE, e
1.86 x 10-9 kg or 1.6 x 10-19 C
• ONE COULOMB CHARGE, Q
1.16 x 1010 kg or 1.0 Coulomb
1.86x10-9 kg Ether
Unifies Electric & Gravitational Fields
Gravitational Field Source
M
1.859222909 1 0 9

 1.346611109 1 0 27 k g/m
R
1.380668038 1 0 36
Electric Field Source
(1.602176537 1 0 19 )2 
1 .8592229091 0 9 1 .3806680311 0 36 1 07
186-Ether & Planck Mass
• THE PLANCK MASS IS ETHER
CONTAINED IN AN EXPANDED 186
• IN OTHER WORDS WHEN THE
BOLTZMANN RADIUS OF 186 DIALATES
BY A FACTOR OF 137.036
Cross section of a photon
F  1.210273708  10 N
44
F  Isquared  1.210273708 1044 107 N
I  3.478898832 1018
3.478898832 1018
0 
A
36
1.38066803110
 0  2.519721434 1054  AWeber
A  8.206596204 10 70
A    R 2 137.036
Planck Length & Mass
• Here r is the Planck
length and A from the
previous slide
A
2
 r
• Utilizing the ether
constant ratio yields
the Planck mass
r 1.346611109 10
A  8.206596204 10 70
27
The Von Klitzing Constant
If we consider the wavelength of 186,
  2  r 137.036
  2  1.380668031  1036  137.036
  1.188786353  1033 m

1.188786353  1033
v 
t 4.605412826  1038
v

t
 25812.80761m / s
Momentum of 186
• 186 x VELOCITY OF VON KLITZING
• Mass x Velocity = Force x Time Period
• 1.86 x 10-9 x VRk = 7.37 x 10-51 x c2/1.38 x 10-29 x 1.0
737 Wave-Maker
The energy of 737 equals the Planck’s constant
times one second
7.37 x 10-51 x c2 = h x 1.0
1.86 x 10-9 x VRk =7.37 x 10-51 x c2/1.38x10-29 x 1.0
So, the imposed condition is 1 second for the wavemaker to exist.
PARTICLES MAKE WAVES IN THE
ETHER FIELD
• Particle:
• Wave:
q  M R 10 
2
7
λ  2R 1
• Field:
M
1.859222909 1 0 9

 1.346611109 1 0 27 k g/m
R
1.380668038 1 0 36
EM FIELD
• Electric Field, E = I/t
• Magnetic Field, B = I/r
Electric Flux
F
eV  r  E  r 
q
Input values for the classical electron radius, force in couplets {ref.1} and elementary charge ,
eV  2.817940325  1015 
29.05350661
The value of 511 keV is the electric
1.60217653  1019
eV  510998.9213
keV  511
ΦE = E A
ΦE =
ΦE =
field, E, manifesting itself through
the radius of an electron. Twice 511
keV is used in experiments for pair
production.
eV
 r2
r
eV  r
r    R 137.036
Electric flux is the electron volts through half the wavelength distance
of a photon, proton or electron
Magnetic Flux Quantum, Φ0
Φ0, Exists only at c
A property of a super current is such that the
magnetic flux passing through any area
bounded by such a current is quantized. The
quantum of magnetic flux is a physical
CODATA constant, Φ0, and is independent of
the underlying material of the current carrying
super conductor.
h
0 
2e
15
 2.067833636  10 Wb
  BA  I R  137.036
Let us consider current generated by the magnetic field, B, of
0.4 T on 0.5m length of the conductor.
I  0.4 T  0.5 m  0.2 A
Method 1: Current Squared & Gravitation
Fgrav  I2
9.8 N
F  0.008 kg 
 0.0784 N
kg
0.0784 N  0.392 A  0.2 A
[Reason for levitation]
A magnetic field, B, contributes 0.2 A and additional
input current of 0.392 A is the reason for levitation.
So, current, I, of 0.392 A is required to flow through the 0.50m conductor
placed 90 degrees to the magnetic field, B, of strength 0.40 T for a
levitation effect. [This is conventional understanding]
Proof of Ether
BROWNIAN MOTION
• UNDULATIONS OF 186 ETHER CAUSE
ATOMIC MASS TO BE IN MOTION
• UNDULATIONS OF 186 ETHER IS
CAUSED BY A PHOTON MASS
Problem
At 300 Kelvin, the speed of hydrogen gas is measured by
experiment to be 1927.31 meters per second and
demonstrates the kinetic theory of gases formula to be
correct.
m  v2  3  k  T
2 1.672622216 10 27 1927.312  3 1.38066803110 2313  300 106 107
eVe  mv2
v2
V  a  10  m  2
e
7
1
V  2  1.672622216  10  1927.31  2
e
a  4.840723482 1017 m / s 2
 27
2
F  1.859222909 10 9  4.840723482 1017  900 106 N
F  3  300 106 N
T  900 106 107 K
Momentum of the Temperature Photon
P = Mass x Velocity = Force x Time period
P = Photon mass x VRK = 3 x Temperature x 10-7 x time period of 186
1.382580326 10 37  25812.807  900 106  t
t  3.965364346 10 42 s
1
 f  2.521836363 10 41 s 1
t
2  1.672622216  1027  1927.312  3  1.380668031  1023  300
1.382580326 10 37  c 2  3 1.38066803110 36  300 1013
1.3806680311036 2
G
v
37
1.382580326 10
v 2  6.683444045 10 12
1.859222909 10 9  v 2  3 1.38066803110 36  300 1013
Acceleration of the Temperature Photon
Acceleration = VRK / time period
a = 25812.807 / 3.965364346 x 10-42
a = 6.509567532 x 1045 m/s2
Acceleration of the temperature photon reveals its mass utilizing
F = 3 x Temp x 10-7 = m x a
Proof of Ether
Black Body Radiation
λ2= 6032649.975 x 10-7m [wavelength of the temperature photon]
λ1= 1.215022737 x 10-7m [emitted light – Bohr model]
6032649.975 x 10-7 / 1.215022737 x 10-7 = 4965051.098
This dimensionless constant, 4965051.098 is the quantity appearing in
Wien’s law and Planck’s derivation.
b
T
 max
2.89776685 10 3
T
1.215022737 10 7
T  23849.50019 K
The momentum of the temperature photon
at VRK is equal to the force[ Temperature] of
186 whose frequency is the inverse of time, t.
m  c  6032649.975 10 7  h
m  3.663761067 10  42
3.663761067 10  42  25812.807  F  t
3.663761067 10  42  25812.807  23849.50019  t
t  3.965364329 10  42 s
LIGHT AND G is ether
r
G   v2
m
36
1
.
380668031

10
6.6742 10 11 
 25812.807  v
 42
3.663761067 10
v  6.861228086 10  21 m / s
r
v
t
r
 21
6.861228086 10 
3.965364329 10  42
r  2.72072691110 62 m
r 1.346611109 10 27  3.663761082 10  42 kg
Emitted Light
Wien’s Law Examined:
2.897763 × 10-3 =
λemitted × T
Energy of a photon wave = Circumference of a torus × Force of
interaction between ether and atomic mass
Energy of 186-ether wave = λemitted ×1.210273708 × 1044ether.force
1.211044
 number.of . photons.that.constitute.186
Force
186-ether wave Interacts with a
photon to cause temperature
Photon mass x c2 = e V e
Force = Photon mass x V
(Temperature)2 = Force x Ether force
2.9 x 10-3 = Temperature x Emitted Wavelength
RADIATED LIGHT & TEMPERATURE
Force, N = Temperature x 10-7 K
Mass kg
1.859222909 x 10-9
1.382580326 x 10-37
9.1093826 x 10-31
7.37249637 x 10-51
1.672622216 x 10-27
1.210273708 x 1037
900 x 106
5.929814093 x 1015
479.9176303 x 10-7
1.088804727 x 1019
During an interaction of ether with amu, force is diminished by 107
m x c x λ1 = h
2.9 x 10-3 = Temperature x 10-7 x Emitted Wavelength
(Temperature)2 = Force x Ether force
(5.929814093 x 1022)2 = 29.05350661 x 1.210273708 x 1044
1
 emitted
 4965051.098
Hydrogen at 300K
Source of Temperature
1.38066803110 36
12
G

6
.
683444

10
1.382580326 10 37
Boltzmann.radius
G
V RKV
Temperature.mass
V 2 V RKV
b
F
 max
2.89776685 10 3
F
3.219740944 10 6
T  900 106 107 N
3.219740944 1012  4965051.098  1.598617831105 m
mc  h
1.382580326 10 37  c 1.598618734 105  h
1.859222909 10 9  V 2  3  300 106 107 1.38066803110 23 10 6 10 7
1.382580326 10 37  c 2  186  V 2
MassH 21927.311487  Temp. photon.mass  c 2
186-Ether useful to quantifylevitation, eV, radial length, atomic structure, temperature
Ether mass Kg
# of particles
comprising 186
7.372496 x 10-51
AITHERON
2.521836314 x 1041
9.1093826 x 10-31
ELECTRON
2.040997717 x 1021
1.8592229 x 10-9
ETHER
1
CBR
GPS satellite
?
?
3.663761067x10-4
BOHR TEMP PHOTON
5.074629254x1032
1.6726222 x 10-27
PROTON
1.111561769 x 1018
1.38258 x 10-37
900K PHOTON
1.344748565 x 1028
THE BOHR MODEL
Current Understanding
Fernandes Model
An electron orbits a nucleus.
The electron is actually a pulsating
Rydberg photon.
Rydberg’s constant appears in Bohr’s
equation.
1
2
Kinetic energy of an electron, m e v
2
Rydberg’s constant is the wave number
of the Rydberg photon.
The angular momentum of the electron
orbit is an integral multiple of h
2
The pulsate velocity of the Rydberg
photon is 4 R
The energy of an orbit is proportional to
The electron volt energy corresponds to
an introduced photon mass which
fuses with the Rydberg photon.
Unable to account for the Fine
Structure.
Relates photo-electric conversions with
the Fine Structure Constant.
An electron is bound by a proton.
Pair production comes about by the
fusion of two photons.
Convergence of shells occurs away
from the nucleus.
The shell shrinks with increased
introduced electron volt energy.
Electron transits between stable orbits.
The electron-positron pair pulsates by a
volumetric factor of 137 cubed.
1
n2
The potential energy of the Rydberg
photon.
t
Application of the Charge Squared
Formula
For an electron:
(1.602176537  10
19 2
) 
9.1093826  10 31 kg  2.817940325  10 15  107 m
For the Rydberg photon:
(1.60217653  10 19 )2  2.425434789  10 35  R  107
R  1.058354422  10 10 m
The Corpuscular Nature of an
H-Atom
The ratio of mass [X] to the Rydberg
photon is,
1.672622216 10 27
7

6
.
896174754

10
2.425434789 10 35
8
9
.
382723128

10
The ratio of the
eV to
the 13.6056923 eV is,
9.382723128  108
 6.89617471  107
13.6056923
Pair Production-No Electron in the H-atom
Matter-Antimatter Hybrid
q 2  mass of photon  radius of photon  10 7
q 2  2.425434789  10 35  1.058354422  10 10  10 7
[for Rydberg photon]
q 2  3.421277314  10 26  0.7502956931  10 19  107
[ for 13.6 eV photon]
q 4  2.425434789  10 35  1.058354422  10 10  107 
3.421277314  10 26  0.7502956931  10 19  107
q 2  [9.1093826  10 31  2.81794029  10 15  10 7 ]
GRAVITATION CONSTANT, G
R
2
G
c
M
R
2
G
v
M
THE ETHER MODEL
SLOWED VELOCITY
F  GMm / R 2  m c 2 / R
c2 / G  M / R  1.346611109 1027 kg/m
Re 
3.794669746 1 012
1.346611109 1 0 27
 2.817940325 1 0 15 m
G  (R / M eth er )c 2  (R / M 0 r est mass electr on )v 2
M 0 c 2 M et h er v 2 
9.1093826 10 31 (2.99792458108 )2 3.794669746 1012  v 2
v  1.468852484  13 m /s
Proof of Ether
The energy of atomic mass units [Photon clusters] equals the energy of ether [186clusters].
In other words, the slowed velocity of ether yields atomic mass units – evolution.
Conversely, the atomic mass at light speed, c will yield ether – involution. Importantly, mass
is conserved, density changes, aggregation to form 186-ether occurs.
In more words, the texture of matter changes while conserving mass and increasing
density. That is why water is a changed texture of light.
Here Mo is a symbol for atomic mass. And v is tangential spin velocity of ether. Mass of
ether is obtained from mean volumetric radius x 1.346611109 x 1027 kg.
Here Mo could represent mass of our earth. Plug in the earth’s radius and get the
tangential velocity, v of the ether. This velocity will yield the measured acceleration of 9.8
m/s2 depending on the radius applied [the string of the pendulum].
M 0 c 2 M eth er v 2 
Constants
G
h
c
k
qe
c k and qe are all attributes of 186-ether
h is the energy of a 737-aitheron – 1sec
G is derived from the ether constant ratio and
formula for charge squared
IT IS IMPORTANT TO FACTOR IN ALL THE VARIABLES
BEFORE STATING THAT A CONSTANT IS CHANGING
18 known descriptors of G
10 Constants & 8 Variables
Constants
186-ether
Boltzmann radius of 186-ether
Speed of light in ether, c
Gravitation constant, G
The Von Klitzing Velocity Constant, VRK
Seeds that sprout mass, S numbers
Energy of an ether wave 2.9 x 10-3 J
Ether force 1.21 x 1044 N
The inverse hand of god 137.036
The wave-maker 7.37 x 10-51kg
Constants & Variables of G
Variables
The radius of a photon
Mass of a photon
Spin velocity of a photon
Number of 186-ether contained in a photon
Number of eV photons that comprise atomic mass units
Frequency of the 737 wave-maker
Quantum leap factor
Distance between interacting photons, particles or bodies
Ether & AMU
•
•
•
•
•
•
•
•
•
•
PxV=nxkxT
G = (r/m) x Vrk x V
F = 29.05350661 and F = 1.21 x 1044 N
I2 x I2 = F x F
eV = H = I x I x R x t
eVe = m x c2
V=IxR
Temperature photon x VRK = Ether Force x time
2.9 x 10-3 = Photon Force x Wavelengthemitted
Twin Mass: 186-ether & 186-photon
Role of 186-Twin Mass
Source of
HEAT
GRAVITY
VONKLITZING FACTOR
EM FIELD RADIATION GRAND UNIFICATION
LIGHT SPEED ETHER FORCE
LEVITATION BOLTZMANN CONSTANT
OXIDATION STATE
TEMPERATURE
FLUX
VOLTAGE
TEMPERATURE
OHMS LAW
GIVES BIRTH TO AMU
The Source of Speed of Light, c
q 1.60217653  1019
t 
I 3.478898832  1018
t  4.605412826 10 38 s
r 1.380668031 1029
c 
t 4.605412826  1038
c  2.99792458 108 m / s
Velocity Squared, v2 or c2
•
V2 appears
v RK 
in

t
G
R
M
v v photonsvRK
2
v
2
 25812.80761m / s
1.38 10
v photons
t
29
Rbolt  1.38 10
m/ s
29
m
M  Photon mass  or  amu
C2
R
G
 c2
M
M 1.859222909 1 0 9

 1.346611109 1 0 27 k g/m
R 1.380668038 1 0 36
c v photonsvRK
2
v RK 

t
 25812.80761m / s
29
1
.
38

10
v186  3.481818846 1012 
m/ s
t
1
f 186  2.521836363 10 41 s 1
t
AVOGADRO’S NUMBER
6.022141536 X 1023
ONE MOLE
The number of particles that occupy a fixed volume of
space as a gas at standard temperature and pressure.
Particles: atoms, molecules, ions
Guiding Question?
Exam question:
What is Avogadro’s number?
Explain the number with examples.[4 marks]
TOK question:
Why is Avogadro’s number so?
Explain why 1023 bananas as gas occupy the same volume
as 1023 atoms of any element. [100 marks]
ELECTROLYSIS OF WATER
Photon mass (M)
PROTON
1.672622216  1027 kg
186-ether seeds (Z)
1
OXIDE ION
2.65601778110-26 kg
2
Photon mass per 186 seed M/Z
1.672622216  1027 kg
number of particles, n
Mass in g
n M
Z
1.3280088911026 kg
7.639607603  10 21 7.639607603  10 21
1.27781774  105 kg
1.01454668 104 kg
Birth of the AMU
The ether seeds constant
A x B = S seeds
A = # of seeds that comprise a photon
B = # of seed 186-ether particles
contained in a photon
My classification of matter
1. Wave-maker :
7.37249637 x 10-51 kg at one second period
2. Temperature-maker : Force = 3 x Temperature x 10-7
ether mass x VRK = Force x time period of 186
3. Elementary charge186-ether :
1.859222909 x 10-9 kg
4. 186-ether seeds :
# x 186 seeds contained in a photon
5. eV photon mass :
like Rydberg mass 2.425434789 x 10-35 kg
6. Atomic mass units :
# x eV photon mass
FRACTAL UNIVERSE
SPHERE TUBE
The basic structure of our Universe could
be a twin mass where one mass is a tube
or torus and the other a spherical point
mass.
New Paradigm
Topic
Oxidation state
Atomic mass
Ionization energy
Current view
Paradigm shift
Loss or gain of electrons
Number of 186-ether seeds
Mass of the nucleus
Mass of a photon cluster
Applied eV removes
Pair production
shell electrons
Energy levels
Energy of electrons
Energy of applied eV
Heat
Energy
Energy of 186 ether per q
Boltzmann Constant Mole concept
Radius of 186-ether
Appears with temperature [kT] in thermodynamics
CHUCKING OUT
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ELECTRONIC CONFIGURATION
QUARK CONRIBUTION
PROTON-ELECTRON INTERACTIONS
PARTICLE CLASSIFICATION
BOND LENGTHS
TYPES OF BONDS
IN-SITU ATOMIC STRUCTURE
NON-INVASIVE METHODS
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PHOTON MASS – eV data
PHOTON CLUSTERS ABOUT SEED ETHER
SCATTERING STUDIES – HERA
SPECTROSCOPY
ELECTROLYSIS
KINETIC THEORY
THERMODYNAMICS
RF & ABLATION OF CELLS
FUNDAMENTAL FREQUENCIES
• RF induce hyperthermia in cells that we need to
ablate.
• Nano-particles heat up at a particular radio
frequency.
• Monoclonal antibodies chaperone nanoparticles to the target cells; thus subjecting a
specific volume of cells to hyperthermic
treatment.
THIS RESEARCH IS GOING GOOD AS MY TEAM ATTEMPTS
TO ABLATE BREAST CANCER & CANDIDA ALBICANS
LOOPS & SENSORS
• Anti – submarine indicator loops on the sea floor acted as a warning
system for approaching submarines in WW 2
• The heart’s magnetic field is well documented. Tell tale fluctuations
in the magnetic field of the heart can be monitored real time using
magnetic biosensors
• Superconducting loops in magnetometers is key to measuring
variations in small magnetic fields
• Superconducting loops can be achieved within the domain of
nanotechnology
• The material that is used to form loops can be doctored with more
186-ether
http://indicatorloops.com/loops.htm
PART 1
Extraordinary ether outcomes
I have unified LIGHT & G via experiment
Proven the source of levitation as ether
Unveiled OHMS LAW as GRAVITY
Solved c2 and v2
Proven the source of light speed, c in ether
Demonstrated the ether-photon interaction
Proved that Temperature is Force of the ether-photon interaction
PART 2 follows ….
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•
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Birth of Elements
Formulae that define Light and Ether
Structure of Light
Water as an example of changed light
Approach the question of composite and noncomposite matter
• Quantify the ether seeds
• Discuss the fractal universe
ACKNOWLEDGMENTS
• Thanks to David and Greg for hosting
video conferences and for input of data on
the NPA website
• Special thanks to members of the NPA for
papers, video presentations and books
that provide useful insights