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Transcript
Physics 24100
Electricity & Optics
Lecture 15 – Chapter 27 sec. 3-5
Fall 2013 Semester
Matthew Jones
Clicker Question
• Treat a lightning bolt like a long, straight wire.
• If the current in a lightning bolt is 100 kA, how
would the magnetic field 1 km away compare
with the Earth’s magnetic field (5 × 10 )?
(a) Much less
(b) Much greater
(c) About the same
(
=
2
4
2 × 10 × 10
=
~10 10
= 4 × 10 ∙
/ )
Physics Help Center Survey
PHYS Building, Rms. 11- 12
How often do you use the Help Center on average?
A.
B.
C.
D.
E.
Never
Once or at most twice a semester
Several times in a semester
Around once a week
More than once a week
Physics Help Center Survey
PHYS Building, Rms. 11- 12
How useful was your Help Center visit?
A.
B.
C.
D.
E.
I did not use the Help Center
Useless
Not very useful
Useful
Very useful
Magnetic Fields
=
4
ℓ× ̂
=
ℓ× !
4
=
4
=
=
2
2
+#
$
/
Forces on Current Carrying Wires
• Two wires carrying currents
on each other:
– Magnetic field from
%
is 0!% =
– Force on
• Conversely
– Magnetic field from
– Force on
%
is 0!
%
=
is
%
and
will exert forces
=
&' +, -ℓ, ×.̂
* ./
()
=
&' +/ -ℓ/ ×.̂
* ./
()
ℓ ×
is
%
ℓ% ×
Forces on Parallel Wires
=
0!% =
Force per unit length:
4
2%
ℓ ×
0%
2 %
=
ℓ
4
Force on Parallel Wires
I1
I2
attraction
I1
I2
repulsion
Will this loop expand
or contract?
Magnetic “Pressure”
Normal dipole magnets
~1
Superconducting dipole magnets
~5
Magnets need to withstand
about 5 tons of internal forces
without distortion.
Remember Gauss’s Law?
• Electric field:
1
1 =
4 2
̂
3
• Gauss’s Law:
37897-:
4 $5 ∙ 1
=
2
6
• If 1 is constant over the surface then we can
bring it outside the integral
– The integral is just the surface area
– This works only when there is sufficient symmetry
Gauss’s Law Applied Magnetism
• In magnetism we can have dipoles or currents
but no magnetic monopoles
• Gauss’s law:
Always zero!
37897-:
4 $5 ∙
=
=0
2
6
• One of Maxwell’s Equations:
Ampere’s Law
• But can we do something similar to calculate the
magnetic field in cases with lots of symmetry?
• Yes:
<
;
<
<
Example
• What is the magnetic field around a long, straight
wire?
• From symmetry, we expect that the magnetic field is
always azimuthal: = =5
<
;
• The path length element is also
azimuthal: ℓ = ℓ=5
4
2
<
∙ ℓ=
=
<
4
<
ℓ=
<
&' +>
).
Magnetic Field Inside a Long Straight Wire
<
Ratio of areas
inside the wire
=
( )=
=
=
2
<
2
(Inside)
2
(Outside)
Magnetic Field Inside a Solenoid
• Symmetry principles:
– The magnetic field always points along the axis of the
solenoid: = @A
– It is independent of #, except at the ends.
• Outside the solenoid, we expect
• Inside the solenoid, does
→ 0 as
→∞
depend on ?
#
Magnetic Field Inside a Solenoid
4
<
∙ ℓ=
D
E
∙ ℓ+
F
D
∙ ℓ+
F
∙ ℓ+
These will all be zero!
E
-
∙ ℓ=
<
Magnetic Field Inside a Solenoid
$ is the number of
turns per unit length.
• Enclosed current:
4
<
<
= $ ℎ
∙ ℓ = ℎ =
Make the path H
very far away, where
≈ 0.
<
Independent of
inside the solenoid.
Magnetic Field Inside a Toroid
When Ampere’s Law doesn’t Help
B can’t be factored
out of the integral.
insufficient symmetry
finite length current segment is
(unphysical)
current is not continuous
(time dependent)
Magnetic Properties of Materials
• Atoms in many materials act like magnetic dipoles.
• Magnetization is the net dipole moment per unit
volume:
!
J=
K
• In the presence of an external magnetic field, these
dipoles can start to line up with the field:
Net current inside the
material is zero. We are
left with a surface current
and therefore a magnetic
moment
Magnetization and “Bound Current”
Magnetic dipole for a current loop: ! =
$5
Magnetic moment per unit length:
= L
Magnetization:
L
J =
=
=
K
ℓ
ℓ
This is the “surface current” per unit length.
Magnetic field due to the surface current is the
same as in a solenoid:
=
$ = current per unit length
J
Magnetization and Magnetic Susceptibility
• How well do the microscopic magnetic dipoles align
with an external applied magnetic field?
• Simplest model: linear dependence on
– Magnetization: J ∝ EMM
– Magnetic field due to surface current:
J ≡ QO EMM
O =
EMM
– Magnetic susceptibility: QO
• Total magnetic field:
= EMM + O = (1 + QO )
– Relative permeability: RO
EMM
≡ RO
EMM
Magnetic Susceptibility
• Different materials react differently to external magnetic
fields:
ST > V small ST
ST < V small |ST |
ST > V large ST
Paramagnetism
aluminum, tungsten
Diamagnetism
bismuth, copper, silver
Ferromagnetism
iron, cobalt, nickel
• Dipoles in paramagnetic materials align with
EMM
• Dipoles in diamagnetic materials align opposite
EMM
• Ferromagnetic materials align strongly even in weak
EMM
Magnetic Susceptibility
Material
Bi
Ag
Al
Fe (annealed)
Permalloy
mu-metal
superconductor
ST
– 1.66 x 10–5
– 2.6 x 10–5
2.3 x 10–5
5,500
25,000
100,000
–1
Type
diamagnetic
diamagnetic
paramagnetic
ferromagnetic
ferromagnetic
ferromagnetic
diamagnetic (perfect)
Clicker Question
Same distance
• Rank the current loops in order of increasing force:
%
(1)
(2)
(3)
A.
B.
C.
D.
E.
1<2<3
2<3<1
3<1<2
3<2<1
3=2=1